We Keep Coding

I've made an anagram function in python, I cannot figure out how to get the output to look like this: "Key": word1, word2, word3 etc

with open('words.txt', 'r') as read:
line = read.readlines()
key_list = []
def make_anagram_dict(line):
word_list = {}
for word in line:
word = word.lower()
key = ''.join(sorted(word))
if key in word_list and len(word) > 5:
word_list[key].append(word)
key_list.append(key)
else:
word_list[key] = [word]
return word_list
if __name__ == '__main__':
word_list = make_anagram_dict(line)
for words in word_list.values():
if len(words) > 1:
print('Words: {}'.format(', '.join(words)))
I.e I need it to look like this:
Key:
aeehrtw
Words:
weather
, whereat
, wreathe
I also have a problem where words in the .txt file are duplicated but one word starts with a capital, i.e Zipper and zipper. How can I have it so that it only uses one of the words?

To get the exact same output, you can try :
if __name__ == '__main__':
word_list = make_anagram_dict(line)
for key, words in word_list.items():
if len(words) > 1:
print('Key:')
print(key)
print()
print('Words:')
print('\n, '.join(words))

Isolating the first word of a string

This is the code i've wrote so far:
def first_word(text: str) -> str:
while text.find(' ') == 0:
text = text[1:]
while text.find('.') == 0:
text = text[1:]
while text.find(' ') == 0:
text = text[1:]
while text.find('.') == 0:
text = text[1:]
if text.find('.') != -1:
text = text.split('.')
elif text.find(',') != -1:
text = text.split(',')
elif text.find(' ') != -1:
text = text.split(' ')
text = text[0]
return text
it's supposed to isolate the first word in a string, it shold delete any ".", " ", "," and keep only the word itself.

Using re, and split():
import re
ss = 'ba&*(*seball is fun'
print(''.join(re.findall(r'(\w+)', ss.split()[0])))
Output:
baseball

sentence="bl.a, bla bla"
first_word=first_word.replace(".","").replace(",","")
first_word=sentence.split(" ")[0]
print(first_word)
Or you could try a list comprehension:
sentence="bl.a, bla bla"
first_word=''.join([e for e in first_word if e not in ".,"]) #or any other punctuation
first_word=sentence.split(" ")[0]
print(first_word)

Custom build validation statement on an iterator

What's the quickest way (processing sense) to iterate over a list and validate them according to set flags?
Or, in other words, what's the optimal approach to filter list with statement depending on configuration.
Example below is on a list of strings and depending on flags I'd like to filter some of them.
class Validator(object):
def __init__(self, digit=False, tag=False, short=False):
self.digit = digit
self.tag = tag
self.short = short
def __call__(self, words):
good_words = []
for word in words:
if self.digit:
if word.is_digit(): continue
if self.tag:
if word[0] == "<": continue
if self.short:
if len(word) < 3: continue
good_words.append(word)
return good_words
Use of Validator
val = Validator(digit=True, short=True)
words = "An apple a day is 20 dollars a month"
print(val(words))
# ["apple", "day", "dollars", "month"]

To avoid creating a new (and potentially long) list, you can instead make a generator function with yield for each succeeded word instead of return for a whole list:
class Validator(object):
def __init__(self, digit=False, tag=False, short=False, *more_filters):
self.digit = digit
self.tag = tag
self.short = short
self.more_filters= more_filters
def __call__(self, words):
for word in words:
if self.digit:
if word.is_digit(): continue
if self.tag:
if word[0] == "<": continue
if self.short:
if len(word) < 3: continue
if any(f(word) for f in self.more_filters):
continue
yield word
Use:
other_tests = [lambda w: w.startswith('#'), lambda w: w.endswith('?')]
val = Validator(digit=True, short=True, *other_tests)
words = "An apple a day is 20 dollars a month #healty toomuch? livelong!"
print(val(words))
# apple day dollars month livelong!

Element by element approach using python filter
from itertools import filterfalse
class Validator(object):
def __init__(self, digit=False, tag=False, short=False):
self.digit = digit
self.tag = tag
self.short = short
def __call__(self, word):
if self.digit:
if word.isdigit(): return True
if self.tag:
if word[0] == "<": return True
if self.short:
if len(word) < 3: return True
return False
val = Validator(digit=True, short=True)
words = "An apple a day is 20 dollars a month".split()
assert list(filter(val, words)) == ['An', 'a', 'is', '20', 'a']
assert list(filterfalse(val, words)) == ['apple', 'day', 'dollars', 'month']

Error in anagram code: python

This function will search for anagrams in a list from a .txt file, I want to be able to check for anagrams and return all anagrams of the word that I input, and if it's not an anagram it will return the input, when I do it in the code below, it iterates through the for loop then ignores my first if statement and heads directly to my else statement. How can I fix this?
def find_in_dict():
input_word = input("Enter input string)")
sorted_word = ''.join(sorted(input_word.strip()))
a_word = ''.join((input_word.strip()))
word_file = open("filename", "r")
word_list = {}
for text in word_file:
simple_text = ''.join(sorted(text.strip()))
word_list.update({text.strip(): simple_text})
alist = []
for key, val in word_list.items():
if val == sorted_word:
alist.append(key)
return alist
else:
return "No words can be formed from:" + a_word

you are making a return statement in the if and else branch, that will break the for (because return invoked inside a function do exactly that, interrupt the execution and return the value) , so, don't do that, just ask if the word is equal, and in the end, check if there is none occurrences (empty list)
for text in word_file:
simple_text = ''.join(sorted(text.strip()))
word_list.update({text.strip(): simple_text})
alist = []
for key, val in word_list.items():
if val == sorted_word:
alist.append(key)
if alist == []: print("No words can be formed from: " + a_word)

Accessing list from function

I am writing a function where a user puts in text and a word and if the word is in the list, it returns the location of the word in the list.
list = ["hello", "goodbye", "name"]
def fact(txt, my_list):
text = txt.split()
for i in range(0, len(my_list)):
for j in range(0, len(text)):
if(my_list[i] == text[i]):
return my_list[i]
value = fact("hello, my name is", "name")
print(value)
However, this only seems to return none every time. Is there any particular reason it is not working?

Example:
def f(text, search):
if search in text.split():
print('Word "{}" has been found # index: {}'.format(search, text.split().index(search)))
Output:
data = 'hello world, my name is -e'
f(data, '-e')
Word "-e" has been found # index: 5

this works fine
def getword(word, text):
text = text.replace(',', '') # remove ',' by nothing
tmp = text.split(' ')
if word in tmp:
print("word: [%s] find at index %s in this text:[ %s]" % (word, tmp.index(word), text))
return tmp.index(word)
else:
print("Did not find [%s] in [%s]" % (word, text))
return -1
word = "what"
text = "Hello, I am groot, what is your name"
index = getword(word, text)