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How to get out of a while loop with a specific key

I am trying to make an auto clicker but when i try to make my code exit it doesnt
here is my code
import mouse
import keyboard
import time
import os
os.system('cls')
def Config():
print("Click every")
hour = int(input("Hour: "))
minute = int(input("Minute: "))
second = int(input("Second: "))
total_time = hour*3600 + minute*60 + second
print("f6 to start and f10 to stop")
keyboard.wait('f6')
while True:
time.sleep(total_time)
mouse.click()
#def Fastest():
print(" Auto clicker!!!")
print(" By ze")
print("-------------------------")
print("Auto click on desired time or Fastest?")
choose = int(input("""
1. Config (No milliseconds)
2. Fastest
"""))
if choose == 1:
Config()
# elif choose == 2:
# Fastest()
#TODO:
# use mouse.click
# make it click with time
# make function fastest start with f1 and stops with f2
# create back up file
i tried an if statement with keyboard.is_pressed('key') thinking it would work but it doesnt my results are that the code exits (if key is pressed then exit)

You need to check if the key is pressed in your infinite loop. If it is pressed, you need to exit
while True:
time.sleep(total_time)
mouse.click()
if keyboard.is_pressed("f10"):
break
But this waits for the sleep function , so you'll need to hold f10 for total_time seconds.
You should use a loop to check for the key, rather than sleeping
import datetime
...
clicking = True
while clicking:
mouse.click()
s = datetime.datetime.now()
while ((datetime.datetime.now()-s).total_seconds() < total_time):
# This runs while the difference in time since you started the loop is less than the time you want to wait
if keyboard.is_pressed("f10"):
clicking = False
break

Use one thread to handle user input and another thread to do the clicking:
from threading import Thread
from msvcrt import getwch
import mouse
done = False
def auto_click():
print("Press \"q\" to quit")
global done
while True:
if getwch() == "q":
done = True
break
Thread( target = auto_click, daemon = True ).start()
while not done: # you can add whatever logic you want including a time gate here
mouse.click()

Python VLC - Next track

I am writing a program in Python to run on a Raspberry Pi in order to control my Wurlitzer jukebox. The program current accepts the codes for "record selection" (A1, B1, C4, etc.), add those codes to a playlist, and executes the list. My issue is that once a song starts, I would like to be able to press a button ("Y" in the current code) to skip the currently playing song. I can't get this to work.
If I use "player.next()" I get an error: 'MediaPlayer' object has no attribute 'next'.
I tried to stop the player and restart it (thinking it would pick up the next song in the Playlist. This doesn't even stop the player.
I do not want to use subprocess if I can avoid it. I'd like to figure out a way within Python to do the skipping. How would one accomplish this?
import os, sys, csv, vlc, time, threading
from pynput.keyboard import Key, Listener
DefaultUSBPath="/media/pi"
PlayHistory="PlayHistory.csv"
#
# Declare variables
#
USBDrive = None
Action = None
Playlist = []
SelectionCount = []
Sel_char = None
#
# Find the USB Drive
#
for item in os.listdir(DefaultUSBPath):
if os.path.isdir(os.path.join(DefaultUSBPath, item)):
if USBDrive is None:
USBDrive = os.path.join(DefaultUSBPath, item)
else:
USBDrive = USBDrive + ";" + os.path.join(DefaultUSBPath, item)
if USBDrive is None:
print ("Error(0) - No USB Drive detected")
sys.exit()
elif ";" in USBDrive:
print ("Error(1) - More than one USB Drive detected.")
sys.exit()
#
# Adding to playlist - Returns directory contents and adds to playlist
#
def addplaylist(track):
list = None
if os.path.isdir(os.path.join(USBDrive, track)):
files = [f for f in os.listdir(os.path.join(USBDrive, track)) if os.path.isfile(os.path.join(USBDrive, track, f))]
for f in files:
if list is None:
list = os.path.join(USBDrive, track, f)
else:
list = list + ";" + os.path.join(USBDrive, track, f)
else:
print ("Error(2) - Selection is invalid")
if list is not None:
if ";" in list:
list = list.split(";")
else:
print ("Error(3) - Selection has no media")
return list
#
# MediaPlayer function
#
def MusicPlayer(P):
global Playlist, player
while len(Playlist) > 0:
song=Playlist.pop(0)
print("Song: ")
print(song)
player=vlc.MediaPlayer(song)
player.play()
#
# Define keyboard actions
#
def on_press(key):
global Action, Playlist, player
try:
Sel_char = int(key.char)
except:
try:
Sel_char = str(key.char)
Sel_char = Sel_char.upper()
except:
Sel_char = None
if Sel_char == "Z":
return False
elif Sel_char == "Y":
print("Skip")
#player.next() This line causes 'MediaPlayer' object has no attribute 'next'
time.sleep(1)
MusicPlayer(Playlist)
elif type(Sel_char) == str:
Action = Sel_char
elif type(Sel_char) == int:
Action = Action + str(Sel_char)
print("Action: " + Action)
Plist = addplaylist(Action)
if Plist is not None:
print("Added to playlist")
Playlist.append(Plist)
print(Plist)
MusicPlayer(Playlist)
else:
pass
#
# Read keyboard input
#
with Listener(on_press=on_press) as listener:
listener.join()
print ("")
print ("Have a nice day!")
print ("")
sys.exit()

