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Unknown problem in Python. Printing does not work and files are not saved correctly

When I try to write something, such as variables, the code is renamed to the file name on the computer.
For example, if I write:
a = 20
f = 15
print(a+f)
then the code file will automatically be renamed to the first line, i.e. "a = 20"
Then, when I try to run the code, the program outputs nothing but "Python" and some incomprehensible words.
What could it be related to?
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I installed the latest version of Visual Stuio Code with Python, they are new, so there should be no problems. But this time it went wrong.
After reinstalling the program, the problem remains.

First of all, if there is no special requirement, please do not use Code Runner to run the script, using the official extension Python is a better choice.
In addition, the dot on your file label means that you have not saved the file, you can add the following setting to enable automatic saving in the settings.
"files.autoSave": "afterDelay",
You may have created the file using the following method. File --> New File... --> Python File. At this time, the file has not been named, also not saved. You can see that there is no such file in the resource manager list at this time.
So the file label shows the first line of codes. This is a feature of vscode, you can refer to this link. And because the file has not been saved, there will be problems executing the script.
You can rename the script file directly (F2), or vscode will remind you to name the file when saving. Another way to create a file is to right click and choose New File..., enter filename and end with .py extension.

ValueError: need more than 0 values to unpack (Python 2)

I am trying to replicate another researcher's findings by using the Python file that he added as a supplement to his paper. It is the first time I am diving into Python, so the error might be extremely simple to fix, yet after two days I haven't still. For context, in the Readme file there's the following instruction:
"To run the script, make sure Python2 is installed. Put all files into one folder designated as “cf_dir”.
In the script I get an error at the following lines:
if __name__ == '__main__':
cf_dir, cf_file, cf_phys_file = sys.argv[1:4]
os.chdir(cf_dir)
cf = pd.read_csv(cf_file)
cf_phys = pd.read_csv(cf_phys_file)
ValueError: need more than 0 values to unpack
The "cf_file" and "cf_phys_file" are two major components of all files that are in the one folder named "cf_dir". The "cf_phys_file" relates only to two survey question's (Q22 and Q23), and the "cf_file" includes all other questions 1-21. Now it seems that the code is meant to retrieve those two files from the directory? Only for the "cf_phys_file" the columns 1:4 are needed. The current working directory is already set at the right location.
The path where I located "cf_dir" is as follows:
C:\Users\Marc-Marijn Ossel\Documents\RSM\Thesis\Data\Suitable for ML\Data en Artikelen\Per task Suitability for Machine Learning score readme\cf_dir
Alternative option in readme file,
In the readme file there's this option, but also here I cannot understand how to direct the path to the right location:
"Run the following command in an open terminal (substituting for file names
below): python cfProcessor_AEAPnP.py cf_dir cf_file cf_phys_file task_file jobTaskRatingFile
jobDataFile OESfile
This should generate the data and plots as necessary."
When I run that in "Command Prompt", I get the following error, and I am not sure how to set the working directory correctly.
- python: can't open file 'cfProcessor_AEAPnP.py': [Errno 2] No such file or directory
Thanks for the reading, and I hope there's someone who could help me!
Best regards & stay safe out there during Corona!!
Marc

cf_dir, cf_file, cf_phys_file = sys.argv[1:4]
means, the python file expects few arguments when called.
In order to run
python cfProcessor_AEAPnP.py cf_dir cf_file cf_phys_file task_file jobTaskRatingFile jobDataFile OESfile
the command prompt should be in that folder.
So, open command prompt and type
cd path_to_the_folder_where_ur_python_file_is_located
Now, you would have reached the path of the python file.
Also, make sure you give full path in double quotes for the arguments.

Python won't create / write to a file

I am new at python and learning the language. The following code should create a file in the running program directory and write to it but it doesn't do this at all in a .py file. If I put the same code in the IDLE shell it returns 17. No errors just doesn't create the file. What am I doing wrong?
with open("st.txt", "w") as f:
f.write("Hi from Python!")
Thanks for the help
Mike

This code is flawless, no problem!
I guess that in your REPL shell, the $PWD environment variable is set for somewhere, so your destination file is in some corner.
No exception thrown indicates that no problem with access authority.
Maybe you can set some absolute path string, such as ~/st.txt
By the way, the successful invoke should return 15 instead of 17, totally count 15 chars.

your code works well, st.txt will be touched at executing path.
other ways, your system account can't write in your execute path.
try in your $HOME path to execute your code, I think, It will work well

Python for Data Analysis, Chapter 2, first example

I'm following along with the examples in a translated version of Wes McKinney's "Python for Data Analysis" and I was blocked in first example of Chapter 2
I think my problem arose because I saved a data file in a wrong path. is that right?
I stored a file, usagov_bitly_data2012-03-16-1331923249.txt, in C:\Users\HRR
and also stored folder, pydata-book-mater, that can be downloaded from http://github.com/pydata-book in C:\Users\HRR\Anaconda2\Library\bin.

