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Finding the mean from input

my 6th grade teacher asked me to code a program in python that input any amount of a number and it outputs the mean so i tried and theirs a problem with the print statement here's the code.i even tried to replace the float(b) statements to float(1) statements but that didn't work either
n = int(input("Enter number of elements :"))
b = input("\nEnter the numbers :")
sum = (float(b)+float(b)+float(b) / float(n)
print("\nThe mean is -",sum())

Please give space separated input here :
input = list(map(float ,input('Enter number of elements : ').split(' ')))
mean = sum(input)/len(input)
print(mean)
: Output :
Enter number of elements : 10 20 30
20.0

i would do something like this.
I assumed you wanted the arithmetic mean and not the geometric one, so the first thing to do is to get the number of values the user wants to input and store it in the variable n. The you iterate over a range n and you sum the inputs to k.
The you divide k by n.
n, k = int(input("Enter number of elements:")), 0
for i in range(n):
k += float(input("Enter value number {}".format(i+1)))
k /= n
print(k)
if you want to use the "cool" way you can do something like this:
n = int(input("Enter number of elements:"))
k = sum([float(input("Enter value number {}".format(i+1))) for i in range(n)]) / n
print(k)

There is an syntax error and logical error in this code.
You haven't closed the opening bracket, It should be like this
sum = (float(b)+float(b)+float(b)) / float(n)
If you want to calculate the mean of 3 values why are you adding the same value for three times here
(float(b)+float(b)+float(b))
Insted of using same values you can get each values from for loop like this
for i in range(3):
num = float(input())
total += num

Finding the largest odd number among 3 variable, program doesn't work properly [duplicate]

This question already has answers here:
Choose largest odd number python
(28 answers)
Closed 4 months ago.
Hi I am new to programming and I made a program for a finger exercise in the book "Introduction to computation and programming using python"
here's the finger exercise : Write a program that examines three variables—x, y, and z—
and prints the largest odd number among them. If none of them are odd, it
should print a message to that effect.
I made this,
l = []
x = int(input("Enter a number for x: "))
y = int(input("Enter a number for y: "))
z = int(input("Enter a number for z: "))
l.append(x)
l.append(y)
l.append(z)
def testodd(n):
return n%2 != 0
def maxodd (l):
oddlist = []
for i in l:
if testodd(i):
oddlist.append(i)
else:
continue
return max(oddlist)
print(maxodd(l))
Program sometimes work properly and sometimes not for example I gave x=231 y=23 and z=678 it says "none of them are odd" what's the problem about this program ?

First we create a list that will contain all the numbers, then we sort that list in descending order (reverse=True) and then we look if there is any odd number. If we don't find any odd number in the list we print the message:
numbers = []
for _ in range(3): # Iterate 3 times
numbers.append(int(input("Enter a number:"))) # Append 1 number each time
numbers.sort(reverse=True) # Sort the numbers in descending order
for n in numbers: # Iterate over the numbers
if n % 2 != 0: # If the number is odd we have found the maximum odd value
print(n) # Print the value
break # Finish the loop
else: # An else block in a for loop will execute if no break was found
print("none of them are odd") # Print the message
A more advanced way to retrieve the numbers would be:
numbers = sorted((int(input("Enter a number:")) for _ in range(3)), reverse=True)
that would replace the first 4 lines.

This is simpler if you put only the odd numbers into a list.
x = int(input("Enter a number for x: "))
y = int(input("Enter a number for y: "))
z = int(input("Enter a number for z: "))
odd_numbers = [value for value in (x,y,z) if value%2]
if odd_numbers:
print("The greatest odd number is", max(odd_numbers))
else:
print("None of the numbers is odd.")

