This question already has an answer here:
Regex Matching - A letter not preceded by another letter
(1 answer)
Closed 4 years ago.
I need to search one key word, for example, "bcd" or "BCD"; but want to exclude the result of "abcd".
How could I use regex to accomplish this?
What I found on this site now is matching everything but excluding one word.
Try this regex,
(?<!a|A)(bcd|BCD)
This will match a bcd, not after 'a'
Regex
You may try this,
(?i)(?:^|[^a])bcd
You may play with it here,
https://regex101.com/r/jp0lqF/4
Related
This question already has answers here:
Python non-greedy regexes
(7 answers)
Closed 2 years ago.
I have a string string = "radios label="Does the command/question above meet the Rules to the left?" name="tq_utt_test" validates="required" gold="true" aggregation="agg"" and I want to be able to extract the substring within the "name". So in this case I want to extract "tq_utt_test" because it is the substring inside name.
I've tried regex re.findall('name=(.*)\s', string) which I thought would extract everything after the substring name= and before the first space. But after running that regex, it actually returned "tq_utt_test" validates="required" gold="true". So seems like it's returning everything between name= and the last space, instead of everything between name= and first space.
Is there a way to twist this regex so that it returns everything after name= and before the first space?
I will just do re.findall('name=([^ ]*)\s', string)
This question already has answers here:
Regular expression to match a line that doesn't contain a word
(34 answers)
Closed 3 years ago.
I'm trying to write a regex that filters out matches if they contain "plex" in them.
plex-release -> should not match
my-release -> should match
potato -> should match
Been playing with pythex and came up with this one that works partially:
(?![plex])(\w+)[-_](release|version)$
However this also messes with any other values containing the letter "p".
I'm trying to come up with a regex that leaves out matches that only contain the string "plex" and in this order, not just any letter from the string.
Yes, you can do it using this regex.
^((?!plex).)*$
Source : Regular expression to match a line that doesn't contain a word
This question already has answers here:
How to find overlapping matches with a regexp?
(4 answers)
Closed 4 years ago.
I am new to RegEx and I want to use regular expression to find words between dots.
For example, the text is something like:
abc.efg.hij.klm.opq.
I tried with below RegEx:
\.(\w+)\.
It only show me 2 matches:
.efg.
.klm.
Why am I getting this result?
Here is the link to the RegEx: https://regex101.com/r/pqMN8t/1/
It only shows two matches because the regex engine will not match what it has already matched. After matching .efg., it won't match the dot before hij, because that dot has already been matched (the dot after efg).
One way to fix this is to not match the dots and use lookaheads and lookbehinds instead:
(?<=\.)\w+(?=\.)
This way, the dots won't get matched.
This question already has answers here:
How to match a whole word with a regular expression?
(4 answers)
Closed 4 years ago.
I'm trying to use the date regex from this post:
^(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]|(?:Jan|Mar|May|Jul|Aug|Oct|Dec)))\1|(?:(?:29|30)(\/|-|\.)(?:0?[1,3-9]|1[0-2]|(?:Jan|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)(?:0?2|(?:Feb))\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9]|(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep))|(?:1[0-2]|(?:Oct|Nov|Dec)))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$
However, I want to find all matches that are also wrapped around white spaces.
For example in this sentence:
I went to Disney World on 11/11/1989 and once more on 12/12/2009
I want to get back:
11/11/1989
12/12/2009
How do I accomplish this? I'm using Python3 regex module if it matters.
If you want to tweak the regex you linked to work in a string like that, change the three ^ and $s to word boundaries (\b) instead:
\b(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]|(?:Jan|Mar|May|Jul|Aug|Oct|Dec)))\1|(?:(?:29|30)(\/|-|\.)(?:0?[1,3-9]|1[0-2]|(?:Jan|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)(?:0?2|(?:Feb))\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))\b|\b(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9]|(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep))|(?:1[0-2]|(?:Oct|Nov|Dec)))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})\b
https://regex101.com/r/WX5Itv/1
This question already has an answer here:
Reference - What does this regex mean?
(1 answer)
Closed 4 years ago.
I am trying to match regular expression using python in this code.
CDS_REGEX = re.compile(r'\+CDS:\s*"([^"]+)",\s*(\d+)$')
cdsiMatch = allLinesMatchingPattern(self.CDS_REGEX, notificationLine)
print cdsiMatch
Matching String:
['+CDS: 24', '079119890400202306A00AA17909913764514010106115225140101061452200']
Please help me i am not able to find my mistake,
As #Blckknght said, are you sure you really want to match that string?
What is ([^"]+) supposed to match?
You're looking for " instead of ' (you probably want ['"]).
You're only checking for numbers here: (\d+), but your long string clearly contains A's.