I'm trying to build a simple flask page that displays links from a dictionary of text/links:
urls = {'look at this page': www.example.com, 'another_page': www.example2.com}
#app.route('/my_page')
def index(urls=urls):
return render_template('my_page.html',urls=urls)
My template page looks like this:
{%- block content %}
{%- for url in urls %}
{{ url }}
{%- endfor %}
{%- endblock content %}
I can't quite seem to understand how to create dynamic urls like this. The code produces this error:
TypeError: 'NoneType' object has no attribute '__getitem__'
Can anyone point out my problem or a solution?
UPDATE: Here's my updated code:
#app.route('/my_page')
def index():
context = {'urls': urls}
return render_template('index.html', context=context)
And the template:
{%- block content %}
{% for key, data in context.items() %}
{% for text, url in data.items() %}
{{ text }}
{% endfor %}
{% endfor %}
{%- endblock content %}
This solution is close, however each link get prepended with my app's url. In other words I get this:
look at this page
I just want:
look at this page
Try this instead:
urls = {
'A search engine.': 'http://google.com',
'Great support site': 'http://stackoverflow.com'
}
#app.route('/my_page')
def index(): # why was there urls=urls here before?
return render_template('my_page.html',urls=urls)
{%- block content %}
{%- for text, url in urls.iteritems() %}
{{ text }}
{%- endfor %}
{%- endblock content %}
url_for is only for building URLs with Flask. Like in your case:
print url_for('index') # will print '/my_page' ... just a string, no magic here
url_for takes an endpoint name as first parameter which is by default the name of the view function. So the endpoint name for your view function index() is simply 'index'.
Related
I'm doing some pagination in Django. I want to show the pages' number which are ahead of the current page. I am using the following code:
{% for page in blogs_page.paginator.page_range|slice:"0:{{ blogs_page.number }}" %}
But this seems useless; the result does the same as the following:
{% for page in blogs_page.paginator.page_range %}
The slice does not work here. How do I fix this?
Never use {{ }} inside of {% %}, don't do this {% {{ }} %}.
{% for page in blogs_page.paginator.page_range|slice:"0:blogs_page.number" %}
I think it won't work. If I were you I would create a custom tag and executed all the logic there. So, it will look like this:
Template:
{% custom_tag blogs_page as result %}
{% for page in result %}
templatetags/tags.py:
from django import template
register = template.Library()
#register.simple_tag
def custom_tag(bl_page):
return bl.page.paginator.page_range[0:bl_page.number]
Details: custom tags
I am passing the dictionary to the view but it is now showing on the page.
i also have print the dictionary on the before passing, and it prints the whole dictionary on the screen perfectly. but when i pass it to the html page, it does not show at all..
view.py
def show_log_messages(request):
context = RequestContext(request)
log_dictionary = {}
count = 0
e = log_messages.objects.filter(log_status='Queue').values('sent_to', 'unique_arguments')
count = 0
logs = {}
for d in e:
count +=1
new_dict = {'email': d["sent_to"], 'log_id': d["unique_arguments"]}
logs[count] = new_dict
for keys in logs:
print logs[keys]['log_id']
print logs[keys]['email']
return render_to_response('show_logs.html', logs, context)
show_logs.html
{% if logs %}
<ul>
{% for log in logs: %}
{% for keys in log %}
<li>{{ log[keys]['email'] }}</li>
{% endfor %}
</ul>
{% else %}
<strong>There are no logs present.</strong>
{% endif %}
it only show the heading not the list element.
Your code is very unpythonic and undjango. You should pass to template a list instead of dictionary.
Also shortcuts.render is much simpler to use than render_to_response.
def show_log_messages(request):
messages = log_messages.objects.filter(log_status='Queue') \
.values('sent_to', 'unique_arguments')
logs = [{'email': msg['sent_to'], 'log_id': msg['unique_arguments']}
for msg in messages]
return render(request, 'show_logs.html', {'logs': logs})
Template:
{% if logs %}
<ul>
{% for log in logs %}
<li>{{ log.email }} - {{ log.log_id }}</li>
{% endfor %}
</ul>
{% else %}
<strong>There are no logs present.</strong>
{% endif %}
BTW, logs list is unnecessary here. You can pass messages queryset directly into template and show {{ log.sent_to }} and {{ log.unique_arguments }} in the <li> tag.