The program finds the maximal number and checks if it's odd.
To find the maximal odd number, you can use list comprehension:
Put the numbers to check at a list numbers = [x, y, z]
Loop over the numbers t for t in numbers, and filter in those who are odd if t % 2 != 0.
Find the maximal among them (#2): max([t for t in numbers if t % 2 != 0])
x = int(input("Enter a number for x: "))
y = int(input("Enter a number for y: "))
z = int(input("Enter a number for z: "))
# Put numbers in a list
numbers = [x, y, z]
# Filter the odd numbers, and find the max
print(max([t for t in numbers if t % 2 != 0]))

You may just append all numbers entered into a list, sort all odds into another list and get the maximum value:
numbs = []
x = int(input("Enter a number for x: "))
numbs.append(x)
y = int(input("Enter a number for y: "))
numbs.append(y)
z = int(input("Enter a number for z: "))
numbs.append(z)
odds = [x for x in numbs if x%2==1]
if odds == []:
print('No odd number was entered')
else:
print(max(odds))

python for loop wont change value

So im new to python and this question should be fairly easy for anybody in here except me obvisouly haha so this is my code
for c in range(0,20):
print("number",c+1)
number = input ("Enter number:\n")
number = int(number)
if (number < 1 or number > 9):
print("try again by inputing a positive number < 10")
c -=1
so as you may think if the number someone inputs is bigger than 9 or smaller than 0 i just want my c to stay where it is so i get 20 positive numbers from 1-9 instead it doesnt do that and it keeps increasing even tho i have the c-=1 thingy down there

First, do not use range(0,20) but range(20) instead.
Second, range returns an iterator. This means, that when you do c-=1 you do not go back in the iterator, you decrease the number returned by the iterator. Meaning that if c=5 and the number you entered in input is 20, c will become 4, but when returning to the start of the loop, c be be 6.
You probably want something of this sort:
c = 0
while c < 20:
print("number",c+1)
number = input ("Enter number:\n")
number = int(number)
if (number < 1 or number > 9):
print("try again by inputing a positive number < 10")
continue
c += 1

an alternative and simple solution to this would be:
i=20
while(i!=0):
number = input("Enter number:\n")
number = int(number)
if (number <1 or number >9):
print("Invalid no try within 0-9 ")
else
print(number)
i-=1

Python, largest odd integer

I am new to coding and have been learning a few days now. I wrote this program in Python while following along in some MIT OpenCourseware lectures and a few books. Are there anyways to more easily express the program?
Finger exercise: Write a program that asks the user to input 10 integers, and then prints the largest odd number that was entered. If no odd number was entered, it should print a message to that effect.
a = int(raw_input('Enter your first integer: '))
b = int(raw_input('Enter your second integer: '))
c = int(raw_input('Enter your third integer: '))
d = int(raw_input('Enter your fourth integer: '))
e = int(raw_input('Enter your fifth integer: '))
f = int(raw_input('Enter your sixth integer: '))
g = int(raw_input('Enter your seventh integer: '))
h = int(raw_input('Enter your eighth integer: '))
i = int(raw_input('Enter your ninth integer: '))
j = int(raw_input('Enter your tenth integer: '))
if a%2 ==0:
a = 0
else:
a = a
if b%2 ==0:
b = 0
else:
b = b
if c%2 ==0:
c = 0
else:
c = c
if d%2 ==0:
d = 0
else:
d = d
if e%2 ==0:
e = 0
else:
e = e
if f%2 ==0:
f = 0
else:
f = f
if g%2 ==0:
g = 0
else:
g = g
if h%2 ==0:
h = 0
else:
h = h
if i%2 ==0:
i = 0
else:
i = i
if j%2 ==0:
j = 0
else:
j = j
value = a, b, c, d, e, f, g, h, i, j
max = max(value)
if max ==0:
print 'There are no odd numbers.'
else:
print max, 'is the largest odd integer.'

A more compact form would be:
from __future__ import print_function
try: # Python 2
raw_input
except NameError: # Python 3 compatibility
raw_input = input
largest = None
for i in range(1, 11):
number = int(raw_input('Enter integer #%d: ' % i))
if number % 2 != 0 and (not largest or number > largest):
largest = number
if largest is None:
print("You didn't enter any odd numbers")
else:
print("Your largest odd number was:", largest)
This uses a simple loop to track how many integers were entered, but only stores the largest odd number encountered so far.

