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Writing List to CSV in Python

I'm writing data from a PDF to a CSV. The CSV needs to have one column, with each word on a separate row.
The code below writes each word on a separate row, but also puts each letter in a separate cell.
with open('annualreport.csv', 'w', encoding='utf-8') as f:
write = csv.writer(f)
for i in keywords:
write.writerow(i)
I have also attempted the following, which writes all the words to one row, with each word in a separate column:
with open('annualreport.csv', 'w', encoding='utf-8') as f:
write = csv.writer(f)
write.writerow(keywords)

As far as I know, writerow expects an array. Thus a word is treated as an array with the individual letters -> each letter is written into a new cell.
Putting the value into a single array should fix the problem:
with open('annualreport.csv', 'w', encoding='utf-8') as f:
write = csv.writer(f)
for i in keywords:
write.writerow( [ i ] ) # <-- before: write.writerow(i)

import csv
# data to be written row-wise in csv fil
data = [['test'], [try], ['goal']]
# opening the csv file in 'w+' mode
file = open('output.csv', 'w+', newline ='')
# writing the data into the file
with file:
write = csv.writer(file)
write.writerows(data)

Converting a Text .txt document to CSV .csv Using a Delimiter

I'd like to create a CSV from a TXT file. I have a text file with lines (300 lines+) separated by backslashes. I'd like each line to be a separate row, and each backslash to be a separate new column.
The text file looks like:
example 1\example 2\example 3\example 4
test 1\test 2\test 3\test 4
I'd like the CSV to look like:
Example 1
Example 2
Example 3
Example 4
Test 1
Test 2
Test 3
Test 4
So far I have:
import csv
with open('Report.txt') as report:
report_txt = report.read()
with open('Report.csv','w',newline='') as csvfile:
writer = csv.writer(csvfile)
writer.writerow(report_txt)
I know I need to use \ as a delimiter, but I'm not sure how. Thanks for any help!

Define your delimiter like this (escape the \):
reader = csv.reader(open("Report.csv"), delimiter="\\")
Code:
import csv
with open('Report.txt') as report:
reader = csv.reader(report, delimiter="\\")
with open('Report_output.csv', 'w', newline='') as csvfile:
writer = csv.writer(csvfile)
for line in reader:
writer.writerow(line)

First you got to split the string based on the delimeter. You can achieve this by using the split operator or regex.
import csv
with open('file.txt', 'r') as in_file:
stripped = (line.strip() for line in in_file)
lines = (line.split("\\") for line in stripped if line)
Then pretty much write it to the csv.
with open('report.csv', 'w') as out_file:
writer = csv.writer(out_file)
writer.writerows(lines)
Tweak your code accordingly. The concept is pretty much the same. Note the double backslash is to account for the escape character.

If you are just trying to convert that text into CSV, you can just replace every "\" character with ";" and you'll have a valid CSV file.
Else, if you want to do something with the parsed data before reexporting to CSV, you can read the file line by line and use the split() Method with "\", then rejoin and write line by line, like here:
with open('in.txt') as input_file:
with open('out.csv','a') as output_file:
txt_line = input_file.readline()
while txt_line:
cells = txt_line.split("\\")
# Do something with each cell...
csv_line = ";".join(cells)
output_file.write(csv_line)
txt_line = input_file.readline()

python parsing string to csv format

I have a file containing a line with the following format
aaa=A;bbb=B;ccc=C
I want to convert it to a csv format so the literals on the equation sides will be columns and the semicolon as a row separator. I tried doing something like this
f = open("aaa.txt", "r")
with open("ccc.csv", 'w') as csvFile:
writer = csv.writer(csvFile)
rows = []
if f.mode == 'r':
single = f.readline()
lns = single.split(";")
for item in lns:
rows.append(item.replace("=", ","))
writer.writerows(rows)
f.close()
csvFile.close()
but I am getting each letter as a column so the result looks like :
a,a,a,",",A
b,b,b,",",B
c,c,c,",",C,"
The expected result should look like
aaa,A
bbb,B
ccc,C

