a= [{
"data" : {
"check": true,
},
"AMI": {
"status": 1,
"firewall":{
"status": enable
},
"d_suffix": "x.y.com",
"id": 4
},
"tags": [ #Sometime tags could be like "tags": ["default","auto"]
"default"
],
"hostname": "abc.com",
}
]
How to get a hostname on the basis of tags?I am trying to implement it using
for i in a:
if i['tags'] == 'default':
output = i['hostname']
but it's failing because 'tags' is a list which is not mapping to hostname key.Is there any way i can get hostname on the basis of 'tags'?
Use in to test if something is in a list. You also need to put default in quotes to make it a string.
for i in a:
if 'default' in i['tags']:
output = i['hostname']
break
If you only need to find one match, you should break out of the loop once you find it.
If you need to find multiple matches, use #phihag's answer with the list comprehension.
To get all hostnames tagged as default, use a list comprehension:
def_hostnames = [i['hostname'] for i in a if 'default' in i['tags']]
print('Default hostnames: %s' % ','.join(def_hostnames))
If you only want the first hit, either use def_hostnames[0] or the equivalent generator expression:
print('first: %s' % next(i['hostname'] for i in a if 'default' in i['tags']))
Your current code fails because it uses default, which is a variable named default. You want to look for a string default.
Make sure that you have everything in Json format like
a= [{
"data" : {
"check": True,
},
"AMI": {
"status": 1,
"firewall":{
"status": "enable"
},
"d_suffix": "x.y.com",
"id": 4
},
"tags": [
"default"
],
"hostname": "abc.com",
}
]
and then you can easily get it by using in
for i in a:
if 'default' in i['tags']:
output = i['hostname']
Related
I am working on a new project in HubSpot that returns nested JSON like the sample below. I am trying to access the associated contacts id, but am struggling to reference it correctly (the id I am looking for is the value '201' in the example below). I've put together this script, but this script only returns the entire associations portion of the JSON and I only want the id. How do I reference the id correctly?
Here is the output from the script:
{'contacts': {'paging': None, 'results': [{'id': '201', 'type': 'ticket_to_contact'}]}}
And here is the script I put together:
import hubspot
from pprint import pprint
client = hubspot.Client.create(api_key="API_KEY")
try:
api_response = client.crm.tickets.basic_api.get_page(limit=2, associations=["contacts"], archived=False)
for x in range(2):
pprint(api_response.results[x].associations)
except ApiException as e:
print("Exception when calling basic_api->get_page: %s\n" % e)
Here is what the full JSON looks like ('contacts' property shortened for readability):
{
"results": [
{
"id": "34018123",
"properties": {
"content": "Hi xxxxx,\r\n\r\nCan you clarify on how the blocking of script happens? Is it because of any CSP (or) the script will decide run time for every URL’s getting triggered from browser?\r\n\r\nRegards,\r\nLogan",
"createdate": "2019-07-03T04:20:12.366Z",
"hs_lastmodifieddate": "2020-12-09T01:16:12.974Z",
"hs_object_id": "34018123",
"hs_pipeline": "0",
"hs_pipeline_stage": "4",
"hs_ticket_category": null,
"hs_ticket_priority": null,
"subject": "RE: call followup"
},
"createdAt": "2019-07-03T04:20:12.366Z",
"updatedAt": "2020-12-09T01:16:12.974Z",
"archived": false
},
{
"id": "34018892",
"properties": {
"content": "Hi Guys,\r\n\r\nI see that we were placed back on the staging and then removed again.",
"createdate": "2019-07-03T07:59:10.606Z",
"hs_lastmodifieddate": "2021-12-17T09:04:46.316Z",
"hs_object_id": "34018892",
"hs_pipeline": "0",
"hs_pipeline_stage": "3",
"hs_ticket_category": null,
"hs_ticket_priority": null,
"subject": "Re: Issue due to server"
},
"createdAt": "2019-07-03T07:59:10.606Z",
"updatedAt": "2021-12-17T09:04:46.316Z",
"archived": false,
"associations": {
"contacts": {
"results": [
{
"id": "201",
"type": "ticket_to_contact"
}
]
}
}
}
],
"paging": {
"next": {
"after": "35406270",
"link": "https://api.hubapi.com/crm/v3/objects/tickets?associations=contacts&archived=false&hs_static_app=developer-docs-ui&limit=2&after=35406270&hs_static_app_version=1.3488"
}
}
}
You can do api_response.results[x].associations["contacts"]["results"][0]["id"].
