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I have a list composed of integers, and I would like to do this :
freeSushi = max(sushiPrices <= sushiPrice)
sushiPrice being an integer and sushiPrices being a list.
Any idea of how I can do this ?
You can use filter before applying max
max(filter(lambda price: price <= sushiPrice, sushiPrices)
This would work, if "something" was a list of prices less than or equal to sushiPrice:
freeSushi = max(something)
So how can we create a list of prices less than sushiPrice? Comprehend?
Use a for loop like so:
for i in sushiPrices:
if i > sushiPrice:
del sushiPrices[sushiPrices.index(i)]
freeSushi = max(sushiPrices)
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I want to append the number in A to 5 if it is more than 5.
A = [1,2,3,4,5,6,7,8,9,10]
To something like this:
A = [1,2,3,4,5,5,5,5,5,5]
You can try using map
A = [1,2,3,4,5,6,7,8,9,10]
list(map(lambda x: x if x<5 else 5, A))
You can use the min function to take the smaller of each list item and 5:
[min(i, 5) for i in A]
Demo: https://replit.com/#blhsing/InsidiousDigitalIntegrationtesting
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def thing():
_list = [1,1,5,6,8,3,4,6,10,23,5,12,67,3,25,2,6,5,4,3,2,1]
_list1 = [str(i) for i<=5 in lista]
return " ".join(_list1)
print(thing()))
I am new to this type of list managment, I am trying to put in _list1 only integers that are less then 5
so like the name of your function, it's created to calculate the sum of integers.
So basically, if your n=0 then your program will return 0 as result.
If not (else), it gonna give you a result of the calculation in return.
And here you want to print the interger sum of 451 which will give you the result of n % 10 + integer_sum(int(n / 10))
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How can I find an element or his index in a list by a few characters of it?
For Example:
x = input()
list = ['alberto', 'kari', 'mino']
#now I want to find the element, which starts or contain x (for exampke x = 'albe')
#the next similir element should be found
#and then remove it
for item in list:
If 'alb' in item:
Item.pop()
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Given:
a=np.array([[-0.00365169, -1.96455717, 1.44163783, 0.52460176, 2.21493637],
[-1.05303533, -0.7106505, 0.47988974, 0.73436447, -0.87708389],
[-0.76841759, 0.8405524, 0.91184575, -0.70652033, 0.37646991]])
I would like to get the maximum subset (in this case, the first row):
[-0.00365169, -1.96455717, 1.44163783, 0.52460176, 2.21493637]
By using print(np.amax(a, axis=0)), I'm getting the wrong result:
[-0.00365169 0.8405524 1.44163783 0.73436447 2.21493637]
How can we get the correct maximum subset?
You can sum along columns and then find the index with the maximum value with argmax:
a[np.argmax(a.sum(axis=1))]
If you make some change:
a=np.array([[-0.00365169, -10.96455717, 1.44163783, 0.52460176, 2.21493637],
[-1.05303533, -0.7106505, 0.47988974, 0.73436447, -0.87708389],
[-0.76841759, 0.8405524, 0.91184575, -0.70652033, 0.37646991]])
The solution will be not right:
a[np.argmax(a.sum(axis=1))]
Try this:
arr = np.where(a == np.amax(a, axis=0))[0]
counts = np.unique(arr)
ind = np.argmax(counts)
print(a[arr[ind]])
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How do I print certain elements of a list for example:
list1=["0","0","0","0","0","0","Element1","0","0","0","0"]
Is there any simple way to print only Element1 that specifies that you should not print out anything that is equal to 0.
Use a list comprehension or (as in this example) a generator expression to filter out the "0" items, and loop through the filtered list:
for item in (x for x in list1 if x != "0"):
print(item)
This prints all items that are not "0".