We Keep Coding

Run a loop while waiting for a user input

I want to run a loop in my script while the user has not input anything. But when they have input something I want the loop to break.
The issue I am currently having is that when using the input() function, the script will stop and wait for an input, but I want to run another part of the script while waiting for the user input.
I have tried using try: with a raw_input():
while True:
try:
print('SCAN BARCODE')
userInput= raw_input()
#doing something with input
except:
#run this while there is no input
With this, I find that whatever is in the except: will always run, but it will not run try: even when there is a user input. If I change raw_input() to input() the script just waits at input() and doesn't run anything in the except:.
How do I achieve what I am after?

you can use python threads:
from threading import Thread
import time
thread_running = True
def my_forever_while():
global thread_running
start_time = time.time()
# run this while there is no input
while thread_running:
time.sleep(0.1)
if time.time() - start_time >= 5:
start_time = time.time()
print('Another 5 seconds has passed')
def take_input():
user_input = input('Type user input: ')
# doing something with the input
print('The user input is: ', user_input)
if __name__ == '__main__':
t1 = Thread(target=my_forever_while)
t2 = Thread(target=take_input)
t1.start()
t2.start()
t2.join() # interpreter will wait until your process get completed or terminated
thread_running = False
print('The end')
In my example you have 2 threads, the first thread is up and executes code until you have some input from the user, thread 2 is waiting for some input from the user. After you got the user input thread 1 and 2 will stop.

It simple bro u use flag boolean values
Flag = True
while Flag:
try:
Print('scan bar code')
User_inp = input()
if User_inp != '':
Flag = False
Except:
Print('except part')

I suggest you to look for select
it allow you to check if a file descriptor is ready for read/write/expect operation

How to stop and start a thread at will

So I'm doing some testing with threads and I realised I could not stop and then start a thread. I could stop it, but starting it again was the issue.I want a script that adds 1 to a var when it is on then its stops when off by pressing shift to turn on and off.I have the detecting shift working (it is on another part of my code), but I just need to find out how to stop and start threadsHere is my test code:
from threading import Thread as th
import time as t
var = 0
def testDef():
global var
var += 1:
t.sleep(1)
test = th(target = testDef)
test.start()
while True:
menu = input("On, Off, Show Var")
if menu == "On":
test.start()
elif menu == "Off":
test._stop():
elif menu == "S":
print(var)
I know there are a few errors, but I mainly need the on and off threading to work.
Thanks, Jeff.

As far as I know, you can't actually stop and restart a thread as you can't use test.start() when the method has been terminated. However, you may be wondering to something similar by using threading.Condition to pause and later resume the execution.
You can read more about it in the documentation.
There is also an error in var += 1:, change it to var += 1

Here's a simple example on how to use threading.Event to enable two threads to communicate. This works by setting the internal flag of the Event to either True or False. While this internal flag is False you can ask thread a to wait (effectively block, which is not very efficient by the way). Then we use the two timers (b, c) to simulate a shift press every 5 seconds. In order to release a we set the event (internal flag = True). 5 seconds later, we clear the value of the internal flag and this will make thread a to block again.
import threading
def do(event):
flag = True
while flag:
if not event.isSet():
print "blocking"
event.wait()
else:
print "resuming"
def pressShift(event, enable):
print "Shift pressed"
if enable:
event.set()
else:
event.clear()
def main():
event = threading.Event()
a = threading.Thread(target=do, args=(event,))
b = threading.Timer(5, pressShift, args=(event, True)).start()
c = threading.Timer(10, pressShift, args=(event, False)).start()
a.start()
a.join()
if __name__ == "__main__":
main()

You cannot restart a thread that has already been started. What you can do, however, is to create another thread.
from threading import Thread as th
import time as t
var = 0
def testDef():
global var
var += 1
t.sleep(1)
test = th(target = testDef)
test.start()
while True:
menu = input("On, Off, Show Var")
if menu == "On":
test = th(target = testDef)
test.start()
elif menu == "Off":
test._stop()
elif menu == "S":
print(var)

