How can you hide letters in a word with an asterisk? - python

I am currently working on a hangman project. I am having problems with hiding characters in words with asterisks - like, "word" would be ****, then when the player makes a guess and it's correct, the letter would appear where it should be, instead of the asterisk, like if you guessed 'o', *o**. How can I do this?
This is my current code.
import random
start = 1
class hangman():
def __init__(self):
self.__word = word
self.__incorrectg = none
word = random.choice(open(input("please type the file you wish to open ")).readlines())
print (word)
lettercount = len([ltr for ltr in word if ltr.isalpha()])
print (lettercount)

If you stored the players guesses in a list for instance:
used_letters = [] # and append guesses to this, both right and wrong
so as soon as the user inputs a guess, you append it to used_letters.
with open(filepath) as f: # this might be a better way to open the file
word = random.choice(f.readlines()) # after this statement the file is auto closed, and frees up the memory
and you have the actual word stored as a list as in:
word = list(word) #made into a list of the letters in the word
then you could do something like:
guessed_string = ''.join(letter if letter in used_letters else '*' for letter in the_word)
EDIT:
#prints out the starred string. i.e. unguessed letters are '*' and guessed letters that appear in the word appear as normal letters.
print guessed_string
let me know if this works for you.
Example:
if word = 'arbitrary'
word = list(word) gives:
['a','r','b','i','t','r','a','r','y']
if the user has so far guessed:
used_letters = ['a', 'b', 'e', 'r']
then
guessed_string = ''.join(letter if letter in used_letters else '*' for letter in word)
print guessed_string
will give:
'arb**rar*'

value="C9T1573518"
new_value=value[0:3]
new_value+="".join(value[l].replace(value[l],"*") for l in range(3,len(value),1))
print(
new_value
)

#!/usr/bin
def password(word):
class __password:
def __repr__(self):
return "*" * len(word)
return __password()
word = password("Mypassword123")
print word
Took a while but I was finally able to get it:
#!/usr/bin
def password(word):
external_repr = set()
class __password:
def __repr__(self):
return ''.join(word[i] if word[i] in external_repr else '*' for i in xrange(len(word)))
def __eq__(self, somestring):
return word == somestring
def guess(self, letter):
external_repr.add(letter[0])
def encrypt(self):
return "*" * len(word)
return __password()
word = password("Mypassword123")
if word == "Mypassword123": print "Passwords match!"
print "The encrypted password is", word.encrypt()
word.guess('s')
print "After your guess, the word is now", word

Related

Why doesn’t my Python code show output in Visual Studio Code?

import random
from words import words
import string
def get_valid_word(word):
word = random.choice(words)
while '-' in word or ' ' in word:
word = random.choice(words)
return word
def hangman():
word = get_valid_word(words)
word_letters = set(word) # letters in word
alphabet = set(string.ascii_uppercase)
used_letters = set()
user_input = ("type something: ")
print(user_input)
I have been following along a YouTube python project, but when I use the import function the code doesn't seem to run. It executes nothing and says its done.
Because you never called hangman():
If you are using a script try this at the end of script:
if __name__ = "__main__":
hangman()
Otherwise, just call hangman() at the end.
A function is a block of code that will only run when it has been called upon. You have declared two functions but never called them, therefore they cannot run. To fix this, simply call the functions like this:
hangman()
get_valid_word()
Add this to the very bottom of your code without an indent so that the compiler knows that is the main code. You should have something looking like this:
import random
from words import words
import string
def get_valid_word(word):
word = random.choice(words)
while '-' in word or ' ' in word:
word = random.choice(words)
return word
def hangman():
word = get_valid_word(words)
word_letters = set(word) # letters in word
alphabet = set(string.ascii_uppercase)
used_letters = set()
user_input = ("type something: ")
print(user_input)
hangman()
get_valid_word()

