I would like to get movie names available between "tracked_by" id to "buzz_off" id. I have already created a selector which can grab names after "tracked_by" id. However, my intention is to let the script do the parsing UNTIL it finds "buzz_off" id. The elements within which the names are:
html = '''
<div class="list">
<a id="allow" name="allow"></a>
<h4 class="cluster">Allow</h4>
<div class="base min">Sally</div>
<div class="base max">Blood Diamond</div>
<a id="tracked_by" name="tracked_by"></a>
<h4 class="cluster">Tracked by</h4>
<div class="base min">Gladiator</div>
<div class="base max">Troy</div>
<a id="buzz_off" name="buzz_off"></a>
<h4 class="cluster">Buzz-off</h4>
<div class="base min">Heat</div>
<div class="base max">Matrix</div>
</div>
'''
from lxml import html as htm
root = htm.fromstring(html)
for item in root.cssselect("a#tracked_by ~ div.base a"):
print(item.text)
The selector I've tried with (also mentioned in the above script):
a#tracked_by ~ div.base a
Results I'm having:
Gladiator
Troy
Heat
Matrix
Results I would like to get:
Gladiator
Troy
Btw, I would like to parse the names using this selector not to style.
this is a reference for css selectors. As you can see, it doesn't have any form of logic, as it is not a programming language. You'd have to use a while not loop in python and handle each element one at a time, or append them to a list.
Related
I am trying to fetch all classes (including the data inside "data_from", "data_to") from the following structure:
<div class="alldata">
<div class="data_from">
<div class="data_to">
<div class="data_to">
<div class="data_from">
</div>
So far I have tried finding all classes, without success. The "data_from", "data_to" classes are not being fetched by:
soup.find_all(class_=True)
When I try to illiterate over "alldata" class I fetch only the first "data_from" class.
for data in soup.findAll('div', attrs={"class": "alldata"}):
print(data.prettify())
All assistance is greatly appreciated. Thank you.
In newer code avoid old syntax findAll() or a mix with new syntax - instead use find_all() only - For more take a minute to check docs
Your HTML is not valid, but to get your goal with valid HTML you could use css selectors that selects all <div> with a class that are contained in your outer <div>:
soup.select('.alldata div[class]')
Example
from bs4 import BeautifulSoup
html='''<div class="alldata">
<div class="data_from"></div>
<div class="data_to"></div>
<div class="data_to"></div>
<div class="data_from"></div>
</div>'''
soup = BeautifulSoup(html)
soup.select('.alldata div[class]')
Output
[<div class="data_from"></div>,
<div class="data_to"></div>,
<div class="data_to"></div>,
<div class="data_from"></div>]
Just in addition if you like to get its texts, iterate over your ResultSet:
for e in soup.select('.alldata div[class]'):
print(e.text)
I'm trying to parse the follow HTML code in python using beautiful soup. I would like to be able to search for text inside a tag, for example "Color" and return the text next tag "Slate, mykonos" and do so for the next tags so that for a give text category I can return it's corresponding information.
However, I'm finding it very difficult to find the right code to do this.
<h2>Details</h2>
<div class="section-inner">
<div class="_UCu">
<h3 class="_mEu">General</h3>
<div class="_JDu">
<span class="_IDu">Color</span>
<span class="_KDu">Slate, mykonos</span>
</div>
</div>
<div class="_UCu">
<h3 class="_mEu">Carrying Case</h3>
<div class="_JDu">
<span class="_IDu">Type</span>
<span class="_KDu">Protective cover</span>
</div>
<div class="_JDu">
<span class="_IDu">Recommended Use</span>
<span class="_KDu">For cell phone</span>
</div>
<div class="_JDu">
<span class="_IDu">Protection</span>
<span class="_KDu">Impact protection</span>
</div>
<div class="_JDu">
<span class="_IDu">Cover Type</span>
<span class="_KDu">Back cover</span>
</div>
<div class="_JDu">
<span class="_IDu">Features</span>
<span class="_KDu">Camera lens cutout, hard shell, rubberized, port cut-outs, raised edges</span>
</div>
</div>
I use the following code to retrieve my div tag
soup.find_all("div", "_JDu")
Once I have retrieved the tag I can navigate inside it but I can't find the right code that will enable me to find the text inside one tag and return the text in the tag after it.
