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How can i add an input in every line of a displayed data? [closed]

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im trying to have an input in every line of the displayed data.
here are the codes
def attendance():
print ("\n\nList of Students\n")
print ("StudNo StudName Age Course Attendance")
for idx in range(len(studNo)):
print (" {0:15} {1:10s} {2:10s} {3:10s}".format(studNo[idx],
studName[idx], Age[idx], Course[idx]))
and this is the output
List of Students
StudNo StudName Age Course Attendance
a1001 Daryl 21 CS
a1002 Akex 21 CS
a1003 John 24 CS
a1004 Jose 22 CS
im creating a simple attendance monitoring system. so im trying to have an input for each line so i can write A for absent or P for present.

You can use the input function. input("Write your prompt here") will print the prompt and ask the user to write an entry of text. This can get messy with your desired output, so I suggest collecting all attendance information and then printing
students = ['Kathy','Will','Nayeon']
attendanceRecord = []
for student in students:
attendance = input("What is "+student+"\'s attendance? ")
attendanceRecord.append(attendance)
print("\n") # add a space before printing student list
print("Name"+" Attendace")
for i in range(len(students)):
print(students[i] + " "+ attendanceRecord[i])

python getting plural of a noun [closed]

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i am trying to make the same functionality using lambda to get the plural of a word, this is my function (i want to write it in lambda form).
import re
def plural(noun):
if re.search("[sxz]$",noun):
return re.sub("$","es",noun)
elif re.search("[^aeioudgkprt]h$",noun):
return re.sub("$","es",noun)
elif re.search("[^aeiou]y$",noun):
return re.sub("y$","ies",noun)
else:
return noun+"s"
i want to make the same function job using lambda ,not sure where to start.
(i am using python 2.7)

import inflect
result = inflect.engine().plural('bike')

import re
rules=((lambda word:re.search('[sxz]$',word),lambda word:re.sub('$','es',word)),
(lambda word: re.search('[^aeioudgkprt]h$', word),lambda word: re.sub('$', 'es', word)),
(lambda word: re.search('[^aeiou]y$', word),lambda word: re.sub('y$', 'ies', word)),
(lambda word: re.search('$', word),lambda word: re.sub('$', 's', word)))
def plural(noun):
for findpattern,rule in rules:
if findpattern(noun):
return rule(noun)
print plural('boy')
This your functions as lambda rules, it will search for pattern if it's true,apply rule

Very simple python cycle string [closed]

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I want to write in a file which changes the name with the counter.
for j in range(30):
fileout.write("bla bla")
and fileout should be
file001 if j=1
file002 if j=2
...
...
I cannot format it in the right way.
Anyone can help me?
Thank you

You can try to use the .zfill( < number of digits > ) option. It will complet your string with 0.
For example, this code should work :
radical ='file'
numberOfDigits = 3
for j in range( 30 ) :
fileout = open ( radical + '%s' %(str(j).zfill(numberOfDigits)) + '.txt' , 'w' )
fileout.write('bla bla')
fileout.close()

Not sure if below means what you needed ?
Code below will create file000 - file029 with 'bla bla' inside
for i in range(30):
with open("file%03d" % i, 'w') as f:
f.write('bla bla')

Create correct loop output with python function [closed]

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Could someone help me with following function:
def nagios_chart():
alpha = [chr(item).upper() for item in range(ord('b'), ord('l')+1)]
for idx, column in enumerate(alpha):
print worksheet.write_column('column + 1', nagios_data[idx])
if __name__ == '__main__':
nagios_chart()
I need output like this:
worksheet.write_column('B1', nagios_data[0])
worksheet.write_column('C1', nagios_data[1])
worksheet.write_column('D1', nagios_data[2])
worksheet.write_column('E1', nagios_data[3])
worksheet.write_column('F1', nagios_data[4])
worksheet.write_column('G1', nagios_data[5])
worksheet.write_column('H1', nagios_data[6])
worksheet.write_column('I1', nagios_data[7])
worksheet.write_column('J1', nagios_data[8])
worksheet.write_column('K1', nagios_data[9])
worksheet.write_column('L1', nagios_data[10])

To use the column as a variable, remove it from the quotes so it isn't treated as a string literal. Then you can concatenate it with '1'.
def nagios_chart():
alpha = [chr(item).upper() for item in range(ord('b'), ord('l')+1)]
for idx, column in enumerate(alpha):
print worksheet.write_column(column + '1', nagios_data[idx])

Python GQL query not working [closed]

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ID = int(data_key)
results = db.GqlQuery("SELECT * FROM PatientMeds WHERE patientinfo_ID='ID'")
where i have done wrong...
Thanks..

Use a parameter (examples 1, 2):
ID = int(data_key)
results = db.GqlQuery("SELECT * FROM PatientMeds WHERE patientinfo_ID=:1", ID)
# or
results = db.GqlQuery("SELECT * FROM PatientMeds WHERE patientinfo_ID=:id", id=ID)

You could also use the more "Pythonic" model API:
from path.to.your.models import PatientMeds
results = PatientMeds.all().filter('patientinfo_ID =', int(data_key))