I have a server, which is running perfectly in this address (example): http://stackoverflow.cloud.com
And I have some files in this address which I would like to be download from there to my computer. I installed in the server the IIS and I can access to the files this way:
http://stackoverflow.cloud.com/files/nameOfFile.png
With this last URL I would like to download the file to my computer.
import urllib
urllib.urlretrieve('http://stackoverflow.cloud.com/files/nameOfFile.png', 'C:\\myFile.png')
With this code instead of saving the file to my computer, it saves the file in the harddisk of the server.
I tried the module Webbrowser, but I'm working with python version 2.6 and Webbrowser is for 3.2 or something.
Any other idea of how I can accomplish this?
Solved.
Seems that openERP has is own way of popup links:
return { 'type': 'ir.actions.act_url', 'url': 'http://stackoverflow.cloud.com/files/nameOfFile.png'}
Thank you all.
I never tried using urllib before but I can guide you to read the documentation for the urllib.urlretrieve function in the Python standard library:
urllib.urlretrieve(url[, filename[, reporthook[, data]]])
Copy a network object denoted by a URL to a local file, if necessary. If the URL points to a local file, or a valid cached copy of the object exists, the object is not copied. Return a tuple (filename, headers) where filename is the local file name under which the object can be found, and headers is whatever the info() method of the object returned by urlopen() returned (for a remote object, possibly cached). Exceptions are the same as for urlopen().
Related
I am working on a Python tool to synchronize files between my local machines and a remote server. When I upload a file to the server the modification time property of that file on the server is set to the time of the upload process and not to the mtime of the source file, which I want to preserve. I am using FTP.storbinary() from the Python ftplib to perform the upload. My question: Is there a simple way to preserve the mtime when uploading or to set it after the upload? Thanks.
Short answer: no. The Python ftplib module offers no option to transport the time of the file. Furthermore, the FTP protocol as defined by rfc-959 has no provision to directly get not set the mtime of a file. It may be possible on some servers through SITE commands, but this is server dependant.
If it is possible for you, you should be able to pass a site command with the sendcmd method of a connection object. For example if the server accepts a special SITE SETDATE filename iso-8601-date-string you could use:
resp = ftp.sendcmd(f'SITE SETDATE {file_name} {date-string}')
Scenario: Website x has a form in which a file can be uploaded from your local machine.
Question: Is it possible to pass in a remote url (e.g. http://blah.whatever/file.ext) instead of a local file, thus causing the remote server to download the file found at http://blah.whatever/file.ext instead of having to download the file to my local machine and then upload it?
I'm most familiar with Python. So, if this is possible through something like the requests module, that would be fantastic.
I wonder how can I send cookie and phpssid with urllib2 in python?
Actually I want to read a page I've logged in with my browser, but when I try to read it with this script I encounter a text which seems to say that you've missed something.
My script :
#!/usr/bin/python
import urllib2
f = urllib2.urlopen('http://mywebsite.com/sub/create.php?id=20')
content = f.read()
file = open('file.txt', 'w')
file.write(content)
file.close()
The error message I save instead of the real page :
Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /home/number/domains/1number.com/public_html/s4/app/mywidgets.php:1) in /home/number/domains/1number.com/public_html/s4/app/mywidgets.php on line 23
Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/number/domains/1number.com/public_html/s4/app/mywidgets.php:1) in /home/number/domains/1number.com/public_html/s4/app/mywidgets.php on line 23
Warning: Cannot modify header information - headers already sent by (output started at /home/number/domains/1number.com/public_html/s4/app/mywidgets.php:1) in /home/number/domains/1number.com/public_html/s4/lib/webservice.php on line 0
What is the exact problem?(Please give me a simple way to implement what I want)
Thanks in advance
For the SID, one of the ways to send that is as part of the query string, and you're already doing that. At least I assume that's what the id=20 part of your URL is.
For cookies, everything you want is in cookielib.
Just creating a CookieJar to use for a session with the server is trivial. If you want to import cookies from your browser, there are three possibilities:
If your browser uses the old Netscape cookie file format, you can use FileCookieJar.
If your browser uses a sqlite database (as at least Firefox and Safari/Chrome do), use the sqlite3 module to read it, and populate a CookieJar manually.
If worst comes to worst, copy and paste the cookies from your browser into your script as hardcoded strings and popular a CookieJar manually.
If you don't want to read the docs on how to use cookielib, just see the examples at the end, which show how to use a CookieJar with urllib2, which is exactly what you want to do.
If you have a problem, read the docs.
Meanwhile, what you're showing us are (a) warnings, not errors, and (b) obviously a problem on the server side, not your script. The server should never be spewing out a bunch of warnings and an otherwise-blank page. If you, or one of your coworkers, is responsible for the server code, that needs to be fixed first (and your current simple Python script can serve as a great regression test case).
I just checked my webspace and it's signature says: Apache/2.2.9 (Debian) mod_python/3.3.1 Python/2.5.2 mod_ssl/2.2.9 OpenSSL/0.9.8g
This give me hope that Python is somehow supported. Why is python listed twice? mod_python/3.3.1 AND Python/2.5.2 ???
There is a cgi-bin folder on my webspace.
What I want to do: I need to do a cross-site call to get some text-data from a server. The text-data is not JSON but I guess I should convert it to JSON (or is there an option to do cross-site without JSON?)
The python script gets the request for some JSONP. Depending on the request (I guess I should somehow parse the URL) the python script is to load the a requested text-data file from the webserver and wrap it in some JSON and return it.
Can somebody tell me how I do these three steps with python on my webspace?
First off, the signature isn't listing python twice. Its listing first the version of mod_python, which is an Apache web server plugin, then it is listing the version of the python interpreter on the system.
python cgi module - This is really an inefficient approach to writing python server code, but here it is. Ultimately you should consider one of the many amazing python web frameworks out there. But, using the cgi module, your response would always start with this:
print 'Content-Type: application/json\n\n'
Your python script would run on the server from an HTTP request. In that script you would check the request and determine the data you will want to serve from either the URL value or the query string.
At the very least you would just wrap your return value in a basic JSON data structure. The text data itself can just be a string:
import json
text_data = "FOO"
json_data = json.dumps({'text': text_data})
print json_data
# {"text": "FOO"}
For the JSONP aspect, you would usually check the query string to see if the request contains a specific name for the callback function the client wants, or just default to 'callback'
print "callback(%s);" % json_data
# callback({"text": "FOO"});
Returning that would be a JSONP type response, because when the client receives it, the callback is executed for the client.
And to conclude, let me add that you should be aware that python cgi scripts will need to start a brand new python interpreter process for every single request (even repeat requests from the same client). This can easily overwhelm a server under increased load. For this reason, people usually go with the wsgi route (mod_wsgi in apache). wsgi allows a persistant application to keep running, and handles ongoing requests.
How can I download files from a website using wildacrds in Python? I have a site that I need to download file from periodically. The problem is the filenames change each time. A portion of the file stays the same though. How can I use a wildcard to specify the unknown portion of the file in a URL?
If the filename changes, there must still be a link to the file somewhere (otherwise nobody would ever guess the filename). A typical approach is to get the HTML page that contains a link to the file, search through that looking for the link target, and then send a second request to get the actual file you're after.
Web servers do not generally implement such a "wildcard" facility as you describe, so you must use other techniques.
You could try logging into the ftp server using ftplib.
From the python docs:
from ftplib import FTP
ftp = FTP('ftp.cwi.nl') # connect to host, default port
ftp.login() # user anonymous, passwd anonymous#
The ftp object has a dir method that lists the contents of a directory.
You could use this listing to find the name of the file you want.