hey I've wrote this code in python and it iterates through the selected text file and reads it. My objective is to read the file, and then write the file on a new file and replace the word "winter" with nothing. or rather delete the word from the second revised file. I have two txt files called odetoseasons and odetoseasons_censored the contents of these two files are identical before the program starts. which is
I love winter
I love spring
Summer, Fall and winter again.
/This is the python file named readwrite.py WHen i run the program it keeps the contents in odetoseasons but somehow deletes the contents of odetoseasons_censored.txt not sure why/
# readwrite.py
# Demonstrates reading from a text file and writing to the other
filename = input("Enter file name (without extension): ")
fil1 = filename+".txt"
fil2 = filename+"_censored.txt"
bad_word = ['winter']
print("\nLooping through the file, line by line.")
in_text_file = open(fil1, "r")
out_text_file = open(fil2,"w")
for line in in_text_file:
print(line)
out_text_file.write(line)
in_text_file.close()
out_text_file.close()
out_text_file = open(fil2,"w")
for line in fil2 :
if "winter" in line:
out_text_file.write(line)
line.replace("winter", "")
Actually there are two errors in your code. Firstly the function a.replace() returns an object with the replaced word and not alter the original object. Secondly you are trying to read a file you have opened in 'w' mode, which is not possible. If you need to both read and write you should use 'r+' mode.
Here is the correct code(and more compact one) that you can use :-
filename = input("Enter file name (without extension): ")
fil1 = filename+".txt"
fil2 = filename+"_censored.txt"
bad_word = ['winter']
print("\nLooping through the file, line by line.")
in_text_file = open(fil1, "r")
out_text_file = open(fil2,"w")
for line in in_text_file:
print(line)
line_censored = line.replace("winter","")
print(line_censored)
out_text_file.write(line_censored)
in_text_file.close()
out_text_file.close()
Related
If you need any more info just Let Me Know
I have a python script that adds a string after each line on a CSV file. the line file_lines = [''.join([x.strip(), string_to_add, '\n']) for x in f.readlines()] is the trouble maker. For each file line it will add the string and then add a new line after each time the string is added.
Here is the script:
#Adding .JPG string to the end of each line for the Part Numbers
string_to_add = ".JPG"
#Open the file and join the .JPG to the current lines
with open("PartNums.csv", 'r') as f:
file_lines = [''.join([x.strip(), string_to_add, '\n']) for x in f.readlines()]
#Writes to the file until its done
with open("PartNums.csv", 'w') as f:
f.writelines(file_lines)
The script works and does what it is supposed to, however my issue is later on in this larger script. This script outputs into a CSV file and it looks like this:
X00TB0001.JPG
X01BJ0003.JPG
X01BJ0004.JPG
X01BJ0005.JPG
X01BJ0006.JPG
X01BJ0007.JPG
X01BJ0008.JPG
X01BJ0026.JPG
X01BJ0038.JPG
X01BJ0039.JPG
X01BJ0040.JPG
X01BJ0041.JPG
...
X01BJ0050.JPG
X01BJ0058.JPG
X01BJ0059.JPG
X01BJ0060.JPG
X01BJ0061.JPG
X01BJ0170.JPG
X01BJ0178.JPG
Without the \n in that line the csv file output looks like this file_lines = [''.join([x.strip(), string_to_add]) for x in f.readlines()]:
X00TB0001.JPGX01BJ0003.JPGX01BJ0004.JPGX01BJ0005.JPGX01BJ0006.JPG
The issue is when I go to read this file later and move files with it using this script:
#If the string matches a file name move it to a new directory
dst = r"xxx"
with open('PicsWeHave.txt') as my_file:
for filename in my_file:
src = os.path.join(XXX") # .strip() to avoid un-wanted white spaces
#shutil.copy(src, os.path.join(dst, filename.strip()))
shutil.copy(os.path.join(src, filename), os.path.join(dst, filename))
When I run this whole Script it works until it has to move the files I get this error:
FileNotFoundError: [Errno 2] No such file or directory: 'XXX\\X15SL0447.JPG\n'
I know the file exist however the '\n' should not be there and that's why I am asking how can I still get everything on a new line and not have \n after each name so when I move the file the strings match.
Thank You For Your Help!
As they said above you should use .strip():
shutil.copy(os.path.join(src, filename.strip()), os.path.join(dst, filename.strip()))
This way it gives you the file name or string you need and then it removes anything else.
I am trying to open a file with this Try/Except block but it is going straight to Except and not opening the file.