Any help would be really really appreciated as I'm new to python and I have hit a dead end.
You can define a function to return the value for the key you enter:
def get_txt(soup, key):
key_tag = soup.find('span', text=key).parent
return key_tag.find_all('span')[1].text
color = get_txt(soup, 'Color')
print('Color: ' + color)
features = get_txt(soup, 'Features')
print('Features: ' + features)
Output:
Color: Slate, mykonos
Features: Camera lens cutout, hard shell, rubberized, port cut-outs, raised edges
I hope this is what you are looking for.
Explanation:
soup.find('span', text=key) returns the <span> tag whose text=key.
.parent returns the parent tag of the current <span> tag.
Example:
When key='Color', soup.find('span', text=key).parent will return
<div class="_JDu">
<span class="_IDu">Color</span>
<span class="_KDu">Slate, mykonos</span>
</div>
Now we've stored this in key_tag. Only thing left is getting the text of second <span>, which is what the line key_tag.find_all('span')[1].text does.
Give it a go. It can also give you the corresponding values. Make sure to wrap the html elements within content=""" """ variable between Triple Quotes to see how it works.
from bs4 import BeautifulSoup
soup = BeautifulSoup(content,"lxml")
for elem in soup.select("._JDu"):
item = elem.select_one("span")
if "Features" in item.text: #try to see if it misses the corresponding values
val = item.find_next("span").text
print(val)
I'm quite new to Programming and OO programming especially. Nonetheless, I'm trying to write a very simple Spider for web crawling. Here's my first approach:
I need to fetch the data out of this page: http://europa.eu/youth/volunteering/evs-organisation_en
Firstly, I do a view on the page source to find HTML elements?
view-source:https://europa.eu/youth/volunteering/evs-organisation_en
Note: I need to fetch the data that comes right below this line:
EVS accredited organisations search results: 6066
I chose beautiful soup for this job - since it is very powerful:
I Use find_all:
soup.find_all('p')[0].get_text() # Searching for tags by class and id
Note: Classes and IDs are used by CSS to determine which HTML elements to apply certain styles to. We can also use them when scraping to specify specific elements we want to scrape.
See the class:
<div class="col-md-4">
<div class="vp ey_block block-is-flex">
<div class="ey_inner_block">
<h4 class="text-center">"People need people" Zaporizhya oblast civic organisation of disabled families</h4>
<p class="ey_info">
<i class="fa fa-location-arrow fa-lg"></i>
Zaporizhzhya, <strong>Ukraine</strong>
</p> <p class="ey_info"><i class="fa fa-hand-o-right fa-lg"></i> Sending</p>
<p><strong>PIC no:</strong> 935175449</p>
<div class="empty-block">
Read more </div>
</div>
so this leads to:
# import libraries
import urllib2
from bs4 import BeautifulSoup
page = requests.get("https://europa.eu/youth/volunteering/evs-organisation_en")
soup = BeautifulSoup(page.content, 'html.parser')
soup
Now, we can use the find_all method to search for items by class or by id. In the below example, we'll search for any p tag that has the class outer-text
<div class="col-md-4">
so we choose:
soup.find_all(class_="col-md-4")
Now I have to combine all.
update: my approach: so far:
I have extracted data wrapped within multiple HTML tags from a webpage using BeautifulSoup4. I want to store all of the extracted data in a list. And - to be more concrete: I want each of the extracted data as separate list elements separated by a comma (i.e.CSV-formated).
