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I am looking for a way to automatically extract dates from a string, but following each other without a delimiter
For example my string is: \n-\n24-04-201923-04-201922-04-201921-04-201920-04-201919-04-201918-04-2019
How can I get this output:
24-04-2019
23-04-2019
22-04-2019
21-04-2019
20-04-2019
19-04-2019
18-04-2019
Any help would be appreciated!
Given that they're all of equal length, you can just clear the \n's then use textwrap:
import textwrap
print(textwrap.wrap(my_string, 10))
You can remove \n's using strip():
my_string = my_string.strip()
You can use this code also.
string='\n-\n24-04-201923-04-201922-04-201921-04-201920-04-201919-04-201918-04-2019'
newStr=string[3:]
for char in range(0,len(newStr),10):
print newStr[char:char+10]
Here's the output
24-04-2019
23-04-2019
22-04-2019
21-04-2019
20-04-2019
19-04-2019
18-04-2019
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I'd like to convert a number like 1323.67 to 1.323,67, how can I do that?
I've tried this
f'{1325.76:.,2f}'
but it prints out 1,325.76
I excpected f'{1325.76:.,2f}' to be 1.325,75 but it's 1,325.76
If you can use external modules, I would suggest you to use babel
>>> from babel.numbers import format_decimal
>>> format_decimal(1323.67, locale='de_DE')
'1.323,67'
The format is
f'{1325.76:,.2f}' and not
f'{1325.76:.,2f}'
:,.2f is what you want. Which means , as separator with 2 decimal positions.
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I am trying to separate all the images from the following string.
how can I get a list of images that start with "comp1/img_" and are either split by a "," or a ";"
/*jsonp*/jsonresp({"img_set":"comp1/img_23434;comp1/img_3243r43r,comp1/img_o43nfjr;comp1/img_wjfno43,comp1/img_nrejfner;comp1/img_jrenckerjv,comp1/img_23434k;comp1/img_rkfnk4n"},"fknreff\",");
so I would end up with a list like...
comp1/img_23434
comp1/img_3243r43r
comp1/img_o43nfjr
comp1/img_wjfno43
comp1/img_nrejfner
comp1/img_jrenckerjv
comp1/img_23434k
comp1/img_rkfnk4n
any help would be appreciated.
thanks
You can do this:
>>> data = '/*jsonp*/jsonresp({"img_set":"comp1/img_23434;comp1/img_3243r43r,comp1/img_o43nfjr;comp1/img_wjfno43,comp1/img_nrejfner;comp1/img_jrenckerjv,comp1/img_23434k;comp1/img_rkfnk4n"},"fknreff\",");'
>>> import re
>>> re.findall(r'comp1/img_[^;,"]+', data)
['comp1/img_23434', 'comp1/img_3243r43r', 'comp1/img_o43nfjr', 'comp1/img_wjfno43', 'comp1/img_nrejfner', 'comp1/img_jrenckerjv', 'comp1/img_23434k', 'comp1/img_rkfnk4n']
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Hi I would like to get everything after the '_' using regex
For example: I have --> I want
'aaa_bbb_ccc' --> 'bbb_ccc'
'dd_aaaa_1' --> 'aaaa_1'
'*/_2d*_//' --> '2d*_//'
Is there anyway to do it?
Thanks in advance.
I rather like the split suggestion given by #Maroun in a comment above. Here is an option using re.sub:
x = "aaa_bbb_ccc"
output = re.sub(r'^[^_]+_', '', x)
print(output)
bbb_ccc
The regex does not require much explanation, and it just removes all content up to, and including, the first underscore in the input string.
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I have a list output:
['Go497f9te(40RAAC34)\n','G0THDU433(40RAAC33)\n']
and I want to clean it up in order to output:
[40RAAC34,40RAAC33]
If you have a string:
'hello (world)'
and want the text between the brackets, you can either use a regex:
import re
re.findall('\((.*?)\)', s)[0]
#'world'
or, if you are sure that there is only one set of brackets (i.e. no leading ) chars) then you can just use slicing:
s[s.index('(')+1:s.index(')')]
#'world'
So then you just need to throw this into a list-comprehension or similar.
l = ['Go497f9te(40RAAC34)\n','G0THDU433(40RAAC33)\n']
[s[s.index('(')+1:s.index(')')] for s in l]
#['40RAAC34', '40RAAC33']
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How to get what I want? For example, I have a string like this
'RC00001 C00003_C00004RC00087 C00756_C01545RC01045 C06756_C03485'
I want to get
'RC00001 C00003_C00004','RC00087 C00756_C01545','RC01045 C06756_C03485'
What should I do? I have tried many times, but I failed. Please help me! Thank you!
answer=[]
a="RC00001 C00003_C00004RC00087 C00756_C01545RC01045 C06756_C03485"
b = a.split("RC")
for i in b[1:]:
answer.append("RC%s" % (i))
print(answer)
This will output:
['RC00001 C00003_C00004', 'RC00087 C00756_C01545', 'RC01045 C06756_C03485']
If you want to achieve this using regex, you could try the following
import re
input_str = 'RC00001 C00003_C00004RC00087 C00756_C01545RC01045 C06756_C03485'
pattern = '(RC[\d+]+\s+C[\d]+_C[\d]+)'
print(re.findall(pattern, input_str))
# output
# [('RC00001 C00003_C00004', 'RC00087 C00756_C01545', 'RC01045 C06756_C03485')]
provided the format is always RC{numbers} C{numbers}