I have the following date I need to convert:
Wed, 09 Jul 2014 12:22:17 +0000
This is currently stored as a String. I wrote this code to convert it to the date format I want (the String above is passed as an argument to the covertDate function):
def convertDate(dictValue):
date_string = dictValue
format_string = '%a, %d %b %Y %H:%M:%S %z'
date_object = datetime.datetime.strptime(date_string, format_string)
date_correct_form = date_object.strftime("%Y-%m-%d")
print(type(date_correct_form))
print(date_correct_form)
return date_correct_form
The output is as follows:
<class 'str'>
2014-10-30
I get the format that I want, but it still isn't recognized as a date.
How can I make it so?
You are returning date_correct_form, which is the result of strftime:
Return a string representing the date, controlled by an explicit format string.
(emphasis mine)
If you want the datetime object, return date_object. If you need both, you can return both:
return date_correct_form, date_object
You can call it like so:
date_string, date_obj = convertDate(dictValue)
You now have the already formatted string in date_string, and if you still need to do logic against the datetime object, that is in date_obj
You can use easy_date to make it easy:
import date_converter
converted_date = date_converter.string_to_date(date_string, '%a, %d %b %Y %H:%M:%S %z')
Related
I'm trying to convert a datetime string into a different timezone. My code works but the result is not what I'm looking for.
I've already tried .localize() and .astimezone but the output is the same.
phtimezone = timezone('Asia/Manila')
test = datetime.datetime.strptime('Sun Sep 16 03:38:40 +0000 2018','%a %b %d %H:%M:%S +0000 %Y')
date = phtimezone.localize(test)
print (date)
date = test.astimezone(phtimezone)
print (date)
The output is 2018-09-16 03:38:40+08:00. I was expecting it to be 2018-09-16 11:38:40+08:00.
Your parsed object test does not contain a timezone. It's a naïve datetime object. Using both localize and astimezone cannot do any conversion, since they don't know what they're converting from; so they just attach the timezone as given to the naïve datetime.
Also parse the timezone:
datetime.strptime('Sun Sep 16 03:38:40 +0000 2018','%a %b %d %H:%M:%S %z %Y')
^^
This gives you an aware datetime object in the UTC timezone which can be converted to other timezones.
I was able to fix it thanks to #deceze. Here is the code:
phtimezone = pytz.timezone('Asia/Manila')
test = datetime.datetime.strptime('Sun Sep 16 03:38:40 +0000 2018','%a %b %d %H:%M:%S %z %Y')
test_utc = test.replace(tzinfo=timezone('UTC'))
date = test_utc.astimezone(pytz.timezone('Asia/Manila'))
print (date)
The output is now 2018-09-16 11:38:40+08:00
I'm having trouble converting a string to data format. I'm using the time module to convert a string to the YYYY-MM-DD format. The code below is what I've tried but I get the following error.
sre_constants.error: redefinition of group name 'Y' as group 5; was group 3
Here is the code
import time
review_date = "April 18, 2018"
review_date = time.strptime(review_date, '%m %d %Y %I:%Y%m%d')
Firstly, the error is because you're using %Y, %m, and %d twice in your time.strptime() call.
Secondly, you're using the wrong format. The format you pass to strptime() has to match the format of the date / time string you pass, which in this case is: %B %d, %Y.
This is a good reference on the different format types.
I normally use datetime for this:
from datetime import datetime
review_date = "April 18, 2018"
review_date = datetime.strptime(review_date, '%B %d, %Y').strftime('%Y-%m-%d')
This code returns review_date = '2018-04-18'. See https://docs.python.org/3/library/datetime.html
The date format for April is %B. strptime() converts to a datetime object, .strftime() converts the datetime object to a string.
time.strptime() is for parsing strings into date/time structures. It takes two arguments, the string to be parsed and another string describing the format of the string to be parsed.
Try this:
time.strptime("April 18, 2018", "%B %d, %Y")
... and notice that "%B %d, %Y" is:
Full locale name of the month ("April")
[Space]
Date of the month (18)
[Comma]
[Space]
Four digit year (2018)
The format string specification that you provided bears no resemblance to the formatting of your date string.
These "magic" formatting codes are enumerated in the documentation for time.strftime()
review_date = time.strptime(review_date, '%B %d, %Y')
import time
review_date = "April 18, 2018"
review_date = time.strptime(review_date, '%B %d, %Y')
That's what you should have
I'm currently trying to convert a file format into a slightly different style to allow easier importing into a program however I can't quite get my head around how to convert datetime strings between formats. The original I have is the following:
2016-12-15 17:26:45
However the required format for the date time is:
Thu Dec 15 17:19:03 2016
Does anyone know if there is an easy way to convert between these? These values are always in the same place and format so it doesn't need to be too dynamic so to speak outside of recognising what a certain day of the month is (if that can be done at all?)