The way you have it coded, I expect you'd have to stop it, remove the current media from the list, then re-start it.
However you may be better off running with a media_list_player, see below for a bare bones version. Note, I'm on Linux and had to hack some code to get the key input, rather than using a specific library or spend time on it, but it should give you enough to work with.
Edit
I apologise, there is a much simpler method when using a media_list_player, although if you want finer control you should use the media_list_player where you control the list's index or for full control use a media_player_new() but that's beyond the scope of this question. (I'll leave the original answer below this code, as it may be useful)
import vlc
import time
## pinched from vlc for keyboard input
import termios
import tty
import sys
mymedia = ["vp.mp3","vp1.mp3","happy.mp3","V1.mp4"]
def getch(): # getchar(), getc(stdin) #PYCHOK flake
fd = sys.stdin.fileno()
old = termios.tcgetattr(fd)
try:
tty.setraw(fd)
ch = sys.stdin.read(1)
finally:
termios.tcsetattr(fd, termios.TCSADRAIN, old)
return ch
## end pinched code
def jukebox():
player.play_item_at_index(0)
while True:
time.sleep(0.25)
k = getch()
if k == "n": #Next
player.next()
if k == "p": #Previous
player.previous()
if k == " ": #Pause
player.pause()
if k == "q": #Quit
player.stop()
return True
player.next()
vlc_instance = vlc.Instance('--no-xlib --quiet ') # no-xlib for linux and quiet don't complain
player = vlc_instance.media_list_player_new()
Media = vlc_instance.media_list_new(mymedia)
player.set_media_list(Media)
print("Welcome to Jukebox")
print("Options - space = Play/Pause, n = Next, p = Previous, q = Quit")
print("Media",mymedia)
jukebox()
Original code
import vlc
import time
## pinched from vlc for keyboard input
import termios
import tty
import sys
def getch(): # getchar(), getc(stdin) #PYCHOK flake
fd = sys.stdin.fileno()
old = termios.tcgetattr(fd)
try:
tty.setraw(fd)
ch = sys.stdin.read(1)
finally:
termios.tcsetattr(fd, termios.TCSADRAIN, old)
return ch
## end pinched code
vlc_instance = vlc.Instance()
player = vlc_instance.media_list_player_new()
mymedia = ["vp.mp3","vp1.mp3","happy.mp3"]
Media = vlc_instance.media_list_new(mymedia)
player.set_media_list(Media)
for index, name in enumerate(mymedia):
print("Playing:",name)
player.play_item_at_index(index)
time.sleep(1)
while player.get_state() != 6:
time.sleep(1)
k = getch()
if k == "y":
player.stop()
break

How to ask Question by if statement via timeout

is there any way for ask question by if statement and after afew sec if user didnot give any answer , if state use a default answer?
inp = input("change music(1) or close the app(2)")
if inp = '1':
print("Music changed)
elif inp = '2':
print("good by")
in this case if user dont give any answer after 30 sec by default if statement choose number 3