I've tried opening multiple different files but they are going directly to not being able to open.
import string
fname = input('Enter a file name: ')
try:
fhand = open(fname)
except:
print('File cannot be opened:', fname)
exit()
counts = dict()
L_N=0
for line in fhand:
line= line.rstrip()
line = line.translate(line.maketrans(' ', ' ',string.punctuation))
line = line.lower()
words = line.split()
L_N+=1
for word in words:
if word not in counts:
counts[word]= [L_N]
else:
if L_N not in counts[word]:
counts[word].append(L_N)
for h in range(len(counts)):
print(counts)
out_file = open('word_index.txt', 'w')
out_file.write('Text file being analyzed is: '+str(fname)+ '\n\n')
out.file_close()
I would like the output to read a specific file and count the created dictionary
make sure you are inputting quotes for your filename ("myfile.txt") if using python 2.7. if python3, quotes are not required.
make sure your input is using absolute path to the file, or make sure the file exists in the same place you are running the python program.
for example,
if your program and current working directory is in ~/code/
and you enter: 'myfile.txt', 'myfile.txt' must exist in ~/code/
however, its best you provide the absolute path to your input file such as
/home/user/myfile.txt
then your script will work 100% of the time, no matter what directory you call your script from.
I'm trying to open .txt file and am getting confused with which part goes where. I also want that when I open the text file in python, the spaces removed.And when answering could you make the file name 'clues'.
My first try is:
def clues():
file = open("clues.txt", "r+")
for line in file:
string = ("clues.txt")
print (string)
my second try is:
def clues():
f = open('clues.txt')
lines = [line.strip('\n') for line in open ('clues.txt')]
The thrid try is:
def clues():
f = open("clues.txt", "r")
print f.read()
f.close()
Building upon #JonKiparsky It would be safer for you to use the python with statement:
with open("clues.txt") as f:
f.read().replace(" ", "")
If you want to read the whole file with the spaces removed, f.read() is on the right track—unlike your other attempts, that gives you the whole file as a single string, not one line at a time. But you still need to replace the spaces. Which you need to do explicitly. For example:
f.read().replace(' ', '')
Or, if you want to replace all whitespace, not just spaces:
''.join(f.read().split())
This line:
f = open("clues.txt")
will open the file - that is, it returns a filehandle that you can read from
This line:
open("clues.txt").read().replace(" ", "")
will open the file and return its contents, with all spaces removed.
I'm trying to write a Python script that will take any playlist and recreate it on another file structure. I have it written now so that all the filenames are stripped off the original playlist and put into a file. That works. Then the function findsong() is supposed to walk thru the new directory and find the same songs and make a new playlist based on the new directory structure.
Here's where it gets weird. If I use 'line' as my argument in the line 'If line in files' I get an empty new playlist. If I use ANY file that I know is there as the argument the entire playlist is recreated, not just the file I used as the argument. That's how I have it set up in this code. I cannot figure out this weird behavior. As long as the file exists, the whole playlist is recreated with the new paths. Wut??
Here is the code:
import os
def check():
datafile = open('testlist.m3u')
nopath = open('nopath.txt', 'w')
nopath.truncate()
for line in datafile:
if 'mp3' in line:
nopath.write(os.path.basename(line))
if 'wma' in line:
nopath.write(os.path.basename(line))
nopath.close()
def findsong():
nopath = open('nopath.txt')
squeezelist = open('squeezelist.m3u' ,'w')
squeezelist.truncate()
for line in nopath:
print line
for root, dirs, files in os.walk("c:\\Documents and Settings\\"):
print files
if ' Tuesday\'s Gone.mp3' in files:
squeezelist.write(os.path.join(root, line))
squeezelist.close()
check()
findsong()
When you iterate over the lines in a file Python retains the trailing newlines \n. You'll want to strip those off:
for line in nopath:
line = line.rstrip()
I'm stuck on why my code is printing a blank line before writing text to a file. What I am doing is reading two files from a zipped folder and writing the text to a new text file. I am getting the expected results in the file, except for the fact that there is a blank line on the first line of the file.
def test():
if zipfile.is_zipfile(r'C:\Users\test\Desktop\Zip_file.zip'):
zf = zipfile.ZipFile(r'C:\Users\test\Desktop\Zip_file.zip')
for filename in zf.namelist():
with zf.open(filename, 'r') as f:
words = io.TextIOWrapper(f)
new_file = io.open(r'C:\Users\test\Desktop\new_file.txt', 'a')
for line in words:
new_file.write(line)
new_file.write('\n')
else:
pass
zf.close()
words.close()
f.close()
new_file.close()
Output in new_file (there is a blank line before the first "This is a test line...")
This is a test line...
This is a test line...
this is test #2
this is test #2
Any ideas?
Thanks!
My guess is that the first file in zf.namelist() doesn't contain anything, so you skip the for line in words loop for that file and just do new_file.write('\n'). It's difficult to tell without seeing the files that you're looping over; perhaps add some debug statements that print out the files' names and some info, e.g. their size.