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I am getting an error TypeError: 'float' object cannot be interpreted as an integerin this part of my code. Can someone tell me why am I getting the error and how to fix it?
for y in range(-x/2, x/2):
#Some function
Replace -x/2 with -int(x/2) and x/2 with int(x/2). Division in Python returns a float and range only takes ints.
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I have column with this kind of data:
I want to count how many times valu occur in a row. It is a string, so I want to convert this '63,63,63,63,63,63,63,63,63,63,63' to this ['63','63','63'...].
I there any way to do this quickly?
Thanks
if given string is s
l=s.split(',')
l is the required list
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Can someone give a suitable example of the XOR Operator in Python ? I understand its definition but couldn’t implement it. So, please explain with a suitable example.
Thanks in advance
This is a fair enough implementation:
def xor(a:bool, b:bool)->bool:
return (not a) == (b)
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Suppose I have the some code in which I used map() function.
I know I can later print it by converting it to list just like this :
get_something = map(some_function, some_list)
print(list(get_something))
But Is there any way other than list. I mean what if I want to print not as list but line by line and don't want to use for loop every now and then?
Why dont you try this:
print(*map(some_function, some_list),sep='\n')
By this print() will refer to map object and will print values with \n as a separator
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How should I do to divide years in half a year in this case if running in Python code?
I wasn't sure if you wanted horizontal or vertical divisions so I gave you both.
More practically, maybe this answer will help?
Creating numpy linspace out of datetime
You can specify start and end date and the number of divisions.
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How can I convert ASCII strings to Hex strings in Python ? Is there any built in function I can use for this ?
It depends on exactly what you mean by "ASCII to hex", but you should be able to adapt this approach to get whatever you're looking for:
>>> foo = "foo"
>>> ''.join(hex(ord(c))[2:] for c in foo)
'666f6f'