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python: Django Page not found (404)

app urls.py
from django.urls import path
from . import views
urlpatterns = [
path('hello', views.index, name='index')
]
project urls.py
from django.contrib import admin
from django.urls import include, path
urlpatterns = [
path('admin/', admin.site.urls),
path('hello/', include("hello.urls"))
]
views.py
from django.http import HttpResponse
from django.shortcuts import render
# Create your views here.
def index(request):
return HttpResponse("Hello, World!")
I've re-watched the tutorial several times and still can't find the error.

Since your project's urls.py includes hello using the prefix 'hello/' in
path('hello/', include("hello.urls"))
and your app's urls.py also has hello as the path in
path('hello', views.index, name='index')
you will need to access /hello/hello in your browser to get to a view that doesn't 404.
Django's technical 404 page (the one with the yellow background) should show the available paths -- if you don't get the technical 404 page, ensure you have the DEBUG setting turned on.

How to Change Django Default Page to your Design?

I uploaded my site to the live server, but still, I am seeing Django default page, I updated my urls.py file, but still, it's not working. and it's showing me this output. Please let me know where I am Mistaking.
I am trying to access this mydomain.com/dashboard
Using the URLconf defined in yoursite.urls, Django tried these URL patterns, in this order:
admin/
The current path, dashboard, didn't match any of these.
here is my urls.py file...
urlpatterns = [
path('admin/', admin.site.urls),
url(r'^dashboard/', include('dashboard.urls')),
url(r'^accounts/', include('accounts.urls')),
url('', include('frontpanel.urls')),
path('', views.index, name='index'),
]+ static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
And here is my views.py file...
def index(request):
category = Category.objects.all().order_by('created_at')
return render(request, "base.html", {'category':category})

What version of Django are you using?
Try changing url to re_path (remember to import it first). I think url has been deprecated.

After Analyzing the question u never mentioned ur app urls.py you only mentioned project urls.py . As u have url(r'^dashboard/', include('dashboard.urls')), in ur project urls.py, there must be a file in your app also named urls.py which handles urls having prefix /dashboard/ , by default django doesnt make that file you need to manually make it add ur function names to redirect . For example this is my main urls.py file
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path('display_report/', include("display_report.urls"))
]
then u have to make a file named urls.py in ur app also to handle the requests and redirect the the approaite functions , in my display_report app i made a urls.py that looks like this
from django.contrib import admin
from django.urls import path, include
from display_report import views
from django.conf.urls.static import static
from django.conf import settings
urlpatterns = [path('', views.index)]
And then it will redirect to function named index in ur views.py file inside ur app
from django.shortcuts import render, redirect, HttpResponse
# from .models import Employee, Tasks, Report, Fileupload, Fileuploadnext
from django.views.decorators.csrf import csrf_exempt
# Create your views here.
def index(request):
return render(request."index.html")
Here my ur will be mydomain.com/display_report and my index.html file will be inside the template folder

Path cannot be found in django

I am working on a django project. The project includes 2 apps namely jobs and blog. The url.py of the main project file is:
from django.contrib import admin
from django.urls import path,include
from django.conf import settings
from django.conf.urls.static import static
import jobs.views
urlpatterns = [
path('admin/', admin.site.urls),
path('', jobs.views.home, name= 'home'),
path('blog/', include('blog.urls'))
] + static(settings.MEDIA_URL, document_root = settings.MEDIA_ROOT)
You can understand that I am calling the output of the jobs in the home. The url.py of the blog is:
from django.urls import path
from . import views
urlpatterns = [
path('', views.allblogs, name= 'allblogs'),
]
and the views.py of the blog is:
from django.shortcuts import render
def allblogs(request):
return render(request, 'blog/allblogs.html')
This gives an error that the blog/ can not be found. I must mention I make a allblogs.html in the address project/blog/templates/blog The webpage shows that it tries to find the page in this ditrectory: ...project\jobs\templates\blog\allblogs.html
The error message is:
TemplateDoesNotExist at /blog/
Request URL: http://localhost:8000/blog/
Exception Type: TemplateDoesNotExist
I dont know why it is trying to find it in jobs where it should search for it in blogs folder.
Can someone help? May be I have done something silly..

How to avoid Page 404 Error on my first app

I am following this tutorial.
https://www.youtube.com/watch?v=a48xeeo5Vnk
Here is my code for views:
from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.
def home(request):
return HttpResponse('<h1>This is our blog</h1>')
def about(request):
return HttpResponse('<h1>This is our About Page</h1>')
def next(request):
return HttpResponse('<h1>This is our next Page</h1>')
This is my App urls page code
from django.urls import path
from . import views
urlpatterns = [
path('', views.home, name='blog-home'),
path('about/', views.about, name='blog-about'),
path('next/', views.next, name='blog-NEXT'),
]
This is my main project URL code
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('firstapp', include('firstapp.urls')),
path('admin/', admin.site.urls),
]
Now when I try this with only single view i.e default page '', it works alone, with no more pages mentioned in code, however when I add more views it gives me a 404 page error. I believe the code is fine and it shoud work, but somehow it chose not to.
Tried different browser, tried forums but nothing.
Here is the error.
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/firstapp/
Using the URLconf defined in first.urls, Django tried these URL patterns, in this order:
firstapp [name='blog-home']
firstapp about/ [name='blog-about']
firstapp next/ [name='blog-NEXT']
admin/
The current path, firstapp/, didn't match any of these.
Any assistance would be appreciated.

Do below changes
from:
path('firstapp', include('firstapp.urls')),
to:
path('firstapp/', include('firstapp.urls')),

my url in django doesn't return HTTPResponse?

there is a problem with a url i've created in django that it doesn't totally work
this is urls.py
from django.conf.urls import include, url
from django.contrib import admin
from pizza import views
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url('', views.home,name='home'),
url('order/', views.order,name='order'),
]
and this is views.py
from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.
def home(request):
return HttpResponse("Home page")
def order(request):
return HttpResponse("Order a pizza page")

That is incorrect syntax, try using path('') instead of url

If pizza it's your app you must use:
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('pizza/', include('pizza.urls')),
]
in urls.py and add your app in settings.py inside INSTALLED_APPS
OR
If when you call from pizza import views is the name of Project you should import as import .views only

Update in project urls.py file.