What am I doing wrong? Should be so simple.After I execute - nothing happens, no errors, no email. Nothing.
I am using Jupyter.
def send_email(user, pwd, recipient, subject, body):
import smtplib
gmail_user = 'email#email.com'
gmail_pwd = 'pass'
FROM = 'email#email.com'
TO = 'email#email.com'
SUBJECT = 'Test'
TEXT = 'Hello, this is test email'
# Prepare actual message
message = """From: %s\nTo: %s\nSubject: %s\n\n%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
try:
server = smtplib.SMTP("smtp.gmail.com", 587)
server.ehlo()
server.starttls()
server.login(gmail_user, gmail_pwd)
server.sendmail(FROM, TO, message)
server.close()
print ('successfully sent the mail')
except:
print ("failed to send mail")
It is only function definiton. You have to execut it like
send_email("me#gmai.com", "MyPaSwOrD", "you#gmail.com", "Money for you", "Hi")
But your code will not use this data because it has hardcoded values inside.
Related
Im trying to write a simple script which has to send a simple email in some cases.
I have the following script which works well if im using just only this script.
import smtplib
mail_user = '123#123.com'
mail_password = 'password'
sent_from = mail_user
to = ['reciever#address.com']
subject = 'My subject'
body = 'Hello mail.'
email_text = """\
From: %s
To: %s
Subject: %s
%s
""" % (sent_from, ", ".join(to), subject, body)
try:
server = smtplib.SMTP_SSL('mail.123.com', 465)
server.ehlo()
server.login(mail_user, mail_password)
server.sendmail(sent_from, to, email_text)
server.close()
print 'Email sent!'
except:
print 'Something went wrong...'
The problem is when im trying to put this code into a def and call from outside the e-mail is missing headers, i mean the email is arriving without sender and without subject. Sender empty and subject empty, but i have only the body.
I also can not get the mail when im sending to another domain, but i think this is because the another domain is rejecting the mail without headers, when using only the script the mail arrives also to other domains.
import smtplib
def sendMail():
mail_user = '123#123.com'
mail_password = 'password'
sent_from = mail_user
to = ['reciever#address.com']
subject = 'My subject'
body = 'Hello mail.'
email_text = """\
From: %s
To: %s
Subject: %s
%s
""" % (sent_from, ", ".join(to), subject, body)
try:
server = smtplib.SMTP_SSL('mail.123.com', 465)
server.ehlo()
server.login(mail_user, mail_password)
server.sendmail(sent_from, to, email_text)
server.close()
print 'Email sent!'
except:
print 'Something went wrong...'
sendMail();
What is the diffenerece when i put this code into a def? Why this happening? What im doing wrong?
Thanks for help.
In your function version, your email headers have become indented
email_text = """\
From: %s
To: %s
Subject: %s
%s
...
In this string, the To: and Subject: are now indented.
def sendMail():
call it with:
sendMail()
not SendMail()
I used server.sendmail(fromaddr, toaddrs, msg) to send automated emails using python.
How can I add an email subject to the mail?
I tried to look in SMTP documentation and didn't find any documentation for that.
From How to send an email with Gmail as provider using Python? :
def send_email(user, pwd, recipient, subject, body):
import smtplib
gmail_user = user
gmail_pwd = pwd
FROM = user
TO = recipient if type(recipient) is list else [recipient]
SUBJECT = subject
TEXT = body
# Prepare actual message
message = """From: %s\nTo: %s\nSubject: %s\n\n%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
try:
server = smtplib.SMTP("smtp.gmail.com", 587)
server.ehlo()
server.starttls()
server.login(gmail_user, gmail_pwd)
server.sendmail(FROM, TO, message)
server.close()
print 'successfully sent the mail'
except:
print "failed to send mail"
I'm using Gmail SMTP to send emails in Python, however sometimes the application may stay idle for an extended period of time.
