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Append the values if it is more than something [closed]

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I want to append the number in A to 5 if it is more than 5.
A = [1,2,3,4,5,6,7,8,9,10]
To something like this:
A = [1,2,3,4,5,5,5,5,5,5]

You can try using map
A = [1,2,3,4,5,6,7,8,9,10]
list(map(lambda x: x if x<5 else 5, A))

You can use the min function to take the smaller of each list item and 5:
[min(i, 5) for i in A]
Demo: https://replit.com/#blhsing/InsidiousDigitalIntegrationtesting

How can I add same text to each item of the list? [closed]

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I have the following list:
a=['c1','c2','c3']
And I would like to get to:
b=[sametext['c1'],sametext['c2'],sametext['c3']]
I've tried to make list in list but I'm not able to get any result? How can I get to b?

In [sametext['c1'],sametext['c2'],sametext['c3']], is sametext a dictionary which contains a mapping of some sort?
If that's the case then the way to do it will be with this list comprehension:
b = [sametext[x] for x in a]
Without list comprehensions:
b=[]
for x in a:
b.append(sametext[x])
If by sametext all you mean is some constant operation, like adding a prefix then similar to the first approach the way would be:
b = [f"yourprefix_{x}]" for x in a]

b= [ele+'some_text' for ele in a]
To make change in-place
a[:] = [ele+'some_text' for ele in a]

The output for floats in list of tuples [closed]

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I have the list of sorted tuples, containing floats. But when I try to output the floats (without commas and brackets) it output separate tuples BUT with brackets and commas, which I do not need.
This is the part of the code:
data=[tuple1, tuple2, tuple3, tuple4]
a=sorted(data, key = lambda x: (x[0], x[1]))
b="\n".join(map(str,a))
print(b)

try this:
data=[tuple1, tuple2, tuple3, tuple4]
s=''
for i in range(len(a)):
for j in a[i]:
s += str(j)
print(s)

Try this:
print('\n'.join(' '.join(map(str, x)) for x in a))

How to make all numbers in a list of lists into just ints [closed]

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Say I have
A = [[1.0,2.3,1.1],[2.2,1.3,3.2]]
and I want to cast all of those numbers into just ints to have
A = [[1,2,1],[2,1,3]]
How do we do that in python?

Try list comprehension*2:
print([[int(x) for x in i] for i in A])
Or list comprehension + map:
print([list(map(int,i)) for i in A])
Or map+map:
print(list(map(lambda x: list(map(int,x)),A)))
Simple ways all return:
[[1,2,1],[2,1,3]]

Here's an approach using a list comprehension and map:
A = [[1.0,2.3,1.1],[2.2,1.3,3.2]]
print([list(map(int, i)) for i in A])

Python using str as bytearray [closed]

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I'm trying to implement a Reed-Solomon encoder.
I start with a list of bytearray and then I have to convert all the elements of the list into str.
So now I have this list: ["bytearray(b'XXXXXXX')"]
But I have to retrieve the value from the list: "bytearray(b'XXXXXXX')" as a bytearray: bytearray(b'XXXXXXX')...
How can I perform this conversion?

I don't think you're doing it right...
If you want to convert all list elements to str, you'd use the bytearray.decode method:
In [10]: lst = [bytearray(b'XXXXXXX')]
In [11]: newlst = [x.decode('ascii') for x in lst]
In [12]: newlst
Out[12]: ['XXXXXXX']
And the reverse of that is
In [13]: [bytearray(s, 'ascii') for s in newlst]
Out[13]: [bytearray(b'XXXXXXX')]