Python Urllib game of guessing words

I've been struggling as I wanted to try the hanged man game on python :
For those who don't know the game, you basically need to guess all the letters of a word (with a limited number of attempts previously announced).
What's difficult, is that I want each guessed letters to appear on the spare parts of the word to guess and the already used letters to be mentionned as well.
And as we've already decided the number of attempts allowed (let's say 10), I want to try to show the remaining attempts left !!
Here's what I've done already (the generate random words) but I'm stuck :
import urllib
response = urllib.request.urlopen('https://random-word-api.herokuapp.com/word?number=1')
word =response.read().decode('utf-8').strip('[\"]')
print(word)
Many thanks for your help.
This worked fine!
import requests
from typing import List
def get_random_word() -> str:
url:str = 'https://random-word-api.herokuapp.com/word?number=1'
response:requests.Response = requests.get(url)
if response.status_code == 200:
word = response.text.strip('[\"]')
return word
else:
print("Impossible to connect!")
def open_letters_in_hidden_word(word:str, hidden_word:str, letter:str) -> str:
hidden_word:List[str] = list(hidden_word)
for index, word_letter in enumerate(word):
if word_letter == letter:
hidden_word[index] = word_letter
hidden_word:str = ''.join(hidden_word)
return hidden_word
def start_game():
# Loading word from server
word:str = get_random_word()
attempts:int = 10
hidden_word:str = '-' * len(word)
while attempts:
print(f"Attempts left: {attempts}")
print(f"Word: {hidden_word}")
letter:str = input("Enter letter: ")
if letter in word:
hidden_word:str = open_letters_in_hidden_word(word, hidden_word, letter)
else:
print("Failed attempt!")
attempts -= 1
if not attempts:
print(f"You lose! Word: {word}")
return
if word == hidden_word:
print(f"You won! Word: {word}")
return
if __name__ == "__main__":
start_game()

infinite loop in Hangman game in Python

I am trying to build a simple Hangman game, but the following program is creating an infinite loop when the letter entered by the user is not part of the word to guess (it's printing "*" indefinitely). What is missing here? Any advice would be appreciated.
import re
import random
folder = open("datas.txt","r")
data = folder.read()
word_list = re.sub("[^\w]"," ", data).split()
chosen_word = random.choice(word_list)
letter_player = input('enter a letter pls:\n')
continue_game = False
masked_word = []
for letter in chosen_word:
masked_word.append("*")
found_letters = []
def guess_letter():
for letter in range(0,len(chosen_word)):
if letter_player == chosen_word[letter]:
found_letters.append(letter_player)
masked_word[letter] = letter_player
else:
masked_word[letter] = '*'
print(masked_word[letter])
return found_letters
str_found_letters = ''.join(found_letters)
print(str_found_letters)
if(str_found_letters != chosen_word):
continue_game = True
while continue_game:
guess_letter()
As there are others answering, why not hand out another try, from where the OP could continue? So here another version fixing also the overwrite error of previous found letters in subsequent iterations.Note also, that the append of letters found in a list may be what one wants, or maybe not, as the o in foo would be appended twice.
# Python 3/2, imports and a literal:
from __future__ import print_function
import re
import random
MASK_CHAR = '*'
# Read words from file and select randomly:
def read_game_data(source="datas.txt"):
"""Randomly select a word from source data."""
with open(source, "r") as f_data:
return random.choice(re.sub("[^\w]", " ", f_data.read()).split())
# Build sequences (here lists) of letters that constitute a word or "mask"
def build_word_seq(a_word, a_mask=None):
return [letter if not a_mask else a_mask for letter in a_word]
# the core evaluation function (previously named guess_letter)
def evaluate_letter(chosen_word, masked_word, letter_player, found=None):
if found is None:
found = set()
for pos in range(len(chosen_word)):
if letter_player == chosen_word[pos]:
found.add(letter_player)
masked_word[pos] = letter_player
return masked_word, found
# The function that replaces the continue_game variable:
def not_ready(chosen_word, masked_word):
"""Evaluate."""
return True if masked_word != chosen_word else False
# Put the business in a main function, minimize globals:
def main():
"""Do the game."""
chosen_word = build_word_seq(read_game_data())
mask = build_word_seq(chosen_word, a_mask=MASK_CHAR)
found_letters = set()
while not_ready(chosen_word, mask):
letter_player = input('enter a letter pls:\n')
mask, found_letters = evaluate_letter(
chosen_word, mask, letter_player, found_letters)
print(''.join(mask))
if found_letters:
print("LettersFound: %s" % (sorted(found_letters),))
if __name__ == '__main__':
main()
A typical run based on a datas.txt file with:
foo bar baz
yes
no
yields e.g:
$ python3 hangman_again_inf_loop.py
enter a letter pls:
f
***
enter a letter pls:
y
***
enter a letter pls:
b
b**
LettersFound: ['b']
enter a letter pls:
a
ba*
LettersFound: ['a', 'b']
enter a letter pls:
r
bar
LettersFound: ['a', 'b', 'r']
The loop again may be infinite (if you do not guess right ;-)
For a hangman game, there should be some equivalent counting logic, where the guessing competes against a line by line drawn hangman ...
Above code still needs replacement of input() by raw_input() when python v2 is being used ... but the OP used print() without future import, thus it is plausible, a Python v3 solution is good nuff.
Happy hacking!
So, the biggest issue was the scope of the continue_game variable. Since it was declared outside of the function. "while continue_game" always evaluates the same.
To fix, add global continue_game in the method definition.
below is code that will break out of the loop. to test I created a datas.txt file with one word and with the current logic, you have to type the word in that order for the str_found_letters != chosen_word to hit the else condition
import re
import random
folder = open("datas.txt","r")
data = folder.read()
word_list = re.sub("[^\w]"," ", data).split()
chosen_word = random.choice(word_list)
found_letters = []
continue_game = True
masked_word = []
for letter in chosen_word:
masked_word.append("*")
def guess_letter():
global continue_game, chosen_word, found_letters, masked_word
letter_player = raw_input('enter a letter pls: ')
for letter in range(0,len(chosen_word)):
if letter_player == chosen_word[letter]:
found_letters.append(letter_player)
masked_word[letter] = letter_player
else:
masked_word[letter] = '*'
print(masked_word[letter])
str_found_letters = ''.join(found_letters)
print(str_found_letters)
if(str_found_letters != chosen_word):
continue_game = True
else:
continue_game = False
while continue_game:
guess_letter()

