I need to get div text with class _50x4 using 5pxsel:
<div...>
<i class="5pxsel">
<div>
<div>
<div class="_50x4">
Work in
<a>London</a>
<div class="_50x4">
Work in
<a> Germany </a>
I need to get text using class 5pxsel, not _50x4, and get only first result - 'Work in London'.
trt with following x-path
//*[#class="5pxsel"]/following-sibling::div/div/div[#class='_50x4']
Related
I'm using Scrapy and i'm trying to scrape something like this:
<html>
<div class='hello'>
some elements
.
.
.
</div>
<div class='hi there'>
<div>
<h3> title </h3>
<h4> another title </h4>
<p> some text ..... </p>
"some text without any tag"
<div class='article'>
some elements
.
.
</div>
<div class='article'>
some elements
.
.
</div>
<div class='article'>
some elements
.
.
</div>
</div>
</div>
</html>
and if I want to extract the text from all elements under the div with class name 'hi there' and before the divs with class name 'article', is there any possible way wither with XPath or CSS selectors?
Never used Scrapy.
Have no idea of what functions it has but,
//div[#class='hi there']/div/(div[#class='article'])[1]/preceding-sibling::*
picks out elements before div with "article" class and,
//div[#class='hi there']/div/(div[#class='article'])[1]/preceding-sibling::text()
gives you inner texts before article div.
I have a html code that looks kind of like this (shortened);
<div id="activities" class="ListItems">
<h2>Standards</h2>
<ul>
<li>
<a class="Title" href="http://www.google.com" >Guidelines on management</a>
<div class="Info">
<p>
text
</p>
<p class="Date">Status: Under development</p>
</div>
</li>
</ul>
</div>
<div class="DocList">
<h3>Reports</h3>
<p class="SupLink">+ <a href="http://www.google.com/test" >View More</a></p>
<ul>
<li class="pdf">
<a class="Title" href="document.pdf" target="_blank" >Document</a>
<span class="Size">
[1,542.3KB]
</span>
<div class="Info">
<p>
text <a href="http://www.google.com" >Read more</a>
</p>
<p class="Date">
14/03/2018
</p>
</div>
</li>
</ul>
</div>
I am trying to select the value in 'href=' under 'a class="Title"' by using this code:
def sub_path02(url):
page = requests.get(url)
tree = html.fromstring(page.content)
url2 = []
for node in tree.xpath('//a[#class="Title"]'):
url2.append(node.get("href"))
return url2
But I get two returns, the one under 'div class="DocList"' is also returned.
I am trying to change my xpath expressions so that I would only look within the node but I cannot get it to work.
Could someone please help me understand how to "search" within a specific node. I have gone through multiple xpath documentations but I cannot seem to figure it out.
Using // you are already selecting all the a elements in the document.
To search in a specific div try specifying the parent with // and then use //a again to look anywhere in the div
//div[#class="ListItems"]//a[#class="Title"]
for node in tree.xpath('//div[#class="ListItems"]//a[#class="Title"]'):url2.append(node.get("href"))
Try this xpath expression to select the div with a specific id recursively :
'//div[#id="activities"]//a[#class="Title"]'
so :
def sub_path02(url):
page = requests.get(url)
tree = html.fromstring(page.content)
url2 = []
for node in tree.xpath('//div[#id="activities"]//a[#class="Title"]'):
url2.append(node.get("href"))
return url2
Note :
It's ever better to select an id than a class because an id should be unique (in real life, there's sometimes bad code with multiple same id in the same page, but a class can be repeated N times)
I'm trying to parse the follow HTML code in python using beautiful soup. I would like to be able to search for text inside a tag, for example "Color" and return the text next tag "Slate, mykonos" and do so for the next tags so that for a give text category I can return it's corresponding information.
However, I'm finding it very difficult to find the right code to do this.
<h2>Details</h2>
<div class="section-inner">
<div class="_UCu">
<h3 class="_mEu">General</h3>
<div class="_JDu">
<span class="_IDu">Color</span>
<span class="_KDu">Slate, mykonos</span>
</div>
</div>
<div class="_UCu">
<h3 class="_mEu">Carrying Case</h3>
<div class="_JDu">
<span class="_IDu">Type</span>
<span class="_KDu">Protective cover</span>
</div>
<div class="_JDu">
<span class="_IDu">Recommended Use</span>
<span class="_KDu">For cell phone</span>
</div>
<div class="_JDu">
<span class="_IDu">Protection</span>
<span class="_KDu">Impact protection</span>
</div>
<div class="_JDu">
<span class="_IDu">Cover Type</span>
<span class="_KDu">Back cover</span>
</div>
<div class="_JDu">
<span class="_IDu">Features</span>
<span class="_KDu">Camera lens cutout, hard shell, rubberized, port cut-outs, raised edges</span>
</div>
</div>
I use the following code to retrieve my div tag
soup.find_all("div", "_JDu")
Once I have retrieved the tag I can navigate inside it but I can't find the right code that will enable me to find the text inside one tag and return the text in the tag after it.
Any help would be really really appreciated as I'm new to python and I have hit a dead end.
