How to structure Flask User app? - python

I use supervisor to run my app. It is structured as follows:
My app layout
my_app
__init__.py
my_app
__init__.py
startup
create_app.py
create_users.py
common_settings.py
core
__init__.py
models.py
views.py
Outer __init__.py
from my_app import app
Inner __init__.py
from flask import Flask
from flask_script import Manager
from flask_sqlalchemy import SQLAlchemy
app = Flask(__name__) # The WSGI compliant web application object
db = SQLAlchemy(app) # Setup Flask-SQLAlchemy
manager = Manager(app) # Setup Flask-Script
from my_app.startup.create_app import create_app
create_app()
create_app.py
def create_app(extra_config_settings={}):
"""
Initialize Flask applicaton
"""
# ***** Initialize app config settings *****
# Read common settings from 'app/startup/common_settings.py' file
app.config.from_object('app.startup.common_settings')
# Read environment-specific settings from file defined by OS environment variable 'ENV_SETTINGS_FILE'
app.config.from_envvar('ENV_SETTINGS_FILE')
# Load all blueprints with their manager commands, models and views
# Setup Flask-User to handle user account related forms
from my_app.core.models import User
# Setup Flask-User
db_adapter = SQLAlchemyAdapter(db, User) # Setup the SQLAlchemy DB Adapter
user_manager = UserManager(db_adapter, app) # Init Flask-User and bind to app
from my_app import core
return app
my_app/core/__init__.py
from . import models
from . import views
views.py
from my_app import db, app
'''
Register a new user
'''
#app.route('/register', methods = ['POST'])
def register_user():
user_manager = app.user_manager
db_adapter = user_manager.db_adapter
I was trying to follow an example I found online.
I'm creating the variables db_adapter and user_manager in create_app(). Are these the same ones being used in my views.py?
If anyone has any suggestions or links to examples that I can follow to structure my project, it would be greatly appreciated.
Thanks.

Assuming that that's how Flask-User works (sets the user_manager attribute on app), this is trivial to determine, just compare them in the create_app function when you still have a direct reference to the objects.
db_adapter = SQLAlchemyAdapter(db, User)
user_manager = UserManager(db_adapter, app)
assert db_adapter is user_manager.db_adapter
assert user_manager is app.user_manager
However, your entire project layout doesn't make much sense. You should be creating the entire app inside the create_app factory. You should not have an __init__.py file at the top level, that's the project folder not the package. You should use current_app within views to access the app, since it will only be created at runtime by the factory. You should create a manage.py file at the project level to use the factory.
my_project/
my_app/
__init__.py
models.py
views.py
defaults.py
instance/
config.py
manage.py
__init__.py:
from flask import Flask
from flask_sqlalchemy import SQLAlchemy
db = SQLAlchemy()
def create_app():
app = Flask(__name__, instance_relative_config=True)
app.config.from_object('my_app.defaults')
app.config.from_pyfile('config.py')
db.init_app(app)
from my_app.views import bp
app.register_blueprint(bp)
return app
models.py:
from my_app import db
class User(db.Model):
...
views.py:
from flask import Blueprint, render_template
from my_app.models import User
bp = Blueprint('app', __name__)
#bp.route('/')
def index():
return render_template('index.html')
manage.py:
#!/usr/bin/env python
from flask_script import Manager
from my_app import create_app
Manager(create_app).run()