numbers = [input('Enter a number: ') for i in range(10)]
odds = [x for x in numbers if x % 2 == 1]
if odds:
print max(odds)
else:
print 'No odd numbers input'
Explanation:
numbers = [input('Enter a number: ') for i in range(10)]
This line is using a list comprehension to ask a user for 10 numbers. These numbers will be in the list object numbers
odds = [x for x in numbers if x % 2 == 1]
Next we are using another list comprehension to filter out all numbers in numbers that are not odd. Since odd numbers modulo 2 always equal 1, we are given a new list (odd) that only contains odd numbers.
if odds:
This is using python's truthy way of testing. Particularly, if a list is empty, this is False. If the list is not empty, it is True.
print max(odds)
Finally, if the above was True, we print the max value in the odds list
else:
print 'No odd numbers input'
If the if statement was False (there are no odds) we tell the user
A running copy looks like this:
Enter a number: 10
Enter a number: 12
Enter a number: 14
Enter a number: 15
Enter a number: 16
Enter a number: 17
Enter a number: 1
Enter a number: 2
Enter a number: 19
Enter a number: 2
19

Python has objects called list and tuple which represent a sequence of numbers—they serve many of the same purposes as "arrays" in other programming languages. An example of a list is [1,2,3,4,5]
Like most popular programming languages, Python also has the concept of a for loop.
myList = [1,2,3,4,5]
for x in myList:
print(x)
Python also has a somewhat unusual but very useful construct called a "list comprehension" which combines for loop, list, and an optional conditional in one neat syntax—check out these examples and see if you can understand how the result relates to the code
myNewList = [x+1 for x in myList]
myNewSelectiveList = [x+1 for x in myList if x >= 3]
and here's an example that's particularly useful in your exercise:
userInputs = [int(raw_input('Enter a number:')) for i in range(10)]
Finally, there's a function max which can take a list as its argument and which returns the largest item in the list. Once you have your 10 inputs in a list, you should be able to use these ingredients to find the highest odd number in one pretty short line (max over a list comprehension with an if conditional in it) .

I'm also studying Guttag's book from scratch. I came with the following solution:
list = []
odds = False
print('You will be asked to enter 10 integer numbers, one at a time.')
for i in range(1,11):
i = int(input('Number: '))
list.append(i)
list = sorted(list, reverse = True)
for j in list:
if j%2 == 1:
print('The largest odd number is', j, 'from', list)
odds = True
break
if odds == False:
print('There is no odd number from', list)
I went through a long(er) version similar to the OP, but since the reading list for MIT 6.00x explicitly suggested studying topic 3.2 alongside chapter 2, I thought that lists would be an acceptable answer.
The code above should allow for negatives and zero.

I'm also working through Guttag's book, this solution uses some of the above code but might have a different spin on things. I filtered out the user input right away to include only odd integer input. If all of the input is even, then the list is empty, the code checks for an empty list, then sorts whatever is left (odd integers) and returns the last one. Please let me know if there are any hidden problems in this (I'm rather new to writing algorithms as well).
arr = []
max = 0
while max < 10:
userNum = int(input('enter an int: '))
if userNum %2 != 0:
arr.append(userNum)
max = max + 1
if len(arr) == 0:
print('all are even')
oddArr = sorted(arr)
print(oddArr[-1])

I just find this question while looking for alternative answers here is my code :
Note:I changed the code a bit so I can decide how many numbers I want to enter
alist=[]
olist=[]
num=int(input("how many numbers ? : "))
for n in range(num):
numbers=int(input())
alist.append(numbers)
for n in range(len(alist)):
while alist[n]%2 != 0 :
olist.append(alist[n])
break
else:
n +=1
olist.sort()
if len(olist) != 0:
print("biggest odd number: ",olist[-1])
else:
print("there is no odd number ")

The question is very early in the book and assumes no knowledge of lists, or indeed the Nonetype (it has mentioned it but not explained how it is used). Also, some solutions here will not work if the highest odd is negative because they initialise largest = 0 before the loop.
This works:
iters = 10
largest = "spam"
while iters != 0:
user_num = int(input("Enter an integer: "))
if user_num % 2 != 0:
if largest == "spam" or user_num > largest:
largest = user_num
iters -= 1
if largest == "spam":
print("You did not enter an odd integer")
else:
print("The largest odd integer was", largest)

itersLeft = 10 #define number of integers
x=0 #creating a variable for storing values
max=0 #creating a variable for defining max
while itersLeft!=0:
x=int(input())
itersLeft = itersLeft-1
if x%2!=0 and x>max:
max=x
if max!=0:
print(max)
elif max==0:
print("No odd number was entered")
*Note: works only for non-negative numbers

