I want to write a spider to crawl a html. I use requests and beautifulsoup ,but I just found out that beautifulsoup can't parse the whole page. Instead, Beautifulsoup just parses half of it.
Here is my code:
import requests
from bs4 import BeautifulSoup as bs
urls = ['http://www.bishefuwu.com/developer/transmit','http://www.bishefuwu.com/developer/transmit/index/p/2.html']
html = requests.get(urls[0]).content
soup = bs(html,'lxml')
table = soup.find('tbody')
trs = table.find_all('tr')
for tr in trs:
r = tr.find_all('td')[:3]
for i in map(lambda x:x.get_text(),r):
print i
and this is the origin page, which has row "13107",
but my spider just has half of it, my row stops at "13192".
For testing, I manually save the origin html requested by requests and I just found that everything was fine. This error is on Beautifulsoup.
How can I solve it ?
Thanks
No, there is nothing wrong with BeautifulSoup here. You are parsing a single page under the http://www.bishefuwu.com/developer/transmit url - it does not contain the row with number 13107 - it is on the second page.
Iterate over all the urls in the list:
with requests.Session() as session:
for url in urls:
html = session.get(url).content
soup = bs(html, 'lxml')
for tr in soup.select("tbody tr"):
r = tr.find_all('td')[:3]
for i in map(lambda x: x.get_text(), r):
print(i)
Note that, you can also think of not hardcoding the list of urls beforehand and handle the pagination in a more dynamic fashion parsing the pagination block on the page and extracting the available page numbers.
Related
from bs4 import BeautifulSoup
import requests
from urllib.request import urlopen
url = f'https://www.apple.com/kr/search/youtube?src=globalnav'
response = requests.get(url)
html = response.text
soup = BeautifulSoup(html, 'html.parser')
links = soup.select(".rf-serp-productname-list")
print(links)
I want to crawl through all links of shown apps. When I searched for a keyword, I thought links = soup.select(".rf-serp-productname-list") would work, but links list is empty.
What should I do?
Just check this code, I think is what you want:
import re
import requests
from bs4 import BeautifulSoup
pages = set()
def get_links(page_url):
global pages
pattern = re.compile("^(/)")
html = requests.get(f"your_URL{page_url}").text # fstrings require Python 3.6+
soup = BeautifulSoup(html, "html.parser")
for link in soup.find_all("a", href=pattern):
if "href" in link.attrs:
if link.attrs["href"] not in pages:
new_page = link.attrs["href"]
print(new_page)
pages.add(new_page)
get_links(new_page)
get_links("")
Source:
https://gist.github.com/AO8/f721b6736c8a4805e99e377e72d3edbf
You can change the part:
for link in soup.find_all("a", href=pattern):
#do something
To check for a keyword I think
You are cooking a soup so first at all taste it and check if everything you expect contains in it.
ResultSet of your selection is empty cause structure in response differs a bit from your expected one from the developer tools.
To get the list of links select more specific:
links = [a.get('href') for a in soup.select('a.icon')]
Output:
['https://apps.apple.com/kr/app/youtube/id544007664', 'https://apps.apple.com/kr/app/%EC%BF%A0%ED%8C%A1%ED%94%8C%EB%A0%88%EC%9D%B4/id1536885649', 'https://apps.apple.com/kr/app/youtube-music/id1017492454', 'https://apps.apple.com/kr/app/instagram/id389801252', 'https://apps.apple.com/kr/app/youtube-kids/id936971630', 'https://apps.apple.com/kr/app/youtube-studio/id888530356', 'https://apps.apple.com/kr/app/google-chrome/id535886823', 'https://apps.apple.com/kr/app/tiktok-%ED%8B%B1%ED%86%A1/id1235601864', 'https://apps.apple.com/kr/app/google/id284815942']
i just started programming.
I have the task to extract data from a HTML page to Excel.
Using Python 3.7.
My Problem is, that i have a website, whith more urls inside.
Behind these urls again more urls.
I need the data behind the third url.
My first Problem would be, how i can dictate the programm to choose only specific links from an ul rather then every ul on the page?
from bs4 import BeautifulSoup
import urllib
import requests
import re
page = urllib.request.urlopen("file").read()
soup = BeautifulSoup(page, "html.parser")
print(soup.prettify())
for link in soup.find_all("a", href=re.compile("katalog_")):
links= link.get("href")
if "katalog" in links:
for link in soup.find_all("a", href=re.compile("alle_")):
links = link.get("href")
print(soup.get_text())
There are many ways, one is to use "find_all" and try to be specific on the tags like "a" just like you did. If that's the only option, then use regular expression with your output. You can refer to this thread: Python BeautifulSoup Extract specific URLs. Also please show us either the link, or html structure of the links you want to extract. We would like to see the differences between the URLs.
PS: Sorry I can't make comments because of <50 reputation or I would have.
