I'm quite new to Programming and OO programming especially. Nonetheless, I'm trying to write a very simple Spider for web crawling. Here's my first approach:
I need to fetch the data out of this page: http://europa.eu/youth/volunteering/evs-organisation_en
Firstly, I do a view on the page source to find HTML elements?
view-source:https://europa.eu/youth/volunteering/evs-organisation_en
Note: I need to fetch the data that comes right below this line:
EVS accredited organisations search results: 6066
I chose beautiful soup for this job - since it is very powerful:
I Use find_all:
soup.find_all('p')[0].get_text() # Searching for tags by class and id
Note: Classes and IDs are used by CSS to determine which HTML elements to apply certain styles to. We can also use them when scraping to specify specific elements we want to scrape.
See the class:
<div class="col-md-4">
<div class="vp ey_block block-is-flex">
<div class="ey_inner_block">
<h4 class="text-center">"People need people" Zaporizhya oblast civic organisation of disabled families</h4>
<p class="ey_info">
<i class="fa fa-location-arrow fa-lg"></i>
Zaporizhzhya, <strong>Ukraine</strong>
</p> <p class="ey_info"><i class="fa fa-hand-o-right fa-lg"></i> Sending</p>
<p><strong>PIC no:</strong> 935175449</p>
<div class="empty-block">
Read more </div>
</div>
so this leads to:
# import libraries
import urllib2
from bs4 import BeautifulSoup
page = requests.get("https://europa.eu/youth/volunteering/evs-organisation_en")
soup = BeautifulSoup(page.content, 'html.parser')
soup
Now, we can use the find_all method to search for items by class or by id. In the below example, we'll search for any p tag that has the class outer-text
<div class="col-md-4">
so we choose:
soup.find_all(class_="col-md-4")
Now I have to combine all.
update: my approach: so far:
I have extracted data wrapped within multiple HTML tags from a webpage using BeautifulSoup4. I want to store all of the extracted data in a list. And - to be more concrete: I want each of the extracted data as separate list elements separated by a comma (i.e.CSV-formated).
To begin with the beginning:
here we have the HTML content structure:
<div class="view-content">
<div class="row is-flex"></span>
<div class="col-md-4"></span>
<div class </span>
<div class= >
<h4 Data 1 </span>
<div class= Data 2</span>
<p class=
<i class=
<strong>Data 3 </span>
</p> <p class= Data 4 </span>
<p class= Data 5 </span>
<p><strong>Data 6</span>
<div class=</span>
<a href="Data 7</span>
</div>
</div>
Code to extract:
for data in elem.find_all('span', class_=""):
This should give an output:
data = [ele.text for ele in soup.find_all('span', {'class':'NormalTextrun'})]
print(data)
Output:
[' Data 1 ', ' Data 2 ', ' Data 3 ' and so forth]
question: / i need help with the extraction part...
try this
data = [ele.text for ele in soup.find_all(text = True) if ele.text.strip() != '']
print(data)
Related
I have a html code that looks kind of like this (shortened);
<div id="activities" class="ListItems">
<h2>Standards</h2>
<ul>
<li>
<a class="Title" href="http://www.google.com" >Guidelines on management</a>
<div class="Info">
<p>
text
</p>
<p class="Date">Status: Under development</p>
</div>
</li>
</ul>
</div>
<div class="DocList">
<h3>Reports</h3>
<p class="SupLink">+ <a href="http://www.google.com/test" >View More</a></p>
<ul>
<li class="pdf">
<a class="Title" href="document.pdf" target="_blank" >Document</a>
<span class="Size">
[1,542.3KB]
</span>
<div class="Info">
<p>
text <a href="http://www.google.com" >Read more</a>
</p>
<p class="Date">
14/03/2018
</p>
</div>
</li>
</ul>
</div>
I am trying to select the value in 'href=' under 'a class="Title"' by using this code:
def sub_path02(url):
page = requests.get(url)
tree = html.fromstring(page.content)
url2 = []
for node in tree.xpath('//a[#class="Title"]'):
url2.append(node.get("href"))
return url2
But I get two returns, the one under 'div class="DocList"' is also returned.
I am trying to change my xpath expressions so that I would only look within the node but I cannot get it to work.