The other answers and comments suggesting lists and loops are much nicer, but they're not the only way to change and shorten your code.
In your tests, the else: a = a sections are doing nothing, assigning a to itself is no change, so they can all be removed, and the if tests brought onto one line each:
a = int(raw_input('Enter your first integer: '))
b = int(raw_input('Enter your second integer: '))
c = int(raw_input('Enter your third integer: '))
d = int(raw_input('Enter your fourth integer: '))
e = int(raw_input('Enter your fifth integer: '))
f = int(raw_input('Enter your sixth integer: '))
g = int(raw_input('Enter your seventh integer: '))
h = int(raw_input('Enter your eighth integer: '))
i = int(raw_input('Enter your ninth integer: '))
j = int(raw_input('Enter your tenth integer: '))
if a%2 == 0: a = 0
if b%2 == 0: b = 0
if c%2 == 0: c = 0
if d%2 == 0: d = 0
if e%2 == 0: e = 0
if f%2 == 0: f = 0
if g%2 == 0: g = 0
if h%2 == 0: h = 0
if i%2 == 0: i = 0
if j%2 == 0: j = 0
value = a, b, c, d, e, f, g, h, i, j
max = max(value)
if max ==0:
print 'There are no odd numbers.'
That's the most obvious change that makes it easier to follow, without fundamentally changing the pattern of what you are doing.
After that, there are ways you could rewrite it - for example, staying with math only, even numbers divide by 2 with remainder 0 and odd numbers have remainder 1. So doing (x % 2) * x will change even numbers into 0, but keep odd numbers the same.
So you could replace all the if tests, with no test, just an assignment:
a = (a % 2) * a
b = (b % 2) * b
c = (c % 2) * c
...
if e%2 == 0: e = 0
if f%2 == 0: f = 0
The lines get slightly shorter, and if you're OK with how that works, you could merge those into the value line, and put that straight into max to get:
a = int(raw_input('Enter your first integer: '))
b = int(raw_input('Enter your second integer: '))
c = int(raw_input('Enter your third integer: '))
d = int(raw_input('Enter your fourth integer: '))
e = int(raw_input('Enter your fifth integer: '))
f = int(raw_input('Enter your sixth integer: '))
g = int(raw_input('Enter your seventh integer: '))
h = int(raw_input('Enter your eighth integer: '))
i = int(raw_input('Enter your ninth integer: '))
j = int(raw_input('Enter your tenth integer: '))
largest = max(a%2*a, b%2*b, c%2*c, d%2*d, e%2*e, f%2*f, g%2*g, h%2*h, i%2*i, j%2*j)
if largest == 0:
print 'There are no odd numbers.'
else:
print largest, 'is the largest odd integer.'
There isn't really a way to shorten assigning ten variables without some kind of loop, and it's arguable whether any of this is 'more easily expressing the program', but it does take 58 lines down to 17, remove 10 conditional tests, 10 else/no-op assignments and 1 variable while keeping approximately the same structure / workings.
PS. I changed max = max() because calling your variable by the same name as the function is a bad idea - you can't use the function again, and it's confusing to other Python programmers reading your code who already know what 'max' does, if you've reused that name for something else.
Edit: A commentor suggests negative numbers matter. The above writing answers "here's my code, how could I express it more easily?" without introducing any new Python or changing the behaviour, but it cannot handle negative odd numbers; max() will always choose a zero over a negative odd number, and the program will wrongly answer that "there are no odd numbers".
I don't think that's fixable without introducing any new concepts at all. And if introducing new concepts is happening, use lists and loops. Andy's suggestion to build a list that includes only the odd numbers, and then take the max value of that, for example.
But, doing something to handle them without lists -- there is another approach that hardly changes the shape of the code at all, introducing the boolean OR operation, which compares two true/false values and returns false if they are both false, otherwise true.
Python does a lot of automagic behind-the-scenes conversion to true/false to make logical operators work well. Variables with no value (zero, empty containers, empty strings) are all "false" and variables with some value are all "true".
From earlier, we have one bit that knocks even numbers to zero (a%2*a) and now we want to knock zero off the numberline completely:
-3 or None -> -3
-1 or None -> -1
0 or None -> None
1 or None -> 1
3 or None -> 3
5 or None -> 5
Introducing: a%2*a or None. It's magical, ugly, hard to follow, but valid Python -- and I'm chuffed because it's like solving a puzzle and it works, you know? Change the max line and the test to:
largest = max(a%2*a or None, b%2*b or None, c%2*c or None, d%2*d or None, e%2*e or None,
f%2*f or None, g%2*g or None, h%2*h or None, i%2*i or None, j%2*j or None)
if largest == None:
Evens get squished to zeros, zeros get squished to nothing, odds come through unchanged. Max now only has odd numbers to work with so it can now pick a negative odd number as the answer. Case closed. btw. use lists.