You can define a function to return the value for the key you enter:
def get_txt(soup, key):
key_tag = soup.find('span', text=key).parent
return key_tag.find_all('span')[1].text
color = get_txt(soup, 'Color')
print('Color: ' + color)
features = get_txt(soup, 'Features')
print('Features: ' + features)
Output:
Color: Slate, mykonos
Features: Camera lens cutout, hard shell, rubberized, port cut-outs, raised edges
I hope this is what you are looking for.
Explanation:
soup.find('span', text=key) returns the <span> tag whose text=key.
.parent returns the parent tag of the current <span> tag.
Example:
When key='Color', soup.find('span', text=key).parent will return
<div class="_JDu">
<span class="_IDu">Color</span>
<span class="_KDu">Slate, mykonos</span>
</div>
Now we've stored this in key_tag. Only thing left is getting the text of second <span>, which is what the line key_tag.find_all('span')[1].text does.
Give it a go. It can also give you the corresponding values. Make sure to wrap the html elements within content=""" """ variable between Triple Quotes to see how it works.
from bs4 import BeautifulSoup
soup = BeautifulSoup(content,"lxml")
for elem in soup.select("._JDu"):
item = elem.select_one("span")
if "Features" in item.text: #try to see if it misses the corresponding values
val = item.find_next("span").text
print(val)
I would like to get movie names available between "tracked_by" id to "buzz_off" id. I have already created a selector which can grab names after "tracked_by" id. However, my intention is to let the script do the parsing UNTIL it finds "buzz_off" id. The elements within which the names are:
html = '''
<div class="list">
<a id="allow" name="allow"></a>
<h4 class="cluster">Allow</h4>
<div class="base min">Sally</div>
<div class="base max">Blood Diamond</div>
<a id="tracked_by" name="tracked_by"></a>
<h4 class="cluster">Tracked by</h4>
<div class="base min">Gladiator</div>
<div class="base max">Troy</div>
<a id="buzz_off" name="buzz_off"></a>
<h4 class="cluster">Buzz-off</h4>
<div class="base min">Heat</div>
<div class="base max">Matrix</div>
</div>
'''
from lxml import html as htm
root = htm.fromstring(html)
for item in root.cssselect("a#tracked_by ~ div.base a"):
print(item.text)
The selector I've tried with (also mentioned in the above script):
a#tracked_by ~ div.base a
Results I'm having:
Gladiator
Troy
Heat
Matrix
Results I would like to get:
Gladiator
Troy
Btw, I would like to parse the names using this selector not to style.
this is a reference for css selectors. As you can see, it doesn't have any form of logic, as it is not a programming language. You'd have to use a while not loop in python and handle each element one at a time, or append them to a list.
I'm trying to collect the text using Bs4, selenium and Python I want to get the text "Lisa Staprans" using:
name = str(profilePageSource.find(class_="hzi-font hzi-Man-Outline").div.get_text().encode("utf-8"))[2:-1]
Here is the code:
<div class="profile-about-right">
<div class="text-bold">
SF Peninsula Interior Design Firm
<br/>
Best of Houzz 2015
</div>
<br/>
<div class="page-tags" style="display:none">
page_type: pro_plus_profile
</div>
<div class="pro-info-horizontal-list text-m text-dt-s">
<div class="info-list-label">
<i class="hzi-font hzi-Ruler">
</i>
<div class="info-list-text">
<span class="hide" itemscope="" itemtype="http://data-vocabulary.org/Breadcr
umb">
<a href="http://www.houzz.com/professionals/c/Menlo-Park--CA" itemprop="url
">
<span itemprop="title">
Professionals
</span>
</a>
</span>
<span itemprop="child" itemscope="" itemtype="http://data-vocabulary.org/Bre
adcrumb">
<a href="http://www.houzz.com/professionals/interior-designer/c/Menlo-Park-
-CA" itemprop="url">
<span itemprop="title">
Interior Designers & Decorators
</span>
</a>
</span>
</div>
</div>
<div class="info-list-label">
<i class="hzi-font hzi-Man-Outline">
</i>
<div class="info-list-text">
<b>
Contact
</b>
: Lisa Staprans
</div>
</div>
</div>
</div>
Please let me know how it would be.
I assumed you are using Beautifulsoup since you are using class_ attribute dictionary-
If there is one div with class name hzi-font hzi-Man-Outline then try-
str(profilePageSource.find(class_="hzi-font hzi-Man-Outline").findNext('div').get_text().split(":")[-1]).strip()
Extracts 'Lisa Staprans'
Here findNext navigates to next div and extracts text.
I can't test it right now but I would do :
profilePageSource.find_element_by_class_name("info-list-text").get_attribute('innerHTML')
Then you will have to split the result considering the : (if it's always the case).
For more informations : https://selenium-python.readthedocs.org/en/latest/navigating.html
Maybe something is wrong with this part:
find(class_="hzi-font hzi-Man-Outline")
An easy way to get the right information can be: right click on the element you need in the page source by inspecting it with Google Chrome, copy the xpath of the element, and then use:
profilePageSource.find_element_by_xpath(<xpath copied from Chorme>).text
Hope it helps.