I'm working on a small application for work w/ python and PyQt4 for the GUI. What I'm trying to accomplish is having a tabbed GUI where when a user clicks on a menu item, the action taken adds a tab to the QTabWidget. I'm currently having trouble getting an action to do such a thing. I've tried creating the GUI by hand and with QT designer, but I cant figure out how, if at all possible, to get an action to add a tab to the QTabWidget. This is my python code:
import sys
from PyQt4 import QtGui, uic
class TestGUI(QtGui.QMainWindow):
def __init__(self):
super(TestGUI, self).__init__()
uic.loadUi('TEST.ui', self)
self.show()
self.actionAdd_Tab.triggered.connect(addTab)
def addTab():
print 'This works'
#Add new tab to GUI
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
window = TestGUI()
sys.exit(app.exec_())
Pressing the menu item prints 'This works' to the console, so I know that its calling the addTab() function, but how do I get it to add a Tab?
Let me know if you would like to see the .ui file if it will help
The handler for your action needs to create a tab label, and also a widget for the contents of the tab, so that they can be added to the tabwidget.
As a start, try something like this:
import sys
from PyQt4 import QtGui, uic
class TestGUI(QtGui.QMainWindow):
def __init__(self):
super(TestGUI, self).__init__()
uic.loadUi('TEST.ui', self)
self.actionAdd_Tab.triggered.connect(self.handleAddTab)
def handleAddTab(self):
contents = QtGui.QWidget(self.tabWidget)
layout = QtGui.QVBoxLayout(contents)
# add other widgets to the contents layout here
# i.e. layout.addWidget(widget), etc
self.tabWidget.addTab(contents, 'Tab One')
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
window = TestGUI()
window.show()
sys.exit(app.exec_())
QTabWidget's addTab() method, coincidentally named the same, adds a tab.
Related
I trying to connect my pyqt6 GUI app to move between stacked widget pages based on the icons you press in the toolbar. I saw that if i use the triggered method it suppose to work but for some reason when I run my python code, I always see the app on page 2 and not my default page 1 and the icons are not triggering movement to a different page. I checked the heirarchy of the elements that I built un the GUI in QT Designer and made sure there are two separate pages, you can see in the image below:
This is the code im running currently:
import sys
from PyQt6.QtWidgets import QApplication
from PyQt6.QtWidgets import QMainWindow
from app_try import Ui_MainWindow
class MainWindow:
def __init__(self):
self.main_win = QMainWindow()
self.ui = Ui_MainWindow()
self.ui.setupUi(self.main_win)
def show_page(self, page):
print("showPage called with page", page)
self.ui.stackedWidget.setCurrentWidget(page)
self.ui.stackedWidget.setCurrentWidget(self.ui.page)
self.ui.action_send_info.triggered(lambda: self.show_page(self.ui.page))
print("Connected action_send_info to showPage")
self.ui.action_data_table.triggered(lambda: self.show_page(self.ui.page_2))
print("Connected action_data_table to showPage")
def show(self):
self.main_win.show()
if __name__ == '__main__':
app = QApplication(sys.argv)
main_win = MainWindow()
main_win.show()
sys.exit(app.exec_())
app_try is the name of my python file which I import in order to get all the elemnts of the GUI. Am I missing something that i need to add in order for the icons to move between the page? thank you for any help!
I need to execute a block of code when the user clicks on the tab of a tabbified QDockWidget. So far I've been doing this via a hack using the "visibilityChanged" event but this is now causing issues (for example, if I have several tabbified dock widgets and I drag one out so that it is floating, the tabbified one underneath will fire its "visibilityChanged" event which I will mistakenly interpret as the user clicking the tab). How can I receive proper notification when a user clicks on a QDockWidgets' tab? I've experimented with the "focusInEvent" of QDockWidget but it doesn't seem to fire when the tab is clicked.
When you use tabifyDockWidget() method QMainWindow creates a QTabBar, this is not directly accessible but using findChild() you can get it, and then use the tabBarClicked signal
from PyQt4 import QtCore, QtGui
class MainWindow(QtGui.QMainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
first_dock = None
for i in range(10):
dock = QtGui.QDockWidget("title {}".format(i), self)
dock.setWidget(QtGui.QTextEdit()) # testing
self.addDockWidget(QtCore.Qt.TopDockWidgetArea, dock)
if first_dock:
self.tabifyDockWidget(first_dock, dock)
else:
first_dock = dock
dock.raise_()
tabbar = self.findChild(QtGui.QTabBar, "")
tabbar.tabBarClicked.connect(self.onTabBarClicked)
def onTabBarClicked(self, index):
tabbar = self.sender()
text = tabbar.tabText(index)
print("index={}, text={}".format(index, text))
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
w = MainWindow()
w.show()
sys.exit(app.exec_())
I have two .py files created from .ui files made in QtDesigner. One is a main window for the program, and the other is a widget that allows users to input information and I'm calling it the "evaluation" widget.
I have a button in the main window called "btn_StartNew", which is meant to open the widget window to allow the user to start a new evaluation. I'm having troubles with opening the main window, and adding the function to the "btn_StartNew" button that opens the "evaluation" widget.