Depends.
You might change the location you save your File or eddit the path you give to your code in Line 10. Since you're yousing relativ Paths i guess your script runs in C:\Users\HRR\Anaconda2\Library\bin, which means you have to go back to C:\Users\HRR or use an absolute Path ... or move the File, but hell you don't want to move a file every time you want to open it, like moving word files into msoffice file to open it, so try to change the Path.
And allways try harder ;)

In python open() will open from the current directory down unless given a full path (in linux that starts with / and windows <C>://). In your case the command is open the folder ch02 in the directory the script is running from and then open usagov_bitly_data2012-03-16-1331923249.txt in that folder.
Since you are storing the text file in C:\Users\HRR\usagov_bitly_data2012-03-16-1331923249.txt and you did not specify the directory of the script. I recommend the following command instead open(C:\\Users\\HRR\\usagov_bitly_data2012-03-16-1331923249.txt)
Note: the double \ is to escape the characters and avoid tabs and newlines showing up in the path.

Including sound files in a pygame script using pyinstaller

I am new to programming, so I made myself the challenge to create Pong, and so I did. Now I want to share it with a couple of friends, so I decided to try using pyinstaller (have tried cx_Freeze).
In this Pong game I have 3 sound effects, located in the folder "sfx". So I've looked into including files using pyinstaller, so my .spec file says:
added_files = [
('E:\Game Development Stuff\Python 3\Games\Pong\sfx\hitOutline.ogg', 'sfx'),
('E:\Game Development Stuff\Python 3\Games\Pong\sfx\hitPaddle.ogg', 'sfx'),
('E:\Game Development Stuff\Python 3\Games\Pong\sfx/score.ogg', 'sfx')
]
a = Analysis(['pong.py'],
pathex=['E:\\Game Development Stuff\\Python 3\\Games\\Pong'],
binaries=None,
datas=added_files,
and in the Pong program itself, I use this code to get the path:
def resource_path(relative):
if hasattr(sys, "_MEIPASS"):
return os.path.join(sys._MEIPASS, relative)
return os.path.join(relative)
fileDir = os.path.dirname(os.path.realpath('__file__'))
hitPaddle = resource_path(os.path.join(fileDir, "sfx", "hitPaddle.ogg"))
hitOutline = resource_path(os.path.join(fileDir, "sfx", "hitOutline.ogg"))
score = resource_path(os.path.join(fileDir, "sfx", "score.ogg"))
hitPaddleSound=pygame.mixer.Sound(hitPaddle)
hitOutlineSound=pygame.mixer.Sound(hitOutline)
scoreSound=pygame.mixer.Sound(score)
So I make the exe file using pyinstaller (with the command pyinstaller pong.spec)
but when I open the pong.exe file the command window says:
Traceback "<string>", Unable to open file 'E:\\Game Development Stuff\\Python 3\\Games\\Pong\\dist\\pong\\sfx\\hitPaddle.ogg'
but in that exact same path is hitPaddle.ogg.
It seems to me that pygame isn't able to found it for some weird reason?

I believe the issue is in this line. You are not refrencing the files correctly. You wrote:
hitPaddle = resource_path(os.path.join(fileDir, "sfx", "hitPaddle.ogg"))
Instead you should of just:
hitpaddle = resource_path("sfx\hitPaddle.ogg")
This is because when you added the files in the spec file, you stated that they should be in "root\sfx" folder. When the .exe is run in onefile mode, all files are actually located in a temp folder called MEIXXXX, with XXXX being some integers. When you run the .exe, if you open this folder you should be able to see your files there.

Solved it for me after struggling with the same issue for hours. Conclusions:
The problem is not in not being able to find it, then it would say something with 'could not find'. It is really an issue with opening the file. Somehow, the .ogg format is giving issues. I changed all my .ogg files to .wav files and my game is running without problems now as executable.
I have no idea why though, because two weeks ago for a previous version I did manage to make a working .exe with the exact same .ogg files. And I don't see how the changes I made should have any effect on this. Anyway, it works now, and perhaps this can also solve this problem for others.