I want to make a json file with results taken from my database so, i am taking the results from database and i am making the json :
for result in data_list:
json_data.append(dict(zip(column_names, result)))
json_out = json.dumps(json_data, indent=4)
My json out is something like :
[{"name" : "Jhon", "surname" : "smith"} , {"name" : "george", "surname" : "black"}]
But i want to be like
["employees":{{"name" : "Jhon", "surname" : "smith"} , {"name" :"george","surname" : "black"}}]
How is tha possible??
Since your expected output is not valid JSON (or makes sense in the first place), you should have a Python dictionary with an element called employees and assign json_data to it.
Then, you call json_dumps() on that dictionary:
for result in data_list:
json_data.append(dict(zip(column_names, result)))
final_json = {} # this is the Python dict I was talking about
final_json['employees'] = json_data
json_out = json.dumps(final_json, indent=4)
Result:
{
"employees": [
{
"surname": "so",
"name": "gi"
},
{
"surname": "lo",
"name": "lo"
}
]
}
This is a good representation of the data you want, because you're representing a static list of employees, which must be represented as an array.
You can try tablib
import tablib
headers = ["name", "surname"]
data = [
("jhon", "smit"),
("george", "black")
]
data = tablib.Dataset(*data, headers=headers)
data.json
Result:
[{"name": "jhon", "surname": "smit"}, {"name": "george", "surname": "black"}]
Related
This question already has answers here:
Python list of dictionaries search
(24 answers)
Closed last month.
First, I am new to Python and working with JSON.
I am trying to extract just one value from an API request response, and I am having a difficult time parsing out the data I need.
I have done a lot of searching on how to do this, but most all the examples use a string or file that is formatted is much more basic than what I am getting.
I understand the key - value pair concept but I am unsure how to reference the key-value I want. I think it has something to do with the response having multiple objects having the same kay names. Or maybe the first line "Bookmark" is making things goofy.
The value I want is for the model name in the response example below.
That's all I need from this. Any help would be greatly appreciated.
{
"Bookmark": "<B><P><p>SerNum</p><p>Item</p></P><D><f>false</f><f>false</f></D><F><v>1101666</v><v>ADDMASTER IJ7102-23E</v></F><L><v>123456</v><v>Model Name</v></L></B>",
"Items": [
[
{
"Name": "SerNum",
"Value": "123456"
},
{
"Name": "Item",
"Value": "Model Name"
},
{
"Name": "_ItemId",
"Value": "PBT=[unit] unt.DT=[2021-07-28 08:20:33.513] unt.ID=[eae2621d-3e9f-4515-9763-55e67f65fae6]"
}
]
],
"Message": "Success",
"MessageCode": 0
}
If you want to find value of dictionary with key 'Name' and value 'Item' you can do:
import json
with open('your_data.json', 'r') as f_in:
data = json.load(f_in)
model_name = next((i['Value'] for lst in data['Items'] for i in lst if i['Name'] == 'Item'), 'Model name not found.')
print(model_name)
Prints:
Model Name
Note: if the dictionary is not found string 'Model name not found.' is returned
First, load the JSON into a python dict:
import json
x = '''{
"Bookmark": "<B><P><p>SerNum</p><p>Item</p></P><D><f>false</f><f>false</f></D><F><v>1101666</v><v>ADDMASTER IJ7102-23E</v></F><L><v>123456</v><v>Model Name</v></L></B>",
"Items": [
[
{
"Name": "SerNum",
"Value": "123456"
},
{
"Name": "Item",
"Value": "Model Name"
},
{
"Name": "_ItemId",
"Value": "PBT=[unit] unt.DT=[2021-07-28 08:20:33.513] unt.ID=[eae2621d-3e9f-4515-9763-55e67f65fae6]"
}
]
],
"Message": "Success",
"MessageCode": 0
}'''
# parse x:
y = json.loads(x)
# The result is a Python dictionary.
Now if you want the value 'Model Name', you would do:
print(y['Items'][0][1]['Value'])
resp = {
"Name": "test",
"os": "windows",
"Agent": {
"id": "2",
"status": [
{
"code": "123",
"level": "Info",
"displayStatus": "Ready",
"message": "running",
"time": "2022-01-18T09:51:08+00:00"
}
]
}
I am trying to get the time value from the JSON.
I tried the below code but faced error with dict
resp1 = json.loads(resp)
resp2 = resp1.values()
creation_time = resp2.get("Agent").get("status")
val= creation_time["time"]
print(val) ## Thrwoing error as dict_values has no 'get'
Any suggestion on python how to take this time values
Few problems I noticed
You are trying to load a Dict type using the json's loads function which is supposed to get a string in json format (ex: '{ "name":"John", "age":30, "city":"New York"}')
You tried to access resp2 before declaration (I guessed you meant "resp1?")
