Unexpected output of weird characters for Python sqlite3 database - python

My python 3.6 code is supposed to create a database and create a table inside it.
import sqlite3
db_filename = 'database.db'
connect = sqlite3.connect(db_filename)
c = connect.cursor()
c.execute('CREATE TABLE IF NOT EXISTS task (id number PRIMARY KEY, priority integer, details text, status text)')
connect.commit()
connect.close()
However the output is not what I intended. I am getting weird characters included in the .db file;
SQLite format 3  # .�
� b b� k�9tabletasktaskCREATE TABLE task (id number PRIMARY KEY, priority integer, details text, status text)'; indexsqlite_autoindex_task_1task


If anyone could tell me where I went wrong I would be grateful.
Thanks.

There is nothing wrong here. To view a .db file you need db viewer or reader tool. http://sqlitebrowser.org/ has DB browser for SQLite which can be used to view your database. You can install it and use it to read your .db file.
If you want to use the table you can do so by inserting elements in the table and viewing it as follows:
import sqlite3
db_filename = 'database.db'
connect = sqlite3.connect(db_filename)
c = connect.cursor()
c.execute('CREATE TABLE IF NOT EXISTS task (id number PRIMARY KEY, priority integer, details text, status text)')
c.execute("INSERT INTO task (id,priority,details,status) \
VALUES (1,22,'ABC','YES' )");
cursor = c.execute("SELECT id,priority,details,status from task")
for row in cursor:
print ("ID = ", row[0])
print ("PRIORITY = ", row[1])
print ("DETAILS = ", row[2])
print ("STATUS = ", row[3], "\n")
connect.commit()
connect.close()
OUTPUT:
ID = 1
PRIORITY = 22
DETAILS = ABC
STATUS = YES

Related

How to initialize a database just once on Python using SQLite 3?

I'm trying to make a python app where the user can add a row to a table and visualize all the rows. My problem is that it seems that every time I run the program, the database is created again, with no values. I say this because there is an autoincrement value that is always the same. When I write the program again on the cmd and insert the values by hand it does show me more than one value.
Here's the code:
import sqlite3
conn = sqlite3.connect("amigo_local_db.db")
c = conn.cursor()
c.execute("CREATE TABLE IF NOT EXISTS images (id INTEGER PRIMARY KEY AUTOINCREMENT, url TEXT, bash TEXT)")
action = int(input("Insert an action: (1: Add row | 2: Close)"))
if(action == 1):
url = input("URL: ")
bash = input("BASH: ")
values = (url,bash)
c.execute("INSERT INTO images VALUES(null,?,?)",values)
else:
conn.close()
quit()
for row in c.execute("SELECT * FROM images"):
print(row)
conn.close()
You need to commit the INSERT transaction before closing, or it will not be persisted:
import sqlite3
conn = sqlite3.connect("amigo_local_db.db")
c = conn.cursor()
c.execute("CREATE TABLE IF NOT EXISTS images (id INTEGER PRIMARY KEY AUTOINCREMENT, url TEXT, bash TEXT)")
action = int(input("Insert an action: (1: Add row | 2: Close)"))
if(action == 1):
url = input("URL: ")
bash = input("BASH: ")
values = (url,bash)
c.execute("INSERT INTO images VALUES(null,?,?)",values)
conn.commit()
else:
conn.close()
quit()
for row in c.execute("SELECT * FROM images"):
print(row)
conn.close()

How to get columns from a query in python?