from threading import Timer
out_of_time = False
def time_ran_out():
print ('You didn\'t answer in time') # Default answer
out_of_time = True
seconds = 5 # waiting time in seconds
t = Timer(seconds,time_ran_out)
t.start()
inp = input("change music(1) or close the app(2):\n")
if inp != None and not out_of_time:
if inp == '1':
print("Music changed")
elif inp == '2':
print("good by")
else:
print ("Wrong input")
t.cancel()
Timer Objects
This class represents an action that should be run only after a certain amount of time has passed — a timer. Timer is a
subclass of Thread and as such also functions as an example of
creating custom threads.
Timers are started, as with threads, by calling their start() method.
The timer can be stopped (before its action has begun) by calling the
cancel() method. The interval the timer will wait before executing its
action may not be exactly the same as the interval specified by the
user.
For example:
def hello():
print("hello, world")
t = Timer(30.0, hello)
t.start() # after 30 seconds, "hello, world" will be printed
class threading.Timer(interval, function, args=None, kwargs=None)
Create a timer that will run function with arguments args and keyword
arguments kwargs, after interval seconds have passed. If args is None
(the default) then an empty list will be used. If kwargs is None (the
default) then an empty dict will be used.
cancel()
Stop the timer, and cancel the execution of the timer’s action. This will only work if the timer is still in its waiting
stage.

Here's an alternative way to do it (python 3), using multiprocessing. Note, to get the stdin to work in the child process, you have to re open it first. I'm also converting the input from string to int to use with the multiprocessing value, so you might want to error check there as well.
import multiprocessing as mp
import time
import sys
import os
TIMEOUT = 10
DEFAULT = 3
def get_input(resp: mp.Value, fn):
sys.stdin = os.fdopen(fn)
v = input('change music(1) or close the app (2)')
try:
resp.value = int(v)
except ValueError:
pass # bad input, maybe print error message, try again in loop.
# could also use another mp.Value to signal main to restart the timer
if __name__ == '__main__':
now = time.time()
end = now + TIMEOUT
inp = 0
resp = mp.Value('i', 0)
fn = sys.stdin.fileno()
p = mp.Process(name='Get Input', target=get_input, args=(resp, fn))
p.start()
while True:
t = end - time.time()
print('Checking for timeout: Time = {:.2f}, Resp = {}'.format(t, resp.value))
if t <= 0:
print('Timeout occurred')
p.terminate()
inp = DEFAULT
break
elif resp.value > 0:
print('Response received:', resp.value)
inp = resp.value
break
else:
time.sleep(1)
print()
if inp == 1:
print('Music Changed')
elif inp == 2:
print('Good Bye')
else:
print('Other value:', inp)

Check for a file's availability for a certain time and then break

I've been trying to break a loop which is meant to look for a file in a certain location. My intention is to make my script look for that file for a certain time and then break whether the file is found or not but I can't get any idea.
How can I make the script wait for a certain time and then break when the time is up?
This is my script at this moment:
import os
import time
file_path = r"C:\Users\WCS\Desktop\item.txt"
time_limit = 5
while not os.path.exists(file_path):
time.sleep(1)
#is there any logic I can apply here to make the following line valid
# if waiting_time>=time_limit:break
print("Time's up")

Calculate the elapsed time by doing actual time minus start time by using time.time() function and assign a variable (file_exists in this code) which will be modified and check whether the file exist or not and use it for the loop.
As below:
import os
import time
file_path = r"C:\Users\WCS\Desktop\item.txt"
time_limit = 5
start = time.time()
file_exists = os.path.exists(file_path)
while not file_exists:
time.sleep(1)
file_exists = os.path.exists(file_path)
elapsed = time.time() - start
if elapsed >= time_limit:
break
else:
print("File exist.")
print(elapsed)
print("Time's up")

def exists_timeout(path, timeout):
"""Return once <path> exists, or after <timeout> seconds,
whichever is sooner
"""
timer = timeout
while (not os.path.exists(path)) and timer > 0:
time.sleep(1)
timer -= 1

import os
import time
file_path = r"C:\Users\WCS\Desktop\item.txt"
cTime=0
time_limit = 5
while cTime<time_limit:
if os.path.exists(file_path)==False:
cTime=cTime+1
time.sleep(1)
else:
pass
if cTime==5:
responce="Time's Up"
else:
responce='Found'
print(responce)

As roganjosh commented, it would be simpler if you used time stamps. I have added relevant code below:
import os
import time
from datetime import datetime, timedelta
file_path = r"C:\Users\WCS\Desktop\item.txt"
time_limit = datetime.now() + timedelta(seconds=5)
present = datetime.now()
while (not os.path.exists(path)) and present < time_limit:
present = datetime.now()
if present >= time_limit:
print("Time's up")
break
time.sleep(1)

