I am trying to get the number of views of my post on Telegram via BeautifulSoup. For example I want to take it from my channel post number 956: https://t.me/dayygesstt/956
<span class="tgme_widget_message_views">3.1K</span>
So "3.1K" is what I need.
import requests
from bs4 import BeautifulSoup
def get_html(url):
r = requests.get(url,'lxml')
return r.text
url='https://t.me/dayygesstt/956'
html=get_html(url)
soup=BeautifulSoup(html, )
x = soup.findAll("div", {"class": "tgme_page tgme_page_post"})
for i in x :
r=i.findAll("div", {"class": "tgme_page_widget"})
print(r)
and it prints:
[<div class="tgme_page_widget" id="widget">
<script async="" data-telegram-post="dayygesstt/956" data-width="100%" src="https://telegram.org/js/telegram-
widget.js?4"></script>
</div>]
I tried different stuff but I can't get more info. Please help me, what am I doing wrong? How to get information properly?
You can use the URL that loads the iframe in your script. Then you get just the widget without the cruft. For this take the original URL and append a query string "embed=1".
import requests
from bs4 import BeautifulSoup
url = 'https://t.me/dayygesstt/956?embed=1'
r = requests.get(url)
soup = BeautifulSoup(r.text, "html.parser")
views = soup.find("span", {"class": "tgme_widget_message_views"})
print(views.text)
I think you need to define which parser to use with BeautifulSoup in order for it to parse the HTML correctly, so this line;
soup=BeautifulSoup(html, )
needs to be this;
soup=BeautifulSoup(html, 'html.parser')
Related
I am trying to parse this page "https://www.imdb.com/title/tt0068112/?ref_=fn_al_tt_1", but I can't find the href that I need (href="/title/tt0068112/episodes?ref_=tt_eps_sm").
I tried with this code:
url="https://www.imdb.com/title/tt0068112/?ref_=fn_al_tt_1"
page(requests.get(url)
soup=BeautifulSoup(page.content,"html.parser")
for a in soup.find_all('a'):
print(a['href'])
What's wrong with this? I also tried to check "manually" with print(soup.prettify()) but it seems that that link is hidden or something like that.
You can get the page html with requests, the href item is in there, no need for special apis. I tried this and it worked:
import requests
from bs4 import BeautifulSoup
page = requests.get("https://www.imdb.com/title/tt0068112/?ref_=fn_al_tt_1")
soup = BeautifulSoup(page.content, "html.parser")
scooby_link = ""
for item in soup.findAll("a", href="/title/tt0068112/episodes?ref_=tt_eps_sm"):
print(item["href"])
scooby_link = "https://www.imdb.com" + "/title/tt0068112/episodes?ref_=tt_eps_sm"
print(scooby_link)
I'm assuming you also wanted to save the link to a variable for further scraping so I did that as well. 🙂
To get the link with Episodes you can use next example:
import requests
from bs4 import BeautifulSoup
url = "https://www.imdb.com/title/tt0068112/?ref_=fn_al_tt_1"
soup = BeautifulSoup(requests.get(url).content, "html.parser")
print(soup.select_one("a:-soup-contains(Episodes)")["href"])
Prints:
/title/tt0068112/episodes?ref_=tt_eps_sm
from bs4 import BeautifulSoup
import requests
from urllib.request import urlopen
url = f'https://www.apple.com/kr/search/youtube?src=globalnav'
response = requests.get(url)
html = response.text
soup = BeautifulSoup(html, 'html.parser')
links = soup.select(".rf-serp-productname-list")
print(links)
I want to crawl through all links of shown apps. When I searched for a keyword, I thought links = soup.select(".rf-serp-productname-list") would work, but links list is empty.
What should I do?
Just check this code, I think is what you want:
import re
import requests
from bs4 import BeautifulSoup
pages = set()
def get_links(page_url):
global pages
pattern = re.compile("^(/)")
html = requests.get(f"your_URL{page_url}").text # fstrings require Python 3.6+
soup = BeautifulSoup(html, "html.parser")
for link in soup.find_all("a", href=pattern):
if "href" in link.attrs:
if link.attrs["href"] not in pages:
new_page = link.attrs["href"]
print(new_page)
pages.add(new_page)
get_links(new_page)
get_links("")
Source:
https://gist.github.com/AO8/f721b6736c8a4805e99e377e72d3edbf
You can change the part:
for link in soup.find_all("a", href=pattern):
#do something
To check for a keyword I think
You are cooking a soup so first at all taste it and check if everything you expect contains in it.
ResultSet of your selection is empty cause structure in response differs a bit from your expected one from the developer tools.