Use an event object like this post, and check that event in your target functoin. Also, you need a new thread each time you re-start. The code shown below adds some debugging that should be useful. (Another approach is to build a custom stop function.)
import logging
import threading
import time as t
var = 0
logging.basicConfig(level=logging.DEBUG,
format='[%(levelname)s] (%(threadName)-10s) %(message)s',
)
def testDef(stop_event):
global var
print 'Thread Running', var
# inThread.stop()
while not stop_event.isSet():
var += 1
logging.debug('Var is %i' % var)
t.sleep(1)
# Use an event to track user input
testStopEvent = threading.Event()
testStopEvent.clear()
test = threading.Thread(name = 'test', target=testDef, args=((testStopEvent,)))
test.setDaemon(True)
while True:
menu = input("On = 1, Off = 2, Show Var = 3")
if menu == 1:
test.start()
elif menu == 2:
testStopEvent.set()
test.join() # Wait for the thread to finish
test = threading.Thread(target=testDef, args=((testStopEvent,))) # "re-start" thread
testStopEvent.clear() # Reset the stop event
elif menu == 3:
print(var)

how to make a timer to a function

def choosePath():
path = ""
while path != "e" and path !="n":
print('\nWhich way do you go (n, s, e, w):\n')
t = Timer(1 * 1, timeout)
t.start()
answer = input(path)
path = path.lower()
if path =="e":
station()
elif path =="n":
estate()
elif path =="s":
building()
else:
print("\nYou return the way you came are but are soon caught by Mansons and assimilated.\n")
return path
I have received this code and want to add a timer that if answer isn't done with a certain amount of time it says gameover.

You want the Timer class in the threading module.
import threading
t = threading.Timer(<delay in secs>, <callback>, [<function args>])
t.start()
If the user has selected an option in time call t.cancel()

You need to start the timer outside of the while loop. There are also several ways to implement a timer, but this should work (I simplified it, you'll need to adjust it to your business logic)
import time
start_time = datetime.now()
max_time_allowed = 45
while path != "e" and path !="n":
#Business logic here
current_time= datetime.now()
if current_time-start_time > max_time_allowed:
return

Try creating another thread to track the time then update a global boolean:
from threading import Thread
from time import sleep
timeIsUp = False
threadKill = False
def answerTime(self):
sleep(self)
if threadKill = True:
self._is_running = False
else:
timeIsUp = True
self._is_running = False
thread = Thread(target = answerTime, args = (10)
And now you could make your main code have an additional statement in the while loop:
while path != "e" and path !="n" and timeIsUp==False:
...
if path =="e":
station()
threadKill=True
elif path =="n":
estate()
threadKill=True
elif path =="s":
building()
threadKill=True
else:
print("Time is up")

Pause and resume a running script in Python 3.42 in Windows

I'm new to Python and have been googling for a couple of days and read all I can find on this forum. Might be that I don't understand it all but I haven't found a solution to my problem yet. Ask for forgiveness already if there's an answer already to my problem, then I haven't understood it.
I want to make a Pause function for my program Tennismatch. The program will when it's being run print the score of a tennis match like this: "15-0, 15-15 etc ongoing till the match ends. It will print the score line by line.
I want the user to be able to pause after x number of balls, games, etc. So I don't know when the user wants to pause and after the user has paused I want the user to be able to resume the tennismatch where it was.
Have seen the time.sleep() but as I have understood it you must know when you want to pause to use this and it also ain't an indefinetie pause like I want. With input() it's the same.
Am going to make a GUI later on when the code is finished. Happy for anything that leads me to solving my problem.
I use Windows and Python 3.42 and run the program in Shell.
A piece of the code (haven't written it all yet, it's more of a general situation when something is being printed line after line for some time and want to be able do pause in the CIL:
#self.__points = [0,0]
def playGame(self):
if self.server == True: #self.server is either True or False when someone calls playGame()
server = self.player_1.get_win_serve() #self.player_1 = an object of a class Player():
else:
server = self.player_2.get_win_serve() #get_win_serve() method returns the probability to win his serv (1-0)
while (0 < self.__points[0] - self.__points[1] >= 2 or 0 < self.__points[1] - self.__points[0] >= 2) and (self.__points[1] >= 4 or self.__points[0] >= 4):
x = random.uniform(0,1)
if x > 0 and x < server:
self.__points[0] += 1
else:
self.__points[1] += 1
# print('The score, by calling a score() function that I haven't written yet')

For dealing with events in main loop you need to make a separated thread which capture input or any other event.
import sys
from sys import stdin
from time import sleep
from threading import Thread
from Queue import Queue, Empty
def do_something():
sleep(1)
print 42
def enqueue_output(queue):
while True:
# reading line from stdin and pushing to shared queue
input = stdin.readline()
print "got input ", input
queue.put(input)
queue = Queue()
t = Thread(target=enqueue_output, args=(queue,))
t.daemon = True
t.start()
pause = False
try:
while True:
try:
command = queue.get_nowait().strip()
print 'got from queue ', command
except Empty:
print "queue is empty"
command = None
if command:
if command == 'p':
pause = True
if command == 'u':
pause = False
if not pause:
print pause
do_something()
except KeyboardInterrupt:
sys.exit(0)