Related

Run flask app with python instead of flask run

I'm trying to run my flask app with "python app.py" instead of "flask run" command.
My goal is to launch the app on cpanel server and just about every tutorial requires the applications to be called using the "python" method.
Here is my folder structure:
project
webapp
init.py
templates
static
auth.py
main.py
app.py <-------------- I want this to be called with python instead of flask run command outside the folder
Here is my init_.py file:
from flask import Flask
from flask_sqlalchemy import SQLAlchemy
from flask_login import LoginManager
# init SQLAlchemy so we can use it later in our models
db = SQLAlchemy()
def create_app():
app = Flask(__name__)
app.config['SECRET_KEY'] = '9OLWxND4o83j4iuopO'
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///db.sqlite'
db.init_app(app)
login_manager = LoginManager()
login_manager.login_view = 'auth.login'
login_manager.init_app(app)
from .models import User
#login_manager.user_loader
def load_user(user_id):
# since the user_id is just the primary key of our user table, use it in the query for the user
return User.query.get(int(user_id))
# blueprint for auth routes in our app
from .auth import auth as auth_blueprint
app.register_blueprint(auth_blueprint)
# blueprint for non-auth parts of app
from .main import main as main_blueprint
app.register_blueprint(main_blueprint)
return app
And app.py is:
from webapp import app
I'm a newbie in flask, any help is appreciated
Insert the call to create_app at the end of init.py:
if __name__ == '__main__':
create_app().run(host='0.0.0.0', port=5000, debug=True)
The if statement avoid calling the app many times. It can only be called directly. Flask default host is 127.0.0.1 (localhost). Use 0.0.0.0 at production for better traffic monitoring. Default port is also 5000, so it's up to you to include. For better readability, you should explicit it.
Then call it
python webapp/init.py

Removing global app reference from blueprint in Flask

I'm currently working on learning Flask and create a working page with login functions. Now I want to remove the global app instance and started using blueprints for the submodules.
My project is structured like this:
+ app
+ auth
- __init__.py
- forms.py
- routes.py
+ main
+ models
+ templates
- __init__.py
+ migrations
- index.py
- config.py
No I added a blueprint to the routes.py and used the decorators there:
from flask import render_template, flash, redirect, url_for, request, Blueprint
from app import app, db
from app.auth.forms import LoginForm, RegistrationForm
# ...
from app.models.User import User
blueprint = Blueprint('auth', __name__)
#blueprint.route('/login', methods=['GET', 'POST'])
def login():
return "example login"
The __init__.py of the auth module:
from . import forms, routes
The blueprint gets added in the __init__.py of the app folder:
# ...
app = Flask(__name__)
app.config.from_object(Config)
db = SQLAlchemy(app)
from app.auth.routes import blueprint as auth_bp
app.register_blueprint(auth_bp)
After using the #blueprint decorators, I don't need #app anymore, but how can I access the db when I want to remove the import app and the from app.models.User import User part?
from . import db
from ..models.User import User
There are two things to understand here. app as a module (the folder) and app the instance of flask inside __init__.py. When you do import app inside authentication blueprint then you are actually importing the whole app module and not the flask instance. When you do from app import app you are actually importing flask instance from app module. This can be confusing to eliminate this I advise you to change the name of app folder to something different like bacher then when you need to import db inside your authentication blueprint use from bacher import db and for User model from bacher.models.User import User

Flask-PyMongo with application factory and blueprints

I am trying to implement Flask-PyMongo with blueprints and an application factory and keep getting AttributeError: 'Flask' object has no attribute 'db'
My directory structure looks like
myapp/
myapp.py
config.py
/app
__init__.py
/v1
__init__.py
endpoints.py
In my python script that starts the Flask app I have:
import os
from app import create_app
app = create_app('dev')
In my top level init.py I have:
mongo = PyMongo()
def create_app(config_name):
app = Flask(__name__)
mongo.init_app(app)
app.config.from_object(config[config_name])
from app.v1 import psapi as psapi_bp
app.register_blueprint(psapi_bp, url_prefix='/api')
if not os.path.exists('logs'):
os.mkdir('logs')
In my endpoints.py I have a route that looks like
#myapp.route('/addentry', methods=['POST'])
def addentry():
username = request.json['username']
userid = current_app.db.user_entry.insert({'username':username})
return jsonify({'userid':userid})
I feel like there is something small that I am missing but I am not seeing it.
You need to call db on your mongo object, not on the app object
to those who may be facing this problem again :
you should first define mongo oustside create_app to have access to it from inside other files.
then init_app with that like the following:
from flask import Flask, current_app
from flask_pymongo import PyMongo
mongo = PyMongo()
def create_app(config_name):
app = Flask(__name__, instance_relative_config=False)
app.config.from_object(app_config[config_name])
# INIT EXTENSIONS ----------------------
mongo.init_app(app)
return app
then in any file you can import mongo from above file. for example:
from ../factory import mongo

how to use config in flask extensions when use factory pattern in flask?

