So I've tried Googling my problem and looking on SO here, but I can't seem to find anything. Maybe I just really suck at using searches. But anyway here it what I am trying to do.
I have a program written in Python and I am trying to implement a very basic "Update Client" inside of it. The way this "Update Client" is suppose to work, is when the user chooses to update, the main program is closed and all of the files of the program are modified.
The only thing I am trying to figure out right now, is it is possible to close the main thread of a Python Program, using a thread that starts from that main thread? Or should I be structuring my code towards my main program starting a completely separate application when the "Update Client" is meant to be opened?
Thanks for any help.
Related
I'm trying to make a program (with GUI) that shows some informations.
I would like to update these informations from outside events.
e.g.
I have another script that do his tasks once a day (once a day a NEW process runs and does it's job), after this job completes I would like to update the informations in my GUI,that is always displayed on my monitor,without closing and reopening it.
Is there a way to retrieve the GUI process from outside and run functions inside it? (or a better way if u can help me)
I dont even know where to start, I feel that is something with threading,but dont know how to proper do it.
I'm working on a script using the PyAutoGUI module. Sometimes the script gets stuck in a while loop because it's looking for pictures/images that are not shown due to connection problems etc. If this happens I want the program to start again from zero, so I want to simulate the play/run-button in Pycharm with a command line. Is this possible?
What it sounds like you want to do is restart your program if it doesnt respond. A similiar question appears to have been posted here: Python help - Need the ability to restart the script when it hangs or automatically set a timer so I would reccommend having a look at that. Simulating the run button in Pycharm might seem like a good idea at first but it is very specific and a bad practice to simulate user actions like that unless there is absolutely no viable alternative.
Thanks to Patel I managed to solve my issue. You can use ctrl+f5 to restart a script so now when I'm stuck in a while loop I'm using this code:
#Click toolbar Pycharm
pyautogui.moveTo(1672,15,1)
pyautogui.click()
#Rerun the script
pyautogui.hotkey("ctrl","f5")
I spent the last hours trying to get to know wxPython, because I want to write a GUI program. I found some tutorials on that (not too many), but all of them just explain how to add yet another kind of widget, down to fancy things like LED number outputs and mouse gestures (this one e.g. takes it quite far: Another Tutorial). But everything I could find so far does nothing more than create a static GUI, waiting for the user to do something, then execute some handlers and wait again. It took me a while to even find out that wx.App takes a part in all of that, and that you can subclass it.
I want to write a program, that does things without input! The GUI is supposed to be a client that logs in on a server, and when the server sends something, I want the GUI to show what happened. I could not find a single tutorial even mentioning, that such programs exist. How can I write such a thing? How do they integrate with wxpython?
Do I need to span another thread? Is there a way to hook into the MainLoop and have some code executed periodically, that checks for change and then updates some of those fancy GUI things? And is there any page that teaches you, how to do this?
First of all, you should figure out how to do what you want WITHOUT a GUI. In this case, you'll need to figure out how to login to a server. You'll probably need to use something like paramiko for that. See http://www.lag.net/paramiko/
Once you've got that figured out, then you can add it to your GUI. Probably in a button handler so when the user presses a button, it pops up a dialog asking for a user name and password to pass to paramiko to login to the server.
If the server query takes a long time to execute (like say you're querying a database for a huge set of data), then you'll want to run the query in a separate thread. Why? Because that query will block the GUI's main loop and make your app freeze until it finishes. See the following articles for information on wxPython and threads:
http://wiki.wxpython.org/LongRunningTasks
http://www.blog.pythonlibrary.org/2010/05/22/wxpython-and-threads/
I wrote up a tutorial on making wxPython talk to a socket server, so you might find that useful: http://www.blog.pythonlibrary.org/2013/06/27/wxpython-how-to-communicate-with-your-gui-via-sockets/
I also have an article on how to make an image viewer, and do CRUD ops to a database on there.
Now I am working in a project where the testscript has to connect many (3-10) remote computers (SSH and do some stuff).
I started to use the pexpect and it is simple as a button. It works fine.
I want to see the communication during test. I know it is possible to redirect the log to the screen. But in this case the logs (from different computer) are mixed.
What I would like is to open new terminal window (or consol or whatever) for every new spawn object. In this case I could see all communication in different windows. Additionally I would like to keep the possibility of spawn.interact() in every window.
I feel that it is possible somehow but I don't know how. I think some file pointer (or pipe) should pass to the new window somehow(?)
(SecureCRT knows sometihng like this, it has tabbed consol windows and can access them separately, but it is a commercial product)
Or let me make the problem more simple.
If I do this, I can open a new shell in a new window:
p=Popen(["cygstart", "bash"])
How can I read and write into this shell from my script (parent) to see it in this new window?
I would really appreciate it, if one of you could point me in the right direction.
It is enough if you tell me what to read or find for (on Google) because I did not find anybody such kind of problem.
The environment is cygwin.
Thanks in advance
br:drv
Have you tried using the logfile parameter?
child = pexpect.spawn('some_command')
mylog = open('/tmp/mylog','w')
child.logfile = mylog
This will automatically log all communication to the file, including commands you enter after calling spawn.interact()
More info available on the website: http://pexpect.sourceforge.net/pexpect.html
Search for 'logfile' to find the relevant documentation.
I wrote a little PyGTK app: Workcycler
Now I have the problem that I need to hit the quit button twice for it to quit and I don't know why.
I´ve tested it extensively and it allways calls all quit functions but the program simply doesn't close after the first time.
It's a pretty short script so could someone please have a look over it?
I think the problem may come from using python's timers or a part from the pygame lib (mixer).
These are the important files I think: workcycle.py and tray.py
You are running the workcycle.ui.tray.WorkcycleTray.start method twice (so gtk.main run twice )
once in the workcycler and another in workcycle.py line 20, comment that line and everything works fine.