To begin with the beginning:
here we have the HTML content structure:
<div class="view-content">
<div class="row is-flex"></span>
<div class="col-md-4"></span>
<div class </span>
<div class= >
<h4 Data 1 </span>
<div class= Data 2</span>
<p class=
<i class=
<strong>Data 3 </span>
</p> <p class= Data 4 </span>
<p class= Data 5 </span>
<p><strong>Data 6</span>
<div class=</span>
<a href="Data 7</span>
</div>
</div>
Code to extract:
for data in elem.find_all('span', class_=""):
This should give an output:
data = [ele.text for ele in soup.find_all('span', {'class':'NormalTextrun'})]
print(data)
Output:
[' Data 1 ', ' Data 2 ', ' Data 3 ' and so forth]
question: / i need help with the extraction part...
try this
data = [ele.text for ele in soup.find_all(text = True) if ele.text.strip() != '']
print(data)
My intention is to scrape the names of the top-selling products on Ali-Express.
I'm using the Requests library alongside Beautiful Soup to accomplish this.
# Remember to import BeautifulSoup, requests and pprint
url = "https://bestselling.aliexpress.com/en?spm=2114.11010108.21.3.qyEJ5m"
soup = bs(req.get(url).text, 'html.parser')
#pp.pprint(soup) Verify that the page has been found
all_items = soup.find_all('li',class_= 'top10-item')
pp.pprint(all_items)
# []
However this returns an empty list, indicating that soup_find_all() did not find any tags fitting that criteria.
Inspect Element in Chrome displays the list items as such
.
However in source code (ul class = "top10-items") contains a script, which seems to iterate through each list item (I'm not familiar with HTML).
<div class="container">
<div class="top10-header"><span class="title">TOP SELLING</span> <span class="sub-title">This week's most popular products</span></div>
<ul class="top10-items loading" id="bestselling-top10">
</ul>
<script class="X-template-top10" type="text/mustache-template">
{{#topList}}
<li class="top10-item">
<div class="rank-orders">
<span class="rank">{{rank}}</span>
<span class="orders">{{productOrderNum}}</span>
</div>
<div class="img-wrap">
<a href="{{productDetailUrl}}" target="_blank">
<img src="{{productImgUrl}}" alt="{{productName}}">
</a>
</div>
<a class="item-desc" href="{{productDetailUrl}}" target="_blank">{{productName}}</a>
<p class="item-price">
<span class="price">US ${{productMinPrice}}</span>
<span class="uint">/ {{productUnitType}}</span>
</p>
</li>
{{/topList}}</script>
</div>
</div>
So this probably explains why soup.find_all() doesn't find the "li" tag.
My question is: How can I extract the item names from the script using Beautiful soup?
This I the Link where I am trying to fetch data flipkart
and the part of code :
<div class="toolbar-wrap line section">
<div class="ratings-reviews-wrap">
<div itemprop="aggregateRating" itemscope="" itemtype="http://schema.org/AggregateRating" class="ratings-reviews line omniture-field">
<div class="ratings">
<meta itemprop="ratingValue" content="1">
<div class="fk-stars" title="1 stars">
<span class="unfilled">★★★★★</span>
<span class="rating filled" style="width:20%">
★★★★★
</span>
</div>
<div class="count">
<span itemprop="ratingCount">2</span>
</div>
</div>
</div>
</div>
</div>
here I have to fetch 1 star from title= 1 star and 2 from <span itemprop="ratingCount">2</span>
I try the following code
x = link_soup.find_all("div",class_='fk-stars')[0].get('title')
print x, " product_star"
y = link_soup.find_all("span",itemprop="ratingCount")[0].string.strip()
print y
but It give the
IndexError: list index out of range
The content that you see in the browser is not actually present in the raw HTML that is retrieved from this URL.
When loaded with a browser, the page executes AJAX calls to load additional content, which is then dynamically inserted into the page. One of the calls gets the ratings info that you are after. Specifically this URL is the one that contains the HTML that is inserted as the "action bar".
But if you retrieve the main page using Python, e.g. with requests, urllib et. al., the dynamic content is not loaded and that is why BeautifulSoup can't find the tags.
You could analyse the main page to find the actual link, retrieve that, and then run it through BeautifulSoup. The link looks like it begins with /p/pv1/spotList1/spot1/actionBar so that, or perhaps actionBar is sufficient to locate the actual link.
Or you could use selenium to load the page and then grab and process the rendered HTML.