I have that query in a python program:
And i should create a multidimensional array (if it possible) or four arrays from this query for every column from the query.
Can you suggest an elegant way to solve it?
conn = #connection to the server
cursor=conn.cursor()
query = (" select id, name, phone, city from guest")
cursor.execute(query)
results = cursor.fetchall
for i in results:
print i
cursor.close()
conn.close()
Not elegant but it may assist to unravel the mysterious Python Connector Cursor Class and transfers the list of tuples (see Copperfield comment) with the data from the query, into a list (phoneList) of dictionaries (entries) with details of each entry in the database, that might be easier to work with in your python script:
# ref: https://dev.mysql.com/doc/connector-python/en/connector-python-api-mysqlcursor.html
import mysql.connector
db = 'test'
table = 'phonebook'
phoneList = []
drop_table = ("DROP TABLE IF EXISTS {};").format(table)
# By default, the starting value for AUTO_INCREMENT is 1, and it will increment by 1 for each new record.
# To let the AUTO_INCREMENT sequence start with another value, use the following SQL statement:
# ALTER TABLE phonebook AUTO_INCREMENT=100;
create_table = ("CREATE TABLE {} ("
"id int NOT NULL AUTO_INCREMENT,"
"name varchar(30) NOT NULL,"
"phone varchar(30) NOT NULL,"
"city varchar(30) NOT NULL,"
"PRIMARY KEY (id))"
" ENGINE=InnoDB DEFAULT CHARSET=latin1;").format(table)
Names = {'Bill':{'phone':'55123123','city':'Melbourne'},
'Mary':{'phone':'77111123','city':'Sydney'},
'Sue':{'phone':'55888123','city':'Melbourne'},
'Harry':{'phone':'77777123','city':'Sydney'},
'Fred':{'phone':'88123444','city':'Yongala'},
'Peter':{'phone':'55999123','city':'Melbourne'}}
cnx = mysql.connector.connect(user='mysqluser', password='xxxx',host='127.0.0.1',database=db)
cursor = cnx.cursor(dictionary=True) # key to using **row format
cursor.execute(drop_table)
cursor.execute(create_table)
# populate db
for name,detail in dict.items(Names):
sql = ("INSERT INTO {} (name,phone,city) VALUES ('{}','{}','{}')".format(table,name,detail['phone'],detail['city']))
cursor.execute(sql)
sql = ("SELECT id,name,phone,city FROM {}".format(table))
cursor.execute(sql)
for row in cursor:
print("{id} {name} {phone} {city}".format(**row))
phoneList.append(row)
print phoneList[0]['name'],phoneList[0]['city']
print phoneList[3]['name'],phoneList[3]['phone']
for entries in phoneList: # list of dictionaries
print entries['name'],entries
for entries in phoneList:
for k,v in dict.items(entries):
print k,v
print "\n"
cnx.close()

Python script and mysql database with update query does't work

I have a python script that I created to update a MySQL database the insert work perfect but when I tried to update it nothing happen and it doesn't change.
The console displays this error from the try and except
Unable to print data
Can anyone help me to fix this error?
MySQL database
Database student
Table structure for table stu
Column Type Null Default
ID int(8) No
Name varchar(255) No
subject varchar(255) No
Dumping data for table stu
11 jhon python
12 jina hjsdhjsd
13 jaSDJ JHAISDJ
Python script
#!/usr/bin/python
# UPDATE AND delete some values from the database ###
import MySQLdb
db = MySQLdb.Connect("localhost", "****", "******", "student")
cursor = db.cursor()
sql = "UPDATE STU SET NAME = MAROUN, SUBJECT = C++ WHERE ID = 13 "
try:
cursor.execute(sql)
# r = cursor.fetchall()
# for row in r:
# ID = row[0]
# NAME = row[1]
# SUBJECT = row[2]
# print "ID = %d, LAST_NAME = %s, SUBJECT = %s " %(ID, NAME, SUBJECT)
print "update ok "
except Exception as e:
print e
db.close()

Cannot copy one table to another?

I am using python to copy one table (dictionary) to another (origin_dictionary) in SQLite, and here is my code to this part:
def copyDictionaryToOrigin(self):
dropTableQueryStr = "DROP TABLE IF EXISTS origin_dictionary"
createTableQueryStr = "CREATE TABLE origin_dictionary (id INTEGER PRIMARY KEY AUTOINCREMENT, word TEXT, type TEXT)"
syncTableQueryStr = "INSERT INTO origin_dictionary (word, type) SELECT word, type FROM dictionary"
self.cur.execute(dropTableQueryStr)
self.cur.fetchone()
self.cur.execute(createTableQueryStr)
result = self.cur.fetchone()
self.cur.execute(syncTableQueryStr)
result = self.cur.fetchone()
With running this code, I can see a origin_dictionary table is created, but there is no data in the table. I could not find out the reason why the data didn't copy over to the new table. can someone please help me with this?
If you need to simply copy one table to another, why don't you use CREATE TABLE ... AS SELECT? Also, you need to commit() your statements.
Simply use code below, and it should work:
import sqlite3
conn = sqlite3.connect(example.db")
cur = conn.cursor()
cur.execute("DROP TABLE IF EXISTS origin_dictionary")
cur.execute("CREATE TABLE origin_dictionary AS SELECT * FROM dictionary")
conn.commit()
conn.close()

