I am trying to plot some meteorological data onto a map and I would like to add an image of a plane using imshow. Plotting i) the trajectory, ii) some contour-data and iii) the image, works fine. But as soon as I add a contourf-plot (see below) the image dissapears!
Any ideas how to fix this?
import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl
import cartopy.crs as crs
import cartopy.feature as cfeature
def plot_test():
#DEFINE DATA
x,y = np.meshgrid(np.linspace(0,90,100),np.linspace(0,90,100))
z = x**3 + y**3
#BEGIN FIGURE (IN THIS CASE A MAP, IM PLOTTING METEOROLOGICAL DATA)
fig = plt.figure(figsize = (6,6))
ax1 = plt.axes(projection=crs.PlateCarree(central_longitude=0))
ax1.set_extent([0,90,0,90], crs=crs.PlateCarree())
ax1.coastlines(resolution='auto', color='k')
#EXAMPLE DATA PLOTTED AS CONTOURF
v_max = int(z.max())
v_min = int(z.min())
qcs = ax1.contourf(x, y, z, cmap = "Blues", vmin = v_min, vmax = v_max)
sm = plt.cm.ScalarMappable(cmap="Blues",norm=qcs.norm)
sm._A = []
cbar = plt.colorbar(sm, ax=ax1,orientation="vertical")
cbar.ax.set_ylabel("some contourf data", rotation=90, fontsize = 15)
#PLOT IMAGE OF A PLANE (THIS IS NOT SHOWING UP ON THE PLOT!)
x0 = 50
y0 = 40
img=plt.imread("plane2.png")
ax1.imshow(img,extent=[x0,x0 - 10, y0, y0-10], label = "plane")
plt.show()
without contourf (code from above with lines 14-20 commented out):
with contourf:
Thank you 1000 times #JohanC (see comments). I simply had to place the z-order:
ax1.imshow(img, ...., zorder=3)
which made the plane show up!
I've been plotting a dataframe using the following code within a Jupyter Notebook: For comparision with older data only available on paper in the scale 0.005mm=1cm, I need to export and print the graph in the same scale: 0.005mm in the figure (both x and y-axis) have to be 1cm in the figure.
Is there any way how I can define a custom scale? For information, the x-range and y-range are not fixed, they will vary depending on the data I am loading into the dataframe.
import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
import seaborn as sns
import matplotlib.ticker as ticker
df = pd.DataFrame(np.array([[1.7, 0], [1.75, -0.012], [1.8, 0]]),
columns=['pos', 'val'])
# Plot results
sns.set()
plt.figure(figsize=(20,30))
plt.plot(df['pos'], df['val'])
ax = plt.axes()
ax.set_aspect('equal')
plt.xlabel('Position [mm]')
plt.ylabel('Höhe [mm]')
ax.xaxis.set_major_locator(ticker.MultipleLocator(0.005))
ax.yaxis.set_major_locator(ticker.MultipleLocator(0.005))
plt.show()
In a
comment
I suggested to use matplotlib.transforms — well I was wrong, the way
to go is to shamelessly steal from Matplotlib's Demo Fixed Size
Axes…
(the figure was resized by StackOverflow to fit in the post, but you
can check that the proportions are correct)
import matplotlib.pyplot as plt
from mpl_toolkits.axes_grid1 import Divider, Size
from mpl_toolkits.axes_grid1.mpl_axes import Axes
cm = lambda d: d/2.54
x, y = [1700.0, 1725.0, 1750.0], [0.0, -12.0, 0.0] # μm
dx, dy = 50.0, 12.0
# take margins into account
xmin, xmax = min(x)-dx*0.05, max(x)+dx*0.05
