python regex with multiple separators [closed] - python

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I am trying to separate all the images from the following string.
how can I get a list of images that start with "comp1/img_" and are either split by a "," or a ";"
/*jsonp*/jsonresp({"img_set":"comp1/img_23434;comp1/img_3243r43r,comp1/img_o43nfjr;comp1/img_wjfno43,comp1/img_nrejfner;comp1/img_jrenckerjv,comp1/img_23434k;comp1/img_rkfnk4n"},"fknreff\",");
so I would end up with a list like...
comp1/img_23434
comp1/img_3243r43r
comp1/img_o43nfjr
comp1/img_wjfno43
comp1/img_nrejfner
comp1/img_jrenckerjv
comp1/img_23434k
comp1/img_rkfnk4n
any help would be appreciated.
thanks


You can do this:
>>> data = '/*jsonp*/jsonresp({"img_set":"comp1/img_23434;comp1/img_3243r43r,comp1/img_o43nfjr;comp1/img_wjfno43,comp1/img_nrejfner;comp1/img_jrenckerjv,comp1/img_23434k;comp1/img_rkfnk4n"},"fknreff\",");'
>>> import re
>>> re.findall(r'comp1/img_[^;,"]+', data)
['comp1/img_23434', 'comp1/img_3243r43r', 'comp1/img_o43nfjr', 'comp1/img_wjfno43', 'comp1/img_nrejfner', 'comp1/img_jrenckerjv', 'comp1/img_23434k', 'comp1/img_rkfnk4n']

Related

data=data={...} How to delete the first data= from such strings? [closed]

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I got data=.... where I've done splitting so text.split("=") and chose the second list element.
But with my new data in this way it deletes even the data= and the "{" "}" Elements
Any suggestions?

You should choose the second element through the end of the list, then rejoin them.
text = "=".join(text.split("=")[1:])
Or you could do a string replacement:
text = text.replace("data=data=", "data=")

How to convert numbers to string with decimal and commas [closed]

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I'd like to convert a number like 1323.67 to 1.323,67, how can I do that?
I've tried this
f'{1325.76:.,2f}'
but it prints out 1,325.76
I excpected f'{1325.76:.,2f}' to be 1.325,75 but it's 1,325.76

If you can use external modules, I would suggest you to use babel
>>> from babel.numbers import format_decimal
>>> format_decimal(1323.67, locale='de_DE')
'1.323,67'

The format is
f'{1325.76:,.2f}' and not
f'{1325.76:.,2f}'
:,.2f is what you want. Which means , as separator with 2 decimal positions.

Easy way to extract multiple dates from string without spaces? [closed]

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I am looking for a way to automatically extract dates from a string, but following each other without a delimiter
For example my string is: \n-\n24-04-201923-04-201922-04-201921-04-201920-04-201919-04-201918-04-2019
How can I get this output:
24-04-2019
23-04-2019
22-04-2019
21-04-2019
20-04-2019
19-04-2019
18-04-2019
Any help would be appreciated!

Given that they're all of equal length, you can just clear the \n's then use textwrap:
import textwrap
print(textwrap.wrap(my_string, 10))
You can remove \n's using strip():
my_string = my_string.strip()

You can use this code also.
string='\n-\n24-04-201923-04-201922-04-201921-04-201920-04-201919-04-201918-04-2019'
newStr=string[3:]
for char in range(0,len(newStr),10):
print newStr[char:char+10]
Here's the output
24-04-2019
23-04-2019
22-04-2019
21-04-2019
20-04-2019
19-04-2019
18-04-2019

How to remove characters from a list. [closed]

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I have a list output:
['Go497f9te(40RAAC34)\n','G0THDU433(40RAAC33)\n']
and I want to clean it up in order to output:
[40RAAC34,40RAAC33]

If you have a string:
'hello (world)'
and want the text between the brackets, you can either use a regex:
import re
re.findall('\((.*?)\)', s)[0]
#'world'
or, if you are sure that there is only one set of brackets (i.e. no leading ) chars) then you can just use slicing:
s[s.index('(')+1:s.index(')')]
#'world'
So then you just need to throw this into a list-comprehension or similar.
l = ['Go497f9te(40RAAC34)\n','G0THDU433(40RAAC33)\n']
[s[s.index('(')+1:s.index(')')] for s in l]
#['40RAAC34', '40RAAC33']

Regex replacing part of link [closed]

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I need to write a regex, that will traverse through my file and replace each :
href='#!/api/API.
with
href='http://www.domain.com/API. . I currently have this kind of code, that will be run from console :
def replace(file, pattern, substring):
my_file = open(file)
for line in my_file:
my_file.write(line.replace(pattern, substring))
Will sending the given strings work in this case ?

So you want to replace #!/api with http://www.domain.com?
You can just do:
line.replace('#!/api','http://www.domain.com')
No need for regex.

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