You're using resp3 without declaration.
You are missing }
You don't need the .value() function because it will return a list.
Also creation time is a list with one object, so you need to access it too.
Considering all this, you can change it as follows:
import json
resp = '{ "Name": "test", "os": "windows","Agent": {"id": "2","status": [{"code": "123","level": "Info","displayStatus": "Ready","message": "running","time": "2022-01-18T09:51:08+00:00"}]}}'
resp1 = json.loads(resp)
creation_time = resp1.get("Agent").get("status")
val= creation_time[0]["time"]
print(val)
You just need to access the dicts using [] like so:
resp = {"Name": "test", "os": "windows", "Agent": {"id": "2","status": [{"code": "123","level": "Info","displayStatus": "Ready","message": "running","time": "2022-01-18T09:51:08+00:00"}]}}
creation_time = resp["Agent"]["status"]
val= creation_time[0]["time"]
print(val)
Output:
2022-01-18T09:51:08+00:00
I'm very new to programming so excuse any terrible explanations. Basically I have 1000 json files all that need to have the same text added to the end. Here is an example:
This is what it looks like now:
{"properties": {
"files": [
{
"uri": "image.png",
"type": "image/png"
}
],
"category": "image",
"creators": [
{
"address": "wallet address",
"share": 100
}
]
}
}
Which I want to look like this:
{"properties": {
"files": [
{
"uri": "image.png",
"type": "image/png"
}
],
"category": "image",
"creators": [
{
"address": "wallet address",
"share": 100
}
]
},
"collection": {"name": "collection name"}
}
I've tried my best with append and update but it always tells me there is no attribute to append. I also don't really know what I'm doing.
This will be embarrassing but here is what I tried and failed.
import json
entry= {"collection": {"name": "collection name"}}
for i in range((5)):
a_file = open("./testjsons/" + str(i) + ".json","r")
json_obj = json.load(a_file)
print(json_obj)
json_obj["properties"].append(entry)
a_file = open(str(i) + ".json","w")
json.dump(json_obj,a_file,indent=4)
a_file.close()
json.dump(a_file, f)
Error code: json_obj["properties"].append(entry)
AttributeError: 'dict' object has no attribute 'append'
you don't use append() to add to a dictionary. You can either assign to the key to add a single entry, or use .update() to merge dictionaries.
import json
entry= {"collection": {"name": "collection name"}}
for i in range((5)):
with open("./testjsons/" + str(i) + ".json","r") as a_file:
a_file = open("./testjsons/" + str(i) + ".json","r")
json_obj = json.load(a_file)
print(json_obj)
json_obj.update(entry)
with open(str(i) + ".json","w") as a_file:
json.dump(json_obj,a_file,indent=4)
JSON, like XML, is a specialized data format. You should always parse the data and work with it as JSON where possible. This is different from a plain text file where you would 'add to the end' or 'append' text.
There are a number of json parsing libraries in Python, but you'll probably want to use the json encoder that is built in to the standard Python library. For a file, myfile.json, you can:
import json
with open('myfile.json`, 'r') as f:
myfile = json.load(f) # read the file into a Python dict
myfile["collection"] = {"name": "collection name"} # here you're adding the "collection" field to the end of the Python dict
# If you want to add "collection" inside "properties", you'd do something like
#. myfile["properties"]["collection"] = {"name": "collection name"}
with open('myfile.json', 'w') as f:
json.dump(myfile, f) # save the modified dict into the json file
I have below sample data in JSON format :
project_cost_details is my database result set after querying.
{
"1": {
"amount": 0,
"breakdown": [
{
"amount": 169857,
"id": 4,
"name": "SampleData",
"parent_id": "1"
}
],
"id": 1,
"name": "ABC PR"
}
}
Here is full json : https://jsoneditoronline.org/?id=2ce7ab19af6f420397b07b939674f49c
Expected output :https://jsoneditoronline.org/?id=56a47e6f8e424fe8ac58c5e0732168d7
I have this sample JSON which i created using loops in code. But i am stuck at how to convert this to expected JSON format. I am getting sequential changes, need to convert to tree like or nested JSON format.
