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I've completed the code however I don't understand what's wrong [closed]

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Question is: Use procedure with parameter. Ask the user to input numbers until they say “no”. Output if each number is greater than or less than or equal to 5.
def output(number):
if number > 5:
print("Greater than 5")
elif number < 5:
print("Less than 5")
else:
print("It is equal to 5")
userInput = "yes"
print(userInput.lower() != "no")
num = input("Enter a number \n")
output(userInput)
userInput = input("Would you like to try again?")

You're trying to compare a str with an int. The following will fix it:
def output(number):
if number > 5:
print("Greater than 5")
elif number < 5:
print("Less than 5")
else:
print("It is equal to 5")
userInput = "yes"
print(userInput.lower() != "no")
num = int(input("Enter a number \n"))
output(userInput)
userInput = input("Would you like to try again?")

Using random in an if statement [closed]

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Closed 5 years ago.
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I am trying to make a random number guessing game but I cant get the if statement to check if the users input is = to the random number
import random
realNumber = random.randint(1, 50)
print(realNumber)
myNumber = print(input("Guess the number from 1 to 50: "))
if int(myNumber) == realNumber:
print("You win")
else:
print("Nope guess again")

The unintended behavior of your program is due to this line:
myNumber = print(input("Guess the number from 1 to 50: "))
Here, you are trying to assign myNumber to the return value of the print statement (Which is None) and not the value obtained from the input() statement. To fix this, simply remove the print() around the input.
myNumber = input("Guess the number from 1 to 50: ")
Hope this helped!

You don't need the print statement around input.
import random
realNumber = random.randint(1, 50)
print(realNumber)
myNumber = input("Guess the number from 1 to 50: ")
if int(myNumber) == realNumber:
print("You win")
else:
print("Nope guess again")
Note that this code will not work if the user enters something besides an integer, because the int() call will not cast correctly

How to debug beginners code [closed]

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I have 2 questions about my code. Why the program doesn't go in the second if statement. How can I end the loop?
from random import *
SecretNumber=randint(1,5)
Guess=int(input("Please enter Guess: "))
NumberofGuesses=1
SecretNumber=0
while Guess != SecretNumber:
NumberofGuesses=NumberofGuesses+1
if Guess>SecretNumber:
print("Please insert a smaller number")
else:
print("Please insert a bigger number")
if Guess==SecretNumber:
print("Number of Guesses: {0}".format(NumberofGuesses))

Your second if is outside the while loop, so it won't get hit until you guesss the secret number. The loop never ends because you never read another guess.
You also have a problem that you are overriding your random secret number with zero.
You need something like:
import random
SecretNumber=random.randint(1,5)
NumberofGuesses=0
while true:
Guess=int(input("Please enter Guess: "))
NumberofGuesses += 1
if Guess == SecretNumber:
break # Got it!
elif Guess>SecretNumber:
print("Please insert a smaller number")
else:
print("Please insert a bigger number")
print("Number of Guesses: {0}".format(NumberofGuesses))

It's because you're setting SecretNumber to 0. Remove it and it should work.

Keep getting a syntax error on creating a loop [closed]

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num = input(float("Enter a number (enter 'q' to quit): ")
p=0
while num>=1:
p=p+1
Why do I keep getting a syntax error on the first p?
Does this mean I can't assign a numerical value on a variable?

You should close the bracket
num = input(float("Enter a number (enter 'q' to quit): "))

import sys
num = input("Enter a number (enter 'q' to quit)")
try:
num = int(num)
except:
if num == 'q':
sys.exit()
p=0
while (num>=1):
p=p+1
num = num - 1 #otherwise it will go to infinite loop

Python assignment for school [closed]

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import random
number= random.randint(1,10)
count=0
guess=""
guess=int(input("please guess:")
while guess!= number:
if guess < number:
print("lower")
count++
elif guess > number:
print("higher")
count++
elif guess==number:
print("Good job, you got my number")
print("You got it in,",count,"tries")
FOr some reason when i try to run it, it says I have invalid syntax. Please help.

This is Python, not C or JS. This:
count++
Should be written as:
count += 1
Also, your keep in mind that Python is indentation-sensitive.
while guess!= number:
if guess < number:
print("lower")
count++
elif guess > number:
print("higher")
count++
elif guess==number:
print("Good job, you got my number")
print("You got it in,",count,"tries")
And lastly, you're missing a closing parenthesis:
guess=int(input("please guess:"))
Well, good luck learning!

You're missing an end parenthesis
guess=int(input("please guess:")
Should be:
guess=int(input("please guess:"))
Hope that helps
You also need to change your indenting on this:
elif guess==number:
print("Good job, you got my number")
print("You got it in,",count,"tries")
Also do increment correctly