The following 1 line change worked for me:
rows.append(item.split('='))
instead of the existing code
rows.append(item.replace("=", ",")).
That way, I was able to create a list of lists which can easily be read by the writer so that the row list looks like [['aaa', 'A'], ['bbb', 'B'], ['ccc', 'C']]instead of ['aaa,A', 'bbb,B', 'ccc,C']

Just write the strings into the target file line by line:
import os
f = open("aaa.txt", "r")
with open("ccc.csv", 'w') as csvFile:
single = f.readline()
lns = single.split(";")
for item in lns:
csvFile.write(item.replace("=", ",") + os.linesep)
f.close()
The output would be:
aaa,A
bbb,B
ccc,C

It helps to interactively execute the commands and print the values, or add debug print in the code (that will be removed or commented when everything works). Here you could have seen that rows is ['aaa,A', 'bbb,B', 'ccc,C'] that is 3 strings when it should be three sequences.
As a string is a (read only) sequence of chars writerows uses each char as a field.
So you do not want to replace the = with a comma (,), but want to split on the equal sign:
...
for item in lns:
rows.append(item.split("=", 1))
...
But the csv module requires for proper operation the output file to be opened with newline=''.
So you should have:
with open("ccc.csv", 'w', newline='') as csvFile:
...

The parameter to writer.writerows() must be an iterable of rows, which must in turn be iterables of strings or numbers. Since you pass it a list of strings, characters in the strings are treated as separate fields. You can obtain the proper list of rows by splitting the line first on ';', then on '=':
import csv
with open('in.txt') as in_file, open('out.csv', 'w') as out_file:
writer = csv.writer(out_file)
line = next(in_file).rstrip('\n')
rows = [item.split('=') for item in line.split(';')]
writer.writerows(rows)

Python - save csv file with tab separated words in separate cell

I have this input file:
one\tone
two\ttwo
three\tthree
With a tab between each word.
I am trying to save it in a csv file where each word ends up in its own cell. This is my code:
import csv
input = open('input.txt').read()
lines = input.split('\n')
with open('output.csv', 'w') as f:
writer = csv.writer(f)
for line in lines:
writer.writerow([line])
However, both words end up in the same cell:
How do I change the code so that each word ends up in its own cell?

Try this:
import csv
input = open('input.txt').read()
lines = input.split('\n')
with open('output.csv', 'w') as f:
writer = csv.writer(f)
for line in lines:
writer.writerow(line.split('\t'))

The writerow method in the CSV writer library takes a list of columns.
Currently, you are providing your whole string the value of the first column
writer.writerow([line])
Instead, try splitting the string by \t, thus creating a list of each individual word and provide that to the library instead.
writer.writerow(line.split("\t"))

You need to split the input lines into a list, so that csv.writer() will put them into seperate columns. Try:
with open('output.csv', 'w') as f:
writer = csv.writer(f)
for line in lines:
writer.writerow(line.split('\t'))

Python: writing an entire row to a CSV file. Why does it work this way?

I had exported a csv from Nokia Suite.
"sms","SENT","","+12345678901","","2015.01.07 23:06","","Text"
Reading from the PythonDoc, I tried
import csv
with open(sourcefile,'r', encoding = 'utf8') as f:
reader = csv.reader(f, delimiter = ',')
for line in reader:
# write entire csv row
with open(filename,'a', encoding = 'utf8', newline='') as t:
a = csv.writer(t, delimiter = ',')
a.writerows(line)
It didn't work, until I put brackets around 'line' as so i.e. [line].
So at the last part I had
a.writerows([line])
Why is that so?

The writerows method accepts a container object. The line object isn't a container. [line] turns it into a list with one item in it.
What you probably want to use instead is writerow.