Updated answer based on understanding:
from bs4 import BeautifulSoup
import urllib
import requests
page = urllib.request.urlopen("https://www.bsi.bund.de/DE/Themen/ITGrundschutz/ITGrundschutzKompendium/itgrundschutzKompendium_node.html").read()
soup = BeautifulSoup(page, "html.parser")
for firstlink in soup.find_all("a",{"class":"RichTextIntLink NavNode"}):
firstlinks = firstlink.get("href")
if "bausteine" in firstlinks:
bausteinelinks = "https://www.bsi.bund.de/" + str(firstlinks.split(';')[0])
response = urllib.request.urlopen(bausteinelinks).read()
soup = BeautifulSoup(response, 'html.parser')
secondlink = "https://www.bsi.bund.de/" + str(((soup.find("a",{"class":"RichTextIntLink Basepage"})["href"]).split(';'))[0])
res = urllib.request.urlopen(secondlink).read()
soup = BeautifulSoup(res, 'html.parser')
listoftext = soup.find_all("div",{"id":"content"})
for text in listoftext:
print (text.text)
I am trying to access the sequence on this webpage:
https://www.ncbi.nlm.nih.gov/protein/EGW15053.1?report=fasta
The sequence is stored under the div class="seq gbff". Each line is stored under
<span class='ff_line' id='gi_344258949_1"> *line 1 of sequence* </span>
When I try to search for the spans containing the sequence, beautiful soup returns None. Same problem when I try to look at the children or content of the div above the spans.
Here is the code:
import requests
import re
from bs4 import BeautifulSoup
# Create a variable with the url
url = 'https://www.ncbi.nlm.nih.gov/protein/EGW15053.1?report=fasta'
# Use requests to get the contents
r = requests.get(url)
# Get the text of the contents
html_content = r.text
# Convert the html content into a beautiful soup object
soup = BeautifulSoup(html_content, 'html.parser')
div = soup.find_all('div', attrs={'class', 'seq gbff'})
for each in div.children:
print(each)
soup.find_all('span', aatrs={'class', 'ff_line'})
Neither method works and I'd greatly appreciate any help :D
This page uses JavaScript to load data
With DevTools in Chrome/Firefox I found this url and there are all <span>
https://www.ncbi.nlm.nih.gov/sviewer/viewer.fcgi?id=344258949&db=protein&report=fasta&extrafeat=0&fmt_mask=0&retmode=html&withmarkup=on&tool=portal&log$=seqview&maxdownloadsize=1000000
Now hard part. You have to find this url in HTML because different pages will use different arguments in url. Or you have to compare few urls and find schema so you could generate this url manually.
EDIT: if in url you change retmode=html to retmode=xml then you get it as XML. If you use retmode=text then you get it as text without HTML tags. retmode=json doesn't works.
I want to scrape information from this page.
Specifically, I want to scrape the table which appears when you click "View all" under the "TOP 10 HOLDINGS" (you have to scroll down on the page a bit).
I am new to webscraping, and have tried using BeautifulSoup to do this. However, there seems to be an issue because the "onclick" function I need to take into account. In other words: The HTML code I scrape directly from the page doesn't include the table I want to obtain.
I am a bit confused about my next step: should I use something like selenium or can I deal with the issue in an easier/more efficient way?
Thanks.
My current code:
from bs4 import BeautifulSoup
import requests
Soup = BeautifulSoup
my_url = 'http://www.etf.com/SHE'
page = requests.get(my_url)
htmltxt = page.text
soup = Soup(htmltxt, "html.parser")
print(soup)
You can get a json response from the api: http://www.etf.com/view_all/holdings/SHE. The table you're looking for is located in 'view_all'.
import requests
from bs4 import BeautifulSoup as Soup
url = 'http://www.etf.com/SHE'
api = "http://www.etf.com/view_all/holdings/SHE"
headers = {'X-Requested-With':'XMLHttpRequest', 'Referer':url}
page = requests.get(api, headers=headers)
htmltxt = page.json()['view_all']
soup = Soup(htmltxt, "html.parser")
data = [[td.text for td in tr.find_all('td')] for tr in soup.find_all('tr')]
print('\n'.join(': '.join(row) for row in data))
I am trying to get the blog content from this blog post and by content, I just mean the first six paragraphs. This is what I've come up with so far:
soup = BeautifulSoup(url, 'lxml')
body = soup.find('div', class_='post-body')
Printing body will also include other stuff under the main div tag.
Try this:
import requests ; from bs4 import BeautifulSoup
res = requests.get("http://www.fashionpulis.com/2017/08/being-proud-too-soon.html").text
soup = BeautifulSoup(res, 'html.parser')
for item in soup.select("div#post-body-604825342214355274"):
print(item.text.strip())
Use this:
import requests ; from bs4 import BeautifulSoup
res = requests.get("http://www.fashionpulis.com/2017/08/acceptance-is-must.html").text
soup = BeautifulSoup(res, 'html.parser')
for item in soup.select("div[id^='post-body-']"):
print(item.text)
I found this solution very interesting: Scrape multiple pages with BeautifulSoup and Python
However, I haven't found any Query String Parameters to tackle on, maybe you can start something out of this approach.
What I find most obvious to do right now is something like this:
Scrape through every month and year and get all titles from the Blog Archive part of the pages (e.g. on http://www.fashionpulis.com/2017/03/ and so on)
Build the URLs using the titles and the according months/years (the URL is always http://www.fashionpulis.com/$YEAR/$MONTH/$TITLE.html)
Scrape the text as described by Shahin in a previous answer