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Replace string which has dynamic character in python

Trying to replace the string with regular expression and could not success.
The strings are "LIVE_CUS2_PHLR182" ,"LIVE_CUS2ee_PHLR182" and "PHLR182 - testing recovery".Here I need to get PHLR182 as an output with all the string but where second string has "ee" which is not constant. It can be string or number with 2 character.Below is the code what I have tried.
For first and last string I just simply used replace function like below.
s = "LIVE_CUS2_PHLR182"
s.replace("LIVE_CUS2_", ""), s.replace(" - testing recovery","")
>>> PHLR182
But for second I tried like below.
1. s= "LIVE_CUS2ee_PHLR182"
s.replace(r'LIVE_CUS2(\w+)*_','')
2. batRegex = re.compile(r'LIVE_CUS2(\w+)*_PHLR182')
mo2 = batRegex.search('LIVE_CUS2dd_PHLR182')
mo2.group()
3. re.sub(r'LIVE_CUS2(?is)/s+_PHLR182', '', r)
In all case I could not get "PHLR182" as an output. Please help me.

I think this is what you need:
import re
texts = """LIVE_CUS2_PHLR182
LIVE_CUS2ee_PHLR182
PHLR182 - testing recovery""".split('\n')
pat = re.compile(r'(LIVE_CUS2\w{,2}_| - testing recovery)')
# 1st alt pattern | 2nd alt pattern
# Look for 'LIV_CUS2_' with up to two alphanumeric characters after 2
# ... or Look for ' - testing recovery'
results = [pat.sub('', text) for text in texts]
# replace the matched pattern with empty string
print(f'Original: {texts}')
print(f'Results: {results}')
Result:
Original: ['LIVE_CUS2_PHLR182', 'LIVE_CUS2ee_PHLR182', 'PHLR182 - testing recovery']
Results: ['PHLR182', 'PHLR182', 'PHLR182']
Python Demo: https://repl.it/repls/ViolentThirdAutomaticvectorization
Regex Demo: https://regex101.com/r/JiEVqn/2

get all occurence of a regex in string python

I am trying to find in the following string TreeModel/Node/Node[1]/Node[4]/Node[1] this :
TreeModel/Node
TreeModel/Node/Node[1]
TreeModel/Node/Node[1]/Node[4]
TreeModel/Node/Node[1]/Node[4]/Node[1]
Using regular expression in python. Here is the code I tried:
string = 'TreeModel/Node/Node[1]/Node[4]/Node[1]'
pattern = r'.+?Node\[[1-9]\]'
print re.findall(pattern=pattern,string=string)
#result : ['TreeModel/Node/Node[1]', '/Node[4]', '/Node[1]']
#expected result : ['TreeModel/Node', 'TreeModel/Node/Node[1]', 'TreeModel/Node/Node[1]/Node[4]', 'TreeModel/Node/Node[1]/Node[4]/Node[1]']

You can use split here:
>>> s = 'TreeModel/Node/Node[1]/Node[4]/Node[1]'
>>> split_s = s.split('/')
>>> ['/'.join(split_s[:i]) for i in range(2, len(split_s)+1)]
['TreeModel/Node',
'TreeModel/Node/Node[1]',
'TreeModel/Node/Node[1]/Node[4]',
'TreeModel/Node/Node[1]/Node[4]/Node[1]']
You can also use regex:
for i in range(2, s.count('/')+2):
s_ = '[^/]+/*'
regex = re.search(r'('+s_*i+')', s).group(0)
print(regex)
TreeModel/Node/
TreeModel/Node/Node[1]/
TreeModel/Node/Node[1]/Node[4]/
TreeModel/Node/Node[1]/Node[4]/Node[1]

I'm not good in Python at all but for regex part with your specific structure of string below regex matches each segment:
/?(?:{[^{}]*})?[^/]+
Where braces and preceding / is optional. It matches a slash mark (if any) then braces with their content (if any) then the rest up to next slash mark.
Python code (see live demo here):
matches = re.findall(r'/?(?:{[^{}]*})?[^/]+', string)
output = ''
for i in range(len(matches)):
output += matches[i];
print(output)

Splitting a string using re module of python

I have a string
s = 'count_EVENT_GENRE in [1,2,3,4,5]'
#I have to capture only the field 'count_EVENT_GENRE'
field = re.split(r'[(==)(>=)(<=)(in)(like)]', s)[0].strip()
#o/p is 'cou'
# for s = 'sum_EVENT_GENRE in [1,2,3,4,5]' o/p = 'sum_EVENT_GENRE'
which is fine
My doubt is for any character in (in)(like) it is splitting the string s at that character and giving me first slice.(as after "cou" it finds one matching char i:e n). It's happening for any string that contains any character from (in)(like).
Ex : 'percentage_AMOUNT' o/p = 'p'
as it finds a matching char as 'e' after p.
So i want some advice how to treat (in)(like) as words not as characters , when splitting occurs/matters.
please suggest a syntax.

