This question already has answers here:
Python regex -- extraneous matchings
(5 answers)
Closed 6 years ago.
I searched in all the internet and didnt get a good answer on this thing.
What parentheses in python are stand for? its very wierd..
For example, if i do:
re.split(r'(/s*)', "ho from there")
its will give me a list of separate words with the spaces between that... how does its happening?
This isn't specific to python, but in regex those denote a capture group.
Further information on how these are handled in re.split can be seen here
Related
This question already has answers here:
Regex to find and replace emoji names within colons
(4 answers)
Closed 3 months ago.
At a complete loss here - trying to match a a colon either side of any given word in a passage of text.
For example:
:wave: Hello guys! :partyface: another huge win for us all to celebrate!
An appropriate regex that would match:
:wave:
:partyface:
Really appreciate your help!
\w*:\b
To catch all the content
:[^:]*:
To catch the content between
(?<=:)[^:]*(?=:)
This question already has answers here:
What is the difference between re.search and re.match?
(9 answers)
Closed 1 year ago.
See title. The behavior here is counterintuitive. I think maybe I am missing some flags or something? Why does the regex z not match the string az?
The reason is that match only matches the beginning of a string. Must use search to do the thing that match would do in all other programming languages.
Sorry to throw shade at you Python, but you're the odd one out here.
This question already has answers here:
strip punctuation with regex - python
(4 answers)
Closed 2 years ago.
I'm looking to remove reoccurring punctuation in a row.
E.g turn 'Hello...' into 'Hello.'
I've been reading some of the documentation on the matter, but am struggling to find a definitive method. (I personally find the docs on regex to a be a little overwhelming, and unclear at times).
I thought it may be something along the lines of:
re.sub('[!()-{};:,<>./?##$%^&*_~]+', '', input)
But this doesn't work. Any help? Thanks.
You can use this:
import re
input='Hello...'
re.sub(r'(\W)(?=\1)', '', input)
Output:
'Hello.'
This question already has answers here:
How to match a whole word with a regular expression?
(4 answers)
Closed 4 years ago.
I'm trying to use the date regex from this post:
^(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]|(?:Jan|Mar|May|Jul|Aug|Oct|Dec)))\1|(?:(?:29|30)(\/|-|\.)(?:0?[1,3-9]|1[0-2]|(?:Jan|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)(?:0?2|(?:Feb))\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9]|(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep))|(?:1[0-2]|(?:Oct|Nov|Dec)))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$
However, I want to find all matches that are also wrapped around white spaces.
For example in this sentence:
I went to Disney World on 11/11/1989 and once more on 12/12/2009
I want to get back:
11/11/1989
12/12/2009
How do I accomplish this? I'm using Python3 regex module if it matters.
If you want to tweak the regex you linked to work in a string like that, change the three ^ and $s to word boundaries (\b) instead:
\b(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]|(?:Jan|Mar|May|Jul|Aug|Oct|Dec)))\1|(?:(?:29|30)(\/|-|\.)(?:0?[1,3-9]|1[0-2]|(?:Jan|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)(?:0?2|(?:Feb))\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))\b|\b(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9]|(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep))|(?:1[0-2]|(?:Oct|Nov|Dec)))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})\b
https://regex101.com/r/WX5Itv/1
This question already has an answer here:
Reference - What does this regex mean?
(1 answer)
Closed 4 years ago.
I am trying to match regular expression using python in this code.
CDS_REGEX = re.compile(r'\+CDS:\s*"([^"]+)",\s*(\d+)$')
cdsiMatch = allLinesMatchingPattern(self.CDS_REGEX, notificationLine)
print cdsiMatch
Matching String:
['+CDS: 24', '079119890400202306A00AA17909913764514010106115225140101061452200']
Please help me i am not able to find my mistake,
As #Blckknght said, are you sure you really want to match that string?
What is ([^"]+) supposed to match?
You're looking for " instead of ' (you probably want ['"]).
You're only checking for numbers here: (\d+), but your long string clearly contains A's.