Sorted this out, posting in case anyone else is struggling with the response from the HubSpot v3 Api. The response schema for this call is:
Response schema type: Object
String results[].id
Object results[].properties
String results[].createdAt
String results[].updatedAt
Boolean results[].archived
String results[].archivedAt
Object results[].associations
Object paging
Object paging.next
String paging.next.after
String paging.next.linkResponse schema type: Object
String results[].id
Object results[].properties
String results[].createdAt
String results[].updatedAt
Boolean results[].archived
String results[].archivedAt
Object results[].associations
Object paging
Object paging.next
String paging.next.after
String paging.next.link
So to access the id of the contact associated with the ticket, you need to reference it using this notation:
api_response.results[1].associations["contacts"].results[0].id
notes:
results[x] - reference the result in the index
associations["contacts"] -
associations is a dictionary object, you can access the contacts item
by it's name
associations["contacts"].results is a list - reference
by the index []
id - is a string
In my case type was ModelProperty or CollectionResponseProperty couldn't reach dict anyhow.
For the record this got me to go through the results.
for result in list(api_response.results):
ID = result.id
I hope everyone is doing well.
I need a little help where I need to get all the strings from a variable and need to store into a single list in python.
For example -
I have json file from where I am getting ids and all the ids are getting stored into a variable called id as below when I run print(id)
17298626-991c-e490-bae6-47079c6e2202
17298496-19bd-2f89-7b5f-881921abc632
17298698-3e17-7a9b-b337-aacfd9483b1b
172986ac-d91d-c4ea-2e50-d53700480dd0
172986d0-18aa-6f51-9c62-6cb087ad31e5
172986f4-80f0-5c21-3aee-12f22a5f4322
17298712-a4ac-7b36-08e9-8512fa8322dd
17298747-8cc6-d9d0-8d05-50adf228c029
1729875c-050f-9a99-4850-bb0e6ad35fb0
1729875f-0d50-dc94-5515-b4891c40d81c
17298761-c26b-3ce5-e77e-db412c38a5b4
172987c8-2b5d-0d94-c365-e8407b0a8860
1729881a-e583-2b54-3a52-d092020d9c1d
1729881c-64a2-67cf-d561-6e5e38ed14cb
172987ec-7a20-7eb6-3ebe-a9fb621bb566
17298813-7ac4-258b-d6f9-aaf43f9147b1
17298813-f1ef-d28a-0817-5f3b86c3cf23
17298828-b62b-9ee6-248b-521b0663226e
17298825-7449-2fcb-378e-13671cb4688a
I want these all values to be stored into a single list.
Can some please help me out with this.
Below is the code I am using:
import json
with open('requests.json') as f:
data = json.load(f)
print(type(data))
for i in data:
if 'traceId' in i:
id = i['traceId']
newid = id.split()
#print(type(newid))
print(newid)
And below is my json file looks like:
[
{
"id": "376287298-hjd8-jfjb-khkf-6479280283e9",
"submittedTime": 1591692502558,
"traceId": "17298626-991c-e490-bae6-47079c6e2202",
"userName": "ABC",
"onlyChanged": true,
"description": "Not Required",
"startTime": 1591694487929,
"result": "NONE",
"state": "EXECUTING",
"paused": false,
"application": {
"id": "16b22a09-a840-f4d9-f42a-64fd73fece57",
"name": "XYZ"
},
"applicationProcess": {
"id": "dihihdosfj9279278yrie8ue",
"name": "Deploy",
"version": 12
},
"environment": {
"id": "fkjdshkjdshglkjdshgldshldsh03r937837",
"name": "DEV"
},
"snapshot": {
"id": "djnglkfdglki98478yhgjh48yr844h",
"name": "DEV_snapshot"
},
},
{
"id": "17298495-f060-3e9d-7097-1f86d5160789",
"submittedTime": 1591692844597,
"traceId": "17298496-19bd-2f89-7b5f-881921abc632",
"userName": "UYT,
"onlyChanged": true,
"startTime": 1591692845543,
"result": "NONE",
"state": "EXECUTING",
"paused": false,
"application": {
"id": "osfodsho883793hgjbv98r3098w",
"name": "QA"
},
"applicationProcess": {
"id": "owjfoew028r2uoieroiehojehfoef",
"name": "EDC",
"version": 5
},
"environment": {
"id": "16cf69c5-4194-e557-707d-0663afdbceba",
"name": "DTESTU"
},
}
]
From where I am trying to get the traceId.