Answering your question, the [(==)(>=)(<=)(in)(like)] is a character class matching single characters you defined inside the class. To match sequences of characters, you need to remove [ and ] and use alternation:
r'==?|>=?|<=?|\b(?:in|like)\b'
or better:
r'[=><]=?|\b(?:in|like)\b'
You code would look like:
import re
ss = ['count_EVENT_GENRE in [1,2,3,4,5]','coint_EVENT_GENRE = "ROMANCE"']
for s in ss:
field = re.split(r'[=><]=?|\b(?:in|like)\b', s)[0].strip()
print(field)
However, there might be other (easier, or safer - depending on the actual specifications) ways to get what you want (splitting with space and getting the first item, use re.match with r'\w+' or r'[a-z]+(?:_[A-Z]+)+', etc.)
If your value is at the start of the string and starts with lowercase ASCII letters, and then can have any amount of sequences of _ followed with uppercase ASCII letters, use:
re.match(r'[a-z]+(?:_[A-Z]+)*', s)
Full demo code:
import re
ss = ['count_EVENT_GENRE in [1,2,3,4,5]','coint_EVENT_GENRE = "ROMANCE"']
for s in ss:
fieldObj = re.match(r'[a-z]+(?:_[A-Z]+)*', s)
if fieldObj:
print(fieldObj.group())

If you want only the first word of your string, then this should do the job:
import re
s = 'count_EVENT_GENRE in [1,2,3,4,5]'
field = re.split(r'\W', s)[0]
# count_EVENT_GENRE

Is there anything wrong with using split?
>>> s = 'count_EVENT_GENRE in [1,2,3,4,5]'
>>> s.split(' ')[0]
'count_EVENT_GENRE'
>>> s = 'coint_EVENT_GENRE = "ROMANCE"'
>>> s.split(' ')[0]
'coint_EVENT_GENRE'
>>>

Python - remove parts of a string

I have many fill-in-the-blank sentences in strings,
e.g. "6d) We took no [pains] to hide it ."
How can I efficiently parse this string (in Python) to be
"We took no to hide it"?
I also would like to be able to store the word in brackets (e.g. "pains") in a list for use later. I think the regex module could be better than Python string operations like split().

This will give you all the words inside the brackets.
import re
s="6d) We took no [pains] to hide it ."
matches = re.findall('\[(.*?)\]', s)
Then you can run this to remove all bracketed words.
re.sub('\[(.*?)\]', '', s)

just for fun (to do the gather and substitution in one iteration)
matches = []
def subber(m):
matches.append(m.groups()[0])
return ""
new_text = re.sub("\[(.*?)\]",subber,s)
print new_text
print matches

import re
s = 'this is [test] string'
m = re.search(r"\[([A-Za-z0-9_]+)\]", s)
print m.group(1)
Output
'test'

For your example you could use this regex:
(.*\))(.+)\[(.+)\](.+)
You will get four groups that you can use to create your resulting string and save the 3. group for later use:
6d)
We took no
pains
to hide it .
I used .+ here because I don't know if your strings always look like your example. You can change the .+ to alphanumeric or sth. more special to your case.
import re
s = '6d) We took no [pains] to hide it .'
m = re.search(r"(.*\))(.+)\[(.+)\](.+)", s)
print(m.group(2) + m.group(4)) # "We took no to hide it ."
print(m.group(3)) # pains

import re
m = re.search(".*\) (.*)\[.*\] (.*)","6d) We took no [pains] to hide it .")
if m:
g = m.groups()
print g[0] + g[1]
Output :
We took no to hide it .

getting string between 2 characters in python

I need to get certain words out from a string in to a new format. For example, I call the function with the input:
text2function('$sin (x)$ is an function of x')
and I need to put them into a StringFunction:
StringFunction(function, independent_variables=[vari])
where I need to get just 'sin (x)' for function and 'x' for vari. So it would look like this finally:
StringFunction('sin (x)', independent_variables=['x']
problem is, I can't seem to obtain function and vari. I have tried:
start = string.index(start_marker) + len(start_marker)
end = string.index(end_marker, start)
return string[start:end]
and
r = re.compile('$()$')
m = r.search(string)
if m:
lyrics = m.group(1)
and
send = re.findall('$([^"]*)$',string)
all seems to seems to give me nothing. Am I doing something wrong? All help is appreciated. Thanks.

Tweeky way!
>>> char1 = '('
>>> char2 = ')'
>>> mystr = "mystring(123234sample)"
>>> print mystr[mystr.find(char1)+1 : mystr.find(char2)]
123234sample

$ is a special character in regex (it denotes the end of the string). You need to escape it:
>>> re.findall(r'\$(.*?)\$', '$sin (x)$ is an function of x')
['sin (x)']

If you want to cut a string between two identical characters (i.e, !234567890!)
you can use
line_word = line.split('!')
print (line_word[1])

You need to start searching for the second character beyond start:
end = string.index(end_marker, start + 1)
because otherwise it'll find the same character at the same location again:
>>> start_marker = end_marker = '$'
>>> string = '$sin (x)$ is an function of x'
>>> start = string.index(start_marker) + len(start_marker)
>>> end = string.index(end_marker, start + 1)
>>> string[start:end]
'sin (x)'
For your regular expressions, the $ character is interpreted as an anchor, not the literal character. Escape it to match the literal $ (and look for things that are not $ instead of not ":
send = re.findall('\$([^$]*)\$', string)
which gives:
>>> import re
>>> re.findall('\$([^$]*)\$', string)
['sin (x)']
The regular expression $()$ otherwise doesn't really match anything between the parenthesis even if you did escape the $ characters.