Compare 10 inputs and print the highest odd number
y = 0
for counter in range(10):
x = int(input("Enter a number: "))
if (x%2 == 1 and x > y):
y = x
if (y == 0):
print("All are even")
else:
print(y, "is the largest odd number")

Try the following -
def largest_odd():
q = int(input('Please enter a number: '))
w = int(input('Please enter a number: '))
e = int(input('Please enter a number: '))
lis = []
if q%2 != 0:
lis.insert (q,q)
if w%2 != 0:
lis.insert (w,w)
if e%2 != 0:
lis.insert (e,e)
Great = max(lis)
print(Great)

I am on the same exercise just now, and came up with the following solution, which seems to work just fine and is in line with the topics taught in the book so far(variable assignments, conditionals, and while loop):
EXERCISE:
Write a program that asks the user to input 10 integers, and
then prints the largest odd number that was entered. If no odd number was entered, it should print a message to that effect.
from __future__ import print_function
try: # Python 2
raw_input
except NameError: # Python 3 compatibility
raw_input = input
numbers_count = 0
next_input = 0
max_odd_number = None
while numbers_count < 10:
numbers_count += 1
next_input = raw_input("Please enter a number: " + str(numbers_count) +
" of 10\n")
if int(next_input)%2 != 0:
# on the entry of first number, we check max_odd_number - if it is of
# type None, it means no value has been assigned to it so far thus the
# first odd number entry becomes the first maximum odd number, be it
# positive or negative.
if max_odd_number == None:
max_odd_number = int(next_input)
if int(next_input) > max_odd_number:
max_odd_number = int(next_input)
if max_odd_number == None:
print ("None of the numbers entered were odd!")
else:
print ("Maximum odd number you entered is: " + str(max_odd_number))
Any comments would be appreciated.
Thanks,
A

A simple answer is :
x = 0
result = None;
while(x < 10):
inputx = raw_input('Enter integer #%d: ' % x)
inputx = int(inputx)
if (inputx % 2 == 1):
if(inputx > result):
result = inputx
x += 1
if result is None:
print 'no odd number was entered'
else:
print result
Note: if enter a String like '3f',it will throw a ValueError:
invalid literal for int() with base 10: '3f'
So finally ，the best anwser is
result = None
x = 0
while(x < 10):
inputx = raw_input('Enter integer #%d: ' % x)
try:
inputx = int(inputx)
except ValueError:
print'you enter value ',inputx,' is not a Integer. please try again!'
continue
if (inputx % 2 == 1):
if(inputx > result):
result = inputx
x+=1
if result is None:
print 'no odd number was entered'
else:
print 'the largest odd number is: ',result

