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num = input(float("Enter a number (enter 'q' to quit): ")
p=0
while num>=1:
p=p+1
Why do I keep getting a syntax error on the first p?
Does this mean I can't assign a numerical value on a variable?
You should close the bracket
num = input(float("Enter a number (enter 'q' to quit): "))
import sys
num = input("Enter a number (enter 'q' to quit)")
try:
num = int(num)
except:
if num == 'q':
sys.exit()
p=0
while (num>=1):
p=p+1
num = num - 1 #otherwise it will go to infinite loop
Related
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I wrote this code snippet:
lowestNumber = int(input("\nWhat would you like your lowest number to be?"))
highestNumber = int(input("What would you like your highest number to be?"))
number = random.randint(lowestNumber, highestNumber)
tries = 0
while tries < 10:
guess = int(input(f'\nEnter a number between', lowestNumber))
if guess == number:
print("You guessed correctly! The number was", number)
break
elif guess < number:
print("Too low!")
elif guess > number:
print("Too high!")
tries += 1
SyntaxError: bad input on line 22 in main.py.
Line 22 was guess = int(input(f'\nEnter a number between', lowestNumber)).
I searched it up on google and got nothing, I pasted it into OpenAI's code fixing and it also didn't help.
How can I fix this error?
When you wrote
guess = int(input(f'\nEnter a number between', lowestNumber))
it passed both the string and lowestNumber into the input function. However, you probably wanted to write something like Enter a number between (lowestNumber) and (highestNumber). To do this, you would have to write
guess = int(input(f'\nEnter a number between {lowestNumber} and {highestNumber}. '))
In my example, it passes in one object, the string, which contains lowestNumber and highestNumber in it. In your example, it passes in two objects, the string and lowestNumber.
The formatting you did in the input functions works in print statements, so the print statements are correct, but the input function is not.
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n = int(input("enter nos of items in List: "))
a = []
for i in range(0,n):
elements = int(input("Enter Elements : "))
a.append(elements)
avg = sum(a)/n
print("average of given numbers", round(avg,2))
I would suggest using validating the user input with a while loop, you can check if the answer contains only number, if it does not, then the loop repeats until the user enters a valid input.
n = input("enter nos of items in List: ")
while n.isdigit() != True:
n = input("Invalid Input!\nEnter nos of items in List: ")
a = []
for i in range(0, int(n)):
elements = input("Enter Elements : ")
while elements.isdigit() != True:
elements = input("Invalid Input!\nEnter Elements : ")
a.append(int(elements))
avg = sum(a)/int(n)
print("average of given numbers", round(avg,2))
ValueErros can be caused, as the result of the you trying to convert a string containing alphabetic characters into an integer.
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I am requesting someone to tell me a program that asks a user to input only 9 digits. Number 0 not at start but having 9 digits.
How can I limit the number of digits?
For example:
Num=int(input('please Enter a Number'))
if num?!
Please help me soon.
If i got this right this should work:
a=input()
if len(a)==9 and a[0] != '0' and a.isdigit():
#if you want it to be integer
a=int(a)
do something
Hope it helps.
Well if I understood correctly you need a program that asks the user to enter exactly 9 digits. In that case it's pretty simple.
i = input("Enter a nine digit number: ")
if len(i) != 9:
print("You must enter 9 digits!")
quit()
if not i.isdigit():
print("Your input must be a number!")
quit()
# num is a 9 digit integer
# i is a 9 digit string
num = int(i)
You can do this.
num = input('Please enter a number')
if not num[0] == "0" and len(num) == 9 and num.isdigit():
# You can print a message or cast the num into an integer here
# like this: input_number = int(num)
print(True)
else:
print(False)
So what's happening here is that the program will accept the user input and evaluate if the first digit is NOT 0 AND that the length is exactly 9 characters.
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I have 2 questions about my code. Why the program doesn't go in the second if statement. How can I end the loop?
from random import *
SecretNumber=randint(1,5)
Guess=int(input("Please enter Guess: "))
NumberofGuesses=1
SecretNumber=0
while Guess != SecretNumber:
NumberofGuesses=NumberofGuesses+1
if Guess>SecretNumber:
print("Please insert a smaller number")
else:
print("Please insert a bigger number")
if Guess==SecretNumber:
print("Number of Guesses: {0}".format(NumberofGuesses))
Your second if is outside the while loop, so it won't get hit until you guesss the secret number. The loop never ends because you never read another guess.
You also have a problem that you are overriding your random secret number with zero.
You need something like:
import random
SecretNumber=random.randint(1,5)
NumberofGuesses=0
while true:
Guess=int(input("Please enter Guess: "))
NumberofGuesses += 1
if Guess == SecretNumber:
break # Got it!
elif Guess>SecretNumber:
print("Please insert a smaller number")
else:
print("Please insert a bigger number")
print("Number of Guesses: {0}".format(NumberofGuesses))
It's because you're setting SecretNumber to 0. Remove it and it should work.
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I was wondering how to reset this program, and I need help. I have been looking everywhere for an answer, but I can't find a program that works. Can someone please help me?
print("Answer These MATH Questions")
def program():
math = int(input("What Is 8 x 4: "))
if math == ("32"):
print("You Got The Question Correct")
else:
print("Sorry You Got The Question Wrong Try Again")
program()
return
Use while like example. Don't use int for input - maybe it will not number:
while 1:
math = input("What Is 8 x 4: ")
if not math.isdigit():
print("It's not number")
elif math == "32":
print("You Got The Question Correct")
break
else:
print("Sorry You Got The Question Wrong Try Again")
change if math == ("32"): to if math == 32: