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I am a python student, and I have a problem [closed]

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def thing():
_list = [1,1,5,6,8,3,4,6,10,23,5,12,67,3,25,2,6,5,4,3,2,1]
_list1 = [str(i) for i<=5 in lista]
return " ".join(_list1)
print(thing()))
I am new to this type of list managment, I am trying to put in _list1 only integers that are less then 5

so like the name of your function, it's created to calculate the sum of integers.
So basically, if your n=0 then your program will return 0 as result.
If not (else), it gonna give you a result of the calculation in return.
And here you want to print the interger sum of 451 which will give you the result of n % 10 + integer_sum(int(n / 10))

How to make all numbers in a list of lists into just ints [closed]

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Say I have
A = [[1.0,2.3,1.1],[2.2,1.3,3.2]]
and I want to cast all of those numbers into just ints to have
A = [[1,2,1],[2,1,3]]
How do we do that in python?

Try list comprehension*2:
print([[int(x) for x in i] for i in A])
Or list comprehension + map:
print([list(map(int,i)) for i in A])
Or map+map:
print(list(map(lambda x: list(map(int,x)),A)))
Simple ways all return:
[[1,2,1],[2,1,3]]

Here's an approach using a list comprehension and map:
A = [[1.0,2.3,1.1],[2.2,1.3,3.2]]
print([list(map(int, i)) for i in A])

max() function on list with an integrer [closed]

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I have a list composed of integers, and I would like to do this :
freeSushi = max(sushiPrices <= sushiPrice)
sushiPrice being an integer and sushiPrices being a list.
Any idea of how I can do this ?

You can use filter before applying max
max(filter(lambda price: price <= sushiPrice, sushiPrices)

This would work, if "something" was a list of prices less than or equal to sushiPrice:
freeSushi = max(something)
So how can we create a list of prices less than sushiPrice? Comprehend?

Use a for loop like so:
for i in sushiPrices:
if i > sushiPrice:
del sushiPrices[sushiPrices.index(i)]
freeSushi = max(sushiPrices)

Recursive sequence $x_n = \sqrt{2}$, $x_{n+1} = \sqrt{2x_n}$ [closed]

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How would I create a script it in python late the values from the recursive sequence:
$x_1 = \sqrt{2}$, $x_{n+1} = \sqrt{2x_n}$ http://www.sciweavers.org/upload/Tex2Img_1392861864/render.png

X = [sqrt(2)]
for i in range(1,10):
X.append(sqrt(2*X[i-1]))

Here is a slow solution. Assuming n is >=1
import math
def recursive(n):
if n = 1:
math.sqrt(2)
return math.sqrt(2*recursive(n-1))

Split elements in a list in Python [closed]

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My code is :
L=['my', 'my']
and I want to split the items of this list so that the output becomes:
['my'],['my']
each item in a new list

Something like this, use a list comprehension:
In [109]: L=['my', 'my']
In [110]: [[x] for x in L]
Out[110]: [['my'], ['my']]
or may you wanted this:
In [129]: print ",".join(str(x) for x in [[x] for x in L] )
['my'],['my']
In [130]: print ",".join("[{0}]".format(x) for x in L)
[my],[my]