This question already has answers here:
Convert string "Jun 1 2005 1:33PM" into datetime
(26 answers)
how to convert a string date into datetime format in python? [duplicate]
(2 answers)
Python: How to convert string into datetime [duplicate]
(3 answers)
Closed 5 years ago.
I have the following string:
'2017-08-15T13:34:35Z'
How to convert this string to object that I can call .isoformat()?
someobject = convert('2017-08-15T13:34:35Z')
someobject.isoformat()
How to implement convert()?
Here to parse a string to date time, then you can:
def convert(s):
return datetime.strptime(s, '%Y-%m-%dT%H:%M:%SZ')
someobject = convert('2017-08-15T13:34:35Z')
print(someobject.isoformat())
You can use dateutil's parser:
>>> import dateutil.parser
>>> date = dateutil.parser.parse('2017-08-15T13:34:35Z', ignoretz=True)
>>> date
datetime.datetime(2017, 8, 15, 13, 34, 35)
>>> date.isoformat()
'2017-08-15T13:34:35'
Related
This question already has answers here:
Convert timestamps with offset to datetime obj using strptime
(4 answers)
How do I parse an ISO 8601-formatted date?
(29 answers)
Closed 2 years ago.
I have a datetime string I get from a database and I want to convert it to unix timestamp.
I am not sure what is the way to do it.
db_timestamp = '2020-08-05 12:48:50+02:00'
f = '%Y-%m-%d %H:%M:%S%z'
timestamp = datetime.strptime(db_timestamp , f)
TypeError: strptime() argument 1 must be str, not datetime.datetime
Another way I tried was as following
python_timestamp = datetime.isoformat(db_timestamp)
test_timestamp = datetime.strptime(python_timestamp , f)
Then I get the following error
ValueError: time data '2020-08-05T12:48:50+02:00' does not match format '%Y-%m-%d %H:%M:%S%z'
How to fix this error?
What should be the correct string format for db_timestamp?
assuming you run Python 3.7 or higher, what you want is fromisoformat to parse the string and timestamp() to get seconds since the epoch UNIX time (POSIX).
from datetime import datetime
db_timestamp = '2020-08-05 12:48:50+02:00'
# to datetime object:
dt = datetime.fromisoformat(db_timestamp)
# to UNIX time:
ts = dt.timestamp()
print(repr(dt), ts)
>>> datetime.datetime(2020, 8, 5, 12, 48, 50, tzinfo=datetime.timezone(datetime.timedelta(seconds=7200))) 1596624530.0
This question already has answers here:
Convert date to datetime in Python
(14 answers)
Closed 2 years ago.
In Python, I convert a date to datetime by:
converting from date to string
converting from string to datetime
Code:
import datetime
dt_format="%d%m%Y"
my_date = datetime.date.today()
datetime.datetime.strptime(my_date.strftime(dt_format), dt_format)
I suspect this is far from the most efficient way to do this. What is the most efficient way to convert a date to datetime in Python?
Use datetime.datetime.combine() with a time object, datetime.time.min represents 00:00 and would match the output of your date-string-datetime path:
datetime.datetime.combine(my_date, datetime.time.min)
Demo:
>>> import datetime
>>> my_date = datetime.date.today()
>>> datetime.datetime.combine(my_date, datetime.time.min)
datetime.datetime(2013, 3, 27, 0, 0)
Alternatively, as suggested here, this might be more readable:
datetime(date.year, date.month, date.day)
This question already has answers here:
How can I parse a time string containing milliseconds in it with python?
(7 answers)
Closed 7 years ago.
How to convert "2013-10-21 12:00:00.004" to datetime object in Python?
The problem is there is decimal number in seconds.
here is a working example
import datetime
dt = datetime.datetime.strptime("2013-10-21 12:00:00.004", "%Y-%m-%d %H:%M:%S.%f")
print (dt.microsecond)
This question already has answers here:
Convert string "Jun 1 2005 1:33PM" into datetime
(26 answers)
Closed 8 years ago.
I have a string '201502190759'. This represents 2015/02/19 at 7:59.
Is there a method within the python library that can convert '201502190759' into a datetime object or timestamp?
Yep, datetime.datetime.strptime will do it.
>>> import datetime
>>> print(datetime.datetime.strptime('201502190759', '%Y%m%d%H%M'))
2015-02-19 07:59:00
The docs on the format modifiers are here.
This question already has answers here:
How do I parse an ISO 8601-formatted date?
(29 answers)
Closed 8 years ago.
I am getting the following string from an API call:
s = '2014-12-11T20:46:12Z'
How would I then convert this into a python object? Is there an easy way, or should I be splitting up the string, for example:
year = s.split('-')[0]
month = s.split('-')[1]
day = s.split('-')[2]
time = s.split('T')[1]
...etc...
You can use the datetime.datetime.strptime function:
>>> from datetime import datetime
>>> s = '2014-12-11T20:46:12Z'
>>> datetime.strptime(s, '%Y-%m-%dT%H:%M:%SZ')
datetime.datetime(2014, 12, 11, 20, 46, 12)
>>>
For a complete list of the available format codes, see strftime() and strptime() Behavior.
Using datetime should do it, recently I found arrow is also a good library to deal with dates.
import arrow
s = '2014-12-11T20:46:12Z'
your_date = arrow.get(s)
print(t.year) # 2014
print(t.hour) # 20