Update - The conversion has worked for 1 date but not the other weirdly :/ The code to grab the two dates is the following:
startDate=startDate.replace("Started : ","")
startDate=startDate.replace(" (ISO format YYYY-MM-DD HH:MM:SS)","")
startDate=startDate.strip()
startDt = datetime.strptime(startDate, '%Y-%m-%d %H:%M:%S')
startDt=startDt.strftime('%a %b %d %H:%M:%S %Y ')
print (startDt)
This part works as inteded and outputs the required format:
"2016-12-15 17:26:45
Thu Dec 15 17:26:45 2016"
The end date part is a bit "ham fisted" so to speak and I'm sure there are better ways to do the re.sub search just to do anything in brackets but I'll edit that later.
endDate=endDate.replace("Ended : ","")
endDate=endDate.strip()
endDate = re.sub("\(.*?\)", "", endDate)
endDate.strip()
endDt = datetime.strptime(endDate, '%Y-%m-%d %H:%M:%S')
endDt=endDt.strftime('%a %b %d %H:%M:%S %Y ')
print (endDt)
This part however despite the outputs being an identical format
"2016-12-15 17:26:45
2016-12-15 21:22:11"
produces the following error:
endDt = datetime.strptime(endDate, '%Y-%m-%d %H:%M:%S')
File "C:\Python27\lib\_strptime.py", line 335, in _strptime
data_string[found.end():])
ValueError: unconverted data remains:
from datetime import datetime
dt = datetime.strptime('2016-06-01 1:33:45', '%Y-%m-%d %H:%M:%S')
dt.strftime('%a %b %d %H:%M:%S %Y ')
>>> 'Wed Jun 01 01:33:45 2016'
It's a pretty easy task with the Datetime module.
As it's been pointed out, checking the docs will get you a lot of useful info, starting from the directives to feed to the strptime and strftime (respectively, parse and format time) functions which you'll need here.
A working example for you case would be:
from datetime import datetime
myDateString = '2016-12-15 17:26:45'
myDateObj = datetime.strptime(myDateString, '%Y-%m-%d %H:%M:%S')
myDateFormat = myDateObj.strftime('%a %b %d %H:%M:%S %Y')
Check out this section of the docs to have a better understanding of the formatting placeholders.
You can use the datetime module:
from datetime import datetime
string = '2016-12-15 17:26:45'
date = datetime.strptime(string, '%Y-%m-%d %H:%M:%S')
date2 = date.strftime("%a %b %d %H:%M:%S %Z %Y")
print(date2)
Output:
Thu Dec 15 17:26:45 2016
I'm pulling the date value from gmail and trying to perform some functions on it. First I simply want to display it, but I can't even do that. See my code and error below.
from datetime import datetime
timeString = 'Sat, 2 Aug 2014 09:29:31 -0700'
myTime = datetime.strptime(timeString, '%m-%d-%Y %I:%M %p')
Here's the error I get. Do you think its the -0700 that's getting in the way?
ValueError: time data 'Sat, 2 Aug 2014 09:29:31 -0700' does not match format '%m-%d-%Y %I:%M %p'
As the error message suggests, you need to put the same format as your date string is in, I've not tried it, but something like this should work:
myTime = datetime.strptime(timeString, '%a, %d %b %Y %I:%M:%S %z')
Check here for complete details.
I am trying to parse string into python datetime object and this is the code:
created = datetime.strptime(r.json()[x]["created_at"], "%a %b %d %H:%M:%S +0000 %Y")
The error I get is:
ValueError: time data '"Wed Jan 16 22:08:18 +0000 2013"' does not match format '%a %b %d %H:%M:%S +0000 %Y'
It should be correct, obviously I am doing something wrong. As a note, the r.json returns the text in unicode, but I tried it with a str() conversion as well.
The full program:
import requests
from datetime import datetime
from simplejson import dumps
url = 'https://api.twitter.com/1/statuses/user_timeline.json?include_entities=true&include_rts=true&screen_name='
username = 'gtklondike'
count = '5'
url += username + "&count=" + count
r = requests.get(url)
x = 0
while x < count:
print "<div id='tw-body'>" + r.json()[x]["text"] + "</div>"
created = datetime.strptime(dumps(r.json()[x]["created_at"]), "%a %b %d %H:%M:%S +0000 %Y")
print "<div id='tw-date'>Date: " + r.json()[x]["created_at"] + "</div><br />\n" # TMP --> until I get datetime working... but at least it shows you the date
x = x + 1
It looks to me like there's an extra set of quotes in your string - one ' denoting that it's a string, and one " inside the string.
Try:
created = datetime.strptime((r.json()[x]["created_at"]).strip('"'), "%a %b %d %H:%M:%S +0000 %Y")
strip('"') removes the "s from the string.
I found the issue! #wrgrs solution worked, but actually it is from the dumps() being around it, created an extra set of quotes. (It was his solution that triggered my idea)
created = datetime.strptime(r.json()[x]["created_at"], "%a %b %d %H:%M:%S +0000 %Y")
works just fine!
I would use the parse function provided by Delorean for future dealings with strptime e.g
>>> from delorean import parse
>>> parse("2011/01/01 00:00:00 -0700")
Delorean(datetime=2011-01-01 07:00:00+00:00, timezone=UTC)
It accepts a wide range of string input as well as take into account different timezones and provides easy mechanisms for shifting, to retrieve the required datetime object simple .datetime on the delorean object.