Checking Palindrome text, with ignored punctuation marks, spaces and case

Homework exercise:
Checking whether a text is a palindrome should also ignore punctuation, spaces and case. For example, "Rise to vote, sir." is also a palindrome but our current program doesn't say it is. Can you improve the above program to recognize this palindrome?
origin code:
def reverse(text):
return text[::-1]
def is_palindrome(text):
return text == reverse(text)
something = input('Enter text: ')
if (is_palindrome(something)):
print("Yes, it is a palindrome")
else:
print("No, it is not a palindrome")
my try:
import re
def reverse(text):
global words
words = text.split()
return words[::-1]
def is_palindrome(text):
return words==reverse(text)
something = input('Enter text: ')
if (is_palindrome(something)):
print("Yes, it is a palindrome")
else:
print("No, it is not a palindrome")
Error:
Enter text: jfldj
Traceback (most recent call last):
File "/Users/apple/PycharmProjects/Problem Solving/user_input.py", line 13, in <module>
print("Yes, it is a palindrome")
File "/Users/apple/PycharmProjects/Problem Solving/user_input.py", line 10, in is_palindrome
NameError: name 'words' is not defined
How should I change my code?
Latest code:
import string
def remove_punctuations(word):
return "".join(i.lower() for i in word if i not in string.ascii_letters)
def reverse(text):
return text[::-1]
def is_palindrome(text):
text = remove_punctuations(text)
return text == reverse(text)
something = input('Enter text: ')
if (is_palindrome(something)):
print("Yes, it is a palindrome"
else:
print("No, it is not a palindrome")
No matter what I input, output is Yes.
Enter text: hggjkgkkkk
Yes, it is a palindrome
What's wrong?
To ignore the punctuations, spaces and case of the given text you need to define a function remove_punctuations() which takes a word as parameter and returns a word with all lower case characters, remove punctuation marks and removed spaces.
To remove the unwanted characters we need to iterate over the given text, if the current character falls in strings.ascii_letters , then generate the character converting it to lower caps using str.lower() method. Finally using "".join() method to concatenate the generated str elements.
import string
def remove_punctuations(word):
return "".join(i.lower() for i in word if i in string.ascii_letters)
def reverse(text):
return text[::-1]
def is_palindrome(text):
text = remove_punctuations(text)
return text==reverse(text)
something = "Rise to vote, sir."
if (is_palindrome(something)):
print("Yes, it is a palindrome")
else:
print("No, it is not a palindrome")
Since the hint says to use a tuple with forbidden punctuation marks, I created the following variant:
forbidden = (' ', ',', "'", '?', '!', '.', '’')
def reverse(text):
return text[::-1]
def cleaning(text):
clean_text = ''
for item in text:
if item not in forbidden:
clean_text += item
return clean_text
def is_palindrome(text):
lower_text = cleaning(text.lower())
return lower_text == reverse(lower_text)
example = input('Enter something: ')
if is_palindrome(example):
print("Yes, it is a palindrome")
else:
print("No, it is not a palindrome")
The cleaning function checks each character for belonging to a tuple of forbidden characters, if not, then concatenates it to the clean_text string
I started studying for python 2 days before so that is what i come up with.
It is not so much advanced but works like a charm. :D
It is pretty straight forward what i do there. I just make a tuple with the "legal" letters (abc=). Then I define a function that 1st change all letters to lower case and then checks every character in the string with the "legal" letters. Then after this "filtering" the rawtext contains only the "legal" ones. Then the 2nd function just reverses the results of the 1st one. Compare and da da..!
# Palindrome recognize
abc='abcdefghijklmnopqrstuvwxyz'
def rawtext(text):
rawtext=''
text=text.lower()
for j in text[::1]:
for i in abc[::1]:
if j==i:
rawtext=rawtext+j
return rawtext
def reverse(text):
rev= rawtext(text)[::-1]
return rev
text=str(input('Write text:'))
if reverse(text)==rawtext:
print('The text is palindrome')
else:
print('The text is not a palindrome')
from itertools import izip_longest
def is_palindrome(s):
l = len(s)
fi = (i for i in xrange(l) if s[i].isalpha())
bi = (i for i in xrange(l-1, -1, -1) if s[i].isalpha())
for f, b in izip_longest(fi, bi):
if f >= b: return True
if s[f].lower() != s[b].lower(): return False
return True
Hope that helps

