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python string find and look up on string until found space from json [closed]

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Below is my data.
'{"Data": {"a":5647953897,"b":"323299901059958183671030","c":1605858513465}}{"Data": {"a":5647953897,"b":"323299901059958183671030","c":1605858513465}}'
My output should be as below
[{"a":5647953897,"b":"323299901059958183671030","c":1605858513465},{"a":5647953897,"b":"323299901059958183671030","c":1605858513465}]

This should solve your case.
from json import JSONDecoder, JSONDecodeError
import re
NOT_WHITESPACE = re.compile(r'[^\s]')
data = '''{"Data": {"a":5647953897,"b":"323299901059958183671030","c":1605858513465}}{"Data": {"a":5647953897,"b":"323299901059958183671030","c":1605858513465}}'''
def decode_stacked(document, pos=0, decoder=JSONDecoder()):
while True:
match = NOT_WHITESPACE.search(document, pos)
if not match:
return
pos = match.start()
try:
obj, pos = decoder.raw_decode(document, pos)
except JSONDecodeError:
raise
yield obj
for obj in decode_stacked(data):
print(obj)

Create email with the firsts letters of the name [closed]

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Is there any magic python way to get the firsts letters of each name and join with '#company.com' to create a email address?
Here is how I did:
name = ['Elon Reeve Musk']
full_name = [word[0].lower() for word in name[0].split(' ')]
firts_letters = "".join(full_name)
username = '%s#company.com' %(firts_letters)
The result is erm#company.com

Here's some "python magic"
name = ['Elon Reeve Musk']
f"{''.join(filter(str.isupper, name[0]))}#company.com".lower()
>>> erm#company.com
Whether this is better than your method is debatable. Most of the time a few lines of easy to read code is better than a one line hack.
My recommendation would be
name = ['Elon Reeve Musk']
initials = ''.join(word[0] for word in name[0].split())
f'{initials.lower()}#company.com'
>>> erm#company.com

Very simple python cycle string [closed]

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I want to write in a file which changes the name with the counter.
for j in range(30):
fileout.write("bla bla")
and fileout should be
file001 if j=1
file002 if j=2
...
...
I cannot format it in the right way.
Anyone can help me?
Thank you

You can try to use the .zfill( < number of digits > ) option. It will complet your string with 0.
For example, this code should work :
radical ='file'
numberOfDigits = 3
for j in range( 30 ) :
fileout = open ( radical + '%s' %(str(j).zfill(numberOfDigits)) + '.txt' , 'w' )
fileout.write('bla bla')
fileout.close()

Not sure if below means what you needed ?
Code below will create file000 - file029 with 'bla bla' inside
for i in range(30):
with open("file%03d" % i, 'w') as f:
f.write('bla bla')

Return outside function error - help needed [closed]

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def getPressAve(odbname):
odb=openOdb(odbname)
lastFrame=odb.steps['Step-1'].frames[-1]
pressure=lastFrame.fieldOutputs['CPRESS']
press=[[0,0]] # sets the first element to [0,0]
for n in pressure.values:
gridPt=part1.nodes.getFromLabel(n.nodeLabel)
coord=assemb.getCoordinates(gridPt)
press.append([n.nodeLabel,n.data,coord])
press=avePress=press[1:] # removes the first element
press.sort(Comp_X)
print ('pressure extracted')
index=0
while index<len(press):
sum=0
tally=0
if index!=0:
sum=sum+press[index-1][1]
tally=tally+1
if index!=1:
sum=sum+press[index-2][1]
tally=tally+1
if index!=2:
sum=sum+press[index][1]
tally=tally+1
if index<len(press)-1:
sum=sum+press[index+1][1]
tally=tally+1
if index<len(press)-2:
sum=sum+press[index+2][1]
tally=tally+1
average=sum/tally
avePress[index][1]=average
index=index+1
odb.close()
print ('pressure averaged')
return avePress

In Python, indentation matters. As is, you're defining a function called getPressAve which does only this:
odb=openOdb(odbname)
After you've defined your function, you go on to do
lastFrame=odb.steps['Step-1'].frames[-1]
and such outside of the function. That's not what you want. The solution is to indent everything after that odb=openOdb(odbname) line to that level, so those lines are interpreted as being part of the body of the function.

You forgot to properly indent your code:
def getPressAve(odbname):
odb=openOdb(odbname)
...
print ('pressure averaged')
return avePress
As yours has not been, the return keyword is featured outside of a function, and hence the error: SyntaxError: 'return' outside function.

Python GQL query not working [closed]

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ID = int(data_key)
results = db.GqlQuery("SELECT * FROM PatientMeds WHERE patientinfo_ID='ID'")
where i have done wrong...
Thanks..

Use a parameter (examples 1, 2):
ID = int(data_key)
results = db.GqlQuery("SELECT * FROM PatientMeds WHERE patientinfo_ID=:1", ID)
# or
results = db.GqlQuery("SELECT * FROM PatientMeds WHERE patientinfo_ID=:id", id=ID)

You could also use the more "Pythonic" model API:
from path.to.your.models import PatientMeds
results = PatientMeds.all().filter('patientinfo_ID =', int(data_key))