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How do I print certain elements of a list for example:
list1=["0","0","0","0","0","0","Element1","0","0","0","0"]
Is there any simple way to print only Element1 that specifies that you should not print out anything that is equal to 0.
Use a list comprehension or (as in this example) a generator expression to filter out the "0" items, and loop through the filtered list:
for item in (x for x in list1 if x != "0"):
print(item)
This prints all items that are not "0".
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How to select the previous number in list comprehension that starts from the second one?
The formula is [w(j-1)* 5 +w for t in y]?
w(j-1) is the first number in list.
Not exactly sure what you are trying to achieve. Therefore, my own interpretation of the problem. Assume you have a list of numbers:
my_list = range(1, 10)
Now we want to iterate over this list starting from the second entry and also access the previous entry:
new_list = [my_list[i - 1]*5 + my_list[i] for i, n in enumerate(my_list) if i > 0]
print(new_list)
This way you can get access to a list element and its predecessor.
Is this what you are trying to achieve?
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How can I find an element or his index in a list by a few characters of it?
For Example:
x = input()
list = ['alberto', 'kari', 'mino']
#now I want to find the element, which starts or contain x (for exampke x = 'albe')
#the next similir element should be found
#and then remove it
for item in list:
If 'alb' in item:
Item.pop()
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If I have a list of elements such as:
items = ["058529-08704-200280", "058529-08704-230330", "058529-08704-140200", "058529-08704-290390",
"058529-08705-140200", "058529-08705-230330", "058529-08704-170240", "058529-08705-290390",
"058529-08705-170240"]
I want to keep the elements with the smallest number after the second " - ". However, they must be compared with the elements which have the same first two numbers in the string.
For e.g. the strings which start with 058529-08704, the smallest number is 058529-08704-140200 and for 058529-08705, the smallest number is 058529-08705-140200
So the final list must end up with ["058529-08704-140200", "058529-08705-140200"].
What is the most pythonic way to achieve this instead of having to write multiple ifs or using string manipulation?
items = ["058529-08704-200280", "058529-08704-230330", "058529-08704-140200", "058529-08704-290390",
"058529-08705-140200", "058529-08705-230330", "058529-08704-170240", "058529-08705-290390",
"058529-08705-170240"]
lst_3th_num = []
for item in items:
lst_3th_num.append(int(item.split('-')[2]))
result = []
for item in items:
if int(item.split('-')[2]) == min(int(s) for s in lst_3th_num):
result.append(item)
print(result)
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I have a list composed of integers, and I would like to do this :
freeSushi = max(sushiPrices <= sushiPrice)
sushiPrice being an integer and sushiPrices being a list.
Any idea of how I can do this ?
You can use filter before applying max
max(filter(lambda price: price <= sushiPrice, sushiPrices)
This would work, if "something" was a list of prices less than or equal to sushiPrice:
freeSushi = max(something)
So how can we create a list of prices less than sushiPrice? Comprehend?
Use a for loop like so:
for i in sushiPrices:
if i > sushiPrice:
del sushiPrices[sushiPrices.index(i)]
freeSushi = max(sushiPrices)
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In the following code, when I create list A and then separate it with list C, then I cannot add list D
a=11
b=21
A=[]
n=10
for y in range (11,b):
for x in range (1,a):
A.append(x*y)
for i in range (a-1):
C=A[i*n:(i+1)*n]
D=A[i*n]
print(D+C)
As far as I can see:
C is a list, while D is an element from list A unless A is a list of lists.
You can do
D=[A[i*n]]
That will make D a list of single element