Could someone please help me understand how to "search" within a specific node. I have gone through multiple xpath documentations but I cannot seem to figure it out.
Using // you are already selecting all the a elements in the document.
To search in a specific div try specifying the parent with // and then use //a again to look anywhere in the div
//div[#class="ListItems"]//a[#class="Title"]
for node in tree.xpath('//div[#class="ListItems"]//a[#class="Title"]'):url2.append(node.get("href"))
Try this xpath expression to select the div with a specific id recursively :
'//div[#id="activities"]//a[#class="Title"]'
so :
def sub_path02(url):
page = requests.get(url)
tree = html.fromstring(page.content)
url2 = []
for node in tree.xpath('//div[#id="activities"]//a[#class="Title"]'):
url2.append(node.get("href"))
return url2
Note :
It's ever better to select an id than a class because an id should be unique (in real life, there's sometimes bad code with multiple same id in the same page, but a class can be repeated N times)
I would like to get movie names available between "tracked_by" id to "buzz_off" id. I have already created a selector which can grab names after "tracked_by" id. However, my intention is to let the script do the parsing UNTIL it finds "buzz_off" id. The elements within which the names are:
html = '''
<div class="list">
<a id="allow" name="allow"></a>
<h4 class="cluster">Allow</h4>
<div class="base min">Sally</div>
<div class="base max">Blood Diamond</div>
<a id="tracked_by" name="tracked_by"></a>
<h4 class="cluster">Tracked by</h4>
<div class="base min">Gladiator</div>
<div class="base max">Troy</div>
<a id="buzz_off" name="buzz_off"></a>
<h4 class="cluster">Buzz-off</h4>
<div class="base min">Heat</div>
<div class="base max">Matrix</div>
</div>
'''
from lxml import html as htm
root = htm.fromstring(html)
for item in root.cssselect("a#tracked_by ~ div.base a"):
print(item.text)
The selector I've tried with (also mentioned in the above script):
a#tracked_by ~ div.base a
Results I'm having:
Gladiator
Troy
Heat
Matrix
Results I would like to get:
Gladiator
Troy
Btw, I would like to parse the names using this selector not to style.
this is a reference for css selectors. As you can see, it doesn't have any form of logic, as it is not a programming language. You'd have to use a while not loop in python and handle each element one at a time, or append them to a list.
My intention is to scrape the names of the top-selling products on Ali-Express.
I'm using the Requests library alongside Beautiful Soup to accomplish this.
# Remember to import BeautifulSoup, requests and pprint
url = "https://bestselling.aliexpress.com/en?spm=2114.11010108.21.3.qyEJ5m"
soup = bs(req.get(url).text, 'html.parser')
#pp.pprint(soup) Verify that the page has been found
all_items = soup.find_all('li',class_= 'top10-item')
pp.pprint(all_items)
# []
However this returns an empty list, indicating that soup_find_all() did not find any tags fitting that criteria.
Inspect Element in Chrome displays the list items as such
.
However in source code (ul class = "top10-items") contains a script, which seems to iterate through each list item (I'm not familiar with HTML).
<div class="container">
<div class="top10-header"><span class="title">TOP SELLING</span> <span class="sub-title">This week's most popular products</span></div>
<ul class="top10-items loading" id="bestselling-top10">
</ul>
<script class="X-template-top10" type="text/mustache-template">
{{#topList}}
<li class="top10-item">
<div class="rank-orders">
<span class="rank">{{rank}}</span>
<span class="orders">{{productOrderNum}}</span>
</div>
<div class="img-wrap">
<a href="{{productDetailUrl}}" target="_blank">
<img src="{{productImgUrl}}" alt="{{productName}}">
</a>
</div>
<a class="item-desc" href="{{productDetailUrl}}" target="_blank">{{productName}}</a>
<p class="item-price">
<span class="price">US ${{productMinPrice}}</span>
<span class="uint">/ {{productUnitType}}</span>
</p>
</li>
{{/topList}}</script>
</div>
</div>
So this probably explains why soup.find_all() doesn't find the "li" tag.
My question is: How can I extract the item names from the script using Beautiful soup?
this is my first question if I have explained anything wrong please forgive me.