To get the list of links select more specific:
links = [a.get('href') for a in soup.select('a.icon')]
Output:
['https://apps.apple.com/kr/app/youtube/id544007664', 'https://apps.apple.com/kr/app/%EC%BF%A0%ED%8C%A1%ED%94%8C%EB%A0%88%EC%9D%B4/id1536885649', 'https://apps.apple.com/kr/app/youtube-music/id1017492454', 'https://apps.apple.com/kr/app/instagram/id389801252', 'https://apps.apple.com/kr/app/youtube-kids/id936971630', 'https://apps.apple.com/kr/app/youtube-studio/id888530356', 'https://apps.apple.com/kr/app/google-chrome/id535886823', 'https://apps.apple.com/kr/app/tiktok-%ED%8B%B1%ED%86%A1/id1235601864', 'https://apps.apple.com/kr/app/google/id284815942']
I am trying to scrape this page https://ntrs.nasa.gov/search .
I am using the code below and Beautiful soup is finding only 3 tags when there are many more. I have tried using html5lib, lxml and HTML parsers but none of them have worked.
Can you advise what might be the problem please?
import requests
import urllib.request
import time
from bs4 import BeautifulSoup
# Set the URL
url = 'https://ntrs.nasa.gov/search'
# Connect to the URL
response = requests.get(url)
# Parse HTML and save to a BeautifulSoup object¶
soup = BeautifulSoup(response.content, "html5lib")
# soup = BeautifulSoup(response.text, "html5lib")
# soup = BeautifulSoup(response.content, "html.parser")
# soup = BeautifulSoup(response.content, "lxml")
# loop through all a-tags
for a_tag in soup.findAll('a'):
if 'title' in a_tag:
if a_tag['title'] == 'Download Document':
link = a_tag['href']
download_url = 'https://ntrs.nasa.gov' + link
urllib.request.urlretrieve(download_url,'./'+link[link.find('/citations/')+1:11])
It is dynamically pulled from a script tag. You can regex out the JavaScript object which contains the download url, handle some string replacements for html entities, parse as json then extract the desired url:
import requests, re, json
r = requests.get('https://ntrs.nasa.gov/search')
data = json.loads(re.search(r'(\{.*/api.*\})', r.text).group(1).replace('&q;','"'))
print('https://ntrs.nasa.gov' + data['http://ntrs-proxy-auto-deploy:3001/citations/search']['results'][0]['downloads'][0]['links']['pdf'])
You could append the ?attachment=true but I don't think that is required.
Your problem stems from the fact that the page is rendered using Javascipt, and the actual page source is only a few script and style tags.
i just started programming.
I have the task to extract data from a HTML page to Excel.
Using Python 3.7.
My Problem is, that i have a website, whith more urls inside.
Behind these urls again more urls.
I need the data behind the third url.
My first Problem would be, how i can dictate the programm to choose only specific links from an ul rather then every ul on the page?
from bs4 import BeautifulSoup
import urllib
import requests
import re
page = urllib.request.urlopen("file").read()
soup = BeautifulSoup(page, "html.parser")
print(soup.prettify())
for link in soup.find_all("a", href=re.compile("katalog_")):
links= link.get("href")
if "katalog" in links:
for link in soup.find_all("a", href=re.compile("alle_")):
links = link.get("href")
print(soup.get_text())
There are many ways, one is to use "find_all" and try to be specific on the tags like "a" just like you did. If that's the only option, then use regular expression with your output. You can refer to this thread: Python BeautifulSoup Extract specific URLs. Also please show us either the link, or html structure of the links you want to extract. We would like to see the differences between the URLs.
PS: Sorry I can't make comments because of <50 reputation or I would have.
Updated answer based on understanding:
from bs4 import BeautifulSoup
import urllib
import requests
page = urllib.request.urlopen("https://www.bsi.bund.de/DE/Themen/ITGrundschutz/ITGrundschutzKompendium/itgrundschutzKompendium_node.html").read()
soup = BeautifulSoup(page, "html.parser")
for firstlink in soup.find_all("a",{"class":"RichTextIntLink NavNode"}):
firstlinks = firstlink.get("href")
if "bausteine" in firstlinks:
bausteinelinks = "https://www.bsi.bund.de/" + str(firstlinks.split(';')[0])
response = urllib.request.urlopen(bausteinelinks).read()
soup = BeautifulSoup(response, 'html.parser')
secondlink = "https://www.bsi.bund.de/" + str(((soup.find("a",{"class":"RichTextIntLink Basepage"})["href"]).split(';'))[0])
res = urllib.request.urlopen(secondlink).read()
soup = BeautifulSoup(res, 'html.parser')
listoftext = soup.find_all("div",{"id":"content"})
for text in listoftext:
print (text.text)
HTML noob here, so I could be misunderstanding something about the HTML document, so bear with me.