Here's how to do it with the threading.Timer() class. These can be configured to delay a specified amount of time and the call as function of your choosing.
import os
from threading import Timer
import time
file_path = r"C:\Users\WCS\Desktop\item.txt"
# Timer callback function.
def timeout():
global time_ran_out
time_ran_out = True
time_limit = 5
time_ran_out = False # Define variable the callback function modifies.
timer = Timer(time_limit, timeout) # Create a timer thread object.
timer.start() # Start the background timer.
while not os.path.exists(file_path):
time.sleep(1)
if time_ran_out:
print('Times up!')
break
print("Done")

To check for the availability of a file in a certain location you can try the following. The script will break as soon as the file is found otherwise it will wait upto 5 seconds for the file to be available before breaking.
import os
import time
file_path = r"C:\Users\WCS\Desktop\item.txt"
time_to_wait = 5
time_counter = 0
while not os.path.exists(file_path):
time.sleep(1)
time_counter += 1
if time_counter > time_to_wait:break
print("done")

How to stop and start a thread at will

So I'm doing some testing with threads and I realised I could not stop and then start a thread. I could stop it, but starting it again was the issue.I want a script that adds 1 to a var when it is on then its stops when off by pressing shift to turn on and off.I have the detecting shift working (it is on another part of my code), but I just need to find out how to stop and start threadsHere is my test code:
from threading import Thread as th
import time as t
var = 0
def testDef():
global var
var += 1:
t.sleep(1)
test = th(target = testDef)
test.start()
while True:
menu = input("On, Off, Show Var")
if menu == "On":
test.start()
elif menu == "Off":
test._stop():
elif menu == "S":
print(var)
I know there are a few errors, but I mainly need the on and off threading to work.
Thanks, Jeff.

As far as I know, you can't actually stop and restart a thread as you can't use test.start() when the method has been terminated. However, you may be wondering to something similar by using threading.Condition to pause and later resume the execution.
You can read more about it in the documentation.
There is also an error in var += 1:, change it to var += 1

Here's a simple example on how to use threading.Event to enable two threads to communicate. This works by setting the internal flag of the Event to either True or False. While this internal flag is False you can ask thread a to wait (effectively block, which is not very efficient by the way). Then we use the two timers (b, c) to simulate a shift press every 5 seconds. In order to release a we set the event (internal flag = True). 5 seconds later, we clear the value of the internal flag and this will make thread a to block again.
import threading
def do(event):
flag = True
while flag:
if not event.isSet():
print "blocking"
event.wait()
else:
print "resuming"
def pressShift(event, enable):
print "Shift pressed"
if enable:
event.set()
else:
event.clear()
def main():
event = threading.Event()
a = threading.Thread(target=do, args=(event,))
b = threading.Timer(5, pressShift, args=(event, True)).start()
c = threading.Timer(10, pressShift, args=(event, False)).start()
a.start()
a.join()
if __name__ == "__main__":
main()

You cannot restart a thread that has already been started. What you can do, however, is to create another thread.
from threading import Thread as th
import time as t
var = 0
def testDef():
global var
var += 1
t.sleep(1)
test = th(target = testDef)
test.start()
while True:
menu = input("On, Off, Show Var")
if menu == "On":
test = th(target = testDef)
test.start()
elif menu == "Off":
test._stop()
elif menu == "S":
print(var)

Use an event object like this post, and check that event in your target functoin. Also, you need a new thread each time you re-start. The code shown below adds some debugging that should be useful. (Another approach is to build a custom stop function.)
import logging
import threading
import time as t
var = 0
logging.basicConfig(level=logging.DEBUG,
format='[%(levelname)s] (%(threadName)-10s) %(message)s',
)
def testDef(stop_event):
global var
print 'Thread Running', var
# inThread.stop()
while not stop_event.isSet():
var += 1
logging.debug('Var is %i' % var)
t.sleep(1)
# Use an event to track user input
testStopEvent = threading.Event()
testStopEvent.clear()
test = threading.Thread(name = 'test', target=testDef, args=((testStopEvent,)))
test.setDaemon(True)
while True:
menu = input("On = 1, Off = 2, Show Var = 3")
if menu == 1:
test.start()
elif menu == 2:
testStopEvent.set()
test.join() # Wait for the thread to finish
test = threading.Thread(target=testDef, args=((testStopEvent,))) # "re-start" thread
testStopEvent.clear() # Reset the stop event
elif menu == 3:
print(var)