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How to get what I want? For example, I have a string like this
'RC00001 C00003_C00004RC00087 C00756_C01545RC01045 C06756_C03485'
I want to get
'RC00001 C00003_C00004','RC00087 C00756_C01545','RC01045 C06756_C03485'
What should I do? I have tried many times, but I failed. Please help me! Thank you!
answer=[]
a="RC00001 C00003_C00004RC00087 C00756_C01545RC01045 C06756_C03485"
b = a.split("RC")
for i in b[1:]:
answer.append("RC%s" % (i))
print(answer)
This will output:
['RC00001 C00003_C00004', 'RC00087 C00756_C01545', 'RC01045 C06756_C03485']
If you want to achieve this using regex, you could try the following
import re
input_str = 'RC00001 C00003_C00004RC00087 C00756_C01545RC01045 C06756_C03485'
pattern = '(RC[\d+]+\s+C[\d]+_C[\d]+)'
print(re.findall(pattern, input_str))
# output
# [('RC00001 C00003_C00004', 'RC00087 C00756_C01545', 'RC01045 C06756_C03485')]
provided the format is always RC{numbers} C{numbers}
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I need to split a really complex line for me. The line I want to split is as follows
2019.10.20-22.01.33: '10.11.111.25 9999995555884411:TechnoBeceT(69)' logged in
how can i split this like this
['2019.10.20-22.01.33', '10.11.111.25', '9999995555884411', 'logged in']
i don't need
TechnoBeceT(69) this area.
Using Regular Expression
import re
p = re.compile(r'(([\d\.-]+)(?::|\s)|(logged in))')
s = "2019.10.20-22.01.33: '10.11.111.25 9999995555884411:TechnoBeceT(69)' logged in"
q = [x[1] or x[2] for x in p.findall(s)]
print(q)
Output
['2019.10.20-22.01.33', '10.11.111.25', '9999995555884411', 'logged in']
Looks like you just need to split by ' ', ':' and 'TechnoBeceT(69)' as an appropriate regex. This existing question is probably what you need: Split string with multiple delimiters in Python
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I am trying to separate all the images from the following string.
how can I get a list of images that start with "comp1/img_" and are either split by a "," or a ";"
/*jsonp*/jsonresp({"img_set":"comp1/img_23434;comp1/img_3243r43r,comp1/img_o43nfjr;comp1/img_wjfno43,comp1/img_nrejfner;comp1/img_jrenckerjv,comp1/img_23434k;comp1/img_rkfnk4n"},"fknreff\",");
so I would end up with a list like...
comp1/img_23434
comp1/img_3243r43r
comp1/img_o43nfjr
comp1/img_wjfno43
comp1/img_nrejfner
comp1/img_jrenckerjv
comp1/img_23434k
comp1/img_rkfnk4n
any help would be appreciated.
thanks
You can do this:
>>> data = '/*jsonp*/jsonresp({"img_set":"comp1/img_23434;comp1/img_3243r43r,comp1/img_o43nfjr;comp1/img_wjfno43,comp1/img_nrejfner;comp1/img_jrenckerjv,comp1/img_23434k;comp1/img_rkfnk4n"},"fknreff\",");'
>>> import re
>>> re.findall(r'comp1/img_[^;,"]+', data)
['comp1/img_23434', 'comp1/img_3243r43r', 'comp1/img_o43nfjr', 'comp1/img_wjfno43', 'comp1/img_nrejfner', 'comp1/img_jrenckerjv', 'comp1/img_23434k', 'comp1/img_rkfnk4n']
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I am looking for a way to automatically extract dates from a string, but following each other without a delimiter
For example my string is: \n-\n24-04-201923-04-201922-04-201921-04-201920-04-201919-04-201918-04-2019
How can I get this output:
24-04-2019
23-04-2019
22-04-2019
21-04-2019
20-04-2019
19-04-2019
18-04-2019
Any help would be appreciated!
Given that they're all of equal length, you can just clear the \n's then use textwrap:
import textwrap
print(textwrap.wrap(my_string, 10))
You can remove \n's using strip():
my_string = my_string.strip()
You can use this code also.
string='\n-\n24-04-201923-04-201922-04-201921-04-201920-04-201919-04-201918-04-2019'
newStr=string[3:]
for char in range(0,len(newStr),10):
print newStr[char:char+10]
Here's the output
24-04-2019
23-04-2019
22-04-2019
21-04-2019
20-04-2019
19-04-2019
18-04-2019
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Hi I would like to get everything after the '_' using regex
For example: I have --> I want
'aaa_bbb_ccc' --> 'bbb_ccc'
'dd_aaaa_1' --> 'aaaa_1'
'*/_2d*_//' --> '2d*_//'
Is there anyway to do it?
Thanks in advance.
I rather like the split suggestion given by #Maroun in a comment above. Here is an option using re.sub:
x = "aaa_bbb_ccc"
output = re.sub(r'^[^_]+_', '', x)
print(output)
bbb_ccc
The regex does not require much explanation, and it just removes all content up to, and including, the first underscore in the input string.
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I have a string
<b>Status : Active<br>Code : C1654<br><br>Shop <a class="top"<b>Shop A</b></a></b>
And I want get Active , C1654 and Shop A.
How to do the same thing in Python?
use python re module
(you didn't explain the pattern you wanted to follow so I can just give an example that will work for the above string):
import re
results = []
reg = '.*?>.*?: (.+?)<br'
my_str = '<b>Status : Active<br>Code : C1654<br><br>Shop <a class="top"<b>Shop A</b></a></b>'
results+=re.findall(reg,my_str)
reg2 = '<a.*?<b>(.*?)</b>'
results += re.findall(reg2,my_str)
print result
>>>['Active', 'C1654', 'Shop A']
I hope I helped