I'm using Beautiful Soup to parse web data in Python. Here is my code:
import urllib
import BeautifulSoup
url = "http://www.nba.com/gameline/20160323/"
page = urllib.urlopen(url).read()
soup = BeautifulSoup.BeautifulSoup(page)
indicateGameDone = str(soup.find("div", {"class": "nbaModTopStatus"}))
print indicateGameDone
now, if you look at the website, the HTML code has the line <p class="nbaLiveStatTxSm"> FINAL </p>, (inspect the 'Final' text on the left side of the container on the first ATL-WAS game on the page to see it for youself.) But when I run the code above, my code doesn't return the 'FINAL' that is seen on the webpage, and instead the nbaLiveStatTxSm class is empty.
On my machine, this is the output when I print indicateGameDone:
<div class="nbaModTopStatus"><p class="nbaLiveStatTx">Live</p><p class="nbaLiveStatTxSm"></p><p class="nbaFnlStatTx">Final</p><p class="nbaFnlStatTxSm"></p></div>
Does anyone know why this is happening?
EDIT: clarification: the problem isn't retrieving the text within the tag, the problem is that when I take the html code from the website and print it out in python, something that I saw when I inspected the element on the web is not there in the print statement in Python.
You can use this logic to extract any text.
This code allows you to extract any data between any tags.
Output - FINAL
import urllib
from bs4 import BeautifulSoup
url = "http://www.nba.com/gameline/20160323/"
page = urllib.urlopen(url)
soup = BeautifulSoup(page)
indicateGameDone = soup.find("div", {"class": "nbaFnlStatTx"})
for p in indicateGameDone:
p_text = soup.find("p", {"class": "nbaFnlStatTxSm"})
print(p_text.getText())
break;
It looks like your problem is not with BeautifulSoup but instead with urllib.
Try running the following commands
>>> import urllib
>>> url = "http://www.nba.com/gameline/20160323/"
>>> page = urllib.urlopen(url).read()
>>> page.find('<div class="nbaModTopStatus">')
44230
Which is no surprise considering that Beautiful Soup was able to find the div itself. However when we look a little deeper into what urllib is actually collecting we can see that the <p class="nbaFnlStatTxSm"> is empty by running
>>> page[44230:45000]
'<div class="nbaModTopStatus"><p class="nbaLiveStatTx">Live</p><p class="nbaLiveStatTxSm"></p><p class="nbaFnlStatTx">Final</p><p class="nbaFnlStatTxSm"></p></div><div id="nbaGLBroadcast"><img src="/.element/img/3.0/sect/gameline/broadcasters/lp.png"></div><div class="nbaTeamsRow"><div class="nbaModTopTeamScr nbaModTopTeamAw"><h5 class="nbaModTopTeamName awayteam">ATL</h5><img src="http://i.cdn.turner.com/nba/nba/.element/img/2.0/sect/gameline/teams/ATL.gif" width="34" height="22" title="Atlanta Hawks"><h4 class="nbaModTopTeamNum win"></h4></div><div class="nbaModTopTeamScr nbaModTopTeamHm"><h5 class="nbaModTopTeamName hometeam">WAS</h5><img src="http://i.cdn.turner.com/nba/nba/.element/img/2.0/sect/gameline/teams/WAS.gif" width="34" '
You can see that the tag is empty, so your problem is the data that's being passed to Beautiful Soup, not the package itself.
changed the import of beautifulsoup to the proper syntax for the current version of BeautifulSoup
corrected the way you were constructing the BeautifulSoup object
fixed your find statement, then used the .text command to get the string representation of the text in the HTML you're after.
With some minor modifications to your code as listed above, your code runs for me.
import urllib
from bs4 import BeautifulSoup
url = "http://www.nba.com/gameline/20160323/"
page = urllib.urlopen(url).read()
soup = BeautifulSoup(page)
indicateGameDone = soup.find("div", {"class": "nbaModTopStatus"})
print indicateGameDone.text ## "LiveFinal "
to address comments:
import urllib
from bs4 import BeautifulSoup
url = "http://www.nba.com/gameline/20160323/"
page = urllib.urlopen(url).read()
soup = BeautifulSoup(page)
indicateGameDone = soup.find("p", {"class": "nbaFnlStatTx"})
print indicateGameDone.text