I am looking for a simple example of how to directly load a QtDesigner generated .ui file into a Python application.
I simply would like to avoid using pyuic4.
For the complete noobs at PySide and .ui files, here is a complete example:
from PySide import QtCore, QtGui, QtUiTools
def loadUiWidget(uifilename, parent=None):
loader = QtUiTools.QUiLoader()
uifile = QtCore.QFile(uifilename)
uifile.open(QtCore.QFile.ReadOnly)
ui = loader.load(uifile, parent)
uifile.close()
return ui
if __name__ == "__main__":
import sys
app = QtGui.QApplication(sys.argv)
MainWindow = loadUiWidget(":/forms/myform.ui")
MainWindow.show()
sys.exit(app.exec_())
PySide, unlike PyQt, has implemented the QUiLoader class to directly read in .ui files.
From the linked documentation,
loader = QUiLoader()
file = QFile(":/forms/myform.ui")
file.open(QFile.ReadOnly)
myWidget = loader.load(file, self)
file.close()
Another variant, based on a shorter load directive, found on https://askubuntu.com/questions/140740/should-i-use-pyqt-or-pyside-for-a-new-qt-project#comment248297_141641. (Basically, you can avoid all that file opening and closing.)
import sys
from PySide import QtUiTools
from PySide.QtGui import *
app = QApplication(sys.argv)
window = QtUiTools.QUiLoader().load("filename.ui")
window.show()
sys.exit(app.exec_())
Notes:
filename.ui should be in the same folder as your .py file.
You may want to use if __name__ == "__main__": as outlined in BarryPye's answer
Here is some example for PySide6 and Windows. (For linux you need use /, not \\)
from PySide6.QtUiTools import QUiLoader
from PySide6.QtCore import QFile
from PySide6.QtWidgets import QApplication
import sys
if __name__ == "__main__":
app = QApplication(sys.argv)
loader = QUiLoader()
file = QFile("gui.ui")
file.open(QFile.ReadOnly)
ui = loader.load(file)
file.close()
ui.show()
sys.exit(app.exec_())
For people coming from PyQt5/6 who are thoroughly confused by this:
PySide does not have the same functionality that we're used to, which is to load the ui file at the top of the window/widget subclass like so:
class MainWindow(QtWidgets.QMainWindow):
def __init__(self, *args, **kwargs):
super(MainWindow, self).__init__(*args, **kwargs)
'''Load ui'''
uic.loadUi("mainwindow.ui", self)
There is nothing very similar to this in PySide.
Instead, the best thing to do is embrace the ui-file compilation that you've avoided because loading the ui file is so easy in PyQt. This has a couple of advantages
There is a performance advantage - the ui file does not need to be compiled at run time
You get type hints for all your widgets without needing to manually add them
The disadvantage is that you have to use pyside6-uic to compile the *.ui files each time you edit them, but this can be made less painful by using scripts to automate the process - either setting it up in VSCode, a batch file or a powershell script. After you've done this, the code is nice:
#ui_mainwindow is the ui_mainwindow.py file
#Ui_MainWindow is the class that was produced within that .py file
from ui_mainwindow import Ui_MainWindow
class MainWindow(QtWidgets.QMainWindow, Ui_MainWindow):
def __init__(self):
super(MainWindow, self).__init__()
'''Load the ui'''
self.setupUi(self)
Related
I have a fresh QtCreator installation, and I set it up to run using a fresh install of Python3.8 on which I pip-installed both pyside2 and pyside6.
When I create a new Qt for Python - Window (UI file) application, whatever I do to the UI file the window always shows up empty and with the default size when I run the app.
I've tried with a QDialog, QMainApplication, using Pyside2 or Pyside6, I've checked that it was correctly loading the UI (and the right one) - no dice. It just won't update, and appears not to have any reason not to.
Default code for completeness:
# This Python file uses the following encoding: utf-8
import os
from pathlib import Path
import sys
from PySide2.QtWidgets import QApplication, QDialog
from PySide2.QtCore import QFile
from PySide2.QtUiTools import QUiLoader
class Dialog(QDialog):
def __init__(self):
super(Dialog, self).__init__()
self.load_ui()
def load_ui(self):
loader = QUiLoader()
path = os.fspath(Path(__file__).resolve().parent / "form.ui")
ui_file = QFile(path)
ui_file.open(QFile.ReadOnly)
loader.load(ui_file, self)
ui_file.close()
if __name__ == "__main__":
app = QApplication([])
widget = Dialog()
widget.show()
sys.exit(app.exec_())
(In the UI I just drag-dropped a button right in the middle and saved the file)
Am I forgetting something fundamental? I'm only used to programming in C++ using QtCreator.
I was expecting this to work right out of the box, but it's not.
This only dynamically load the UI as a new widget, with this custom class as a parent.
