Add 1 word after readlines() - python

I am still learning python and have a question about the function readlines() The following is a part of my script:
f = open("demofile.txt", "r")
text = "".join(f.readlines())
print(text)
demofile.txt contains:
This is the first line
This is the second line
This is the third line
Now I want to add a single word to this so I get:
This is the first line
This is the second line
This is the third line
Example
I thought of something easy way of doing it:
f = open("demofile.txt", "r")
text = "".join(f.readlines())."Example"
print(text)
But that doesn't work (of course) I googled and looked around here but didn't really have the good keywords to search for this issue. Hopefully someone can point me in the right direction.

.readlines() returns list you can append() to it:
with open("demofile.txt") as txt:
lines = txt.readlines()
lines.append("Example")
text = "".join(lines)
print(text)
or you can unpack the file object txt, since its an iterator to a new list with the word you wanted to add:
with open("demofile.txt") as txt:
text = "".join([*txt, "Example"])
print(text)

Firstly, the open function in python opens a file in read mode by default. Thus, you do not need to specify the mode r when opening the file. Secondly, you should always close a file after you are done with it. A with statement in python handles this for you. Moreover, instead of using . to add Example onto the end of the string, you should use the concatenation operator in python to add a newline character, \n, and the string, Example.
with open("demofile.txt") as f:
text = "".join(f.readlines()) + "\nExample"
print(text)

This should help you. While dealing with files. It is always recommended to use with open('filename','r') as f instead of f=open('filename','r'). Using ContextManager during file open is the idea that this file will be open in any case whether everything is ok or any exception is raised. And you don't need to explicitly close the file i.e f.close().
end_text='Example'
with open('test.txt','r') as f:
text=''.join(f.readlines())+'\n'+end_text
print(text)

Related

Reading through a .m File and Python keeps reading a character in the .m File as a line?

I am trying to read the text within a .m file in Python and Python keeps reading a single character within the .m file as a line when I use file.readline(). I've also had issues with trying to remove certain parts of the line before adding it to a list.
I've tried adjusting where the readline is on for loops that I have set up since I have to read through multiple files in this program. No matter where I put it, the string always comes out separated by character. I'm new to Python so I'm trying my best to learn what to do.
# Example of what I did
with open('MyFile.m') as f:
for line in f:
text = f.readline()
if text.startswith('%'):
continue
else:
my_string = text.strip("=")
my_list.append(my_string)
This has only partially worked as it will still return parts of lines that I do not want and when trying to format the output by putting spaces between new lines it output like so:
Expected: "The String"
What happened: "T h e S t r i n g"
Without your input file I've had to make some guesses here
Input file:
%
The
%
String
%
Solution:
my_list = []
with open('MyFile.m') as f:
for line in f:
if not line.startswith('%'):
my_list.append(line.strip("=").strip())
print(' '.join(my_list))
The readLine() call was unnecessary as the for loop already gets you the line. The empty if was negated to only catch the part that you cared about. Without your actual input file I can't help with the '=' part. If you have any clarifications I'd be glad to help further.
As suggested by Xander, you shouldn't call readline since the for line in f does that for you.
my_list = []
with open('MyFile.m') as f:
for line in f:
line = line.strip() # lose the \n if you want to
if line.startswith('%'):
continue
else:
my_string = line.strip("=")
my_list.append(my_string)

Checking if string is in text file is not working

I am writing in python 3.6 and am having trouble making my code match strings in a short text document. this is a simple example of the exact logic that is breaking my bigger program:
PATH = "C:\\Users\\JoshLaptop\\PycharmProjects\\practice\\commented.txt"
file = open(PATH, 'r')
words = ['bah', 'dah', 'gah', "fah", 'mah']
print(file.read().splitlines())
if 'bah' not in file.read().splitlines():
print("fail")
with the text document formatted like so:
bah
gah
fah
dah
mah
and it is indeed printing out fail each time I run this. Am I using the incorrect method of reading the data from the text document?
the issue is that you're printing print(file.read().splitlines())
so it exhausts the file, and the next call to file.read().splitlines() returns an empty list...
A better way to "grep" your pattern would be to iterate on the file lines instead of reading it fully. So if you find the string early in the file, you save time:
with open(PATH, 'r') as f:
for line in f:
if line.rstrip()=="bah":
break
else:
# else is reached when no break is called from the for loop: fail
print("fail")
The small catch here is not to forget to call line.rstrip() because file generator issues the line with the line terminator. Also, if there's a trailing space in your file, this code will still match the word (make it strip() if you want to match even with leading blanks)
If you want to match a lot of words, consider creating a set of lines:
lines = {line.rstrip() for line in f}
so your in lines call will be a lot faster.
Try it:
PATH = "C:\\Users\\JoshLaptop\\PycharmProjects\\practice\\commented.txt"
file = open(PATH, 'r')
words = file.read().splitlines()
print(words)
if 'bah' not in words:
print("fail")
You can't read the file two times.
When you do print(file.read().splitlines()), the file is read and the next call to this function will return nothing because you are already at the end of file.
PATH = "your_file"
file = open(PATH, 'r')
words = ['bah', 'dah', 'gah', "fah", 'mah']
if 'bah' not in (file.read().splitlines()) :
print("fail")
as you can see output is not 'fail' you must use one 'file.read().splitlines()' in code or save it in another variable otherwise you have an 'fail' message

