I just copied this code for a client/server example:
http://www.bogotobogo.com/python/python_network_programming_server_client.php
and when I run the code I get this error:
OSError: [Errno 99] Cannot assign requested address
Server:
# server.py
import socket
import time
# create a socket object
serversocket = socket.socket(
socket.AF_INET, socket.SOCK_STREAM)
# get local machine name
host = socket.gethostname()
port = 9999
# bind to the port
serversocket.bind((host, port))
# queue up to 5 requests
serversocket.listen(5)
while True:
# establish a connection
clientsocket,addr = serversocket.accept()
print("Got a connection from %s" % str(addr))
currentTime = time.ctime(time.time()) + "\r\n"
clientsocket.send(currentTime.encode('ascii'))
clientsocket.close()
Client:
# client.py
import socket
# create a socket object
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
# get local machine name
host = socket.gethostname()
port = 9999
# connection to hostname on the port.
s.connect((host, port))
# Receive no more than 1024 bytes
tm = s.recv(1024)
s.close()
print("The time got from the server is %s" % tm.decode('ascii'))
Replace host = socket.gethostname() with host = '127.0.0.1' and it should work.
Check this
Hope this wil help :)
Related
I am trying to simply send a list from one computer to another.
I have my server set up on one computer, where the IP address is 192.168.0.101
The code for the server:
import socket
import pickle
import time
import errno
HEADERSIZE = 20
HOST = socket.gethostbyname(socket.gethostname())
PORT = 65432
print(HOST)
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(10)
while True:
conn, adrs = s.accept()
print(f"Connection with {adrs} has been established")
conn.setblocking(1)
try:
data = conn.recv(HEADERSIZE)
if not data:
print("connection closed")
conn.close()
break
else:
print("Received %d bytes: '%s'" % (len(data), pickle.loads(data)))
except socket.error as e:
if e.args[0] == errno.EWOULDBLOCK:
print('EWOULDBLOCK')
time.sleep(1) # short delay, no tight loops
else:
print(e)
break
The client is on another computer. The code:
import socket
import pickle
HOST = '192.168.0.101'
PORT = 65432
def send_data(list):
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.settimeout(10)
print(".")
print(s.connect_ex((HOST, PORT)))
print(".")
data = pickle.dumps(list)
print(len(data))
s.send(data)
s.close()
send_data([1,1,1])
The outputted error number of connect_ex is 10035. I read a lot about the error, but all I found was about the server side. To me, it looks like the problem is with the client and that it is unable to make a connection to 192.168.0.101. But then, I don't understand why the error I get is about non-blocking.
What is it that I am doing wrong that I am unable to send data?
First of all, how user207421 suggested, change the timeout to a longer duration.
Also, as stated here Socket Programming in Python raising error socket.error:< [Errno 10060] A connection attempt failed I was trying to run my server and connect to a private IP address.
The fix is: on the server side, in the s.bind, to leave the host part empty
HOST = ''
PORT = 65432
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
And on the client side, use the public IP of the PC where the server is running (I got it from ip4.me)
HOST = 'THE PUBLIC IP' #not going to write it
PORT = 65432
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((host, PORT))
So i would like to create a small online game. (I am a complete noob with networking)
I got a server-client connection going if they are both on the same network but would need to do it over the internet. How do i do this?
server.py
import socket
s = socket.socket()
host = "0.0.0.0"
port = 5000
s.bind((host,port))
s.listen(5)
while True:
c, addr = s.accept()
print("Connection from", addr)
c.close()
client.py
import socket
s = socket.socket()
host = "192.168.1.66"
port = 5000
s.connect((host, port))
s.send(bytearray("Message", "ascii"))
I have tried using my public IP but i cannot connect.
#!/usr/bin/env python
import socket
clientsocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
clientsocket.connect(('192.168.1.123', 5162))
clientsocket.send('getval.1')
clientsocket.close
clientsocket.bind(('192.168.1.124', 5163))
clientsocket.listen(1)
while True:
connection, address=clientsocket.accept()
value=connection.recv(1024)
print value
I'm trying to get python to send a message to the server, and in return the server responds. Yet when I execute this code it gives me
Socket.error: [Errno 10022] An invalid argument was supplied
It seems you wrote a mixed code of server and client
Here a simple sample of codes for socket programming the first on server side and the second on client
Server side code:
# server.py
import socket
import time
# create a socket object
serversocket = socket.socket(
socket.AF_INET, socket.SOCK_STREAM)
# get local machine name
host = socket.gethostname()
port = 9999
# bind to the port
serversocket.bind((host, port))
# queue up to 5 requests
serversocket.listen(5)
while True:
# establish a connection
clientsocket,addr = serversocket.accept()
print("Got a connection from %s" % str(addr))
currentTime = time.ctime(time.time()) + "\r\n"
clientsocket.send(currentTime.encode('ascii'))
clientsocket.close()
and now the client
# client.py
import socket
# create a socket object
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
# get local machine name
host = socket.gethostname()
port = 9999
# connection to hostname on the port.
s.connect((host, port))
# Receive no more than 1024 bytes
tm = s.recv(1024)
s.close()
print("The time got from the server is %s" % tm.decode('ascii'))
The server simply remained listened for any client and when it finds out a new connection it returns current datetime and closes the client connection
I want to know the Exception name that happen when a server have connection with a client in specific port, and another client wanna make a connection to server from that port ...
So i make server, client1 and client2 but when server and client1 are connected together and i run client3 amazingly without any error they all continue running.
I wanto to know why i didn`t get any error?
what's exactly the role of '1' in this line: serverSocket.listen(1)
This is server code:
import socket
serverSocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
serverSocket.bind(('', 80))
print("Host=%s" %str(serverSocket.getsockname()))
serverSocket.listen(1)
clientSocket, addr = serverSocket.accept()
print("Got a connection from %s" % str(addr))
data = clientSocket.recv(1024)
print("from Client:%s "%str(addr))
print("\n data:%s "%str(data.decode("utf-8")))
#consciously i didn't close the the sockets
client1:
import socket
TCP_IP = '127.0.0.1'
TCP_PORT = 80
BUFFER_SIZE = 1024
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((TCP_IP, TCP_PORT))
s.send(bytes("test code", 'utf-8'))
data = s.recv(BUFFER_SIZE)
print(type(data))
s.close()
client2
import socket
TCP_IP = '127.0.0.1'
TCP_PORT = 80
BUFFER_SIZE = 1024
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((TCP_IP, TCP_PORT))
s.send(bytes("test3", 'utf-8'))
data = s.recv(BUFFER_SIZE)
print(type(data))
s.close()
sth else,why when i run client2, the server didn`t show any message that got connection from it, like:
Got a connection from ('127.0.0.1', 64358)
The code of client1 fails with error:
TypeError: str() takes at most 1 argument (2 given)
It's because that bytes in python 2 is the same as str and it accepts only one string argument, credit goes to alecxe.
When the client tries to connect to the server it always raise an exception. I have disabled Windows firewall and my antivirus and I have also opened the port 50100 on the router configuration panel.
Server:
import socket
HOST = ''
PORT = 8882
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(1)
conn, addr = s.accept()
s.close()
Client:
import socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = 'localhost'
port = 50100
remote_ip = s.gethostbyname(host)
s.connect((remote_ip, port))
s.close()
Specify the correct remote port in the client (i.e., the same port as the in the server script).
# Client
import socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = 'localhost'
port = 8882
remote_ip = socket.gethostbyname(host)
s.connect((remote_ip, port))
s.close()