We Keep Coding

cant save an 4d array int .txt file

I am using the sliding window technic to an image and i am extracting the mean values of pixels of each one window. So the results are someting like this [[[[215.015625][123.55036272][111.66057478]]]].now the question is how could i save all these values for every one window into a txt file or at a CSV because i want to use them for further compare similarities? whatever i tried the error is same..that it is a 4D array and not an 1D or 2D. I ll appreciate any help really.! Thank you in advance
import cv2
import matplotlib.pyplot as plt
import numpy as np
# read the image and define the stepSize and window size
# (width,height)
image2 = cv2.imread("bird.jpg")# your image path
image = cv2.resize(image2, (224, 224))
tmp = image # for drawing a rectangle
stepSize = 10
(w_width, w_height) = (60, 60 ) # window size
for x in range(0, image.shape[1] - w_width, stepSize):
for y in range(0, image.shape[0] - w_height, stepSize):
window = image[x:x + w_width, y:y + w_height, :]
# classify content of the window with your classifier and
# determine if the window includes an object (cell) or not
# draw window on image
cv2.rectangle(tmp, (x, y), (x + w_width, y + w_height), (255, 0, 0), 2) # draw rectangle on image
plt.imshow(np.array(tmp).astype('uint8'))
# show all windows
plt.show()
mean_values=[]
mean_val, std_dev = cv2.meanStdDev(image)
mean_val = mean_val[:3]
mean_values.append([mean_val])
mean_values = np.asarray(mean_values)
print(mean_values)

Human Readable Option
Assuming that you want the data to be human readable, saving the data takes a little bit more work. My search showed me that there's this solution for saving 3D data to a text file. However, it's pretty simple to extend this example to 4D for your use case. This code is taken and adapted from that post, thank you Joe Kington and David Cheung.
import numpy as np
data = np.arange(2*3*4*5).reshape((2,3,4,5))
with open('test.csv', 'w') as outfile:
# We write this header for readable, the pound symbol
# will cause numpy to ignore it
outfile.write('# Array shape: {0}\n'.format(data.shape))
# Iterating through a ndimensional array produces slices along
# the last axis. This is equivalent to data[i,:,:] in this case.
# Because we are dealing with 4D data instead of 3D data,
# we need to add another for loop that's nested inside of the
# previous one.
for threeD_data_slice in data:
for twoD_data_slice in threeD_data_slice:
# The formatting string indicates that I'm writing out
# the values in left-justified columns 7 characters in width
# with 2 decimal places.
np.savetxt(outfile, twoD_data_slice, fmt='%-7.2f')
# Writing out a break to indicate different slices...
outfile.write('# New slice\n')
And then once the data has been saved all you need to do is load it and reshape it (np.load()) will default to reading in the data as a 2D array but np.reshape() will allow us to recover the structure. Again, this code is adapted from the previous post.
new_data = np.loadtxt('test.csv')
# Note that this returned a 2D array!
print(new_data.shape)
# However, going back to 3D is easy if we know the
# original shape of the array
new_data = new_data.reshape((2,3,4,5))
# Just to check that they're the same...
assert np.all(new_data == data)
Binary Option
Assuming that human readability is not necessary, I would recommend using the built-in *.npy format which is described here. This stores the data in a binary format.
You can save the array by doing np.save('NAME_OF_ARRAY.npy', ARRAY_TO_BE_SAVED) and then load it with SAVED_ARRAY = np.load('NAME_OF_ARRAY.npy').
You can also save several numpy array in a single zip file with the np.savez() function like so np.savez('MANY_ARRAYS.npz', ARRAY_ONE, ARRAY_TWO). And you load the zipped arrays in a similar fashion SEVERAL_ARRAYS = np.load('MANY_ARRAYS.npz').

How to do alpha compositing with a list of RGBA data in numpy arrays?