I use factory pattern and flask extensions such as flask-admin during the development of web application. I want to load some configurations in flask-admin when the app haven't created. So i use the current_app.config["SOME_CONFIG"] to get the config value.But i got the Working outside of application context. exception. The code as follows:
# __init__.py
from flask import Flask
def create_app(config_name):
app = Flask(__name__)
app.config.from_object(config_name)
app.config.from_pyfile("config.py")
from admin import admin
admin.init_app(app)
return app
# admin/__init__.py
from flask import current_app
from flask_admin import Admin
admin = Admin(name=current_app.config["ADMIN_NAME"], template="bootstrap2")
Your application is still in the setup state during the create_app function (see http://flask.pocoo.org/docs/0.11/appcontext/). During the setup state you need to have a reference to the application object to access it, you can't use current_app.
You could instantiate the Admin object within the create_app function using:
admin = Admin(name=app.config["ADMIN_NAME"], template="bootstrap2")
OR
change the admin variable and create a function in your admin/__init__.py:
admin = object()
def instantiate_admin(config):
global admin
admin = Admin(name=config["ADMIN_NAME"], template="bootstrap2")
return admin
and use this in create_app():
from admin import instantiate_admin
admin = instantiate_admin(app.config)
admin.init_app(app)
All you need to do is set it up like the following.
# config.py
class Config(object):
ADMIN_NAME = 'admin'
# __init__.py
from flask import Flask
from flask_admin import Admin
# initiate all extensions here
admin = Admin(template='bootstrap2')
def create_app(config):
app = Flask(__name__)
app.config.from_object(config)
admin.init_app(app)
return app
# wsgi.py
from . import create_app
from config import Config
app = create_app(Config)
if __name__ == '__main__':
app.run()
And in you admin package
# admin/__init__.py
from .. import admin # import extensions from __init__.py
admin.add_view('blah')
Below is a link to an real world example. I scrubbed info so it is more generic but this is how i setup all my flask apps.
http://hastebin.com/likupoxoxi.py
As long as you are running the dev server you shouldn't have issues that keeps it in the context of the application.

Trying to run the sql-alchemy tutorial steps. Can't import db from console (ImportError: cannot import name 'db')

Trying to run the tutorial here: http://flask-sqlalchemy.pocoo.org/2.1/quickstart/ using my app
I have looked at the circular imports problem but I don't think that's it. I'm an absolute beginner to python and flask (and sqlalchemy). My app currently runs, but the database part doesn't
This is the current setup:
mysite
|- __init__.py
|- flask_app.py
|- models.py
|- views.py
init.py
from flask import Flask
app = Flask(__name__)
flask_app.py
from flask import Flask, request, url_for
import random
app = Flask(__name__)
app.config['SQLALCHEMY_DATABASE_URI'] = 'mysql:// -- database uri --'
... app continues here
models.py
from app import app
from flask.ext.sqlalchemy import SQLAlchemy
db = SQLAlchemy(app)
class Foo(db.Model):
... model continues here
views.py
from app import app,models
... views continue here, still not using anything from models
when I run from mysite import db in the python console I get:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ImportError: cannot import name 'db'
Declare your db object in __init__.py. The stuff that is declared in __init__.py defines what can be imported under mysite/.
See: What is __init__.py for?
Also consider moving to the application factory pattern.
For example in __init__.py:
from flask import Flask
from flask_sqlalchemy import SQLAlchemy
db = SQLAlchemy()
def create_app():
app = Flask(__name__)
app.config['DEBUG'] = True
... more application config ...
db.init_app(app)
return app
Then in flask_app.py:
from mysite import create_app, db
app = create_app()
if __name__ == '__main__':
app.run()
I point this out because you instantiate the app object twice in the code you've shown. Which is definitely wrong.

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