The code I have right now opens both the main window and the evaluation widget in the same window when I run the code:
import sys
from PyQt4 import QtCore, QtGui
from wid_Main import Ui_wid_Main
from wid_Eval_v2 import Ui_wid_Eval
class Win_Eval(QtGui.QWidget):
def __init__(self, parent=None):
super(Win_Eval, self).__init__(parent)
self.ui=Ui_wid_Eval()
self.ui.setupUi(self)
class Win_Main(QtGui.QMainWindow):
def __init__(self, parent=None):
super(Win_Main, self).__init__(parent)
self.ui=Ui_wid_Main()
self.ui.setupUi(self)
#RUN "start new eval" button
self.ui.btn_StartNew.clicked.connect(self.btn_StartNew_click)
self.dialog = Win_Eval(self)
def btn_StartNew_click(self):
self.dialog.show()
def main():
app = QtGui.QApplication(sys.argv)
main = Win_Main()
main.show()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
Where wid_Main and Ui_wid_Main are the main window file and the main window class, respectively. And wid_Eval_v2 and Ui_wid_Eval are the evaluation widget file and class, respectively.
Any help would be much appreciated!
You must change:
self.dialog = Win_Eval(self)
to
self.dialog = Win_Eval()
I'm trying to set up an app in Linux using PyQt4 designer and I'm struggling to connect signals and slots to it. Right now all I want it to do is connect a button clicked signal to a custom slot, saveEnergyScheme which simply prints 'energy list' to the terminal.
I've translated the .ui code for my app to a python class with pyuic4 -w sumcorr.ui > sumcorr_ui.py. This created a class in the sumcorr_ui.py module called SumCorr_ui:
class SumCorr_ui(QtGui.QMainWindow, Ui_SumCorr_ui):
def __init__(self, parent=None, f=QtCore.Qt.WindowFlags()):
QtGui.QMainWindow.__init__(self, parent, f)
self.setupUi(self)
I then made my app as a custom widget and tried to add a simple signal-slot connection to a button to show it works:
from PyQt4 import QtGui, QtCore
from sumcorr_ui import SumCorr_ui
class SumCorr(SumCorr_ui):
def __init__(self):
SumCorr_ui.__init__(self)
self.save_energies_button.clicked.connect(self.saveEnergyScheme)
def saveEnergyScheme(self):
print 'energyList'
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
mySumCorr = QtGui.QMainWindow()
ui = SumCorr()
ui.setupUi(mySumCorr)
mySumCorr.show()
sys.exit(app.exec_())
I expect to get the line 'energy list' when I click the button named save_energies_button, but nothing happens. Could this be because I haven't built the UI as a widget, but as a main window? Why doesn't it print out??
Try to add ui.show() and you'll see that your code is creating two different windows, one should have the signal connected and one doesn't. That's because you are showing only the mySumCorr window, but you call only setupUi on it, which does not connect the signal.
When you create the SumCorr instance, you are creating a window and setting it up, then, by no reason, you do ui.setupUi(mySumCorr), which setups the mySumCorr instance without connecting the signal, and you show this last window.
I believe your code should be like this:
class SumCorr(QtGui.QMainWindow, Ui_SumCorr_ui):
def __init__(self):
SumCorr_ui.__init__(self)
self.setupUi(self)
self.save_energies_button.clicked.connect(self.saveEnergyScheme)
def saveEnergyScheme(self):
print 'energyList'
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
mySumCorr = SumCorr()
mySumCorr.show()
sys.exit(app.exec_())
Note that it doesn't make any sense to have a SumCorr_ui class, that's because Qt is a UI library so you are just introducing a worthless level of abstraction. The designer file already gives you an abstraction over the ui layout.
I just started dwelling into the realm of Qt (coming from PyGTK) and I'm using PySide. So I found this great example on another answer here on stack exchange.
import sys
from PySide.QtCore import *
from PySide.QtGui import *
from PySide.QtWebKit import *
app = QApplication(sys.argv)
web = QWebView()
web.settings().setAttribute(
QWebSettings.WebAttribute.DeveloperExtrasEnabled, True)
# or globally:
# QWebSettings.globalSettings().setAttribute(
# QWebSettings.WebAttribute.DeveloperExtrasEnabled, True)
web.load(QUrl("http://www.google.com"))
web.show()
inspect = QWebInspector()
inspect.setPage(web.page())
inspect.show()
sys.exit(app.exec_())
My question is as follows, how do I make the inspector show up in the same window instead of a new one? I understand I need to add the QWebInspector to another widget inside the main window (a vbox for example), what I want to know is how to connect that event to the signal the context menu "Inspect" triggers. In PyGTK I would need to use .connect() but I can't find the right SIGNAL for this specific action.
Thanks for your time guys/gals
It shouldn't be necessary to do anything special for the context menu to work. Just add an inspector widget to your layout, and hide() it to start with. The default context menu action can then show() the inspector as needed.
A slightly trickier issue is how to hide the inspector again once it's shown, as there doesn't seem to be a corresponding context menu item for that.
The demo script below simply creates a keyboard shortcut to hide/show the inspector:
from PySide import QtGui, QtCore, QtWebKit
class Window(QtGui.QWidget):
def __init__(self):
QtGui.QWidget.__init__(self)
self.view = QtWebKit.QWebView(self)
self.view.settings().setAttribute(
QtWebKit.QWebSettings.WebAttribute.DeveloperExtrasEnabled, True)
self.inspector = QtWebKit.QWebInspector(self)
self.inspector.setPage(self.view.page())
self.inspector.hide()
self.splitter = QtGui.QSplitter(self)
self.splitter.addWidget(self.view)
self.splitter.addWidget(self.inspector)
layout = QtGui.QVBoxLayout(self)
layout.addWidget(self.splitter)
QtGui.QShortcut(QtGui.QKeySequence('F7'), self,
self.handleShowInspector)
def handleShowInspector(self):
self.inspector.setShown(self.inspector.isHidden())
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
window = Window()
window.view.load(QtCore.QUrl('http://www.google.com'))
window.show()
sys.exit(app.exec_())