Following this formula for alpha blending two color values, I wish to apply this to n numpy arrays of rgba image data (though the expected use-case will, in practice, have a very low upper bound of arrays, probably > 5). In context, this process will be constrained to arrays of identical shape.
I could in theory achieve this through iteration, but expect that this would be computationally intensive and terribly inefficient.
What is the most efficient way to apply a function between two elements in the same position between two arrays across the entire array?
A loose example:
# in context, the numpy arrays come from here, as either numpy data in the
# first place or a path
def import_data(source):
# first test for an extant numpy array
try:
assert(type(source) is np.ndarray)
data = source
except AssertionError:
try:
exists(source)
data = add_alpha_channel(np.array(Image.open(source)))
except IOError:
raise IOError("Cannot identify image data in file '{0}'".format(source))
except TypeError:
raise TypeError("Cannot identify image data from source.")
return data
# and here is the in-progress method that will, in theory composite the stack of
# arrays; it context this is a bit more elaborate; self.width & height are just what
# they appear to be—-the final size of the composited output of all layers
def render(self):
render_surface = np.zeros((self.height, self.width, 4))
for l in self.__layers:
foreground = l.render() # basically this just returns an np array
# the next four lines just find the regions between two layers to
# be composited
l_x1, l_y1 = l.origin
l_x2 = l_x1 + foreground.shape[1]
l_y2 = l_y1 + foreground.shape[0]
background = render_surface[l_y1: l_y2, l_x1: l_x2]
# at this point, foreground & background contain two identically shaped
# arrays to be composited; next line is where the function i'm seeking
# ought to go
render_surface[l_y1: l_y2, l_x1: l_x2] = ?

Starting with these two RGBA images:
I implemented the formula you linked to and came up with this:
#!/usr/local/bin/python3
from PIL import Image
import numpy as np
# Open input images, and make Numpy array versions
src = Image.open("a.png")
dst = Image.open("b.png")
nsrc = np.array(src, dtype=np.float)
ndst = np.array(dst, dtype=np.float)
# Extract the RGB channels
srcRGB = nsrc[...,:3]
dstRGB = ndst[...,:3]
# Extract the alpha channels and normalise to range 0..1
srcA = nsrc[...,3]/255.0
dstA = ndst[...,3]/255.0
# Work out resultant alpha channel
outA = srcA + dstA*(1-srcA)
# Work out resultant RGB
outRGB = (srcRGB*srcA[...,np.newaxis] + dstRGB*dstA[...,np.newaxis]*(1-srcA[...,np.newaxis])) / outA[...,np.newaxis]
# Merge RGB and alpha (scaled back up to 0..255) back into single image
outRGBA = np.dstack((outRGB,outA*255)).astype(np.uint8)
# Make into a PIL Image, just to save it
Image.fromarray(outRGBA).save('result.png')
Output image

Image of Mnist data Python - Error when displaying the image

I'm working with the Mnist data set, in order to learn about Machine learning, and as for now I'm trying to display the first digit in the Mnist data set as an image, and I have encountered a problem.
I have a matrix with the dimensions 784x10000, where each column is a digit in the data set. I have created the matrix myself, because the Mnist data set came in the form of a text file, which in itself caused me quite a lot of problems, but that's a question for itself.
The MN_train matrix below, is my large 784x10000 matrix. So what I'm trying to do below, is to fill up a 28x28 matrix, in order to display my image.
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.image as mpimg
grey = np.zeros(shape=(28,28))
k = 0
for l in range(28):
for p in range(28):
grey[p,l]=MN_train[k,0]
k = k + 1
print grey
plt.show(grey)
But when I try to display the image, I get the following error:
The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
Followed by a image plot that does not look like the number five, as I would expect.
Is there something I have overlooked, or does this tell me that my manipulation of the text file, in order to construct the MN_train matrix, has resulted in an error?

The error you get is because you supply the array to show. show accepts only a single boolean argument hold=True or False.
In order to create an image plot, you need to use imshow.
plt.imshow(grey)
plt.show() # <- no argument here
Also note that the loop is rather inefficient. You may just reshape the input column array.
The complete code would then look like
import numpy as np
import matplotlib.pyplot as plt
MN_train = np.loadtxt( ... )
grey = MN_train[:,0].reshape((28,28))
plt.imshow(grey)
plt.show()