ymin, ymax = min(y)-dy*0.05, max(y)+dy*0.05
dx, dy = xmax-xmin, ymax-ymin
# 5 μm data == 1 cm plot
scale = 5/1
xlen, ylen = dx/scale, dy/scale
# Now we know the extents of our data and the axes dimension,
# so we can set the Figure dimensions, taking borders into account
left, right = 2, 1
bot, top = 1.5, 1.5
fig = plt.figure(
figsize=(cm(left+xlen+right), cm(bot+ylen+top)),
dpi=118)
# change bg color to show so that one can measure the figure
# and the axes when pasted into SO and do their math…
fig.set_facecolor('xkcd:grey teal')
########## Below is stolen from Matplotlib Fixed Size Axes
########## (please don't ask me…)
# Origin and size of the x axis and y axis
h = [Size.Fixed(cm(left)), Size.Fixed(cm(xlen))]
v = [Size.Fixed(cm(bot)), Size.Fixed(cm(ylen))]
divider = Divider(fig, (0.0, 0.0, 1., 1.), h, v, aspect=False)
# NB: Axes is from mpl_toolkits.axes_grid1.mpl_axes
ax = Axes(fig, divider.get_position())
ax.set_axes_locator(divider.new_locator(nx=1, ny=1))
fig.add_axes(ax)
######### Above is stolen from Matplotlib Fixed Size Axes Demo
plt.plot(x,y)
plt.grid()
ax.set(xlim=(xmin, xmax), ylim=(ymin, ymax), yticks=range(-12,1,3),
xlabel='X/μm', ylabel='Y/μm',
title='X vs Y, 1 cm on plot equals 5 μm')
fig.suptitle('Figure dimensions: w = %.2f cm, h = %.2f cm.'%(
left+xlen+right, bot+ylen+top))
fig.savefig('Figure_1.png',
# https://stackoverflow.com/a/4805178/2749397, Joe Kington's
facecolor=fig.get_facecolor(), edgecolor='none')
1 inch = 2.54 cm, so 254/0.005 = 50800 dpi
plt.figure(figsize=(20,30), dpi=50800)
I'd like to draw a lognormal distribution of a given bar plot.
Here's the code
import matplotlib.pyplot as plt
from matplotlib.pyplot import figure
import numpy as np; np.random.seed(1)
import scipy.stats as stats
import math
inter = 33
x = np.logspace(-2, 1, num=3*inter+1)
yaxis = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0.01,0.03,0.3,0.75,1.24,1.72,2.2,3.1,3.9,
4.3,4.9,5.3,5.6,5.87,5.96,6.01,5.83,5.42,4.97,4.60,4.15,3.66,3.07,2.58,2.19,1.90,1.54,1.24,1.08,0.85,0.73,
0.84,0.59,0.55,0.53,0.48,0.35,0.29,0.15,0.15,0.14,0.12,0.14,0.15,0.05,0.05,0.05,0.04,0.03,0.03,0.03, 0.02,
0.02,0.03,0.01,0.01,0.01,0.01,0.01,0.0,0.0,0.0,0.0,0.0,0.01,0,0]
fig, ax = plt.subplots()
ax.bar(x[:-1], yaxis, width=np.diff(x), align="center", ec='k', color='w')
ax.set_xscale('log')
plt.xlabel('Diameter (mm)', fontsize='12')
plt.ylabel('Percentage of Total Particles (%)', fontsize='12')
plt.ylim(0,8)
plt.xlim(0.01, 10)
fig.set_size_inches(12, 12)
plt.savefig("Test.png", dpi=300, bbox_inches='tight')
Resulting plot:
What I'm trying to do is to draw the Probability Density Function exactly like the one shown in red in the graph below:
An idea is to convert everything to logspace, with u = log10(x). Then draw the density histogram in there. And also calculate a kde in the same space. Everything gets drawn as y versus u. When we have u at a top twin axes, x can stay at the bottom. Both axes get aligned by setting the same xlims, but converted to logspace on the top axis. The top axis can be hidden to get the desired result.
