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I need help on a python guessing game

I need help changing the range and showing the user what the range is so they know if they are closer or not. I have given the description I have been given. On what I need to do . I have given the code that I have come up wit so far. Let me know if you need anything else from me.
Step 6 – Guiding the user with the range of values to select between
Add functionality so that when displaying the guess prompt it will display the current range
to guess between based on the user’s guesses accounting for values that are too high and too
low. It will start out by stating What is your guess between 1 and 100, inclusive?, but as
the user guesses the range will become smaller and smaller based on the value being higher
or lower than what the user guessed, e.g., What is your guess between 15 and 32,
inclusive? The example output below should help clarify.
EXAMPLE
----------------
What is your guess between 1 and 44 inclusive? 2
Your guess was too low. Guess again.
import random
import sys
def main():
print("Assignment 6 BY enter name.")
welcome()
play()
#Part 1
def welcome():
print("Welcome to the guessing game. I have selected a number between 1 and 100 inclusive. ")
print("Your goal is to guess it in as few guesses as possible. Let’s get started.")
print("\n")
def play():
''' Plays a guessing game'''
number = int(random.randrange(1,10))
guess = int(input("What is your guess between 1 and 10 inclusive ?: "))
number_of_guess = 0
while guess != number :
(number)
#Quit
if guess == -999:
print("Thanks for Playing")
sys.exit(0)
#Guessing
if guess < number:
if guess < number:
guess = int(input("Your guess was too low. Guess Again: "))
number_of_guess += 1
elif guess not in range(1,11):
print("Invalid guess – out of range. Guess doesn’t count. : ")
guess = int(input("Guess Again: "))
else:
guess = input("Soemthing went wrong guess again: ")
if guess > number:
if guess > number:
guess = int(input("Your guess was too high. Guess Again: "))
number_of_guess += 1
elif guess not in range(1,11):
print("Invalid guess – out of range. Guess doesn’t count. : ")
guess = int(input("Guess Again: "))
else:
guess = input("Soemthing went wrong guess again: ")
#Winner
if guess == number :
number_of_guess += 1
print("Congratulations you won in " + str(number_of_guess) + " tries!")
again()
def again():
''' Prompts users if they want to go again'''
redo = input("Do you want to play again (Y or N)?: ")
if redo.upper() == "Y":
print("OK. Let’s play again.")
play()
elif redo.upper() == "N":
print("OK. Have a good day.")
sys.exit(0)
else:
print("I’m sorry, I do not understand that answer.")
again()
main()

What you'll need is a place to hold the user's lowest and highest guess. Then you'd use those for the range checks, instead of the hardcoded 1 and 11. With each guess, if it's a valid one, you then would compare it to the lowest and highest values, and if it's lower than the lowest then it sets the lowest value to the guess, and if it's higher than the highest it'll set the highest value to the guess. Lastly you'll need to update the input() string to display the lowest and highest guesses instead of a hardcoded '1' and '10'.

You need to simplify a lot your code. Like there is about 6 different places where you ask a new value, there sould be only one, also don't call method recursivly (call again() in again()) and such call between again>play>again.
Use an outer while loop to run games, and inside it an inner while loop for the game, and most important keep track of lower_bound and upper_bound
import random
import sys
def main():
print("Assignment 6 BY enter name.")
welcome()
redo = "Y"
while redo.upper() == "Y":
print("Let’s play")
play()
redo = input("Do you want to play again (Y or N)?: ")
def welcome():
print("Welcome to the guessing game. I have selected a number between 1 and 100 inclusive. ")
print("Your goal is to guess it in as few guesses as possible. Let’s get started.\n")
def play():
lower_bound, upper_bound = 0, 100
number = int(random.randrange(lower_bound, upper_bound))
print(number)
guess = -1
number_of_guess = 0
while guess != number:
guess = int(input(f"What is your guess between {lower_bound} and {upper_bound - 1} inclusive ?: "))
if guess == -999:
print("Thanks for Playing")
sys.exit(0)
elif guess not in list(range(lower_bound, upper_bound)):
print("You're outside the range")
continue
number_of_guess += 1
if guess < number:
print("Your guess was too low")
lower_bound = guess
elif guess > number:
print("Your guess was too high")
upper_bound = guess
print("Congratulations you won in", number_of_guess, "tries!")

