This question already has an answer here:
Reference - What does this regex mean?
(1 answer)
Closed 4 years ago.
I am trying to match regular expression using python in this code.
CDS_REGEX = re.compile(r'\+CDS:\s*"([^"]+)",\s*(\d+)$')
cdsiMatch = allLinesMatchingPattern(self.CDS_REGEX, notificationLine)
print cdsiMatch
Matching String:
['+CDS: 24', '079119890400202306A00AA17909913764514010106115225140101061452200']
Please help me i am not able to find my mistake,
As #Blckknght said, are you sure you really want to match that string?
What is ([^"]+) supposed to match?
You're looking for " instead of ' (you probably want ['"]).
You're only checking for numbers here: (\d+), but your long string clearly contains A's.
Related
This question already has answers here:
What is the difference between re.search and re.match?
(9 answers)
Closed 1 year ago.
See title. The behavior here is counterintuitive. I think maybe I am missing some flags or something? Why does the regex z not match the string az?
The reason is that match only matches the beginning of a string. Must use search to do the thing that match would do in all other programming languages.
Sorry to throw shade at you Python, but you're the odd one out here.
This question already has answers here:
My regex is matching too much. How do I make it stop? [duplicate]
(5 answers)
What do 'lazy' and 'greedy' mean in the context of regular expressions?
(13 answers)
Closed 4 years ago.
I am new to Python and I am struggling a bit with regular expressions. If I have an input like this:
text = <tag>xyz</tag>\n<tag>abc</tag>
Is it possible to get an output list with elements like:
matches = ['<tag>xyz</tag>','<tag>abc</tag>]
Right now I am using the following regex
matches = re.findall(r"<tag>[\w\W]*</tag>", text)
But instead of a list with two elements I am getting only one element with the whole input string like:
matches = ['<tag>xyz</tag>\n<tag>abc</tag>']
Could someone please guide me?
Thank you.
You just need to make your capture non-greedy.
Change this regex,
<tag>[\w\W]*</tag>
to
<tag>[\w\W]*?</tag>
import re
text = '<tag>xyz</tag>\n<tag>abc</tag>'
matches = re.findall(r"<tag>[\w\W]*?</tag>", text)
print(matches)
Prints,
['<tag>xyz</tag>', '<tag>abc</tag>']
This question already has answers here:
My regex is matching too much. How do I make it stop? [duplicate]
(5 answers)
Closed 4 years ago.
I would like to get, from the following string "/path/to/%directory_1%/%directory_2%.csv"
the following list: [directory_1, directory_2]. I would like to avoid using split by "%" my string. I was hoping to find a regex that could help me. However I cannot find the correct one.
For now, I have the following:
re.findall('%(.*)%', dirty_arg)
which output ["directory_1%/%directory_2"]
Do you have any recommandation about that?
Thank you very much for your help.
Try this:
import re
regex = r"%(.*?)%"
dirty_arg = "/path/to/%directory_1%/%directory_2%.csv"
print(re.findall(regex, dirty_arg))
I've added ? to your regex which makes sure it matches as few times as possible. The output of this code is ['directory_1', 'directory_2']
This question already has answers here:
Python regex -- extraneous matchings
(5 answers)
Closed 6 years ago.
I searched in all the internet and didnt get a good answer on this thing.
What parentheses in python are stand for? its very wierd..
For example, if i do:
re.split(r'(/s*)', "ho from there")
its will give me a list of separate words with the spaces between that... how does its happening?
This isn't specific to python, but in regex those denote a capture group.
Further information on how these are handled in re.split can be seen here
This question already has answers here:
What is the difference between re.search and re.match?
(9 answers)
Closed 7 years ago.
I am trying to match string with mypattern, somehow I do not get correct result. Can you please point where am I wrong?
import re
mypattern = '_U_[R|S]_data.csv'
string = 'X003_U_R_data.csv'
re.match(mypattern, string)
I like to compile the regex statement first. Then I do whatever kind of matching/searching I would like.
mypattern = re.compile(ur'_U_[R|S]_data.csv')
Then
re.search(mypattern, string)
Here's a great website for regex creation- https://regex101.com/#python