Having trouble when replacing in a list-Python

I am having trouble replacing lists on python, my code is below.
def words_open():
global words
wordsfile = open("words.txt","r")
words_list = wordsfile.readlines()
words = []
for i in range(len(words_list)):
words.append(words_list[i].strip())
return words_list
return words
def replace_symbol_for_letter(letter,symbol):
print([s.replace(symbol,letter) for s in words])
return words
def enter_pairing():
correct_symbol = False
while correct_symbol == False:
symbol = input("Please enter a symbol: ")
if symbol not in symbols_list:
correct_symbol = False
elif symbol in symbols_list:
correct_symbol = True
correct_letter = False
while correct_letter == False:
letter = input("Please enter a letter: ")
letter = letter.upper()
if letter not in alphabet:
correct_letter = False
elif letter in alphabet:
correct_letter = True
current_pairings.append(symbol and letter)
replace_symbol_for_letter(letter,symbol)
return letter
return symbol
The code runs fine, without syntax errors, however I am having trouble replacing the 'words' list.
When I run the code this happens:
The words are:
#+/084&"
#3*#%#+
8%203:
,1$&
!-*%
.#7&33&
#*#71%
&-&641'2
#))85
9&330*
Please enter a symbol: #
Please enter a letter: A
['A+/084&"', 'A3*A%A+', '8%203:', ',1$&', '!-*%', '.A7&33&', 'A*A71%', "&-&641'2", 'A))85', '9&330*']
Please enter a symbol: +
Please enter a letter: b
['#B/084&"', '#3*#%#B', '8%203:', ',1$&', '!-*%', '.#7&33&', '#*#71%', "&-&641'2", '#))85', '9&330*']
As you can see the symbol is replaced to the letter, which works fine, however as soon as I enter a new symbol/letter pairing it deletes the previous replacement and the replaces it again.
Thanks!
In your code you don't modify the words list in replace_symbol_for_letter
print([s.replace(symbol,letter) for s in words])
This does not modify words list it just creates a new list having the pairing changed but words does not change
Replace it by this:
words = [s.replace(symbol,letter) for s in words]
print words
This should make it.
By the way: global vars are evil :)
You forgot to close your file avec reading it, you should consider to use the with statement to open your file, it will close it automaticly after your actions on it.
def words_open():
with open('words.txt', 'r') as file:
words_list = file.readlines()
words = [line.split() for line in words_list]
return words_list, words

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