you could use simple split method like the follwing:
ids = '''17298626-991c-e490-bae6-47079c6e2202 17298496-19bd-2f89-7b5f-881921abc632 17298698-3e17-7a9b-b337-aacfd9483b1b 172986ac-d91d-c4ea-2e50-d53700480dd0 172986d0-18aa-6f51-9c62-6cb087ad31e5 172986f4-80f0-5c21-3aee-12f22a5f4322 17298712-a4ac-7b36-08e9-8512fa8322dd 17298747-8cc6-d9d0-8d05-50adf228c029 1729875c-050f-9a99-4850-bb0e6ad35fb0 1729875f-0d50-dc94-5515-b4891c40d81c 17298761-c26b-3ce5-e77e-db412c38a5b4 172987c8-2b5d-0d94-c365-e8407b0a8860 1729881a-e583-2b54-3a52-d092020d9c1d 1729881c-64a2-67cf-d561-6e5e38ed14cb 172987ec-7a20-7eb6-3ebe-a9fb621bb566 17298813-7ac4-258b-d6f9-aaf43f9147b1 17298813-f1ef-d28a-0817-5f3b86c3cf23 17298828-b62b-9ee6-248b-521b0663226e 17298825-7449-2fcb-378e-13671cb4688a'''
l = ids.split(" ")
print(l)
This will give the following result, I assumed that the separator needed is simple space you can adjust properly:
['17298626-991c-e490-bae6-47079c6e2202', '17298496-19bd-2f89-7b5f-881921abc632', '17298698-3e17-7a9b-b337-aacfd9483b1b', '172986ac-d91d-c4ea-2e50-d53700480dd0', '172986d0-18aa-6f51-9c62-6cb087ad31e5', '172986f4-80f0-5c21-3aee-12f22a5f4322', '17298712-a4ac-7b36-08e9-8512fa8322dd', '17298747-8cc6-d9d0-8d05-50adf228c029', '1729875c-050f-9a99-4850-bb0e6ad35fb0', '1729875f-0d50-dc94-5515-b4891c40d81c', '17298761-c26b-3ce5-e77e-db412c38a5b4', '172987c8-2b5d-0d94-c365-e8407b0a8860', '1729881a-e583-2b54-3a52-d092020d9c1d', '1729881c-64a2-67cf-d561-6e5e38ed14cb', '172987ec-7a20-7eb6-3ebe-a9fb621bb566', '17298813-7ac4-258b-d6f9-aaf43f9147b1', '17298813-f1ef-d28a-0817-5f3b86c3cf23', '17298828-b62b-9ee6-248b-521b0663226e', '17298825-7449-2fcb-378e-13671cb4688a']
Edit
You get list of lists because each iteration you read only 1 id, so what you need to do is to initiate an empty list and append each id to it in the following way:
l = []
for i in data
if 'traceId' in i:
id = i['traceId']
l.append(id)
you can append the ids variable to the list such as,
#list declaration
l1=[]
#this must be in your loop
l1.append(ids)
I'm assuming you get the id as a str type value. Using id.split() will return a list of all ids in one single Python list, as each id is separated by space here in your example.