import matplotlib.pyplot as plt
import numpy as np
from scipy import stats
inter = 33
u = np.linspace(-2, 1, num=3*inter+1)
x = 10**u
us = np.linspace(u[0], u[-1], 500)
yaxis = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0.01,0.03,0.3,0.75,1.24,1.72,2.2,3.1,3.9,
4.3,4.9,5.3,5.6,5.87,5.96,6.01,5.83,5.42,4.97,4.60,4.15,3.66,3.07,2.58,2.19,1.90,1.54,1.24,1.08,0.85,0.73,
0.84,0.59,0.55,0.53,0.48,0.35,0.29,0.15,0.15,0.14,0.12,0.14,0.15,0.05,0.05,0.05,0.04,0.03,0.03,0.03, 0.02,
0.02,0.03,0.01,0.01,0.01,0.01,0.01,0.0,0.0,0.0,0.0,0.0,0.01,0,0]
yaxis = np.array(yaxis)
# reconstruct data from the given frequencies
u_data = np.repeat((u[:-1] + u[1:]) / 2, (yaxis * 100).astype(np.int))
kde = stats.gaussian_kde((u[:-1]+u[1:])/2, weights=yaxis, bw_method=0.2)
total_area = (np.diff(u)*yaxis).sum() # total area of all bars; divide by this area to normalize
fig, ax = plt.subplots()
ax2 = ax.twiny()
ax2.bar(u[:-1], yaxis, width=np.diff(u), align="edge", ec='k', color='w', label='frequencies')
ax2.plot(us, total_area*kde(us), color='crimson', label='kde')
ax2.plot(us, total_area * stats.norm.pdf(us, u_data.mean(), u_data.std()), color='dodgerblue', label='lognormal')
ax2.legend()
ax.set_xscale('log')
ax.set_xlabel('Diameter (mm)', fontsize='12')
ax.set_ylabel('Percentage of Total Particles (%)', fontsize='12')
ax.set_ylim(0,8)
xlim = np.array([0.01,10])
ax.set_xlim(xlim)
ax2.set_xlim(np.log10(xlim))
ax2.set_xticks([]) # hide the ticks at the top
plt.tight_layout()
plt.show()
PS: Apparently this also can be achieved directly without explicitly using u (at the cost of being slightly more cryptic):
x = np.logspace(-2, 1, num=3*inter+1)
xs = np.logspace(-2, 1, 500)
total_area = (np.diff(np.log10(x))*yaxis).sum() # total area of all bars; divide by this area to normalize
kde = gaussian_kde((np.log10(x[:-1])+np.log10(x[1:]))/2, weights=yaxis, bw_method=0.2)
ax.bar(x[:-1], yaxis, width=np.diff(x), align="edge", ec='k', color='w')
ax.plot(xs, total_area*kde(np.log10(xs)), color='crimson')
ax.set_xscale('log')
Note that the bandwidth set for gaussian_kde is a somewhat arbitrarily value. Larger values give a more equalized curve, smaller values keep closer to the data. Some experimentation can help.
I'm currently working in a plot in which I show to datas combined.
I plot them with the following code:
plt.figure()
# Data 1
data = plt.cm.binary(data1)
data[..., 3] = 1.0 * (data1 > 0.0)
fig = plt.imshow(data, interpolation='nearest', cmap='binary', vmin=0, vmax=1, extent=(-4, 4, -4, 4))
# Plotting just the nonzero values of data2
x = numpy.linspace(-4, 4, 11)
y = numpy.linspace(-4, 4, 11)
data2_x = numpy.nonzero(data2)[0]
data2_y = numpy.nonzero(data2)[1]
pts = plt.scatter(x[data2_x], y[data2_y], marker='s', c=data2[data2_x, data2_y])
And this gives me this plot:
As can be seen in the image, my background and foreground squares are not aligned.
Both of then have the same dimension (20 x 20). I would like to have a way, if its possible, to align center with center, or corner with corner, but to have some kind of alignment.
In some grid cells it seems that I have right bottom corner alignment, in others left bottom corner alignment and in others no alignment at all, with degrades the visualization.
Any help would be appreciated.
Thank you.
As tcaswell says, your problem may be easiest to solve by defining the extent keyword for imshow.
If you give the extent keyword, the outermost pixel edges will be at the extents. For example:
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = fig.add_subplot(111)
ax.imshow(np.random.random((8, 10)), extent=(2, 6, -1, 1), interpolation='nearest', aspect='auto')
Now it is easy to calculate the center of each pixel. In X direction:
interpixel distance is (6-2) / 10 = 0.4 pixels
center of the leftmost pixel is half a pixel away from the left edge, 2 + .4/2 = 2.2
Similarly, the Y centers are at -.875 + n * 0.25.
So, by tuning the extent you can get your pixel centers wherever you want them.
An example with 20x20 data:
import matplotlib.pyplot as plt
import numpy
# create the data to be shown with "scatter"
yvec, xvec = np.meshgrid(np.linspace(-4.75, 4.75, 20), np.linspace(-4.75, 4.75, 20))
sc_data = random.random((20,20))
# create the data to be shown with "imshow" (20 pixels)
im_data = random.random((20,20))
fig = plt.figure()
ax = fig.add_subplot(111)
ax.imshow(im_data, extent=[-5,5,-5,5], interpolation='nearest', cmap=plt.cm.gray)
ax.scatter(xvec, yvec, 100*sc_data)
Notice that here the inter-pixel distance is the same for both scatter (if you have a look at xvec, all pixels are 0.5 units apart) and imshow (as the image is stretched from -5 to +5 and has 20 pixels, the pixels are .5 units apart).
here is a code where there is no alignment problem.