Moving/running window of a Multi-dimensional image array

I am trying to work on an efficient numpy solution to perform a running average of an array of color images across the 4th dimension. A set of color images in a directory is read in a loop and I would like to average in subsets of 3. ie. If there are n = 5 color images in the directory I would like to average [1,2,3],[2,3,4], [3,4,5], [4,5,1], and [5,1,2] thus writing 5 output average images.
from os import listdir
from os.path import isfile, join
import numpy as np
import cv2
from matplotlib import pyplot as plt
mypath = 'C:/path/to/5_image/dir'
onlyfiles = [f for f in listdir(mypath) if isfile(join(mypath, f))]
img = np.empty(len(onlyfiles), dtype=object)
temp = np.zeros((960, 1280, 3, 3), dtype='uint8')
temp_avg = np.zeros((960, 1280, 3), dtype='uint8')
for n in range(0, len(onlyfiles)):
img[n] = cv2.imread(join(mypath, onlyfiles[n]))
for n in range(0, len(img)):
if (n+2) < len(img)-1:
temp[:, :, :, 0] = img[n]
temp[:, :, :, 1] = img[n + 1]
temp[:, :, :, 2] = img[n + 2]
temp_avg = np.mean(temp,axis=3)
plt.imshow(temp_avg)
plt.show()
else:
break
This script is in no way complete or elegant. The issues i am having is while plotting the average images the color space seems distorted and appears like CMKY. I am not accounting for the last two moving windows [4,5,1] and [5,1,2]. Critique and suggestions welcome.

For performing local operations (such as a running average) across the pixels of an image (or across multiple images), convolution with a kernel is usually a good approach.
Here's how this could be done in your case.
Generating Some Example Data
I used the following to generate 10 images containing random noise to work with:
for i in range(10):
an_img = np.random.randint(0, 256, (960,1280,3))
cv2.imwrite("img_"+str(i)+".png", an_img)
Preparing the Images
This is how I load the images back in:
# Get target file names
mypath = os.getcwd() # or whatever path you like
fnames = [f for f in listdir(mypath) if f.endswith('.png')]
# Create an array to hold all the images
first_img = cv2.imread(join(mypath, fnames[0]))
y,x,c = first_img.shape
all_imgs = np.empty((len(fnames),y,x,c), dtype=np.uint8)
# Load all the images
for i,fname in enumerate(fnames):
all_imgs[i,...] = cv2.imread(join(mypath, fnames[i]))
Some notes:
I use f.endswith('.png') to be a bit more specific with how I generate the list of filenames, allowing other files to be in the same directory without causing problems.
I place all of the images in a single 4D uint8 array of shape (image,y,x,c) instead of the object array you were using. This is necessary to employ the convolution approach below.
I use the first image to get the dimensions of the images, which makes the code just a little bit more general.
Performing Local Averaging by Kernel Convolution
This is all it takes.
from scipy.ndimage import uniform_filter
done = uniform_filter(all_imgs, size=(3,0,0,0), origin=-1, mode='wrap')
Some notes:
I am using scipy.ndimage because it readily allows for its convolution filters to be applied to images with many dimensions (4 in your case). For cv2, I am only aware of cv2.filter2D, which does not have that functionality as far as I know. However, I am not very familiar with cv2, so I may be wrong about this (will edit if someone corrects me in a comment).
The size kwarg specifies the size of the kernel to use along each dimension of the array. By using (3,0,0,0), I make sure that only the first dimension (=the different images) is used for the averaging.
By default, the running window (or rather the kernel) is used to compute the value of its central pixel. To match this more closely with your code, I used origin=-1, so the kernel computes the value of the pixel one to the left of its center.
By default, the edge cases (the two last images in this case) are handled by padding with a reflection. Your question suggests that what you want is to use the first images again instead. This is done using mode='wrap'.
By default, the filter returns the result in the same dtype as the input, here np.uint8. This is probably desirable, but your example code produces floats, so perhaps you want the filter to return floats as well, which you can do by simply changing the dtype of the input, i.e. done = uniform_filter(all_imgs.astype(np.float), size....
As for the distorted color space when you plot your averages; I cannot reproduce that. Your approach seems to produce the correct output for my random noise example images (after correction of the issue I pointed out in my comment to your question). Perhaps you could try plt.imshow(temp_avg, interpolation='none') to avoid possible artefacting from imshow's interpolation?

OpenCV - Fastest method to check if two images are 100% same or not

There are many questions over here which checks if two images are "nearly" similar or not.
My task is simple. With OpenCV, I want to find out if two images are 100% identical or not.
They will be of same size but can be saved with different filenames.