id = """17298626-991c-e490-bae6-47079c6e2202 17298496-19bd-2f89-7b5f-881921abc632
17298698-3e17-7a9b-b337-aacfd9483b1b 172986ac-d91d-c4ea-2e50-d53700480dd0
172986d0-18aa-6f51-9c62-6cb087ad31e5 172986f4-80f0-5c21-3aee-12f22a5f4322
17298712-a4ac-7b36-08e9-8512fa8322dd 17298747-8cc6-d9d0-8d05-50adf228c029
1729875c-050f-9a99-4850-bb0e6ad35fb0 1729875f-0d50-dc94-5515-b4891c40d81c
17298761-c26b-3ce5-e77e-db412c38a5b4 172987c8-2b5d-0d94-c365-e8407b0a8860
1729881a-e583-2b54-3a52-d092020d9c1d 1729881c-64a2-67cf-d561-6e5e38ed14cb
172987ec-7a20-7eb6-3ebe-a9fb621bb566 17298813-7ac4-258b-d6f9-aaf43f9147b1
17298813-f1ef-d28a-0817-5f3b86c3cf23 17298828-b62b-9ee6-248b-521b0663226e
17298825-7449-2fcb-378e-13671cb4688a"""
id_list = id.split()
print(id_list)
Output:
['17298626-991c-e490-bae6-47079c6e2202', '17298496-19bd-2f89-7b5f-881921abc632',
'17298698-3e17-7a9b-b337-aacfd9483b1b', '172986ac-d91d-c4ea-2e50-d53700480dd0',
'172986d0-18aa-6f51-9c62-6cb087ad31e5', '172986f4-80f0-5c21-3aee-12f22a5f4322',
'17298712-a4ac-7b36-08e9-8512fa8322dd', '17298747-8cc6-d9d0-8d05-50adf228c029',
'1729875c-050f-9a99-4850-bb0e6ad35fb0', '1729875f-0d50-dc94-5515-b4891c40d81c',
'17298761-c26b-3ce5-e77e-db412c38a5b4', '172987c8-2b5d-0d94-c365-e8407b0a8860',
'1729881a-e583-2b54-3a52-d092020d9c1d', '1729881c-64a2-67cf-d561-6e5e38ed14cb',
'172987ec-7a20-7eb6-3ebe-a9fb621bb566', '17298813-7ac4-258b-d6f9-aaf43f9147b1',
'17298813-f1ef-d28a-0817-5f3b86c3cf23', '17298828-b62b-9ee6-248b-521b0663226e',
'17298825-7449-2fcb-378e-13671cb4688a']
split() splits by default with space as a separator. You can use the sep argument to use any other separator if needed.
I receive a fairly uncomfortable JSON to work with, which looks as follows:
[
{
"attributes": [
{
"type": "COMMAND",
"name": "COMMAND",
"value": [
"buttonState"
]
},
{
"type": "std_msgs.msg.Bool",
"name": "buttonState",
"value": {
"data": false
}
}
],
"type": "sensor",
"id": "s_2"
}]
And I would like to compare a piece of data (more precisely - value of Button state) but I seem to fail. Tried following:
import requests
import json
yo = 1
switchPost = "http://192.168.0.104:7896/iot/d?k=123456789&i=san_1_switch&d=sw|{}"
robGet = "http://192.168.0.109:10100/robot/sen_2"
r = requests.get(robGet, headers={"content-type":"application/json"})
resp = json.loads(r.text)
for attrs in (resp['attributes']['value']):
if attrs['data'] == false:
yo = 100
break
g = requests.post(switchPost.format(yo), headers={"content-type":"text/plain"})
print(r.text)
Unfortunately, the error I receive is the following:
for attrs in (resp['attributes']['value']):
TypeError: list indices must be integers, not str
In your JSON, the fact that it is wrapped in [ then ] means it is a JSON array, but with just one element.
So, as your error message suggests, resp needs an integer as its index, for which element of the array you want. resp[0] then refers to
{
"attributes": [
{
"type": "COMMAND",
"name": "COMMAND",
"value": [
"buttonState"
]
},
{
"type": "std_msgs.msg.Bool",
"name": "buttonState",
"value": {
"data": false
}
}
],
"type": "sensor",
"id": "s_2"
}
(notice no [] now, so it's a JSON object)
Then you want resp[0]['attributes'] to refer to the single part of this object, 'attributes' which again refers to an array.
Therefore for attribute in resp[0]['attributes'] will allow you to loop through this array.
To get the boolean value you want, you'll then want to find which element of that array has 'name' of 'buttonState' and check the corresponding 'value'.
In all, you're probably looking for something like:
for attribute in resp[0]['attributes']:
if attribute['name'] == 'buttonState' and attribute['value']['data'] is False:
# Do your thing here
resp is a list so, to get first element, access it as resp[0]. Same with resp[0]['attributes']
So you can access it as follows
resp[0]['attributes'][0]['value']
You can restructure your for loop as follows
for d in resp[0]['attributes']:
if isinstance(d['value'], dict) and d['value'].get('data') == false:
yo = 100
break
The answer is in the error message I think:
TypeError: list indices must be integers, not str
The first entry in attributes has a value that is a list, so you can't get 'data' from that.
Since you have a mix of types, you might need to check if 'value' is a list or a dict.
Edit:
Jumped the gun here I think. #dennlinger gives an explanation to your error message. But you'll get it again once you're past that...
