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I am new to python, and I have just started to learn from a book that I have recently bought.
I am at the if, elif and else chapter.
I have copied the code from the book, and I ran it.
Suddenly, it says about "elif", that is a Syntax Error.
Please help
num = int(input('Please Enter A Number:'))
if num > 5:
print('Number Exceeds 5')
elif num < 5:
print('Number is Less than 5')
else:
print('Number is 5')
In Python, indentation is key. You need to make sure your indentation is proper. Please change your code as follows, it should work.
In your code elif is not a part of your if block, therefore, it should be outside it.
num = int(input('Please Enter A Number:'))
if num > 5:
print('Number Exceeds 5')
elif num < 5:
print('Number is Less than 5')
else:
print('Number is 5')
In Python indenting matters because it is used to control code execution flow.
Your if, elif, and else statements in your code should all be at the same level of indent:
num = int(input('Please Enter A Number:'))
if num > 5:
print('Number Exceeds 5')
elif num < 5:
print('Number is Less than 5')
else:
print('Number is 5')
Related
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In python I got a "TypeError: 'int' object is not callable" during execution.
I had read other posts but I still can't figure out why it is like this.
# Python code to find if a number is
# prime or not using divmod()
# Given integer
n = int(input("Enter a number"))
x = n
# Initialising counter to 0
count = 0
while x != 0:
p, q = divmod(n, x)
x -= 1
if q == 0:
count += 1
if count > 2:
print(n, 'is Not Prime')
else:
print(n, 'is Prime')
And, please note that it doesn't gives any error by replacing:
n = int(input("Enter a number")) to n = int(input("Enter a number"))
I have also provided a screenshot regarding my problem 👇
image
Answer if anybody knows, Appreciation for any suggestions and comments.
Have you tried something like this?
z = input("Enter a number")
n = int(z)
x = n
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I'm trying to create a game of last man standing in python, but when you input a number it outputs the negative version of the correct answer? Also, when i enter anything other than 1, 2, or 3, I get the error: ValueError: could not convert string to float: '(anything other than the numbers)'
any help is appreciated. Thanks!
import random
num = random.randrange(20, 30)
print ("The number is " + str(num) + ", take either one, two or three away from it!")
take = float(input("input either 1, 2 or 3: "))
newnum = take - num
if take == 1:
print(newnum)
elif take == 2:
print(newnum)
elif take == 3:
print(newnum)
else:
print("please enter either 1, 2 or 3!")
You could just use a while loop to make sure the user only inputs 1,2 or 3.
import random
num = random.randrange(20, 30)
print ("The number is " + str(num) + ", take either one, two or three away from it!")
take = None
while take not in {1,2,3}: #{} faster than ()
take = int(input("input either 1, 2 or 3: "))
print("please enter either 1, 2 or 3!")
print(num-take)
Also as the above code shows, you need to use num-take instead of vice-versa.
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def factorial(n):
if(n == 1):
fact = 1
return fact
else:
fact = a * factorial(n - 1)
return fact
a = int(input("Enter a number to find its factorial: ")
if (a > 0):
print("The factorial of", a, "is:", fact)
else:
print("Enter a positive value to find its factorial")
In the above code it tells me that - NameError name 'fact' is not defined .
Lines starting from a = int... should be outside your function. Once that is done all you need is to add fact = factorial(a).
Find the correct logic below.
def recur_factorial(n):
if n == 1:
return n
else:
return n*recur_factorial(n-1)
num = 7
# check if the number is negative
if num < 0:
print("Sorry, factorial does not exist for negative numbers")
elif num == 0:
print("The factorial of 0 is 1")
else:
print("The factorial of", num, "is", recur_factorial(num))
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I'm getting a syntax error on my 2nd while loop. Can't figure out why, any help appreciated :)
#intro
print("Welcome to my prime number detector.")
print("Provide an integer and I will determine if it is prime.")
#again loop
again = "Y"
while again == "Y":
num = (int(input("Enter an integer"))
#check for valid input
while num < 1:
num = (int(input("Enter an integer"))
#test for prime
for d in range(2,num):
if (num % d) == 0:
print(num,"is not prime.")
else:
print(num,"is prime.")
#ask again
again = intput("Do you want to play again? (Y/N)")
You are missing a closing parenthesis ) in the two of your following lines. The correct line of code is
num = (int(input("Enter an integer")))
Also, as sheepez mentioned below, your outer brackets are redundant. You can simply use
num = int(input("Enter an integer"))
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I am trying to make a random number guessing game but I cant get the if statement to check if the users input is = to the random number
import random
realNumber = random.randint(1, 50)
print(realNumber)
myNumber = print(input("Guess the number from 1 to 50: "))
if int(myNumber) == realNumber:
print("You win")
else:
print("Nope guess again")
The unintended behavior of your program is due to this line:
myNumber = print(input("Guess the number from 1 to 50: "))
Here, you are trying to assign myNumber to the return value of the print statement (Which is None) and not the value obtained from the input() statement. To fix this, simply remove the print() around the input.
myNumber = input("Guess the number from 1 to 50: ")
Hope this helped!
You don't need the print statement around input.
import random
realNumber = random.randint(1, 50)
print(realNumber)
myNumber = input("Guess the number from 1 to 50: ")
if int(myNumber) == realNumber:
print("You win")
else:
print("Nope guess again")
Note that this code will not work if the user enters something besides an integer, because the int() call will not cast correctly