import matplotlib.pyplot as plt
import numpy
data1 = numpy.random.rand(10, 10)
data2 = numpy.random.rand(10, 10)
data2[data2 < 0.4] = 0.0
plt.figure()
# Plotting data1
fig = plt.imshow(data1, interpolation='nearest', cmap='binary', vmin=0.0, vmax=1.0)
# Plotting data2
data2_x = numpy.nonzero(data2)[0]
data2_y = numpy.nonzero(data2)[1]
pts = plt.scatter(data2_x, data2_y, marker='s', c=data2[data2_x, data2_y])
plt.show()
which gives a perfectly aligned combined plots:
Thus the use of additional options in your code might be the reason of the non-alignment of the combined plots.
I am trying to make a polar plot that goes 180 degrees instead of 360 in Matplotlib similar to http://www.mathworks.com/matlabcentral/fileexchange/27230-half-polar-coordinates-figure-plot-function-halfpolar in MATLAB. Any ideas?
The following works in matplotlib 2.1 or higher. There is also an example on the matplotlib page.
You may use a usual polar plot, ax = fig.add_subplot(111, polar=True) and confine the theta range. For a half polar plot
ax.set_thetamin(0)
ax.set_thetamax(180)
or for a quarter polar plot
ax.set_thetamin(0)
ax.set_thetamax(90)
Complete example:
import matplotlib.pyplot as plt
import numpy as np
theta = np.linspace(0,np.pi)
r = np.sin(theta)
fig = plt.figure()
ax = fig.add_subplot(111, polar=True)
c = ax.scatter(theta, r, c=r, s=10, cmap='hsv', alpha=0.75)
ax.set_thetamin(0)
ax.set_thetamax(180)
plt.show()
The example code in official matplotlib documentation may obscure things a little bit if someone just needs a simple quarter of half plot.
I wrote a code snippet that may help someone who is not that familiar with AxisArtists here.
"""
Reference:
1. https://gist.github.com/ycopin/3342888
2. http://matplotlib.org/mpl_toolkits/axes_grid/users/overview.html#axisartist
"""
import numpy as np
import matplotlib.pyplot as plt
from matplotlib.projections import PolarAxes
from mpl_toolkits.axisartist.floating_axes import GridHelperCurveLinear, FloatingSubplot
import mpl_toolkits.axisartist.grid_finder as gf
def generate_polar_axes():
polar_trans = PolarAxes.PolarTransform()
# Setup the axis, here we map angles in degrees to angles in radius
phi_degree = np.arange(0, 90, 10)
tlocs = phi_degree * np.pi / 180
gl1 = gf.FixedLocator(tlocs) # Positions
tf1 = gf.DictFormatter(dict(zip(tlocs, map(str, phi_degree))))
# Standard deviation axis extent
radius_min = 0
radius_max = 1
# Set up the axes range in the parameter "extremes"
ghelper = GridHelperCurveLinear(polar_trans, extremes=(0, np.pi / 2, # 1st quadrant
radius_min, radius_max),
grid_locator1=gl1,
tick_formatter1=tf1,
)
figure = plt.figure()
floating_ax = FloatingSubplot(figure, 111, grid_helper=ghelper)
figure.add_subplot(floating_ax)
# Adjust axes
floating_ax.axis["top"].set_axis_direction("bottom") # "Angle axis"
floating_ax.axis["top"].toggle(ticklabels=True, label=True)
floating_ax.axis["top"].major_ticklabels.set_axis_direction("top")
floating_ax.axis["top"].label.set_axis_direction("top")
floating_ax.axis["top"].label.set_text("angle (deg)")
floating_ax.axis["left"].set_axis_direction("bottom") # "X axis"
floating_ax.axis["left"].label.set_text("radius")
floating_ax.axis["right"].set_axis_direction("top") # "Y axis"
floating_ax.axis["right"].toggle(ticklabels=True)
floating_ax.axis["right"].major_ticklabels.set_axis_direction("left")
floating_ax.axis["bottom"].set_visible(False) # Useless
# Contours along standard deviations
floating_ax.grid(True)
floating_ax.set_title("Quarter polar plot")
data_ax = floating_ax.get_aux_axes(polar_trans) # return the axes that can be plotted on
return figure, data_ax
if __name__ == "__main__":
# Plot data onto the defined polar axes
fig, ax = generate_polar_axes()
theta = np.random.rand(10) * np.pi / 2
radius = np.random.rand(10)
ax.scatter(theta, radius)
fig.savefig("test.png")