The render_to_response shortcut takes a dictionary. If you want to access logs in the template, it should be in that dictionary:
return render_to_response("show_logs.html", {'logs': logs}, context)
The second problem is that your django template is invalid. It looks like you're trying to write Python in the template. You'd probably find it helpful to read through the Django template language docs.
It's not clear to me what you're trying to display, so here's an example of looping through each log, and displaying its id and email. You should be able to adjust this to get the result you want.
{% if logs %}
{% for key, value in logs.items %}
{{ key }}, {{ key.log_id}}, {{ key.email }}
{% endf
{% else %}
<strong>There are no logs present.</strong>
{% endif %}
I'm working on an Inclusion Tag. In the super shell, the tag returns the appropiate data set nevertheles, I dont see the inclusion template rendered on the calling template. I can only guess the inclusion template is in the wrong location. As of this moment, the template is at MYPROJECT/templates which is the ONLY folder in TEMPLATE_DIRS. Please help me figure out what am I doing wrong here. TIA!
MYPROJECT/newsroom/templatetags/blog_extras.py -> http://pastebin.com/ssuLuVUq
from mezzanine.blog.models import BlogPost
from django import template
register = template.Library()
#register.inclusion_tag('featured_posts.html')
def featured_posts_list():
"""
Return a set of blog posts whose featured_post=True.
"""
blog_posts = BlogPost.objects.published().select_related("user")
blog_posts = blog_posts.filter(featured_post=True)
# import pdb; pdb.set_trace()
return {'featured_posts_list': blog_posts}
MYPROJECT/templates/featured_posts.html -> http://pastebin.com/svyveqq3
{% load blog_tags keyword_tags i18n future %}
Meant to be the the infamous "Featured Posts" Section!
{{ featured_posts_list.count }}
<ul>
{% for featured_post in featured_posts_list %}
<li> {{ featured_post.title }} </li>
{% endfor %}
</ul>
MYPROJECT/settings.py -> pastebin.com/Ed53qp5z
MYPROJECT/templates/blog/blog_post_list.html -> pastebin.com/tJedXjnT
As #Victor Castillo Torres said, you need to change the name of the tag you're loading, which will fix that aspect of your template tag. However, even though they are in different namespaces, I would still change the name of the context variable your tag returns just for sanity:
#register.inclusion_tag('featured_posts.html')
def featured_posts_list():
blog_posts = BlogPost.objects.published().filter(
featured_post=True).select_related("user")
return {'blog_posts': blog_posts}
Then in your template:
{{ blog_posts.count }}
<ul>
{% for blog_post in blog_posts %}
<li>{{ blog_post.title }} </li>
{% endfor %}
</ul>
And finally, in your main template:
{% load blog_extras keyword_tags i18n_future %}
...
{% featured_posts_list %}
I've 2 urls pointing to the same place:
url(r'^index/$', 'proj.views.index'),
url(r'^index/show_closed/$', 'proj.views.index'),
If I use in a template file this:
{% url proj.views.index %}
it' ll return /index/show_closed
and this is OK, but how can i make {% url %} to return only /index ?
Use named patterns; giving your pattern a unique name:
url(r'^index/$', 'proj.views.index', name='index_direct'),
url(r'^index/show_closed/$', 'proj.views.index', name='index_closed'),
then refer to those names in the {% url %} tag instead of the view:
{% url 'index_direct' %}
{% url 'index_closed' %}
I'm trying to write a custom inclusion_tag in django.
Following the example on http://docs.djangoproject.com/en/dev/howto/custom-template-tags/
I'm just writing
from django import template
from libmas import models
register = template.Library()
#register.inclusion_tag('records.html')
def display_records(book_id):
book = models.book.objects.get(id__exact=book_id)
records = models.objects.filter(books=book)[0:10]
return {'records':records}
But I'm getting a
Invalid block tag: 'libmas_tags'
error in ie .
'records.html' file:
{% for record in records %}
<blockquote>{{record.id}}</blockquote>
{% endfor %}
my other html file is :
{% extends "admin/change_form.html" %}
{% libmas_tags %}
{% block after_field_sets %}
{% if object_id %}
{% display_records object_id %}
{% endif %}
{% endlock %}
The problem lies in your template. Its calling {% libmas_tags %}. Have you created template tags called libmas_tags? If so you might need to change it to
{% load libmas_tags %}
What is libmas_tags? The tag you have defined is called display_records, and that's what you should be calling in your template. If the tags file is called libmas_tags, you'll need to load that first as czarchaic points out.