In place replacement of text in a file in Python

I am using the following code to upload a file on server using FTP after editing it:
import fileinput
file = open('example.php','rb+')
for line in fileinput.input('example.php'):
if 'Original' in line :
file.write( line.replace('Original', 'Replacement'))
file.close()
There is one thing, instead of replacing the text in its original place, the code adds the replaced text at the end and the text in original place is unchanged.
Also, instead of just the replaced text, it prints out the whole line. Could anyone please tell me how to resolve these two errors?
1) The code adds the replaced text at the end and the text in original place is unchanged.
You can't replace in the body of the file because you're opening it with the + signal. This way it'll append to the end of the file.
file = open('example.php','rb+')
But this only works if you want to append to the end of the document.
To bypass this you may use seek() to navigate to the specific line and replace it. Or create 2 files: an input_file and an output_file.
2) Also, instead of just the replaced text, it prints out the whole line.
It's because you're using:
file.write( line.replace('Original', 'Replacement'))
Free Code:
I've segregated into 2 files, an inputfile and an outputfile.
First it'll open the ifile and save all lines in a list called lines.
Second, it'll read all these lines, and if 'Original' is present, it'll replace it.
After replacement, it'll save into ofile.
ifile = 'example.php'
ofile = 'example_edited.php'
with open(ifile, 'rb') as f:
lines = f.readlines()
with open(ofile, 'wb') as g:
for line in lines:
if 'Original' in line:
g.write(line.replace('Original', 'Replacement'))
Then if you want to, you may os.remove() the non-edited file with:
More Info: Tutorials Point: Python Files I/O
The second error is how the replace() method works.
It returns the entire input string, with only the specified substring replaced. See example here.
To write to a specific place in the file, you should seek() to the right position first.
I think this issue has been asked before in several places, I would do a quick search of StackOverflow.
Maybe this would help?
Replacing stuff in a file only works well if original and replacement have the same size (in bytes) then you can do
with open('example.php','rb+') as f:
pos=f.tell()
line=f.readline()
if b'Original' in line:
f.seek(pos)
f.write(line.replace(b'Original',b'Replacement'))
(In this case b'Original' and b'Replacement' do not have the same size so your file will look funny after this)
Edit:
If original and replacement are not the same size, there are different possibilities like adding bytes to fill the hole or moving everything after the line.

Remove backslash instances from a file in Python

Okay, this may sound like a stupid question, but I can't solve this problem...
I need remove all instances of backslash from downloaded file... But,
output.replace("\","")
doesn't work. Python considers "\"," a string, rather than "\" one string and "" the other one.
How can I remove backslashes?
EDIT:
New problem...
Originally, downloaded file had to be processed, which I did using:
fn = "result_cache.txt"
f = open(fn)
output = []
for line in f:
if content in line:
output.append(line)
f.close()
f = open(fn, "w")
f.writelines(output)
f.close()
output=str(output)
#irrelevant stuff
with open("result_cache.txt", "wt") as out:
out.write(output.replace("\\n","\n"))
Which worked okay, reducing file's content to only one line...
And finally ended with having this contents only:
Line of text\
Another line of text\
There\\\'s more text here\
Last line of text
I can't use the same thing again, because it would transform every line to a value in a list, leaving brackets and commas... So, I need to have:
out.write(output.replace("\\n","\n"))
out.write(output.replace("\\",""))
in the same line... How? Or is there another way?
Just escape the backslash with a backslash:
output.replace("\\","")

Delete newline / return carriage in file output

I have a wordlist that contains returns to separate each new letter. Is there a way to programatically delete each of these returns using file I/O in Python?
Edit: I know how to manipulate strings to delete returns. I want to physically edit the file so that those returns are deleted.
I'm looking for something like this:
wfile = open("wordlist.txt", "r+")
for line in wfile:
if len(line) == 0:
# note, the following is not real... this is what I'm aiming to achieve.
wfile.delete(line)
>>> string = "testing\n"
>>> string
'testing\n'
>>> string = string[:-1]
>>> string
'testing'
This basically says "chop off the last thing in the string" The : is the "slice" operator. It would be a good idea to read up on how it works as it is very useful.
EDIT
I just read your updated question. I think I understand now. You have a file, like this:
aqua:test$ cat wordlist.txt
Testing
This
Wordlist
With
Returns
Between
Lines
and you want to get rid of the empty lines. Instead of modifying the file while you're reading from it, create a new file that you can write the non-empty lines from the old file into, like so:
# script
rf = open("wordlist.txt")
wf = open("newwordlist.txt","w")
for line in rf:
newline = line.rstrip('\r\n')
wf.write(newline)
wf.write('\n') # remove to leave out line breaks
rf.close()
wf.close()
You should get:
aqua:test$ cat newwordlist.txt
Testing
This
Wordlist
With
Returns
Between
Lines
If you want something like
TestingThisWordlistWithReturnsBetweenLines
just comment out
wf.write('\n')
You can use a string's rstrip method to remove the newline characters from a string.
>>> 'something\n'.rstrip('\r\n')
>>> 'something'
The most efficient is to not specify a strip value
'\nsomething\n'.split() will strip all special characters and whitespace from the string
simply use, it solves the issue.
string.strip("\r\n")
Remove empty lines in the file:
#!/usr/bin/env python
import fileinput
for line in fileinput.input("wordlist.txt", inplace=True):
if line != '\n':
print line,
The file is moved to a backup file and standard output is directed to the input file.
'whatever\r\r\r\r\r\r\r\r\n\n\n\n\n'.translate(None, '\r\n')
returns
'whatever'
This is also a possible solution
file1 = open('myfile.txt','r')
conv_file = open("numfile.txt","w")
temp = file1.read().splitlines()
for element in temp:
conv_file.write(element)
file1.close()
conv_file.close()

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