The question if introduced in the book just after giving knowledge to if condition and while iteration statement.
Though there are lot many datatypes that could be used in python to get easy solution, we need to use only primitives that too the very basics.
The code below takes 10 user inputs(only odd) and outputs the largest of the 10 numbers.
Answer to the question:(Code)
a1= int(input("Enter the number1: "))
while a1%2 ==0:
print("Entered number is not an odd number.")
a1= int(input("Enter the number1: "))
a2= int(input("Enter the number2: "))
while a2%2 ==0:
print("Entered number is not an odd number.")
a2= int(input("Enter the number2: "))
a3= int(input("Enter the number3: "))
while a3%2 ==0:
print("Entered number is not an odd number.")
a3= int(input("Enter the number3: "))
a4= int(input("Enter the number4: "))
while a4%2 ==0:
print("Entered number is not an odd number.")
a4= int(input("Enter the number4: "))
a5= int(input("Enter the number5: "))
while a5%2 ==0:
print("Entered number is not an odd number.")
a5= int(input("Enter the number5: "))
a6= int(input("Enter the number6: "))
while a6%2 ==0:
print("Entered number is not an odd number.")
a6= int(input("Enter the number6: "))
a7= int(input("Enter the number7: "))
while a7%2 ==0:
print("Entered number is not an odd number.")
a7= int(input("Enter the number7: "))
a8= int(input("Enter the number8: "))
while a8%2 ==0:
print("Entered number is not an odd number.")
a8= int(input("Enter the number8: "))
a9= int(input("Enter the number9: "))
while a9%2 ==0:
print("Entered number is not an odd number.")
a9= int(input("Enter the number9: "))
a10= int(input("Enter the number10: "))
while a10%2 ==0:
print("Entered number is not an odd number.")
a10= int(input("Enter the number10: "))
if a1>a2 and a1>a3 and a1>a4 and a1>a5 and a1>a6 and a1>a7 and a1>a8 and a1>a9 and a1>a10:
print(str(a1) +" is the largest odd number.")
elif a2>a1 and a2>a3 and a2>a4 and a2>a5 and a2>a6 and a2>a7 and a2>a8 and a2>a9 and a2>a10:
print(str(a2) +" is the largest odd number.")
elif a3>a1 and a3>a2 and a3>a4 and a3>a5 and a3>a6 and a3>a7 and a3>a8 and a3>a9 and a3>a10:
print(str(a3) +" is the largest odd number.")
elif a4>a1 and a4>a2 and a4>a3 and a4>a5 and a4>a6 and a4>a7 and a4>a8 and a4>a9 and a4>a10:
print(str(a4) +" is the largest odd number.")
elif a5>a1 and a5>a2 and a5>a3 and a5>a4 and a5>a6 and a5>a7 and a5>a8 and a5>a9 and a5>a10:
print(str(a5) +" is the largest odd number.")
elif a6>a1 and a6>a2 and a6>a3 and a6>a4 and a6>a5 and a6>a7 and a6>a8 and a6>a9 and a6>a10:
print(str(a6) +" is the largest odd number.")
elif a7>a1 and a7>a2 and a7>a3 and a7>a4 and a7>a5 and a7>a6 and a7>a8 and a7>a9 and a7>a10:
print(str(a7) +" is the largest odd number.")
elif a8>a1 and a8>a2 and a8>a3 and a8>a4 and a8>a5 and a8>a6 and a8>a7 and a8>a9 and a8>a10:
print(str(a8) +" is the largest odd number.")
elif a9>a1 and a9>a2 and a9>a3 and a9>a4 and a9>a5 and a9>a6 and a9>a7 and a9>a8 and a9>a10:
print(str(a9) +" is the largest odd number.")
else:
print(str(a10) +" is the largest odd number.")
Hope this helps.

In my experience the way to more easily express the program is with a function.
This would have been my answer in Syntax tested for Python 3.7.6:
'''
Finger exercise:
Write a program that asks the user to input 10 integers,
and then prints the largest odd number that was entered.
If no odd number was entered, it should print a message to that effect.
'''
def LargestOdd(numbers=[]):
'''
Parameters
----------
numbers : list, whcih should contain 10 integers.
DESCRIPTION. The default is [].
Returns
-------
The largest odd integer in the list number.
'''
odd_numbers=[]
if len(numbers)==10:
for n in numbers:
if n%2 != 0:
odd_numbers.append(n)
max_numb=max(odd_numbers)
print('The largest odd number is '+str(max_numb))
else:
print('Please, enter 10 numbers')
LargestOdd([1,2,3,7,45,8,9,10,30,33])
Output: The largest odd number is 45

n = int(input("Enter the no of integers:"))
lst = []
count = 1
while count <=n:
no = int(input("Enter an integer:"))
count = count +1
if (no%2!=0):
lst.append(no)
print ("The list of odd numbers",lst)
print("The maximum number from the list of odd number is:",max(lst))