I came up with the following.
while True:
try:
## Keep doing something here
## your regular code
print '.',
except KeyboardInterrupt:
## write or call pause function which could be time.sleep()
print '\nPausing... (Hit ENTER to continue, type quit to exit.)'
try:
response = raw_input()
if response.lower() == 'quit':
break
print 'Quitting...'
except KeyboardInterrupt:
print 'Resuming...'
continue

The Event loop might as well be the code I wrote with.
I don't see any user input so I assume that x emulates it. To pause the game if x < 0.1 and to unpause(/resume) it if x > 0.9, you could:
while your_condition(self.__points):
x = random.random()
if x < 0.1: # pause
self.pause()
elif x > 0.9: # resume
self.resume()
if self.is_paused:
continue # do nothing else only wait for input (`x`)
# assume your_condition() has no side-effects
# here's what the resumed version does:
print("...")
# change self.__points, etc
where pause(), resume(), is_paused() methods could be implemented as:
def __init__(self):
self.is_paused = False
def pause(self):
self.is_paused = True
def resume(self):
self.is_paused = False
as you can see the implementation is very simple.

How to set time limit on raw_input

in python, is there a way to, while waiting for a user input, count time so that after, say 30 seconds, the raw_input() function is automatically skipped?

The signal.alarm function, on which #jer's recommended solution is based, is unfortunately Unix-only. If you need a cross-platform or Windows-specific solution, you can base it on threading.Timer instead, using thread.interrupt_main to send a KeyboardInterrupt to the main thread from the timer thread. I.e.:
import thread
import threading
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
timer = threading.Timer(timeout, thread.interrupt_main)
astring = None
try:
timer.start()
astring = input(prompt)
except KeyboardInterrupt:
pass
timer.cancel()
return astring
this will return None whether the 30 seconds time out or the user explicitly decides to hit control-C to give up on inputting anything, but it seems OK to treat the two cases in the same way (if you need to distinguish, you could use for the timer a function of your own that, before interrupting the main thread, records somewhere the fact that a timeout has happened, and in your handler for KeyboardInterrupt access that "somewhere" to discriminate which of the two cases occurred).
Edit: I could have sworn this was working but I must have been wrong -- the code above omits the obviously-needed timer.start(), and even with it I can't make it work any more. select.select would be the obvious other thing to try but it won't work on a "normal file" (including stdin) in Windows -- in Unix it works on all files, in Windows, only on sockets.
So I don't know how to do a cross-platform "raw input with timeout". A windows-specific one can be constructed with a tight loop polling msvcrt.kbhit, performing a msvcrt.getche (and checking if it's a return to indicate the output's done, in which case it breaks out of the loop, otherwise accumulates and keeps waiting) and checking the time to time out if needed. I cannot test because I have no Windows machine (they're all Macs and Linux ones), but here the untested code I would suggest:
import msvcrt
import time
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
finishat = time.time() + timeout
result = []
while True:
if msvcrt.kbhit():
result.append(msvcrt.getche())
if result[-1] == '\r': # or \n, whatever Win returns;-)
return ''.join(result)
time.sleep(0.1) # just to yield to other processes/threads
else:
if time.time() > finishat:
return None
The OP in a comment says he does not want to return None upon timeout, but what's the alternative? Raising an exception? Returning a different default value? Whatever alternative he wants he can clearly put it in place of my return None;-).
If you don't want to time out just because the user is typing slowly (as opposed to, not typing at all!-), you could recompute finishat after every successful character input.

I found a solution to this problem in a blog post. Here's the code from that blog post:
import signal
class AlarmException(Exception):
pass
def alarmHandler(signum, frame):
raise AlarmException
def nonBlockingRawInput(prompt='', timeout=20):
signal.signal(signal.SIGALRM, alarmHandler)
signal.alarm(timeout)
try:
text = raw_input(prompt)
signal.alarm(0)
return text
except AlarmException:
print '\nPrompt timeout. Continuing...'
signal.signal(signal.SIGALRM, signal.SIG_IGN)
return ''
Please note: this code will only work on *nix OSs.