If I want signals and slots to work, the only thing I've found was to add a custom build step:
Command: <path to pyside6 install, use pip show to know where>\uic.exe
Arguments: <filename of the .ui file> -o <the python translation .py
which will serve as baseclass> -g python
Working directory: [your project dir]
Then signals and slots need to be connected manually, so QtCreator really only enables you to draw the user interface but all the logic still needs to be done by hand. Component variables are normally named after their UI name, but you can see for yourself in the baseclass file. This is a big step back from how QtCreator is used in C++ ("go to slot" will not work).
Code to use:
import sys
from PySide6.QtWidgets import QApplication, QMainWindow
from PySide6.QtCore import QFile
from PySide6.QtUiTools import QUiLoader
from YourGenPyFileName import Ui_YourUIName
class MainWindow(QMainWindow, Ui_YourUIName):
def __init__(self):
super(MainWindow, self).__init__()
self.setupUi(self)
if __name__ == "__main__":
app = QApplication([])
widget = MainWindow()
widget.show()
sys.exit(app.exec_())
I'm writing a program which will have multiple windows. I have a main program (attached) that calls the Ui files (that have been converted into .py). The main window and customise window open correctly (the first two listed) but neither the third or fourth windows open correctly, giving me the error
'Ui_MainWindow' object has no attribute 'show'
The main program;
from PyQt4 import QtCore, QtGui
import sys
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
mainwin = main_menu_ui.Ui_MainWindow()
mainwin.show()
sys.exit(app.exec_())
def openCustomise(self):
customiseOpen = question_set_menu_ui.Ui_MainWindow()
customiseOpen.show()
sys.exit(app.exec_())
def openQuiz(self):
quizOpen = quiz_window_ui.Ui_MainWindow()
quizOpen.show()
sys.exit(app.exec_())
def addNewSet(self):
addNewOpen = question_set_edit_ui.Ui_MainWindow()
addNewOpen.show()
sys.exit(app.exec_())
Sorry if I'm missing something obvious, I'm learning Qt/Python for college.
The auto-generated UI class that you are importing extends object and doesn't have a show method (open up the .py file for yourself and verify this).
In general, you should structure your GUIs like this:
from PyQt4 import QtCore, QtGui
import sys
from layout_file import main_menu_ui
class MyForm(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = main_menu_ui()
self.ui.setupUi(self)
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
mainwin = MyForm()
mainwin.show()
sys.exit(app.exec_())
You import your UI from your autogenerated UI file. You have a class that contains your GUI logic. It then sets up your UI layout from your imported UI in its __init__() method.
I tried compiling my .ui file via this:
pyuic4 gui.ui > gui.py
then I tried importing it, but I get:
ImportError: cannot import name GUI
I tried plenty of tutorials but none of them were helpful, they were all linux.
Is there a way I could modify my gui.py and use it like a normal program?
EDIT:
Figured it out!
much easier then I thought
import sys
from PyQt4 import QtCore, QtGui, uic
form_class = uic.loadUiType("gui.ui")[0] # Load the UI
class MyWindowClass(QtGui.QMainWindow, form_class):
def __init__(self, parent=None):
QtGui.QMainWindow.__init__(self, parent)
self.setupUi(self)
app = QtGui.QApplication(sys.argv)
myWindow = MyWindowClass(None)
myWindow.show()
app.exec_()
If your want to run directly your ui form without subclassing it you can use '-x' parameter with uic;
pyuic4 -x gui.ui -o gui.py
I've created many GUI interfaces in PyQT using QT Designer, but now I'm trying to open an interface from another one, and I don't know how to do it..
Start.py is the file which run the GUI Interface Authentification_1 and Acceuil_start.py is the file which run the GUI interface Acceuil_2.py, now I want from Start.py to lunch Acceuil_start.py.
Do you have any idea about that ? Thank you.
Here's my code :
Start.py :
import sys
from PyQt4 import QtCore, QtGui
from Authentification_1 import Ui_Fenetre_auth
from Acceuil_2 import Ui_MainWindow #??? Acceuil_2.py is the file which I want to open
class StartQT4(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_Fenetre_auth()
self.ui.setupUi(self)
def authentifier(val): #Slot method
self.Acceuil = Acceuil() #???
self.Acceuil.show() #???
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = StartQT4()
myapp.show()
sys.exit(app.exec_())
Acceuil_start.py
import sys
from PyQt4 import QtCore, QtGui
from Authentification_1 import Ui_Fenetre_auth
from Acceuil_2 import Ui_MainWindow
class StartQT4(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_MainWindow()
self.ui.setupUi(self)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = StartQT4()
myapp.show()
sys.exit(app.exec_())
First, you should to name your GUI classes so they have a different name, and not the generic one, so you could distinct them.
Why you would need to do that? Well - simply, because it makes sense - if every class is representing different type of dialog, so it is the different type - and it should be named differently. Some of the names are/may be: QMessageBox, AboutBox, AddUserDialog, and so on.