I am trying scrape url's from a specific website in python and parse the links to a csv. The thing is when i parse the website in BeautifulSoup I can't extract the url's because when I parse it in python I can only get <div id="dvScores" style="min-height: 400px;">\n</div>, and nothing under that branch. But when I open the console and copy the table where the links are and paste it to a text editor it pastes 600 pages of html. What I want to do is to write a for loop that shows the links. The structure of the html is below:
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
#shadow-root (open)
<head>...</head>
<body>
<div id="body">
<div id="wrapper">
#multiple divs but i don't need them
<div id="live-master"> #what I need is under this div
<span id="contextual">
#multiple divs but i don't need them
<div id="live-score-master"> #what I need is under this div
<div ng-app="live-menu" id="live-score-rightcoll">
#multiple divs but i don't need them
<div id="left-score-lefttemp" style="padding-top: 35px;">
<div id="dvScores">
<table cellspacing=0 ...>
<colgroup>...</colgroup>
<tbody>
<tr class="row line-bg1"> #this changes to bg2 or bg3
<td class="row">
<span class="row">
<a href="www.example.com" target="_blank" class="td_row">
#I need to extract this link
</span>
</td>
#Multiple td's
</tr>
#multiple tr class="row line-bg1" or "row line-bg2"
.
.
.
</tbody>
</table>
</div>
</div>
</div>
</div>
</span>
</div>
</div>
</body>
</html>
What am I doing wrong? I need to automate a system for python to do rather than pasting the html to text and extracting links with a regex.
My python code is below also:
import requests
from bs4 import BeautifulSoup
r=requests.get("http://example.com/example")
c=r.content
soup=BeautifulSoup(c,"html.parser")
all=soup.find_all("span",id="contextual")
span=all[0].find_all("tbody")
if you are trying scrape urls then you should get hrefs :
urls = soup.find_all('a', href=True)
This site uses JavaScript for populating its content, therefore, you can't get url via beautifulsoup. If you inspect network tab in your browser you can spot a this link. It contains all data what you need. You can simply parse it and extract all desired value.
import requests
req = requests.get('http://goapi.mackolik.com/livedata?group=0').json()
for el in req['m'][4:100]:
index = el[0]
team_1 = el[2].replace(' ', '-')
team_2 = el[4].replace(' ', '-')
print('http://www.mackolik.com/Mac/{}/{}-{}'.format(index, team_1, team_2))
It seems like the html is being dynamically generated by js. You would need to crawl it with a crawler to mimic a browser. Since you are using requests, it already has a crawler session.
session = requests.session()
data = session.get ("http://website.com").content #usage xample
After this you can do the parsing, additional scraping, etc.
Could someone please explain how the filtering works with Beautiful Soup. Ive got the below HTML I am trying to filter specific data from but I cant seem to access it. Ive tried various approaches, from gathering all class=g's to grabbing just the items of interest in that specific div, but I just get None returns or no prints.
Each page has a <div class="srg"> div with multiple <div class="g"> divs, the data i am looking to use is the data withing <div class="g">. Each of these has
multiple divs, but im only interested in the <cite> and <span class="st"> data. I am struggling to understand how the filtering works, any help would be appreciated.
I have attempted stepping through the divs and grabbing the relevant fields:
soup = BeautifulSoup(response.text)
main = soup.find('div', {'class': 'srg'})
result = main.find('div', {'class': 'g'})
data = result.find('div', {'class': 's'})
data2 = data.find('div')
for item in data2:
site = item.find('cite')
comment = item.find('span', {'class': 'st'})
print site
print comment
I have also attempted stepping into the initial div and finding all;
soup = BeautifulSoup(response.text)
s = soup.findAll('div', {'class': 's'})
for result in s:
site = result.find('cite')
comment = result.find('span', {'class': 'st'})
print site
print comment
Test Data
<div class="srg">
<div class="g">
<div class="g">
<div class="g">
<div class="g">
<!--m-->
<div class="rc" data="30">
<div class="s">
<div>
<div class="f kv _SWb" style="white-space:nowrap">
<cite class="_Rm">http://www.url.com.stuff/here</cite>
<span class="st">http://www.url.com. Some info on url etc etc
</span>
</div>
</div>
</div>
<!--n-->
</div>
<div class="g">
<div class="g">
<div class="g">
</div>
UPDATE
After Alecxe's solution I took another stab at getting it right but was still not getting anything printed. So I decided to take another look at the soup and it looks different. I was previously looking at the response.text from requests. I can only think that BeautifulSoup modifies the response.text or I somehow just got the sample completely wrong the first time (not sure how). However Below is the new sample based on what I am seeing from a soup print. And below that my attempt to get to the element data I am after.