How do I make sure that the session hasn't expired? Here's my code:
def send_email(user, pwd, recipient, subject, body):
import smtplib
gmail_user = user
gmail_pwd = pwd
FROM = user
TO = recipient if type(recipient) is list else [recipient]
SUBJECT = subject
TEXT = body
# Prepare actual message
message = """\From: %s\nTo: %s\nSubject: %s\n\n%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
try:
server = smtplib.SMTP("smtp.gmail.com", 587)
server.ehlo()
server.starttls()
server.login(gmail_user, gmail_pwd)
server.sendmail(FROM, TO, message)
server.close()
print 'successfully sent the mail'
except:
print "failed to send mail"
Can I always reuse the server session, or can it expire after let's say 5 hours?
I am trying to send an email in Python using SMTP, with a From address, To address, BCC address, subject, and message. I have the email sending, and it even sends to the BCC as it should, the only issue is that the message of the email says:
To: example#gmail.com
Subject: Subject goes here
this is the email that I’m sending
when I only want the message itself to show where the message belongs, and the subject of the email isn't set, so there's a blank subject. Here is how I have it set up:
def sendEmail(fromAddress, toAddress, bccAddress, appName, message):
subject = "Subject goes here"
BODY = string.join((
"From: %s\r\n" % fromAddress,
"To: %s\r\n" % toAddress,
"Subject: %s\r\n" % subject,
"\r\n",
message
), "\r\n")
#im using arbitrary values here, when I run it I use actual login info
username = 'example#gmail.com'
password = 'password'
server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.login(username,password)
toList = []
bccList = []
toList.append(toAddress)
bccList.append(bccAddress)
server.sendmail(fromAddress, toList + bccList, BODY)
server.quit()
Use the email package (docs).
from email.mime.text import MIMEText
def send_mail(to, from_addr, subject, text):
msg = MIMEText(text)
msg['Subject'] = subject
msg['From'] = from_addr
msg['To'] = to
s = smtplib.SMTP_SSL("smtp.gmail.com")
s.login(smtp_user, smtp_pass)
# for Python 3
s.send_message(msg)
# OR
# for Python 2 (or 3, will still work)
s.sendmail(from_addr, [to], msg.as_string())
s.quit()
I have this code and I cannot seem to get it to work. When I run it, the script doesn't finish in IDLE unless I kill it manually. I have looked all over and rewritten the code a few times, and no luck.
import smtplib
SMTP_SERVER = 'smtp.gmail.com'
SMTP_PORT = 587
sender = 'abc#gmail.com'
password = '123'
recipient = 'cba#gmail.com'
subject = 'Test Results'
body = """** AUTOMATED EMAIL ** \r\n Following are
the test results: \r\n"""
headers = ["From: " + sender,
"Subject: " + subject,
"To: " + recipient]
headers = "\r\n".join(headers)
try:
session = smtplib.SMTP(SMTP_SERVER, SMTP_PORT)
session.ehlo()
session.starttls()
session.ehlo()
session.login(sender, password)
session.sendmail(sender, recipient, headers + "\r\n\r\n" + body)
except smtplib.SMTPException:
print "Error: Unable to send email."
session.quit()
Not sure why you're using ehlo; contrary to popular opinion, it's not actually required so long as you set the headers correctly. Here's a tested and working script -- it works on *nix and OSX. Since you're using Windows though, we need to troubleshoot further.
import smtplib, sys
def notify(fromname, fromemail, toname, toemail, subject, body, password):
fromaddr = fromname+" <"+fromemail+">"
toaddrs = [toname+" <"+toemail+">"]
msg = "From: "+fromaddr+"\nTo: "+toemail+"\nMIME-Version: 1.0\nContent-type: text/plain\nSubject: "+subject+"\n"+body
# Credentials (if needed)
username = fromemail
password = password
# The actual mail send
try:
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login(username,password)
server.sendmail(fromaddr, toaddrs, msg)
server.quit()
print "success"
except smtplib.SMTPException:
print "failure"
fromname = "Your Name"
fromemail = "yourgmailaccount#gmail.com"
toname = "Recipient"
toemail = "recipient#other.com"
subject = "Test Mail"
body = "Body....."
notify(fromname, fromemail, toname, toemail, subject, body, password)