In Acceuil_start.py (you should rename class in other module, too).
import sys
from PyQt4 import QtCore, QtGui
from Authentification_1 import Ui_Fenetre_auth
from Acceuil_2 import Ui_MainWindow
class Acceuil(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_MainWindow()
self.ui.setupUi(self)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = Acceuil()
myapp.show()
sys.exit(app.exec_())
in the parent class, when you want to create the window, you are close (but it should work in any case):
def authentifier(val): #Slot method
self.Acceuil = Acceuil(self) # You should always pass the parent to the child control
self.Acceuil.show() #???
About parent issue: If your widget/window is creating another widget, setting creator object to be parent is always a good idea (apart from some singular cases), and you should read this to see why is that so:
QObjects organize themselves in object trees. When you create a QObject with another object as parent, it's added to the parent's children() list, and is deleted when the parent is. It turns out that this approach fits the needs of GUI objects very well. For example, a QShortcut (keyboard shortcut) is a child of the relevant window, so when the user closes that window, the shorcut is deleted too.
Edit - Minimal Working Sample
To see what I am trying to tell you, I've built a simple example. You have two classes - MainWindow and
ChildWindow. Every class can work without other class by creating separate QApplication objects. But, if you import ChildWindow in MainWindow, you will create ChildWindow in slot connected to singleshot timer which will trigger in 5 seconds.
MainWindow.py:
import sys
from PyQt4 import QtCore, QtGui
from ChildWindow import ChildWindow
class MainWindow(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
QtCore.QTimer.singleShot(5000, self.showChildWindow)
def showChildWindow(self):
self.child_win = ChildWindow(self)
self.child_win.show()
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = MainWindow()
myapp.show()
sys.exit(app.exec_())
ChildWindow.py:
import sys
from PyQt4 import QtCore, QtGui
class ChildWindow(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.setWindowTitle("Child Window!")
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = ChildWindow()
myapp.show()
sys.exit(app.exec_())
To reference the other dialog from Start.py, you must prefix it by the module name, which in this case is Acceuil_start. As such, it is OK if there are duplicated function names in each module. So, you would have:
def authentifier(val): #Slot method
dlg = Acceuil_start.StartQT4()
dlg.exec_()
However, if you want these to run from the same process, keep in mind that you can't have two app objects. You would probably want to structure Acceuil_start.py to act like a dialog, rather than a main window. If these are two distinct main windows, you might find it easier to just invoke another Python interpreter with the Acceuil_start.py as a parameter.
I am working on pyqt4 and python26 application.I created forms using qt designer (.ui files).
I converted them to .py and .pyc files.But when i try to run .py file ,python command line comes and goes within a second,the form (corresponding .ui file) cannot be seen...what can be the problem??
this is my code:(.py file)
from DlgAbout_ui import Ui_DlgAbout
from PyQt4.QtCore import *
from PyQt4.QtGui import *
import resources
class DlgAbout(QDialog, Ui_DlgAbout):
def __init__(self, parent=None):
QDialog.__init__(self, parent)
self.setupUi(self)
self.logo.setPixmap( QPixmap( ":/icons/faunalia_logo.png" ) )
text = self.txt.toHtml()
text = text.replace( "$PLUGIN_NAME$", "RT Sql Layer" )
self.txt.setHtml(text)
First, don't use:
from PyQt4.QtCore import *
from PyQt4.QtGui import *
Instead:
from PyQt4 import QtCore, QtGui
And reference the modules explicitly.
class DlgAbout(QtGui.QDialog, Ui_DlgAbout):
etc.
In your code, all you've done is defined a dialog box. You haven't defined any main application to run, or any way to show the dialog box.
For an example, here's a basic main application to run:
from PyQt4 import QtGui
import sys
class MyMainWindow(QtGui.QMainWindow):
def __init__(self, parent=None):
super(MyMainWindow, self).__init__(parent)
self.form_widget = FormWidget(self)
self.setCentralWidget(self.form_widget)
class FormWidget(QtGui.QWidget):
def __init__(self, parent):
super(FormWidget, self).__init__(parent)
self.layout = QtGui.QVBoxLayout(self)
self.button = QtGui.QPushButton("Button!")
self.layout.addWidget(self.button)
if __name__ == "__main__":
app = QtGui.QApplication([])
foo = MyMainWindow()
foo.show()
sys.exit(app.exec_())
This defines a main window, and a form (Which MyMainWindow sets up, as you can see).
I then check if this is the main file being run (if __name__ == "__main__":), and I start the application (The app = QtGui.QApplication([]), create the main window, and show the main window.
In your case, you could define a main application like I did, and make it alert your QDialog.
Your python code just imports some modules and then defines a new class. It doesn't do anything with the class it has defined, though. In other words, once Python is done creating the new class, it is finished, and it exits.
I don't know PyQT at all, but most likely you need to start the GUI's main loop, and also instantiate an instance of your new class and pass it to PyQT.