Here is my solution:
def max_odd():
"""Returns largest odd number from given 10 numbers by the use.
if the input is not valid, the message is displayed to enter valid numbers"""
x = [input('Enter a value: ') for i in range(10)]
x = [int(i) for i in x if i]
if x:
try:
x = [i for i in x if i%2 != 0]
return(max(x))
except:
return('All even numbers provided.')
else:
return('Please enter a valid input')

I started learning coding from Guttag's book. And since this is in the 2nd chapter, the solution follows only basic if condition and while loop
#input 10 integers
n1 = int(input('Enter 1st integer: '))
n2 = int(input('Enter 2nd integer: '))
n3 = int(input('Enter 3rd integer: '))
n4 = int(input('Enter 4th integer: '))
n5 = int(input('Enter 5th integer: '))
n6 = int(input('Enter 6th integer: '))
n7 = int(input('Enter 7th integer: '))
n8 = int(input('Enter 8th integer: '))
n9 = int(input('Enter 9th integer: '))
n10 = int(input('Enter 10th integer: '))
#create list from input
list = [n1,n2,n3,n4,n5,n6,n7,n8,n9,n10]
largest = list[0] #Assign largest to the first integer
x = 1 #index starts at 1
while x < len(list):
if list[x]%2 != 0:
if list[x] > largest:
largest = list[x]
x += 1
if largest%2 == 0:
print('All numbers are even')
else:
print('Largest odd number is', largest)

#This is the simplest program for this question
a=[input('Enter a number: ') for i in range(10)]
#This gets 10 inputs from the user and stores it as a string in a list
b=[int(a[i]) for i in range(10)]
#Here the string values were converted into integer values
for i in range(10):
if max(b)%2==0:
b.remove(max(b))
#Now the loop checks for the max number and if it's even it deletes it.
c=max((b),default='Nil')
if c=="Nil":
print("Please enter an odd number")
else:
print(c,"Is the Largest Odd Number")
#Now the largest number left is an odd number and we finally print it!!!!

This code should work work as well. Syntax tested for python 2.7
def tenX(): #define function
ten = [] #empty list for user input
odds = [] #empty list for odd numbers only
counter = 10
ui = 0
while counter > 0 :
ui = raw_input('Enter a number: ')
ten.append(int(ui)) #add every user input to list after int conversion
counter -= 1
for i in ten:
if i % 2 != 0:
odds.append(i)
print "The highest number is", max(odds) #max() returns highest value in a list
>>> tenX() #call function

The while conditional loop doesn't save itself

First, I just want to say I recently started with programming, so I'm not very good. This is my problem:
x = int(input("Write a number between 1-100: "))
while x > 100:
x = int(input("The number must be less than 101: "))
while x < 1:
x = int(input("The number must be higher than 0: "))
else:
print ("The number is:",x)
There's a way to cheat the code by doing this:
Write a number between 1-100: 101
The number must be less than 101: 0
The number must be higher than 0: 101
The number is: 101
I basically don't want the user to be able to write a number higher than 100 or lower than 1.
I'm sorry for the bad explanation but I tried my best and, one again, i recently started programming.

I would just do it like this:
x = int(input("Enter a number in the range [1, 100]: "))
while not (1 <= x <= 100):
x = int(input("That number isn't in the range [1, 100]!: "))
else:
print ("The number is:",x)
You can of course, use nested if statements to make your prompt more informative of the error as follows:
x = int(input("Enter a number in the range [1, 100]: "))
while not (1 <= x <= 100):
if x > 100:
x = int(input("The number must be less than 101: "))
else:
x = int(input("The number must be greater than 0: "))
else:
print ("The number is:",x)
Remember that you can test multiple conditions at once!

Use logical or to test both the condition in a single while:
while not 1 <= x <= 100:
x = int(input("The number must be in range [1, 100]: "))
This will iterate the while loop till the user enters the input less than 1 or greater than 100. You can also notice that, this will lead you to an infinite loop, if user keeps on entering invalid input. I'll let you figure out how to solve this issue.

In Python, unlike other programming languages, expressions like a < b < c have the interpretation that is conventional in mathematics. This means that you can write your while-loop just like this:
x = int(input("Write a number between 1-100: "))
while not 1 <= x <= 100:
x = int(input("The number must be in the range 1-100: "))
else:
print ("The number is:", x)