Python while loop number guessing game with limited guesses

For a class assignment, I'm trying to make a number guessing game in which the user decides the answer and the number of guesses and then guesses the number within those limited number of turns. I'm supposed to use a while loop with an and operator, and can't use break. However, my issue is that I'm not sure how to format the program so that when the maximum number of turns is reached the program doesn't print hints (higher/lower), but rather only tells you you've lost/what the answer was. It doesn't work specifically if I choose to make the max number of guesses 1. Instead of just printing " You lose; the number was __", it also prints a hint as well. This is my best attempt that comes close to doing everything that this program is supposed to do. What am I doing wrong?
answer = int(input("What should the answer be? "))
guesses = int(input("How many guesses? "))
guess_count = 0
guess = int(input("Guess a number: "))
guess_count += 1
if answer < guess:
print("The number is lower than that.")
elif answer > guess:
print("The number is higher than that")
while guess != answer and guess_count < guesses:
guess = int(input("Guess a number: "))
guess_count += 1
if answer < guess:
print("The number is lower than that.")
elif answer > guess:
print("The number is higher than that")
if guess_count >= guesses and guess != answer:
print("You lose; the number was " + str(answer) + ".")
if guess == answer:
print("You win!")

What about something like this?
answer = int(input("What should the answer be? "))
guesses = int(input("How many guesses? "))
guess_count = 1
guess_correct = False
while guess_correct is False:
if guess_count < guesses:
guess = int(input("Guess a number: "))
if answer < guess:
print("The number is lower than that.")
elif answer > guess:
print("The number is higher than that")
else: # answer == guess
print("You win!")
break
guess_count += 1
elif guess_count == guesses:
guess = int(input("Guess a number: "))
if guess != answer:
print("You lose; the number was " + str(answer) + ".")
if guess == answer:
print("You win!")
break
It's very similar to your program, but has a couple break statements in there. This tells Python to immediately stop execution of that loop and go to the next block of code (nothing in this case). In this way you don't have to wait for the program to evaluate the conditions you specify for your while loop before starting the next loop. If this helped solve your problem, it'd be great of you to click the checkmark by my post

basic looping in Python

New to this so please bear with me. I'm trying to run a loop that asks the user to input a number between 1 and 100. I want to make it to where if they enter a number outside of 100 it asks again. I was able to do so but I can't figure out if I'm using the correct loop. Also whenever I do get inbetween 1 and 100 the loop continues.
code below:
user_input = int(input("Enter a number between 1 and 100: "))
if user_input >= 1 and user_input <= 100:
print("NICE!")
else:
while user_input > 100:
try_again = int(input("try again "))
if try_again >= 1 and try_again <= 100:
print("There you go!")

I think the clearest way to do this is to start with a loop that you break out of when you finally get the right answer. Be sure to handle a bad input like "fubar" that isn't an integer
while True:
try:
user_input = int(input("Enter a number between 1 and 100: "))
if user_input >= 1 and user_input <= 100:
print("NICE!")
break
print("Not between 1 and 100, try again")
except ValueError:
print("Not a number, try again")
In python 3 you can use range to do bounds checking. If you do
if user_input in range(1, 101)
range will calculate the result without actually generating all of the numbers.

When your code is run, it will continue to ask for an input, even if the input given is less than 100. One way to fix this would be to do this:
try_again = 1000
user_input = int(input("Enter a number between 1 and 100: "))
if user_input >= 1 and user_input <= 100:
print("NICE!")
elif user_input > 100:
while try_again > 100:
try_again = int(input("try again "))
if try_again >= 1 and try_again <= 100:
print("There you go!")
This code first tests if the user's input is more than 100, then runs a while statement in which the base value is more than 100. When the user inputs another value, if it is over 100, it continues, otherwise it does not.

Below is an example of a program that gets you the output that you are seeking:
attempts = 0
while True:
user_input = int(input("Enter a number between 1 and 100: "))
if user_input > 100 or user_input < 1:
print('Please try again')
attempts += 1
continue
elif attempts >= 1 and user_input <= 100 and user_input >= 1:
print('There you go!')
break
else:
print('Nice!')
break
Start by putting your prompt for the user within the loop so that the user can be asked the same prompt if the fail to enter a number between 1 and 100 the first time. If the user input is greater than 100 or less than 1, we will tell the user to try again, we will add 1 to attempts and we will add a continue statement which starts the code again at the top of the while loop. Next we add an elif statement. If they've already attempted the prompt and failed (attempts >= 1) and if the new input is less than or equal to 100 AND the user input is also greater than or equal to 1, then the user will get the 'There you go' message that you assigned to them. Then we will break out of the loop with a break statement in order to avoid an infinite loop. Lastly we add an else statement. If the user satisfies the prior conditions on the first attempt, we will print 'Nice' and simply break out of the loop.