I'm using the following python code to connect to a jsonrpc server and nick some song information. However, I can't work out how to get the current title in to a variable to print elsewhere. Here is the code:
TracksInfo = []
for song in playingSongs:
data = { "id":1,
"method":"slim.request",
"params":[ "",
["songinfo",0,100, "track_id:%s" % song, "tags:GPASIediqtymkovrfijnCYXRTIuwxN"]
]
}
params = json.dumps(data, sort_keys=True, indent=4)
conn.request("POST", "/jsonrpc.js", params)
httpResponse = conn.getresponse()
data = httpResponse.read()
responce = json.loads(data)
print json.dumps(responce, sort_keys=True, indent=4)
TrackInfo = responce['result']["songinfo_loop"][0]
TracksInfo.append(TrackInfo)
This brings me back the data in json format and the print json.dump brings back:
pi#raspberrypi ~/pithon $ sudo python tom3.py
{
"id": 1,
"method": "slim.request",
"params": [
"",
[
"songinfo",
"0",
100,
"track_id:-140501481178464",
"tags:GPASIediqtymkovrfijnCYXRTIuwxN"
]
],
"result": {
"songinfo_loop": [
{
"id": "-140501481178464"
},
{
"title": "Witchcraft"
},
{
"artist": "Pendulum"
},
{
"duration": "253"
},
{
"tracknum": "1"
},
{
"type": "Ogg Vorbis (Spotify)"
},
{
"bitrate": "320k VBR"
},
{
"coverart": "0"
},
{
"url": "spotify:track:2A7ZZ1tjaluKYMlT3ItSfN"
},
{
"remote": 1
}
]
}
}
What i'm trying to get is result.songinfoloop.title (but I tried that!)
The songinfo_loop structure is.. peculiar. It is a list of dictionaries each with just one key.
Loop through it until you have one with a title:
TrackInfo = next(d['title'] for d in responce['result']["songinfo_loop"] if 'title' in d)
TracksInfo.append(TrackInfo)
A better option would be to 'collapse' all those dictionaries into one:
songinfo = reduce(lambda d, p: d.update(p) or d,
responce['result']["songinfo_loop"], {})
TracksInfo.append(songinfo['title'])
songinfo_loop is a list not a dict. That means you need to call it by position, or loop through it and find the dict with a key value of "title"
positional:
responce["result"]["songinfo_loop"][1]["title"]
loop:
for info in responce["result"]["songinfo_loop"]:
if "title" in info.keys():
print info["title"]
break
else:
print "no song title found"
Really, it seems like you would want to have the songinfo_loop be a dict, not a list. But if you need to leave it as a list, this is how you would pull the title.
The result is really a standard python dict, so you can use
responce["result"]["songinfoloop"]["title"]
which should work
I'm reading in a JSON string which is littered with u'string' style strings. Example:
[
{
"!\/award\/award_honor\/honored_for": {
"award": {
"id": "\/en\/spiel_des_jahres"
},
"year": {
"value": "1996"
}
},
"guid": "#9202a8c04000641f80000000003a0ee6",
"type": "\/games\/game",
"id": "\/en\/el_grande",
"name": "El Grande"
},
{
"!\/award\/award_honor\/honored_for": {
"award": {
"id": "\/en\/spiel_des_jahres"
},
"year": {
"value": "1995"
}
},
"guid": "#9202a8c04000641f80000000000495ec",
"type": "\/games\/game",
"id": "\/en\/settlers_of_catan",
"name": "Settlers of Catan"
}
]
If I assign name = result.name. Then when I log of pass that value to a Django template, it displays as u'Dominion'
How do I format it to display as Dominion?
++ UPDATE ++
I think the problem has to do with printing values from a list or dictionary. For example:
result = freebase.mqlread(query)
games = {}
count = 0
r = result[0]
name = r.name
games["name"] = name,
self.response.out.write(games["name"])
self.response.out.write(name)
This displays as:
(u'Dominion',) // saved response to dictionary, and then printed
Dominion // when calling the value directly from the response
I need to iterate through an array of JSON items and the values are being shown with the unicode. Why?
The comma at the end of games["name"] = name, makes it a 1-tuple. Remove it.
>>> # example
>>> s = u"Jägermütze"
>>> s.encode("utf-8")
'J\xc3\xa4germ\xc3\xbctze'
>>> print s.encode("utf-8") # on a utf-8 terminal
Jägermütze
Don't know much about Django, but not accepting snicode strings seems unpythonic to me.
You can use str(your string) to do this.