This question already has answers here:
What is the difference between re.search and re.match?
(9 answers)
Closed 7 years ago.
I am trying to match string with mypattern, somehow I do not get correct result. Can you please point where am I wrong?
import re
mypattern = '_U_[R|S]_data.csv'
string = 'X003_U_R_data.csv'
re.match(mypattern, string)
I like to compile the regex statement first. Then I do whatever kind of matching/searching I would like.
mypattern = re.compile(ur'_U_[R|S]_data.csv')
Then
re.search(mypattern, string)
Here's a great website for regex creation- https://regex101.com/#python
Related
This question already has an answer here:
Learning Regular Expressions [closed]
(1 answer)
Closed 3 years ago.
I cant find the solution for a regex that looks for a pattern but only in a specific range of the string
I want to find $ $ but only if it is in the 5-7 position of the string and it doesnt matter which character is between those two
Example
xxxx$x$xxxxx would match
xx$x$xxxxxxx would not
import re
should = "xxxx$x$xxxxx would match"
shouldnt = "xx$x$xxxxxxx would not"
pattern = r'^.{4}\$.\$.+'
re.match(pattern, should)
re.match(pattern, shouldnt)
gives
match
None
https://regex101.com/r/RLHrZb/1
This question already has answers here:
My regex is matching too much. How do I make it stop? [duplicate]
(5 answers)
What do 'lazy' and 'greedy' mean in the context of regular expressions?
(13 answers)
Closed 4 years ago.
I am new to Python and I am struggling a bit with regular expressions. If I have an input like this:
text = <tag>xyz</tag>\n<tag>abc</tag>
Is it possible to get an output list with elements like:
matches = ['<tag>xyz</tag>','<tag>abc</tag>]
Right now I am using the following regex
matches = re.findall(r"<tag>[\w\W]*</tag>", text)
But instead of a list with two elements I am getting only one element with the whole input string like:
matches = ['<tag>xyz</tag>\n<tag>abc</tag>']
Could someone please guide me?
Thank you.
You just need to make your capture non-greedy.
Change this regex,
<tag>[\w\W]*</tag>
to
<tag>[\w\W]*?</tag>
import re
text = '<tag>xyz</tag>\n<tag>abc</tag>'
matches = re.findall(r"<tag>[\w\W]*?</tag>", text)
print(matches)
Prints,
['<tag>xyz</tag>', '<tag>abc</tag>']
This question already has answers here:
What is the difference between re.search and re.match?
(9 answers)
Closed 6 years ago.
This is the code:
import re
regex = re.compile('java')
print regex.match('/something.java')
This is the output:
None
Because python match matches from the beginning. see
python -- re.match vs. re.search
you need to use pattern .*java if you want to use match.
This question already has answers here:
What's the u prefix in a Python string?
(5 answers)
Closed 6 years ago.
I am trying to parse the 'Meghan' part from the line:
link = http://python-data.dr-chuck.net/known_by_Meghan.html
...with the following regex:
print re.findall('by_(\S+).html$',link)
I am getting the output:
[u'Meghan']
Why I am getting the 'u'?
It means unicode. Depending on what you'll do with it, you can ignore it for the most part, of you can convert it to ascii by doing .encode('ascii')
This question already has an answer here:
Reference - What does this regex mean?
(1 answer)
Closed 4 years ago.
I am trying to match regular expression using python in this code.
CDS_REGEX = re.compile(r'\+CDS:\s*"([^"]+)",\s*(\d+)$')
cdsiMatch = allLinesMatchingPattern(self.CDS_REGEX, notificationLine)
print cdsiMatch
Matching String:
['+CDS: 24', '079119890400202306A00AA17909913764514010106115225140101061452200']
Please help me i am not able to find my mistake,
As #Blckknght said, are you sure you really want to match that string?
What is ([^"]+) supposed to match?
You're looking for " instead of ' (you probably want ['"]).
You're only checking for numbers here: (\d+), but your long string clearly contains A's.