You can use a logical operator like xor operator. If you are using python you can use the following one-line function:
Python
def is_similar(image1, image2):
return image1.shape == image2.shape and not(np.bitwise_xor(image1,image2).any())
where shape is the property that shows the size of matrix and bitwise_xor is as the name suggests. The C++ version can be made in a similar way!
C++
Please see #berak code.
Notice: The Python code works for any depth images(1-D, 2-D, 3-D , ..), but the C++ version works just for 2-D images. It's easy to convert it to any depth images by yourself. I hope that gives you the insight! :)
Doc: bitwise_xor
EDIT: C++ was removed. Thanks to #Micka and # berak for their comments.

the sum of the differences should be 0 (for all channels):
bool equal(const Mat & a, const Mat & b)
{
if ( (a.rows != b.rows) || (a.cols != b.cols) )
return false;
Scalar s = sum( a - b );
return (s[0]==0) && (s[1]==0) && (s[2]==0);
}

import cv2
import numpy as np
a = cv2.imread("picture1.png")
b = cv2.imread("picture2.png")
difference = cv2.subtract(a, b)
result = not np.any(difference)
if result is True:
print("Pictures are the same")
else:
print("Pictures are different")

If they are same files except being saved in different file-names, you can check whether their Checksums are identical or not.

Importing the packages we’ll need — matplotlib for plotting, NumPy for numerical processing, and cv2 for our OpenCV bindings. Structural Similarity Index method is already implemented for us by scikit-image, so we’ll just use their implementation
# import the necessary packages
from skimage.measure import structural_similarity as ssim
import matplotlib.pyplot as plt
import numpy as np
import cv2
Then define the compare_images function which we’ll use to compare two images using both MSE and SSIM. The mse function takes three arguments: imageA and imageB, which are the two images we are going to compare, and then the title of our figure.
We then compute the MSE and SSIM between the two images.
We also simply display the MSE and SSIM associated with the two images we are comparing.
def mse(imageA, imageB):
# the 'Mean Squared Error' between the two images is the
# sum of the squared difference between the two images;
# NOTE: the two images must have the same dimension
err = np.sum((imageA.astype("float") - imageB.astype("float")) ** 2)
err /= float(imageA.shape[0] * imageA.shape[1])
# return the MSE, the lower the error, the more "similar"
# the two images are
return err
def compare_images(imageA, imageB, title):
# compute the mean squared error and structural similarity
# index for the images
m = mse(imageA, imageB)
s = ssim(imageA, imageB)
# setup the figure
fig = plt.figure(title)
plt.suptitle("MSE: %.2f, SSIM: %.2f" % (m, s))
# show first image
ax = fig.add_subplot(1, 2, 1)
plt.imshow(imageA, cmap = plt.cm.gray)
plt.axis("off")
# show the second image
ax = fig.add_subplot(1, 2, 2)
plt.imshow(imageB, cmap = plt.cm.gray)
plt.axis("off")
# show the images
plt.show()
Load images off disk using OpenCV. We’ll be using original image, contrast adjusted image, and our Photoshopped image
We then convert our images to grayscale
# load the images -- the original, the original + contrast,
# and the original + photoshop
original = cv2.imread("images/jp_gates_original.png")
contrast = cv2.imread("images/jp_gates_contrast.png")
shopped = cv2.imread("images/jp_gates_photoshopped.png")
# convert the images to grayscale
original = cv2.cvtColor(original, cv2.COLOR_BGR2GRAY)
contrast = cv2.cvtColor(contrast, cv2.COLOR_BGR2GRAY)
shopped = cv2.cvtColor(shopped, cv2.COLOR_BGR2GRAY)
We will generate a matplotlib figure, loop over our images one-by-one, and add them to our plot. Our plot is then displayed to us.
Finally, we can compare our images together using the compare_images function.
# initialize the figure
fig = plt.figure("Images")
images = ("Original", original), ("Contrast", contrast), ("Photoshopped", shopped)
# loop over the images
for (i, (name, image)) in enumerate(images):
# show the image
ax = fig.add_subplot(1, 3, i + 1)
ax.set_title(name)
plt.imshow(image, cmap = plt.cm.gray)
plt.axis("off")
# show the figure
plt.show()
# compare the images
compare_images(original, original, "Original vs. Original")
compare_images(original, contrast, "Original vs. Contrast")
compare_images(original, shopped, "Original vs. Photoshopped")
Reference- https://www.pyimagesearch.com/2014/09/15/python-compare-two-images/

I have done this task.
Compare file sizes.
Compare exif data.
Compare first 'n' byte, where 'n' is 128 to 1024 or so.
Compare last 'n' bytes.
Compare middle 'n' bytes.
Compare checksum