The input() function is designed to wait for the user to enter something (at least the [Enter] key).
If you are not dead set to use input(), below is a much lighter solution using tkinter. In tkinter, dialog boxes (and any widget) can be destroyed after a given time.
Here is an example :
import tkinter as tk
def W_Input (label='Input dialog box', timeout=5000):
w = tk.Tk()
w.title(label)
W_Input.data=''
wFrame = tk.Frame(w, background="light yellow", padx=20, pady=20)
wFrame.pack()
wEntryBox = tk.Entry(wFrame, background="white", width=100)
wEntryBox.focus_force()
wEntryBox.pack()
def fin():
W_Input.data = str(wEntryBox.get())
w.destroy()
wSubmitButton = tk.Button(w, text='OK', command=fin, default='active')
wSubmitButton.pack()
# --- optionnal extra code in order to have a stroke on "Return" equivalent to a mouse click on the OK button
def fin_R(event): fin()
w.bind("<Return>", fin_R)
# --- END extra code ---
w.after(timeout, w.destroy) # This is the KEY INSTRUCTION that destroys the dialog box after the given timeout in millisecondsd
w.mainloop()
W_Input() # can be called with 2 parameter, the window title (string), and the timeout duration in miliseconds
if W_Input.data : print('\nYou entered this : ', W_Input.data, end=2*'\n')
else : print('\nNothing was entered \n')

from threading import Timer
def input_with_timeout(x):
def time_up():
answer= None
print('time up...')
t = Timer(x,time_up) # x is amount of time in seconds
t.start()
try:
answer = input("enter answer : ")
except Exception:
print('pass\n')
answer = None
if answer != True: # it means if variable have somthing
t.cancel() # time_up will not execute(so, no skip)
input_with_timeout(5) # try this for five seconds
As it is self defined... run it in command line prompt , I hope you will get the answer
read this python doc you will be crystal clear what just happened in this code!!

A curses example which takes for a timed math test
#!/usr/bin/env python3
import curses
import curses.ascii
import time
#stdscr = curses.initscr() - Using curses.wrapper instead
def main(stdscr):
hd = 100 #Timeout in tenths of a second
answer = ''
stdscr.addstr('5+3=') #Your prompt text
s = time.time() #Timing function to show that solution is working properly
while True:
#curses.echo(False)
curses.halfdelay(hd)
start = time.time()
c = stdscr.getch()
if c == curses.ascii.NL: #Enter Press
break
elif c == -1: #Return on timer complete
break
elif c == curses.ascii.DEL: #Backspace key for corrections. Could add additional hooks for cursor movement
answer = answer[:-1]
y, x = curses.getsyx()
stdscr.delch(y, x-1)
elif curses.ascii.isdigit(c): #Filter because I only wanted digits accepted
answer += chr(c)
stdscr.addstr(chr(c))
hd -= int((time.time() - start) * 10) #Sets the new time on getch based on the time already used
stdscr.addstr('\n')
stdscr.addstr('Elapsed Time: %i\n'%(time.time() - s))
stdscr.addstr('This is the answer: %s\n'%answer)
#stdscr.refresh() ##implied with the call to getch
stdscr.addstr('Press any key to exit...')
curses.wrapper(main)

under linux one could use curses and getch function, its non blocking.
see getch()
https://docs.python.org/2/library/curses.html
function that waits for keyboard input for x seconds (you have to initialize a curses window (win1) first!
import time
def tastaturabfrage():
inittime = int(time.time()) # time now
waitingtime = 2.00 # time to wait in seconds
while inittime+waitingtime>int(time.time()):
key = win1.getch() #check if keyboard entry or screen resize
if key == curses.KEY_RESIZE:
empty()
resize()
key=0
if key == 118:
p(4,'KEY V Pressed')
yourfunction();
if key == 107:
p(4,'KEY K Pressed')
yourfunction();
if key == 99:
p(4,'KEY c Pressed')
yourfunction();
if key == 120:
p(4,'KEY x Pressed')
yourfunction();
else:
yourfunction
key=0

This is for newer python versions, but I believe it will still answer the question. What this does is it creates a message to the user that the time is up, then ends the code. I'm sure there's a way to make it skip the input rather than completely end the code, but either way, this should at least help...
import sys
import time
from threading import Thread
import pyautogui as pag
#imports the needed modules
xyz = 1 #for a reference call
choice1 = None #sets the starting status
def check():
time.sleep(15)#the time limit set on the message
global xyz
if choice1 != None: # if choice1 has input in it, than the time will not expire
return
if xyz == 1: # if no input has been made within the time limit, then this message
# will display
pag.confirm(text = 'Time is up!', title = 'Time is up!!!!!!!!!')
sys.exit()
Thread(target = check).start()#starts the timer
choice1 = input("Please Enter your choice: ")