Can't get the last row id from SQLITE3 database

I have a script that asks for input, and that input is then inserted into a table.
The next time the script is run, I'd like for it to tell the user what id the last input has.
The table looks like: id INTEGER PRIMARY KEY AUTOINCREMENT, userid TEXT, domain TEXT, password TEXT, webserver TEXT, sqlserver TEXT
I was told I could use SELECT seq from SQLITE_SEQUENCE WHERE name='table_name' but it yields the following text: instead of the id from the last row.
Please note that I'm an extremely new Python / SQLite3 coder!
For your reference, the code sofar looks like this:
#!/usr/bin/python
import os, sys, sqlite3
######## CHECK SYSTEM COMPATIBILITY ########
if os.name =='posix':
os.system("clear")#CLEAR SCREEN#
pass
else:
sys.exit("Operating System is not supported")
######## END CHECK SYSTEM COMPATIBILITY ########
######## CHECK IF SCRIPT IS RUN AS ROOT ########
#if os.geteuid() != 0:
# sys.exit("Script must be run as root")
#else:
# pass
####### END CHECK IF SCRIPT IS RUN AS ROOT ########
####### CREATE DATABASE AND CHECK IF TABLE EXISTS ##########
conn = sqlite3.connect("dat.db")
c = conn.cursor()
c.execute ('''CREATE TABLE IF NOT EXISTS kunder
(id INTEGER PRIMARY KEY AUTOINCREMENT, userid TEXT, domain TEXT, password TEXT, webserver TEXT, sqlserver TEXT)''')
conn.commit()
print c.execute ("SELECT seq from SQLITE_SEQUENCE WHERE name='kunder'")
conn.close()
######## DONE CREATE DATABASE AND CHECK IF TABLE EXISTS #########
###### ASK FOR INPUT ##########
########### HERE NEEDS TO BE A CHECK TO DETERMINE THE LATEST USERID - ALSO NEEDS TO BE FOR WEBSERVER AND PASSWORD #################
userid = raw_input("Enter userid: ")
########### HERE NEEDS TO BE A CHECK TO SEE IF USERID EXISTS!!!!!#####################
domain = raw_input("Enter domain: ")
password = raw_input("Enter password: ")
########### NEEDS TO BE A WAY TO AUTOGENERATE A PASSWORD!!! ####################
webserver = raw_input("Enter webserver: ")
sqlserver = raw_input("Enter sqlserver: ")
###### FINISHED ASK FOR INPUT #######
######## DATABASE ###########
conn = sqlite3.connect("dat.db")
c = conn.cursor()
c.execute ("INSERT INTO kunder (userid, domain, password, webserver, sqlserver) VALUES (?,?,?,?,?)", (userid, domain, password, webserver, sqlserver))
conn.commit()
conn.close()
####### DONE WITH DATABASE ##########
The SQL statement SELECT max(id) FROM table_name should give you the maximum id. If you're auto-incrementing then this would be the same as the last inserted.
Edit: To get the actual value in python means reading it from the cursor:
cursor = sqlite3.execute('SELECT max(id) FROM table_name')
max_id = cursor.fetchone()[0]
fetchone() returns the first row from the select statement as a tuple (unless a row_factory is used), so fetchone()[0] will, in this case, return the first (and only) column in the first (and only) row, i.e. the max(id).
See http://docs.python.org/2/library/sqlite3.html for more info.
Try using sqlite3_last_insert_rowid()
import sqlite3
data_person_name = [('Michael', 'Fox'),
('Adam', 'Miller'),
('Andrew', 'Peck'),
('James', 'Shroyer'),
('Eric', 'Burger')]
con = sqlite3.connect(":memory:")
c = con.cursor()
c.execute('''CREATE TABLE q1_person_name
(name_id INTEGER PRIMARY KEY,
first_name varchar(20) NOT NULL,
last_name varchar(20) NOT NULL)''')
for data_person in data_person_name:
c.execute('INSERT INTO q1_person_name(first_name, last_name) VALUES (?,?)', data_person)
# get the last rowid inserted
last_name_id = c.lastrowid
print(last_name_id)

Categories