Python Guessing Game Reject Invalid User Input

I'm taking my first-ever Python class and, like most Python classes, the last assignment is to create a guessing game from 1-100 that tracks the number of VALID tries. The element that I just cannot get (or find here on stackoverflow) is how to reject invalid user input. The user input must be whole, positive digits between 1 and 100. I can get the system to reject everything except 0 and <+ 101.
The only things I can think to do end up telling me that you can't have operators comparing strings and integers. I keep wanting to use something like guess > 0 and/or guess < 101. I've also tried to create some sort of function, but can't get it to work right.
# Generate random number
import random
x = random.randint(1,100)
# Prompt user for input
print("I'm thinking of a number from 1 to 100")
counter = 0
while True:
guess = input("Try to guess my number: ")
# Check if input is a positive integer and is not 0 or >=101
# this line doesn't actually stop it from being a valid guess and
# counting against the number of tries.
if guess == "0":
print(guess, "is not a valid guess")
if guess.isdigit() == False:
print(guess, "is not a valid guess")
else:
counter += 1
guess = int(guess)
# Begin playing
if guess > x:
print(guess, "is too high.")
elif guess < x:
print(guess, "is too low.")
else:
print(guess, "is correct! You guessed my number in", counter, "tries!")

import random
x = random.randint(1,100)
# Prompt user for input
print("I'm thinking of a number from 1 to 100")
counter = 0
while True:
guess = input("Try to guess my number: ")
try:
guess = int(guess)
if(100 > guess > 0):
counter += 1
guess = int(guess)
# Begin playing
if guess > x:
print(guess, "is too high.")
elif guess < x:
print(guess, "is too low.")
else:
print(guess, "is correct! You guessed my number in", counter, "tries!")
break
else:
print("Number not in range between 0 to 100")
except:
print("Invalid input")

# Generate random number
import random
x = random.randint(1,100)
# Prompt user for input
print("I'm thinking of a number from 1 to 100")
counter = 1
while True:
try:
guess = int(input("Try to guess my number: "))
if guess > 0 and guess < 101:
print("That's not an option!")
# Begin playing
elif guess == x:
print(guess, "is correct! You guessed my number in", counter, "tries!")
break
elif guess > x:
print(guess, "is too high.")
elif guess < x:
print(guess, "is too low.")
else:
counter += 1
except:
print("That's not a valid option!")

My instructor helped me out. (I posted to keep from needing that from the guy who's giving me the grade.) Here is what we came up with. I'm posting it to help out any future Python learner that may have this particular rejecting user input problem.
Thank you guys for posting SO FAST! Even though I needed the instructor's help, I would've looked even more incompetent without your insights. Now I can actually enjoy my holiday weekend. Have a great Memorial Day weekend!!!
import random
x = random.randint(1,100)
print("I'm thinking of a number from 1 to 100.")
counter = 0
while True:
try:
guess = input("Try to guess my number: ")
guess = int(guess)
if guess < 1 or guess > 100:
raise ValueError()
counter += 1
if guess > x:
print(guess, "is too high.")
elif guess < x:
print(guess, "is too low.")
else:
print(guess, "is correct! You guessed my number in", counter, "tries!")
break
except ValueError:
print(guess, "is not a valid guess")

I'm trying to write a number guessing game in python but my program isn't working

The program is supposed to randomly generate a number between 1 and 10 (inclusive) and ask the user to guess the number. If they get it wrong, they can guess again until they get it right. If they guess right, the program is supposed to congratulate them.
This is what I have and it doesn't work. I enter a number between 1 and 10 and there is no congratulations. When I enter a negative number, nothing happens.
import random
number = random.randint(1,10)
print "The computer will generate a random number between 1 and 10. Try to guess the number!"
guess = int(raw_input("Guess a number: "))
while guess != number:
if guess >= 1 and guess <= 10:
print "Sorry, you are wrong."
guess = int(raw_input("Guess another number: "))
elif guess <= 0 and guess >= 11:
print "That is not an integer between 1 and 10 (inclusive)."
guess = int(raw_input("Guess another number: "))
elif guess == number:
print "Congratulations! You guessed correctly!"

Just move the congratulations message outside the loop. You can then also only have one guess input in the loop. The following should work:
while guess != number:
if guess >= 1 and guess <= 10:
print "Sorry, you are wrong."
else:
print "That is not an integer between 1 and 10 (inclusive)."
guess = int(raw_input("Guess another number: "))
print "Congratulations! You guessed correctly!"

The problem is that in a if/elif chain, it evaluates them from top to bottom.
Move the last condition up.
if guess == number:
..
elif other conditions.
Also you need to change your while loop to allow it to enter in the first time. eg.
while True:
guess = int(raw_input("Guess a number: "))
if guess == number:
..
then break whenever you have a condition to end the game.

The problem is that you exit the while loop if the condition of guessing correctly is true. The way I suggest to fix this is to move the congratulations to outside the while loop
import random
number = random.randint(1,10)
print "The computer will generate a random number between 1 and 10. Try to guess the number!"
guess = int(raw_input("Guess a number: "))
while guess != number:
if guess >= 1 and guess <= 10:
print "Sorry, you are wrong."
guess = int(raw_input("Guess another number: "))
elif guess <= 0 and guess >= 11:
print "That is not an integer between 1 and 10 (inclusive)."
guess = int(raw_input("Guess another number: "))
if guess == number:
print "Congratulations! You guessed correctly!"