<li class="g">
<h3 class="r">
context
</h3>
<div class="s">
<div class="kv" style="margin-bottom:2px">
<cite>www.url.com/index.html</cite> #Data I am looking to grab
<div class="_nBb">
<div style="display:inline"snipped">
<span class="_O0"></span>
</div>
<div style="display:none" class="am-dropdown-menu" role="menu" tabindex="-1">
<ul>
<li class="_Ykb">
<a class="_Zkb" href="/url?/search">Cached</a>
</li>
</ul>
</div>
</div>
</div>
<span class="st">Details about URI </span> #Data I am looking to grab
Update Attempt
I have tried taking Alecxe's approach to no success so far, am I going down the right road with this?
soup = BeautifulSoup(response.text)
for cite in soup.select("li.g div.s div.kv cite"):
span = cite.find_next_sibling("span", class_="st")
print(cite.get_text(strip=True))
print(span.get_text(strip=True))
First get div with class name srg then find all div with class name s inside that srg and get text of that site and comment. Below is the working code for me-
from bs4 import BeautifulSoup
html = """<div class="srg">
<div class="g">
<div class="g">
<div class="g">
<div class="g">
<!--m-->
<div class="rc" data="30">
<div class="s">
<div>
<div class="f kv _SWb" style="white-space:nowrap">
<cite class="_Rm">http://www.url.com.stuff/here</cite>
<span class="st">http://www.url.com. Some info on url etc etc
</span>
</div>
</div>
</div>
<!--n-->
</div>
<div class="g">
<div class="g">
<div class="g">
</div>"""
soup = BeautifulSoup(html , 'html.parser')
labels = soup.find('div',{"class":"srg"})
spans = labels.findAll('div', {"class": 'g'})
sites = []
comments = []
for data in spans:
site = data.find('cite',{'class':'_Rm'})
comment = data.find('span',{'class':'st'})
if site:#Check if site in not None
if site.text.strip() not in sites:
sites.append(site.text.strip())
else:
pass
if comment:#Check if comment in not None
if comment.text.strip() not in comments:
comments.append(comment.text.strip())
else: pass
print sites
print comments
Output-
[u'http://www.url.com.stuff/here']
[u'http://www.url.com. Some info on url etc etc']
EDIT--
Why your code does not work
For try One-
You are using result = main.find('div', {'class': 'g'}) it will grab single and first encountered element but first element has not div with class name s . So the next part of this code will not work.
For try Two-
You are printing site and comment that is not in the print scope. So try to print inside for loop.
soup = BeautifulSoup(html,'html.parser')
s = soup.findAll('div', {'class': 's'})
for result in s:
site = result.find('cite')
comment = result.find('span', {'class': 'st'})
print site.text#Grab text
print comment.text
You don't have to deal with the hierarchy manually - let BeautifulSoup worry about it. Your second approach is close to what you should really be trying to do, but it would fail once you get the div with class="s" with no cite element inside.
Instead, you need to let BeautifulSoup know that you are interested in specific elements containing specific elements. Let's ask for cite elements located inside div elements with class="g" located inside the div element with class="srg" - div.srg div.g cite CSS selector would find us exactly what we are asking about:
for cite in soup.select("div.srg div.g cite"):
span = cite.find_next_sibling("span", class_="st")
print(cite.get_text(strip=True))
print(span.get_text(strip=True))
Then, once the cite is located, we are "going sideways" and grabbing the next span sibling element with class="st". Though, yes, here we are assuming it exists.
For the provided sample data, it prints:
http://www.url.com.stuff/here
http://www.url.com. Some info on url etc etc
The updated code for the updated input data:
for cite in soup.select("li.g div.s div.kv cite"):
span = cite.find_next("span", class_="st")
print(cite.get_text(strip=True))
print(span.get_text(strip=True))
Also, make sure you are using the 4th BeautifulSoup version:
pip install --upgrade beautifulsoup4
And the import statement should be:
from bs4 import BeautifulSoup