Trying in Python :
project_cost = {}
for cost in project_cost_details:
if cost.get('Parent_Cost_Type_ID'):
project_id = str(cost.get('Project_ID'))
parent_cost_type_id = str(cost.get('Parent_Cost_Type_ID'))
if project_id not in project_cost:
project_cost[project_id] = {}
if "breakdown" not in project_cost[project_id]:
project_cost[project_id]["breakdown"] = []
if 'amount' not in project_cost[project_id]:
project_cost[project_id]['amount'] = 0
project_cost[project_id]['name'] = cost.get('Title')
project_cost[project_id]['id'] = cost.get('Project_ID')
if parent_cost_type_id == cost.get('Cost_Type_ID'):
project_cost[project_id]['amount'] += int(cost.get('Amount'))
#if parent_cost_type_id is None:
project_cost[project_id]["breakdown"].append(
{
'amount': int(cost.get('Amount')),
'name': cost.get('Name'),
'parent_id': parent_cost_type_id,
'id' : cost.get('Cost_Type_ID')
}
)
from this i am getting sample JSON. It will be good if get in this code only desired format.
Also tried this solution mention here : https://adiyatmubarak.wordpress.com/2015/10/05/group-list-of-dictionary-data-by-particular-key-in-python/
I got approach to convert sample JSON to expected JSON :
data = [
{ "name" : "ABC", "parent":"DEF", },
{ "name" : "DEF", "parent":"null" },
{ "name" : "new_name", "parent":"ABC" },
{ "name" : "new_name2", "parent":"ABC" },
{ "name" : "Foo", "parent":"DEF"},
{ "name" : "Bar", "parent":"null"},
{ "name" : "Chandani", "parent":"new_name", "relation": "rel", "depth": 3 },
{ "name" : "Chandani333", "parent":"new_name", "relation": "rel", "depth": 3 }
]
result = {x.get("name"):x for x in data}
#print(result)
tree = [];
for a in data:
#print(a)
if a.get("parent") in result:
parent = result[a.get("parent")]
else:
parent = ""
if parent:
if "children" not in parent:
parent["children"] = []
parent["children"].append(a)
else:
tree.append(a)
Reference help : http://jsfiddle.net/9FqKS/ this is a JavaScript solution i converted to Python
It seems that you want to get a list of values from a dictionary.
result = [value for key, value in project_cost_details.items()]
I'm using the following python code to connect to a jsonrpc server and nick some song information. However, I can't work out how to get the current title in to a variable to print elsewhere. Here is the code:
TracksInfo = []
for song in playingSongs:
data = { "id":1,
"method":"slim.request",
"params":[ "",
["songinfo",0,100, "track_id:%s" % song, "tags:GPASIediqtymkovrfijnCYXRTIuwxN"]
]
}
params = json.dumps(data, sort_keys=True, indent=4)
conn.request("POST", "/jsonrpc.js", params)
httpResponse = conn.getresponse()
data = httpResponse.read()
responce = json.loads(data)
print json.dumps(responce, sort_keys=True, indent=4)
TrackInfo = responce['result']["songinfo_loop"][0]
TracksInfo.append(TrackInfo)
This brings me back the data in json format and the print json.dump brings back:
pi#raspberrypi ~/pithon $ sudo python tom3.py
{
"id": 1,
"method": "slim.request",
"params": [
"",
[
"songinfo",
"0",
100,
"track_id:-140501481178464",
"tags:GPASIediqtymkovrfijnCYXRTIuwxN"
]
],
"result": {
"songinfo_loop": [
{
"id": "-140501481178464"
},
{
"title": "Witchcraft"
},
{
"artist": "Pendulum"
},
{
"duration": "253"
},
{
"tracknum": "1"
},
{
"type": "Ogg Vorbis (Spotify)"
},
{
"bitrate": "320k VBR"
},
{
"coverart": "0"
},
{
"url": "spotify:track:2A7ZZ1tjaluKYMlT3ItSfN"
},
{
"remote": 1
}
]
}
}
What i'm trying to get is result.songinfoloop.title (but I tried that!)
The songinfo_loop structure is.. peculiar. It is a list of dictionaries each with just one key.
Loop through it until you have one with a title:
TrackInfo = next(d['title'] for d in responce['result']["songinfo_loop"] if 'title' in d)
TracksInfo.append(TrackInfo)
A better option would be to 'collapse' all those dictionaries into one:
songinfo = reduce(lambda d, p: d.update(p) or d,
responce['result']["songinfo_loop"], {})
TracksInfo.append(songinfo['title'])
songinfo_loop is a list not a dict. That means you need to call it by position, or loop through it and find the dict with a key value of "title"
positional:
responce["result"]["songinfo_loop"][1]["title"]
loop:
for info in responce["result"]["songinfo_loop"]:
if "title" in info.keys():
print info["title"]
break
else:
print "no song title found"
Really, it seems like you would want to have the songinfo_loop be a dict, not a list. But if you need to leave it as a list, this is how you would pull the title.
The result is really a standard python dict, so you can use
responce["result"]["songinfoloop"]["title"]
which should work